Returning Duplicate Rows

Hi. I'm working on this query, and I'm having problems. When I add an inner join, I start getting multiple rows returned.
What I want returned is ONLY the first row below, but I'm instead getting both rows (which are identical).
SALESMAN_NO | CUSTOMER_NO | ORDER | SALES | COGS | MARGIN
97 | 1306969000 | 00477023 | 517.40 | 298.20 | 219.18
97 | 1306969000 | 00477023 | 517.40 | 298.20 | 219.18
Here's my query. And when I add the inner joins, I get the 2nd row above. If I run the SAME query without the inner joins, I get the 1 and only 1 row - which is what I'm trying to get to. Getting this 2nd row is screwing up the SUM functions I'm ultimately trying to use.
SELECT
SOE.SALESMAN_NO AS [SALESMAN],
SOE.CUSTOMER_NO AS [CUSTOMER #],
(SOE.SALE_ORDER_NO) AS [ORDERS],
(SOE.SALES_AMT/100) AS [SALES],
(SOE.COST_GOODS_SOLD/100) AS [COGS],
((SOE.SALES_AMT/100) - (SOE.COST_GOODS_SOLD/100)) AS [MARGIN]
FROM
SOE_HEADER SOE
INNER JOIN CUST_NAME CUST
ON SOE.CUSTOMER_NO = CUST.CUSTOMER_NO
INNER JOIN OUTSIDE_SALES OUTSIDE
ON CUST.SALESMAN_NO = OUTSIDE.SALESMAN_NO
WHERE
SOE.SALESMAN_NO <> '83'
AND SOE.TYPE_OF_ORDER = '00'
AND SOE.ORDERS_STATUS = '06'
AND SOE.DATE_OF_ORDER > 20080101
AND SOE.TYPE_OF_FRGHT IN ('13','14')
AND SOE.CUSTOMER_NO = '1306969000'
I've looked at the data and at this query for about an hour now, and need some help. Thanks.

If you want to get the distinct rows only in this SELECT then you may use DISTINCT. ie replace the table with a query
,(Select Distinct SALESMAN_NO,CUSTOMER_NO, ORDER SALES ,COGS , MARGIN From YourTableName) AS AliasName
Check this too
Find and/or Delete Duplicate Rows
http://code.msdn.microsoft.com/SQLExamples/Wiki/View.aspx?title=DuplicateRows&referringTitle=Home
Madhu
SQL Server Blog
SQL Server 2008 Blog

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Crystal report returning duplicate rows - Linking issue?

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Thank you very much Don - this is a feature I wasn't aware of previously, and is a big step in the right direction for me. Really useful.
In the report mentioned, this sort of works. It works very well on individual fields - so I could just "Suppress If Duplicated" on the forename and then remove duplicates on that column when exported to Excel (or simply bring in a unique field such as the party reference number and do likewise).
However, is there a way to get Crystal to do this for me? So to suppress the whole line based on whether or not I'm suppressing this one field?
Just applying "Suppress If Duplicated" to all fields at once seems to have slightly unpredictable behaviour - not suppressing every field in the row. So I experimented a bit with using the "Suppress" tick to do this, then applying a formula to it. But the closest I can get for the formula is something like:
- {PARTIES.PAR_PER_FORENAME} = previous({PARTIES.PAR_PER_FORENAME}) and
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Report Builder 2.0 returning duplicate rows in query designer

Hi,
I have a query running off a model, when I explore the data in the model and in a standard sql table it returns one row for each record, which include a unique id for each which is correct.
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Anyway, the other post that I found reported that they had solved their problem by converting the field to a VARCHAR (255).    I tried this (by casting the column in my View to VARCHAR(255)) and this resolved the problem
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Can anybody explain why having a VARCHAR(max) column in my entity causes duplicate rows.
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Can you tell us more about the options you have selected in the Adapter to select the records ?

Join returns duplicate rows

Hi All,
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Hi Ian,
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-- application release 11.5.10.2 (both environments)
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AAAKOGAAPAAAETMAAQ
AAAKOGAAPAAAETMAAQ
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Have you changed the partition definitions since you first created the index?
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Hi All,
Just got the following question that I could not understand at all. Let's assume we have a query like this:
select d.d_name, e.e_name
from dept d, emp e
where d.d_id = e.d_id
And this query returns 3 rows only:
IT JOHN
IT JAMES
ADMIN BILL
It was found that if the query was changed as:
select d.d_name, e.e_name
from dept d, emp e
where d.d_id = e.d_id
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sometimes it returns as 4 rows instead of 3:
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IT JAMES
IT JAMES
IT JOHN
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This happened sometimes on windows platform.

