Requirements gateway & regular expressions

I'm trying to create a regular expression that will match a Requirement ID type in a MS Word document using Requirements Gateway.
Our syntax for a Requirement ID is as follows:
    '* shall [::requirement id] *'
An example would be
    'The system shall [::requirement1] self destruct after 1 minute of use.'
I'm using the following RE.
    shall[ \t]*\[[ \t]*(.*):.+)\]
I've been able to get it to match 'most' of Requirement ID's ,but a few aren't caught...most noteably those Requirement ID's that run past the end of the
line.
When 'shall' is on one line and '[::requirement1]' is on the next, the Requirement ID isn't matched.
Are there any limitations to the RE engine that Requirements Gateway uses?
If not, any help with the RE would be MUCH appreciated.
thanks
Pat

Allen,
Thanks for the advice. Unfortunately it didn't help
Again, our requirements are identified by a 'shall' followed by a tag in brackets.
Ie The unit shall [<optional source>::requirement id] be expensive.
The RE, "shall\[(.*):.+)\]" doesn't always work. (Sorry for the embedded emoticon)
Most of the time it identifies the tag but says
Requirement ' : XYZ' can't be covered.
Error: Requirement defined several times
Other times is combines two tags into one.
I'm attaching the modifed type and the doc thats causing the problems.
Thanks for your continued help,
Pat

Similar Messages

Regular expression help needed

Hello experts,
I am looking to implement a search & replace regular expression
my regular expressions are as follows:
search regular expression = (test\\s+--\\s*)?this is a test(.*)?
replace regular expression = (new) brand new test$2
i.e. The results I require are
case 1
input string = test -- this is a test 1999
correct result = (new) brand new test 1999
or (since I require the regular expression to be optional)
case 2
input string = this is a test
correct result = brand new test
How do I implement this using pattern and matcher? Sample code would be useful
I am having difficulties because matcher.appendReplacement will always replace because my regular expressions are optional. (which is incorrect)
i.e. I am getting the following incorrect result ((new) is being appended)
input string = this is a test
incorrect result = (new) brand new test
At the moment my non working code is
StringBuffer sb = new StringBuffer();
Pattern pattern = Pattern.compile("(test\s+--\s*)?this is a test(.*)?");
Matcher matcher = pattern.matcher("this is a test");
if(matcher.find())
matcher.appendReplacement(sb, "(new) brand new test$2");
String result = sb.toString();
System.out.println(result);
}In the above scenario I want the output to be 'brand new test' without the (new) because the input string did not contain 'test --'
Hope this makes sense
Thanks

For example: StringBuffer sb = new StringBuffer();
Pattern pattern = Pattern.compile("(test\s+--\s*)?this is a test(.*)");
Matcher matcher = pattern.matcher("this is a test");
if(matcher.find())
matcher.appendReplacement(sb, ""); // copy everything before the match
if (matcher.start(1) != -1)
sb.append("(new) ");
sb.append("brand new test");
sb.append(matcher.group(2));
matcher.appendTail(sb); // copy everything after the match
System.out.println(sb.toString()); Because the first group is optional, you need to find out whether it participated in the match before you add the "(new) " bit. The second group doesn't need to be optional because (1) the subexpression with the group can match nothing, and (2) you don't need to perform a different action depending on what that group did. You just append the captured text, which may be an empty string.

NIRG LabVIEW regular expression for covering multiple requirements

The Word document type in NI Requirements Gateway allows for comma separating the requirements in a Reference / coverage statement. I would like to do the same within my LabVIEW code, but the type does not have the same Sub regular expression field available. Is there any way to have a LabVIEW regular expression find coverage statements such as the following:
[Covers: REQ-5, REQ-9, REQ-15]
currently within LabVIEW comments I have to have 3 separate [Covers: REQ-5] type statements

cdweiss,
I'm very interested to know if you have any other feedback on NI Requirements Gateway. I'd also be curious to know what products are you're using with it and how extensive your requirements are.
Feel free to email me directly at [email protected]
Cheers,
Eli
Message Edited by Elijah K on 01-19-2010 11:40 PM
Elijah Kerry
Senior Product Manager, LabVIEW
Follow my Software Engineering for LabVIEW Blog

