Salary Management

hi
When the HR user enters the proposed salary for an employee. It is not going to the Employee supervisor for the approval.
Also i like to know is it possible to setup the salary approval hierarchy.
Please advice
Thanks
Regards
Ramesh Kumar S

Hi
It sounds as if you are using the new salary admin form which replaces the old salary admin form in the PUI (Professional User Interface).
AME is used in HR workflow, and therefore is relevant only to SSHR transactions (in the HR product). I don't know of a way you can link AME to a PUI form because there is no workflow involved.
You will need to find another way of involving the manager for approval. I have soemtimes had one user enter the salary on a salary admin form without the salary admin:approve profile. Then I had an alert which fired when the salary admin record is inserted and sent a message to the manager. The man ager could then go back into the salary admin form with the salary admin:approve profile on and approve it.
Regards
Tim

Similar Messages

Exporting xmltype table data into xml/txt file

I want to export data stored in oracle as xmltype table into xml format file.
I want to use alternatives to the method shown below as my xml file is large.
set long 10000000
spool c:\\StudentXMLJan08.xml
SELECT
XMLElement("Student",
XMLForest(s.studentid "studentid",
s.firstname "firstname",
s.lastname "surname"),
XMLElement("enrollments",
(SELECT XMLAGG(
XMLForest(sc.coursecode "courseid"))
FROM studentcourse sc
WHERE sc.studentid = s.studentid
and sc.is_approved='Y'
and sc.takenyear='2008'
and sc.takenterm='1')))
FROM student s
where s.statuscode in (select studentstatuscode from studentstatus where studentstatusactive=1)
order by s.studentid;
spool off
please help, thank you