Hi All,
Just got the following question that I could not understand at all. Let's assume we have a query like this:
select d.d_name, e.e_name
from dept d, emp e
where d.d_id = e.d_id
And this query returns 3 rows only:
IT JOHN
IT JAMES
ADMIN BILL
It was found that if the query was changed as:
select d.d_name, e.e_name
from dept d, emp e
where d.d_id = e.d_id
ORDER BY d.d_name, d.e_name
sometimes it returns as 4 rows instead of 3:
ADMIN BILL
IT JAMES
IT JAMES
IT JOHN
How this be possible?
This happened sometimes on windows platform.

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First attempt to remove duplicate rows from a table...

I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
tell application "Numbers"
activate
tell document 1
-- DETERMINE THE CURRENT SHEET
set currentsheetindex to 0
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of (tables whose selection range is not missing value)
end tell
if x is not 0 then
set the currentsheetindex to i
exit repeat
end if
end repeat
if the currentsheetindex is 0 then error "No sheet has a selected table."
-- GET THE TABLE WITH CELLS
tell sheet currentsheetindex
set the current_table to the first table whose selection range is not missing value
end tell
end tell
log current_table
tell current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
repeat with i from 1 to (z - 1)
set m to m & value of (cell i of row j)
end repeat
set value of cell z of row j to m
end repeat
set MyRange to value of every cell of column z
repeat with i from 1 to (count of items of MyRange)
set n to item i of MyRange
if n is in list1 then
set end of list1 to "Delete"
else
set end of list1 to n
end if
end repeat
repeat with i from (count of items of list1) to 1 by -1
set n to item i of list1
if n = "Delete" then remove row i
end repeat
remove column z
end tell
end tell
Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
Thanks,
Jason
Message was edited by: jaxjason

Hi jason
I hope that with the added comments it will be clear.
Ask if something is always opaque.
set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
tell application "Numbers09"
tell document current_Doc to tell sheet current_Sheet to tell table current_table
set list1 to {}
add column after column (count of columns)
set z to (count of columns)
repeat with j from 1 to (count of rows)
set m to ""
tell row j
repeat with i from 1 to (z - 1)
set m to m & value of cell i
end repeat
set value of cell z to m
end tell
end repeat
set theRange to value of every cell of column z
repeat with i from (count of items of theRange) to 1 by -1
(* As I scan the table backwards (starting from the bottom row),
I may remove a row immediately when I discover that it is a duplicate *)
set n to item i of theRange
if n is in list1 then
remove row i
else
set end of list1 to n
end if
end repeat
remove column z
end tell
end tell
--=====
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers09" to tell document 1
set theSheet to ""
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
(* Open a trap to catch the selection range.
The structure of this item
«class
can't be coerced as text.
So, when the instruction (selection range of table y) as text
receive 'missing value' it behaves correctly and the lup continue.
But, when it receive THE true selection range, it generates an error
whose message is errMsg and number is errNum.
We grab them just after the on error instruction *)
try
(selection range of table y) as text
on error errMsg number errNum (*
As we reached THE selection range, we are here.
We grab the errMsg here. In French it looks like:
"Impossible de transformer «class
The handler cuts it in pieces using quots as delimiters.
item 1 (_) "Impossible de transformer «class » "
item 2 (theRange) "A2:M25"
item 3 (_) " of «class NmTb» "
item 4 (theTable) "Tableau 1"
item 5 (_) " of «class NmSh» "
item 6 (theSheet) "Feuille 1"
item 7 (_) " of document "
item 8 (theDoc) "Sans titre"
item 9 ( I drop it ) " of application "
item 10 ( I drop it ) "Numbers"
item 11 (I drop it ) " en type string."
I grab these items in the list
{_, theRange, _, theTable, _, theSheet, _, theDoc}
Yes, underscore is a valid name of variable.
I often uses it when I want to drop something.
An alternate way would be to code:
set ll to my decoupe(errMsg, quote)
set theRange to item 2 of ll
set theTable to item 4 of ll
set theSheet to item 8 of ll
set theDoc to item 10 of ll
it works exactly the same but it's not so elegant.
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
exit repeat (*
as we grabbed the interesting datas, we exit the lup indexed by y.*)
end try
end repeat -- y
if theSheet > "" then exit repeat (*
If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
end if
end tell -- sheet
end repeat -- i
(* We may arrive here with two kinds of results.
if we grabbed a selection, theSheet is something like "Feuille 1"
if we didn't grabbed a selection, theSheet is the "" defined on entry
and we generate an error which is not trapped so it stops the program *)
if theSheet = "" then error "No sheet has a selected table."
end tell -- document
(* Now, we send to the caller the interesting datas :
theRange "A2:M25"
theTable "Tableau 1"
theSheet "Feuille 1"
theDoc "Sans titre" *)
return {theRange, theTable, theSheet, theDoc}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d (*
Cut the text t in pieces using d as delimiter *)
set l to text items of t
set AppleScript's text item delimiters to "" (*
Resets the delimiters to the standard value. *)
(* Send the list to the caller *)
return l
end decoupe
--=====
Have fun
And if it's not clear enough, you may ask for more explanations.
Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19)

How to Create primary key index with duplicate rows.