Requirement to update a column by using Regular Expression

Hi All,
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based on the conditinos I need to update from ‘E’ to ‘Z’. Few positions I need to update and remaining positions I need leave as it is.
How I can achive this requirement by using regular expression regexp_replace.
Actual value --> 'AEAAAEAA    EE    AA    EE    AA    EE    EEEAA    AA    AA       '
After update --> 'AZAAAZAA    EE    AA    EE    AA    EE    EEEAA    AA    AA       '

below is my requirement. I am adding the conditions dynamically as per the conditions. I dont know the position of the E. If 'E' is in any position I need to update with 'Z' if that 'E' satisfy the condition.
I dont want to update all the E's to Z's.
I want to update specific E's which satisfy the condition.
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        l_where := l_where||' SUBSTR(OVERRIDEFIELD,1,1) = ''E'' OR ';
        l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\1';
    END IF;
    IF l_kwhilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,2,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\2';
    END IF;
    IF l_kvahilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,3,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\3';
    END IF;
    IF l_kvarhilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,4,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\4';
    END IF;
    IF l_todkwh1hilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,5,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\5';
    END IF;
    IF l_todkwh2hilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,6,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\6';
    END IF;
    l_exp := ''''||l_exp||'''';
    l_exp1 := '\1\2\3\4'||l_exp1;
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        l_where := l_where||' SUBSTR(OVERRIDEFIELD,11,1) = ''E'' OR ';
         l_exp1 := l_exp1||'Z';
    ELSE
        l_exp1 := l_exp1||'\5';
    END IF;
    IF l_todkw2hilow = 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,12,1) = ''E'' OR ';
         l_exp1 := l_exp1||'Z';
    ELSE
        l_exp1 := l_exp1||'\6';
    END IF;
    l_exp1 := ''''||l_exp1||'''';
IF i give 10 in the regexp_replace it is not working.
SET OVERRIDEFIELD =     REGEXP_REPLACE(SUBSTR(overridefield,1,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp||')'||
                                          ' ||REGEXP_REPLACE(SUBSTR(overridefield,7,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp1||')'||
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WebTest - VS2013 - Extract Regular Expression - Required=False

I have an "Extract Regular Expression" that may or may not be able to extract a value. I set the property value of Required to False. The next block checks for the existence of that Context Parameter. If the Context Parameter is there, it does
some work, if the Context Parameter is not there, it skips the condition.
When I run my WebTest, it tells me that it passes the extraction rule but it never created the Context Parameter so the condition is skipped.
If I set Required=True, everything works as expected.
I remembered that there was a defect in VS2010 with the Required=False, so I added this Extraction Plug-In
[DisplayName("Extract Regular Expression Not Required")]
[Description("Extract text matching a regex and add it to the test context. If no match is found, do not fail webtest. This gets around a VSTS bug where 'Required' property of the Extract Regular Expression rule is not honored.")]
public class ExtractRegularExpressionNotRequired : ExtractRegularExpression
public override void Extract(object sender, ExtractionEventArgs e)
base.Extract(sender, e);
e.Success = true;
That too passes the regular expression but fails to create the Context Parameter.

By setting the Required parameter to False, I am expecting that a Context Parameter does not get created if the regular expression is not found and that is does get created if the regular expression is found.
So when I run my test, it tells me that the regular expression was found but my Context Parameter was not created.
When I created this webtest in VS2010, I found that there was a bug with the Extract Regular Expression when the Required property was False. This
thread showed the code for a custom Extraction rule to fix the problem. When I run this webtest in VS2013, both the built-in Extract Regular Expression and the custom Extract Regular Expression Not Required are not creating the Context Parameter if the
regex is found.
Try this yourself:
Create a webtest
Add "Extract Regular Expression"
Set the Regular expression to . (this will match any one character)
Set the Requiredto False
Set the Context Parameter Name to TEST
Run the webtest
Although the result from the extraction rule will be Passed, there is no Context Parameter TEST created.
If you create the custom Extract Regular Expression Not Required plugin, the same problem occurs.

Regular Expression help required

{color:#000000}Hi....
I am having a product table in oracle with products like CZS20T and CZSS30T and so on....
But for printing on the invoice we need only the product name without the micron thickness like CZS and CZSS{color}{color:#000000}
I tried regular expression with....."select regexp_substr('CZSS20T','([[:digit:]]{2})') from dual"
{color}
and the result was "20"*...*
But I cant figure out how to use regular expression to get only the product name.
Maybe there is another way without using Regular exp...
Please help....

regexp_substr (prod, '[[:alpha:]]*')and an example:
SQL> with x as
2 ( select 'CZS20T' prod from dual union all
3    select 'CZSS30T' from dual union all
4    select 'A10CSD' from dual
5 )
6 select prod
7       , regexp_substr (prod, '[[:alpha:]]*')
8    from x
9 ;
PROD    REGEXP_SUBSTR(PROD,'[[:ALPHA
CZS20T CZS
CZSS30T CZSS
A10CSD A
SQL> Edited by: Alex Nuijten on Jan 27, 2009 8:52 AM

Regular expression not giving the required output.

