Resolve node with two nodes (nested tables)

Question

Hello,
I want to hide a field depending of the value of another field of the same line. the issue is that the line is from a nested table.
here is the code :
var nodList = xfa.resolveNodes("xfa.record.LISTE_POSTES_TRAVAIL.DATA[].LISTE_CARAC.DATA[].CARAC");
I want to get the value of "carac" field in table LISTE_CARAC_DATA.
So when I display this :
xfa.host.messageBox(""+nodList.item(this.parent.index).value);
I always see the values of the table LISTE_CARAC_DATA for the first line of LISTE_POSTES_TRAVAIL.
Could you help me ?
Thank you.

Answer 1

No Otto you won't make me rebuild my form
I think I just get what is wrong, the value of this.index is always 0, that explain why sometimes it works, and sometimes not.
Maybe I just need to put a counter in my table. I will do that if I don't find a javscript solution.
Anyway, thanks a lot Otto for your time and very helpful advice.
This is the code if it can help someone :
var nodTry = xfa.resolveNodes("$.parent.parent.parent.POSTE[*].multiple_resultat.RESULTAT_T1");
//The nodtry is complex because of all the subforms.
var selection = $.boundItem(xfa.event.newText);
if ( this.CARAC.rawValue == "LISTERIA" )
     if ( selection == "YES" )
//COMPTEUR is the index that I created (I add a columns in my table and filled it in the ABAP program).
// I don't need to do "+1" because index started at 0 in adobe form.
     nodTry.item(this.COMPTEUR.rawValue).mandatory = "error";
     nodTry.item(this.COMPTEUR.rawValue).access = "open";
     nodTry.item(this.COMPTEUR.rawValue).fillColor = "255,255,255";
     else if ( selection != "YES" )
     nodTry.item(this.COMPTEUR.rawValue).mandatory = "disabled";
     nodTry.item(this.COMPTEUR.rawValue).access = "readOnly";
     nodTry.item(this.COMPTEUR.rawValue).fillColor = "230,230,230";
     nodTry.item(this.COMPTEUR.rawValue).rawValue = "";
Edited by: Louis-Arnaud Bouquin on Feb 9, 2010 11:39 AM