How's this one for size
SQL> create or replace view DEPARTMENT_XML of xmltype
2 with object id
3 (
4    'DEPARTMENT'
5 )
6 as
7 select xmlElement
8         (
9           "Departments",
10           (
11             select xmlAgg
12                    (
13                      xmlElement
14                      (
15                      "Department",
16                      xmlAttributes( d.DEPARTMENT_ID as "DepartmentId"),
17                      xmlElement("Name", d.DEPARTMENT_NAME),
18                      xmlElement
19                      (
20                        "Location",
21                        xmlForest
22                        (
23                           STREET_ADDRESS as "Address", CITY as "City", STATE_PROVINCE as "State",
24                           POSTAL_CODE as "Zip",COUNTRY_NAME as "Country"
25                        )
26                      ),
27                      xmlElement
28                      (
29                        "EmployeeList",
30                        (
31                          select xmlAgg
32                                 (
33                                   xmlElement
34                                   (
35                                     "Employee",
36                                     xmlAttributes ( e.EMPLOYEE_ID as "employeeNumber" ),
37                                     xmlForest
38                                     (
39                                       e.FIRST_NAME as "FirstName", e.LAST_NAME as "LastName", e.EMAIL as "EmailAddre
ss",
40                                       e.PHONE_NUMBER as "Telephone", e.HIRE_DATE as "StartDate", j.JOB_TITLE as "Job
Title",
41                                       e.SALARY as "Salary", m.FIRST_NAME || ' ' || m.LAST_NAME as "Manager"
42                                     ),
43                                     xmlElement ( "Commission", e.COMMISSION_PCT )
44                                   )
45                                 )
46                            from HR.EMPLOYEES e, HR.EMPLOYEES m, HR.JOBS j
47                           where e.DEPARTMENT_ID = d.DEPARTMENT_ID
48                             and j.JOB_ID = e.JOB_ID
49                             and m.EMPLOYEE_ID = e.MANAGER_ID
50                        )
51                      )
52                    )
53                  )
54             from HR.DEPARTMENTS d, HR.COUNTRIES c, HR.LOCATIONS l
55            where d.LOCATION_ID = l.LOCATION_ID
56              and l.COUNTRY_ID = c.COUNTRY_ID
57           )
58         )
59    from dual
60 /
View created.
SQL> create or replace trigger DEPARTMENT_DML
2 instead of INSERT or UPDATE or DELETE
3 on DEPARTMENT_XML
4 begin
5    null;
6 end;
7 /
Trigger created.
SQL> declare
2    cursor getDepartments is
3      select ref(d) XMLREF
4        from DEPARTMENT_XML d;
5    res boolean;
6    targetFolder varchar2(1024) := '/public/Departments';
7 begin
8    if dbms_xdb.existsResource(targetFolder) then
9       dbms_xdb.deleteResource(targetFolder,dbms_xdb.DELETE_RECURSIVE_FORCE);
10    end if;
11    res := dbms_xdb.createFolder(targetFolder);
12    for dept in getDepartments loop
13      res := DBMS_XDB.createResource(targetFolder || '/Departments.xml', dept.XMLREF);
14    end loop;
15 end;
16 /
PL/SQL procedure successfully completed.
SQL> select path
2    from path_view
3   where equals_path(RES,'/public/Departments/Departments.xml') = 1
4 /
PATH
/public/Departments/Departments.xml
SQL> select xdburitype('/public/Departments/Departments.xml').getXML()
2    from dual
3 /
XDBURITYPE('/PUBLIC/DEPARTMENTS/DEPARTMENTS.XML').GETXML()
<Departments>
<Department DepartmentId="60">
    <Name>IT</Name>
    <Location
SQL> quit
Disconnected from Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
C:\Temp>ftp localhost
Connected to mdrake-lap.
220- mdrake-lap
Unauthorised use of this FTP server is prohibited and may be subject to civil and criminal prosecution.
220 mdrake-lap FTP Server (Oracle XML DB/Oracle Database) ready.
User (mdrake-lap:(none)): SCOTT
331 pass required for SCOTT
Password:
230 SCOTT logged in
ftp> cd /public/Departments
250 CWD Command successful
ftp> ls -l
200 EPRT Command successful
150 ASCII Data Connection
-rw-r--r--   1 SCOTT    oracle         0 NOV 10 20:18 Departments.xml
226 ASCII Transfer Complete
ftp: 71 bytes received in 0.01Seconds 7.10Kbytes/sec.
ftp> get Departments.xml -
200 EPRT Command successful
150 ASCII Data Connection
<Departments><Department DepartmentId="60"><Name>IT</Name><Location><Address>2014 Jabberwocky Rd</Address><City>Southlak
e</City><State>Texas</State><Zip>26192</Zip><Country>United States of America</Country></Location><EmployeeList><Employe
e employeeNumber="103"><FirstName>Alexander</FirstName><LastName>Hunold</LastName><EmailAddress>AHUNOLD</EmailAddress><T
elephone>590.423.4567</Telephone><StartDate>2006-01-03</StartDate><JobTitle>Programmer</JobTitle><Salary>9000</Salary><M
anager>Lex De Haan</Manager><Commission></Commission></Employee><Employee employeeNumber="105"><FirstName>David</FirstNa
me><LastName>Austin</LastName><EmailAddress>DAUSTIN</EmailAddress><Telephone>590.423.4569</Telephone><StartDate>2005-06-
25</StartDate><JobTitle>Programmer</JobTitle><Salary>4800</Salary><Manager>Alexander Hunold</Manager><Commission></Commi
ssion></Employee><Employee employeeNumber="106"><FirstName>Valli</FirstName><LastName>Pataballa</LastName><EmailAddress>
VPATABAL</EmailAddress><Telephone>590.423.4560</Telephone><StartDate>2006-02-05</StartDate><JobTitle>Programmer</JobTitl
e><Salary>4800</Salary><Manager>Alexander Hunold</Manager><Commission></Commission></Employee><Employee employeeNumber="
107"><FirstName>Diana</FirstName><LastName>Lorentz</LastName><EmailAddress>DLORENTZ</EmailAddress><Telephone>590.423.556
7</Telephone><StartDate>2007-02-07</StartDate><JobTitle>Programmer</JobTitle><Salary>4200</Salary><Manager>Alexander Hun
old</Manager><Commission></Commission></Employee><Employee employeeNumber="104"><FirstName>Bruce</FirstName><LastName>Er
nst</LastName><EmailAddress>BERNST</EmailAddress><Telephone>590.423.4568</Telephone><StartDate>2007-05-21</StartDate><Jo
bTitle>Programmer</JobTitle><Salary>6000</Salary><Manager>Alexander Hunold</Manager><Commission></Commission></Employee>
</EmployeeList></Department><Department DepartmentId="50"><Name>Shipping</Name><Location><Address>2011 Interiors Blvd</A
ddress><City>South San Francisco</City><State>California</State><Zip>99236</Zip><Country>United States of America</Count
ry></Location><EmployeeList><Employee employeeNumber="120"><FirstName>Matthew</FirstName><LastName>Weiss</LastName><Emai
lAddress>MWEISS</EmailAddress><Telephone>650.123.1234</Telephone><StartDate>2004-07-18</StartDate><JobTitle>Stock Manage
r</JobTitle><Salary>8000</Salary><Manager>Steven King</Manager><Commission></Commission></Employee><Employee employeeNum
ber="122"><FirstName>Payam</FirstName><LastName>Kaufling</LastName><EmailAddress>PKAUFLIN</EmailAddress><Telephone>650.1
23.3234</Telephone><StartDate>2003-05-01</StartDate><JobTitle>Stock Manager</JobTitle><Salary>7900</Salary><Manager>Stev
en King</Manager><Commission></Commission></Employee><Employee employeeNumber="121"><FirstName>Adam</FirstName><LastName
Fripp</LastName><EmailAddress>AFRIPP</EmailAddress><Telephone>650.123.2234</Telephone><StartDate>2005-04-10</StartDate><JobTitle>Stock Manager</JobTitle><Salary>8200</Salary><Manager>Steven King</Manager><Commission></Commission></Employee
<Employee employeeNumber="124"><FirstName>Kevin</FirstName><LastName>Mourgos</LastName><EmailAddress>KMOURGOS</EmailAddress><Telephone>650.123.5234</Telephone><StartDate>2007-11-16</StartDate><JobTitle>Stock Manager</JobTitle><Salary>5800<
/Salary><Manager>Steven King</Manager><Commission></Commission></Employee><Employee employeeNumber="123"><FirstName>Shan
ta</FirstName><LastName>Vollman</LastName><EmailAddress>SVOLLMAN</EmailAddress><Telephone>650.123.4234</Telephone><Start
Date>2005-10-10</StartDate><JobTitle>Stock Manager</JobTitle><Salary>6500</Salary><Manager>Steven King</Manager><Commiss
ion></Commission></Employee><Employee employeeNumber="128"><FirstName>Steven</FirstName><LastName>Markle</LastName><Emai
lAddress>SMARKLE</EmailAddress><Telephone>650.124.1434</Telephone><StartDate>2008-03-08</StartDate><JobTitle>Stock Clerk
</JobTitle><Salary>2200</Salary><Manager>Matthew Weiss</Manager><Commission></Commission></Employee><Employee employeeNu
mber="127"><FirstName>James</FirstName><LastName>Landry</LastName><EmailAddress>JLANDRY</EmailAddress><Telephone>650.124
.1334</Telephone><StartDate>2007-01-14</StartDate><JobTitle>Stock Clerk</JobTitle><Salary>2400</Salary><Manager>Matthew
Weiss</Manager><Commission></Commission></Employee><Employee employeeNumber="126"><FirstName>Irene</FirstName><LastName>
Mikkilineni</LastName><EmailAddress>IMIKKILI</EmailAddress><Telephone>650.124.1224</Telephone>
<StartDate>2002-06-07</St
artDate><JobTitle>Public Relations Representative</JobTitle><Salary>10000</Salary><Manager>Neena Kochhar</Manager><Commi
ssion></Commission></Employee></EmployeeList></Department></Departments>226 ASCII Transfer Complete
ftp: 40392 bytes received in 0.08Seconds 480.86Kbytes/sec.
ftp>