Hi , I have msgs that look like this :
dear john smith you Bought 500 shares of Nile Cotton Ginning at 14.9 L.E On 21/01/10
Im using the Regular expression to get 4 substrings of this msg
1-Bought|Sold
2-Quantity of shares (ex: 500)
3-Name of the stock (ex:Nile Cotton Ginning)
4-price (ex:14.9)
Here is my code , but the output returns the whole msg back :
select SMSID,SMSNO,CUSTOMERACCOUNTID,SENDDATE,ENTRYDATE,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\1')),'(watheeqa)') buy_sell
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\2')),'(watheeqa)') amount ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\3')),'(watheeqa)') company ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at ([0-9]*\.[0-9]*|[0-9][^A-Z][^a-z]) .*','\4')),'(watheeqa)') price
from SMSOUTMSG@bimsic s
where trunc(SENDDATE) = trunc(sysdate) -1
and exists (select 1 from PHONEDETAIL@bimsic p
where s.CUSTOMERACCOUNTID = p.CUSTOMERACCOUNTID
and SMSFLAG = 1);Thanks.

It does check it out
with t
as
select 'dear john smith you Bought 500 shares of Nile Cotton Ginning at 14.9 L.E On 21/01/10' smstext from dual
select
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\1')),'(watheeqa)') buy_sell,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\2')),'(watheeqa)') amount ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\3')),'(watheeqa)') company ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at ([0-9]*\.[0-9]*|[0-9][^A-Z][^a-z]) .*','\4')),'(watheeqa)') price
from t

Required regular expression code

HI All,
i have date like this
select 'A COM' TEST from dual
union all
select 'B LAP' from dual
union all
select 'A LAP COM' from dual
union all
select 'C COM' from dual
union all
select 'A MON-COM' from dual
union all
select 'A COM LAP MON' from dual;
Example 1)when i am filtering data like
select * from table where test like or regulare expression 'A COM LAP MON' ..
it should display above All contain COM LAP MON All datas.
2)select * from table where test like or regulare expression 'A LAP COM' ..
it should display LAP AND COM contain data..
please give me query for this...
Edited by: anbarasan on Jun 20, 2012 6:52 AM

anbarasan wrote:
Hi Kartick..what u did't not get in my question..plese let me knowAn Unmatchable Feat achieved!!!
*<font color="red">Total Posts: 186*
Total Questions: 66 (66 unresolved)</font>
What astonishes me more is, 186 posts on this forum and you still are Ignorant of how you must ask a question. Moreover, you ask people what they did not understand?
Do you not think its time for you to Learn how to post a question from the link posted by Karthick_ARP????
I think I read a similar question from you today itself.
Re: Need sql query
Regards,
P.
Edited by: PurveshK on Jun 20, 2012 8:55 PM

Regular Expression Required for Checksum variable

I am wanting to create a regular expression that extracts a variable checksum value (cs=) which is unique to a given server response string.
The issue I am having is that a simple regex being name="cs" value="(.+?)" just does not work because there are 18 different checksum values being returned per session id/server response.
So a simple regex just picks up any "cs" value and I guess gets confused since there are 18 different ones contained within the server response (all user related)
What i need is a regex to use say this value from the server response (JONHONEYMAN%40YAHOO.COM) or any other unique value which is contained within the string response from the server then extract the cs (Checksum) value from that string and make it variable :)
Here is the server response string:-
"fp=220:1200:2977638312763704:: NO::P1200_EMAIL_ADDRESS,P1200_ORGANISATION_NAME,P1200_UCRN,P1200_ORG_ID,P1200_CALLING_PAGE:JONHONEYMAN%40YAHOO.COM%2C john%20Honeyman%2C260%2C220%2C1190&cs=336788D01EC6E80B1877B3EE982E8B2D8" >Select</td></tr
can anyone help?
Thanks

You need an XML Parser.