Hi All,
While rebuilding an index on a table , I am getting error that there are duplicate rows in a table.
Searching out the reason led me to an interesting observation.
Please follow.
SELECT * FROM user_ind_columns WHERE table_name='SERVICE_STATUS';
INDEX_NAME     TABLE_NAME     COLUMN_NAME     COLUMN_POSITION     COLUMN_LENGTH     CHAR_LENGTH     DESCEND
SERVICE_STATUS_PK     SERVICE_STATUS     SUBSCR_NO_RESETS     2     22     0      ASC
SERVICE_STATUS_PK     SERVICE_STATUS     STATUS_TYPE_ID     3     22     0     ASC
SERVICE_STATUS_PK     SERVICE_STATUS     ACTIVE_DT     4     7     0     ASC
SERVICE_STATUS_PK     SERVICE_STATUS     SUBSCR_NO     1     22     0     ASC
SELECT index_name,index_type,table_name,table_type,uniqueness, status,partitioned FROM user_indexes WHERE index_name='SERVICE_STATUS_PK';
INDEX_NAME     INDEX_TYPE      TABLE_NAME     TABLE_TYPE     UNIQUENESS     STATUS     PARTITIONED
SERVICE_STATUS_PK     NORMAL     SERVICE_STATUS     TABLE     UNIQUE     VALID     NO
SELECT constraint_name ,constraint_type,table_name,status,DEFERRABLE,DEFERRED,validated,index_name
FROM user_constraints WHERE constraint_name='SERVICE_STATUS_PK';
CONSTRAINT_NAME     CONSTRAINT_TYPE     TABLE_NAME      STATUS     DEFERRABLE     DEFERRED     VALIDATED     INDEX_NAME
SERVICE_STATUS_PK     P     SERVICE_STATUS     ENABLED     NOT DEFERRABLE     IMMEDIATE VALIDATED     SERVICE_STATUS_PK
1. Using index scan:
SELECT COUNT (*)
FROM (SELECT subscr_no, active_dt, status_type_id, subscr_no_resets
FROM service_status
GROUP BY subscr_no, active_dt, status_type_id, subscr_no_resets
HAVING COUNT (*) > 1) ;
no rows returned
Explain plan:
Operation     OBJECT Name     ROWS     Bytes     Cost     OBJECT Node     IN/OUT     PStart     PStop
SELECT STATEMENT Optimizer MODE=CHOOSE          519 K          14756
FILTER
SORT GROUP BY NOSORT          519 K     7 M     14756
INDEX FULL SCAN     ARBOR.SERVICE_STATUS_PK     10 M     158 M     49184
2. Using Full scan:
SELECT COUNT (*)
FROM (SELECT /*+ full(s) */ subscr_no, active_dt, status_type_id, subscr_no_resets
FROM service_status s
GROUP BY subscr_no, active_dt, status_type_id, subscr_no_resets
HAVING COUNT (*) > 1) ;
71054 rows returned.
Explain Plan:
Operation     Object Name     Rows     Bytes     Cost     Object Node     In/Out     PStart     PStop
SELECT STATEMENT Optimizer Mode=CHOOSE          1           24123
SORT AGGREGATE          1
VIEW          519 K          24123
FILTER
SORT GROUP BY          519 K     7 M     24123
TABLE ACCESS FULL     ARBOR.SERVICE_STATUS     10 M     158 M     4234
Index SERVICE_STATUS_PK is a unique and composite primary key VALID index. And the constraint is ENABLED and VALIDATED still having duplicate rows in table.
How it is possible?
Is it an Oracle soft Bug??
Regards,
Saket Bansal

saket bansal wrote:
Values are inserted as single rows inserts through an GUI interface.And you still claim to have over 71K duplicate records, without the GUI getting any kind of errors?
That does not add up and can only be explained by a "bug".
I tried inserting a duplicate record but failed.
SQL> insert into service_status (select * from service_status where rownum <2);
insert into service_status (select * from service_status where rownum <2)
ERROR at line 1:
ORA-00001: unique constraint (ARBOR.SERVICE_STATUS_PK) violatedAre you really sure there is no other way data in this table is populated/manipulated in bulk?