Requirements Gateway - Searching for requirements in table rows in a Adobe PDF file

In my quest for creating a good understanding of the coverage of requirements of my test cases I download the NIRG (NI Requirements Gateway) and started out importing my SRS (System Requirement Specifications) documents and some of the test cases. There are many different types of sources which can be imported (Word, Excel, Visio, Access, PDF, ...) and NIRG uses REGEX (Regular Expressions) for extracting the requirement and coverage information of the sources. NI have defined some standardized REGEX formats but they (NI) have also made it possible for tweaking these to fit your purpose.
Instead of adding/changing the SRS documents to fit these standardized REGEX formats, I dived into how to create REGEX for my purpose.
Check out
- http://www.regular-expressions.info/
- http://opencompany.org/download/regex-cheatsheet.pdf
NI Requirements Gateway Coupling Series
(http://zone.ni.com/devzone/cda/tut/p/id/8414)
NI Requirements Gateway for Test, Measurement, and Control Applications
(http://zone.ni.com/devzone/cda/tut/p/id/3721)
Is there anyone who have any experience on using NIRG on a PDF document to get information from the rows in a table?
Best Regards,
Marcus
Marcus Törndahl
Senior Software Designer @ Prevas AB

Hi Manooch_H,
Here is the example document and thank you for taking the time and helping me out .
The columns which I would like to import into NIRG are actually all of them. The UC, Verification, Priority and Responsible columns should be imported as attributes to the requirement. The ID and Requirement columns should be imported as the Requirement and Text respectivaly.
Best regards,
Marcus
Marcus Törndahl
Senior Software Designer @ Prevas AB
Attachments:
SRS.pdf ‏212 KB

NI Requirement Gateway Table Requirements

I am trying to pull requirements out of a *.docx table and understand that I must first create a custom type in order to perform this. As I understand I must edit the regular expression for the Requirement Type in order to parse the requirement from the Intermediate File. Where can I find this intermediate file in order to base my regular expression off of it?
References:
http://forums.ni.com/t5/LabVIEW/Associating-requirements-in-my-Word-Document-with-NI-Gateway/m-p/987...
http://forums.ni.com/t5/LabVIEW/Requirements-Gateway-1-1-doesn-t-recognize-requirements-defined/td-p...
Thanks,
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Hi Craige,
In order to generate the intermediate file, you'll need to enable it in the Project tab of the Configuration Window (see the checkbox in the image below). Once this is selected, a folder called "Intermediate" will be created in the location of the document file, and this folder will contain the intermediate file. Once you have this file, you can paste the contents into the Text analysis zone (in the Expressions tab in Configuration) to test your regular expressions.
Hopefully this clarifies things - let me know if you have further questions!
Al B.
Staff Software Engineer - TestStand
CTA/CLD

Inline display of error message for a regular expression validation

Hi All,
I am using ApexLib in my application.
I am using regular expression validation for some of the items.
Those validation will happen when the button is pressed and the message will be displayed as per the error.
But, I want the errors to be displayed immediately when the focus is away from that item.
as we do for required items.
could anybody help me to achieve it?
Thanks in advance
bye
Srikavi

Hi Srikavi,
to achieve a Validation of an item when leaving the field you'll have to use some javascript code (as ApexLib does internally).
What do you need:
- onChange - Event on your Item
- some Javascript code which is called in the onChange Event (you can put this code either in your page html header or, if it is used more often in your application, in a seperate js File)
- call the ApexLib method apexlib.error.showError to display your error
I actually never tried it myself, but i'm pretty sure that this will work (according to what i've seen in the ApexLib code).
Have fun and tell us how it went,
Peter
Edited by: peter_raganitsch on Sep 5, 2008 11:56 AM

Help!!!!! Regular Expressions!!

I am trying to use Regular Expressions, for parsing. For that the pakage required is
java.util.regex.*;
I am also using the import statement in a sample code. But compiling it, gives an error,
ERRORS:
Replacement.java:6: package java.util.regex does not exist
import java.util.regex.*;
^
I have also set the path to C:\jdk1.4\bin
I have also set the classpath to C:\jdk1.4\lib
I don't know, Why it doesn't recognise the java.util.regex package
please help!!
gaurav_k1

Have you checked if the regex package is part of the
JDK1.4? I can't find it. What classes does it
implement?Yeah, since 1.4
http://java.sun.com/j2se/1.4/docs/api/java/util/regex/package-summary.html
I'm not sure what the original problem could be, possibly using a previously installed jre? If you had one previously installed, check the classpaths and uninstall any old jre (some forget that thinking they only need to remove the jdk). Could you give us anymore hints?

Java – Regular Expressions – Finding any non digit byte in a multiple byte

Hello,
I’m new to JAVA and Regular Expressions; I’m trying to write a regular expression that will find any records that contain a non digit byte in a multiple byte field.
I thought the following was the correct expression but it is only finding records that contain “all” non digit bytes.
\D{1,}
\D = Non Digit
{1,} = at least 1 or more
Below is my sample data. I would like the regular expression to find all of the records that are not all numeric. However when I use the regular expression \D{1,} it is only finding the 2 records that all bytes are non digits. (i.e. “ “ and “A “)
“ 111229”
“2 111229”
“20091229”
“200912c9”
“201#1229”
“20101229”
“20110229”
“20111*29”
“20111029”
“20111229”
“20B11229”
“A “
“A0111229”
Please note I have also tried \D{1,}+ and \D{1,}? And they also do not return my desired results
Any assistance someone can provide would be greatly appreciated.

You don't show the code you are using but I surmise you are using String.matches() which requires that the whole target must match the regular expression not just part of it. Instead you should create a Pattern and then a Matcher and use the Matcher.find() method. Check the Javadoc for Pattern and Matcher and look at the Java regex tutorial - http://docs.oracle.com/javase/tutorial/essential/regex/ .
P.S. You can re-use the Pattern object - you don't have to create it every time you need one.
P.P.S. Java regular expressions work with characters not bytes and characters are not not not bytes.

Regular expressions in Workshop 8.1

Hello,
I'm posting this question here because I don't see a "jdk" subcategory in this
newsgroup and it might be problem peculiar to Workshop.
I'm trying to use the Pattern and Matcher classes in java.util.regex (JDK 1.4.2)
in BEA Workshop 8.1, but I'm getting "ERROR: Unknown escape code" (red squiggly
line appears under the regex and this message is the screen tip) whenever I try
to use the backslash to escape a special character in the Pattern.compile() and
the Pattern.matches() methods.
For example, it doesn't allow "\d" to mean "any digit". For this particular one,
I can get around the problem by specifying "[0-9]", but in the case of the period
character, I'm stuck. I cannot use "\." However, the JDK API doc (http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html)
says the backslash is to be used for this purpose, if I'm reading it correctly.
Is this a problem with Workshop, and is there a workaround? I need to specify
that I require one and exactly one period.
Any help would be most appreciated!
Thanks.

Yes, I had read the Java doc, but I guess I hadn't fully understood it. Now I
do! Thanks!!
David
Josh Eckels <[email protected]> wrote:
This isn't particular to Workshop, but you'll need to use two
backslashes in your source code. Inside a string, backslash is used to
escape the next character so that you can enter special characters like
newlines ('\n'), tabs ('\t'), etc.
So, in order to enter a backslash character into your string, you need
to escape it, like '\\'.
There's a small section on this in the java.util.regex.Pattern JavaDoc,
under the "Backslashes, escapes, and quoting" header:
Backslashes within string literals in Java source code are interpreted
as required by the Java Language Specification as either Unicode escapes
or other character escapes. It is therefore necessary to double
backslashes in string literals that represent regular expressions to
protect them from interpretation by the Java bytecode compiler. The
string literal "\b", for example, matches a single backspace character
when interpreted as a regular expression, while "\\b" matches a word
boundary. The string literal "$hello$" is illegal and leads to a
compile-time error; in order to match the string (hello) the string
literal "\$hello\$" must be used.
Josh
David Chang wrote:
Hello,
I'm posting this question here because I don't see a "jdk" subcategoryin this
newsgroup and it might be problem peculiar to Workshop.
I'm trying to use the Pattern and Matcher classes in java.util.regex(JDK 1.4.2)
in BEA Workshop 8.1, but I'm getting "ERROR: Unknown escape code" (redsquiggly
line appears under the regex and this message is the screen tip) wheneverI try
to use the backslash to escape a special character in the Pattern.compile()and
the Pattern.matches() methods.
For example, it doesn't allow "\d" to mean "any digit". For this particularone,
I can get around the problem by specifying "[0-9]", but in the caseof the period
character, I'm stuck. I cannot use "\." However, the JDK API doc
(http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html)
says the backslash is to be used for this purpose, if I'm reading itcorrectly.
Is this a problem with Workshop, and is there a workaround? I needto specify
that I require one and exactly one period.
Any help would be most appreciated!
Thanks.

Requirements gateway & regular expressions

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