Duplicate Rows In Oracle Pipelined Table Functions

Hi fellow oracle users,
I am trying to create an Oracle piplined table function that contains duplicate records. Whenever I try to pipe the same record twice, the duplicate record does not show up in the resulting pipelined table.
Here's a sample piece of SQL:
/* Type declarations */
TYPE MY_RECORD IS RECORD(
MY_NUM INTEGER
TYPE MY_TABLE IS TABLE OF MY_RECORD;
/* Pipelined function declaration */
FUNCTION MY_FUNCTION RETURN MY_TABLE PIPELINED IS
V_RECORD MY_RECORD;
BEGIN
-- insert first record
V_RECORD.MY_NUM = 1;
PIPE ROW (V_RECORD);
-- insert second duplicate record
V_RECORD.MY_NUM = 1;
PIPE ROW (V_RECORD);
-- return piplined table
RETURN;
END;
/* Statement to query pipelined function */
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I am trying to get the duplicate row to show up in the select statement. Any help would be greatly appreciated.

Can you provide actual output from an SQL*Plus prompt trying this? I don't see the same behavior
SQL> SELECT * FROM V$VERSION;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE    10.2.0.4.0      Production
TNS for 64-bit Windows: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
SQL> CREATE TYPE MY_RECORD IS OBJECT(MY_NUM INTEGER);
2 /
Type created.
SQL> CREATE TYPE MY_TABLE IS TABLE OF MY_RECORD;
2 /
Type created.
SQL> CREATE OR REPLACE FUNCTION MY_FUNCTION
2 RETURN MY_TABLE
3 PIPELINED
4          AS
5                  V_RECORD        MY_RECORD;
6          BEGIN
7                  V_RECORD.MY_NUM := 1;
8                  PIPE ROW(V_RECORD);
9
10                  V_RECORD.MY_NUM := 1;
11                  PIPE ROW(V_RECORD);
12
13                  RETURN;
14          END;
15 /
Function created.
SQL> SELECT * FROM TABLE(MY_FUNCTION);
              MY_NUM
                   1
                   1

Deleting Duplicate Rows in a list

Hey folks, I've scowered around a bit for the answer to this and can't for the life of my figure it out.
I've got a list of ~2,000-3,000 words in the following format:
Fact
Fiction
Funny
Funny
Funny
Funky
etc etc. I am looking to make numbers delete all the duplicate rows such that the above list would become:
Fact
Fiction
Funny
Funky
All of these words are in column A on a separate sheet in a numbers document I'm using to run an experiment. Is there a built in command or something that would do this? (I'm a COMPLETE beginner at using Numbers as a heads up)
Any help with this would be GREATLY appreciated.

Teaghue wrote:
Never mind! I found an old old post explaining that this can't be done in numbers, so I just did it in excel.
Perfectly wrong !
The way to achieve the described goal was described several times in this forum.
*_You just didn't search carefully !_*
Searching for delet AND duplicate return several threads.
Here are two of them.
I didn't made a typo. I used delet so that it retrieve delete as well as deleting
http://discussions.apple.com/thread.jspa?messageID=12992492
http://discussions.apple.com/thread.jspa?messageID=11559125
Yvan KOENIG (VALLAURIS, France) mercredi 2 mars 2011 17:59:40

Duplicate rows in 5 table

I have five tables(A,B,C,D,E), and I am trying to check for duplicate rows in all the tables, I tried using inner join, but the first three join did not return any table. is there another way.the tables only have two columns , the email(different values)
and authour (which is the same person in the table)
when i tried
select * from TABLE A
INNER JOIN TABLE B
ON TABLEA. EMAIL = TABLEB.EMAIL
INNER JOIN TABLEC
ON TABLEA.EMAIL=TABLEC.EMAIL
it came back with no result, the other way I am thinking is to unioun all all the tables and try to use count and group by ,but this will only show me the duplicates and not the authours
please any other way

it came back with no result, the other way I am thinking is to unioun all all the tables and try to use count and group by (but I could not insert my result in a new table)
please any other way
I dont understand your point here...Are you trying the below?
Create Table T1(name varchar(50),Email Varchar(50))
Insert into T1 Values('SQL','[email protected]'),('.NET','[email protected]')
Create Table T2(name varchar(50),Email Varchar(50))
Insert into T2 Values('Server','[email protected]'),('BizTalk','[email protected]')
Create Table T3(name varchar(50),Email Varchar(50))
Insert into T2 Values('Sql','[email protected]'),('server','[email protected]')
;With cte as
(Select * From T1
Union All
Select * From T2
Union All
Select * From T3)
Select name,email, count(1) From cte Group by name , email having count(1)>1
Drop table T1,T2,T3
I was able to insert the union product in a table, and i used this
SELECT EMAIL,AUTHOR,COUNT(EMAIL) AS AMOUNT FROM ALLEMAIL
GROUP BY AUTHOR,EMAIL
ORDER BY AMOUNT DESC, email desc
but its showing the email and the count but its appearing like the duplicate is only associated with one authour

Returning Duplicate Rows

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