Single Row Returns More than 1 row

I have this query that displays the HOME telephone number of an EMP, however I have to put that Select on the field, since that field is HOME phone.
The Outputs are:
Name
Address
Birthday
Home Phone
Mobile Phone
Salary
Manager
My input is:
ID
How am I going to query the HomePhone and CellPhone, those number are on 1 field called CONTACT_NO however there is an INDICATOR field that tell either its HOME, CELL, BUSS, FAX... etc..

What they have done is a correlated subquery and what you have done is a direct join both give different result.
Check this out.
SQL> select * from emp order by empno;
     EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
         1 SMITH      CLERK           7902 17-DEC-80        800                    20
         2 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
         3 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
         4 JONES      MANAGER         7839 02-APR-81       2975                    20
         5 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
         6 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
         7 CLARK      MANAGER         7839 09-JUN-81       2450                    10
         8 SCOTT      ANALYST         7566 19-APR-87       3000                    20
         9 KING       PRESIDENT            17-NOV-81       5000                    10
        10 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
10 rows selected.
SQL> select * from phone order by empno;
     EMPNO PHONE_TYPE   PHONE_NO
         1 HOME       9999999999
         2 CELL       1111111111
         2 HOME       9999999999
         3 HOME       9999999999
         8 CELL       1111111111
         8 HOME       9999999999
        10 HOME       9999999999
7 rows selected.A direct join gives this output.
SQL> select e.empno, e.ename, p.phone_no
2    from emp e, phone p
3   where e.empno = p.empno
4     and p.phone_type = 'HOME';
     EMPNO ENAME        PHONE_NO
         1 SMITH      9999999999
         2 ALLEN      9999999999
         3 WARD       9999999999
         8 SCOTT      9999999999
        10 TURNER     9999999999And a Correlated subquery gives this output.
SQL> select e.empno,e.ename,(select phone_no
2                            from phone
3                           where empno = e.empno
4                             and phone_type = 'HOME') phone_no
5    from emp e;
     EMPNO ENAME        PHONE_NO
         1 SMITH      9999999999
         2 ALLEN      9999999999
         3 WARD       9999999999
         4 JONES
         5 MARTIN
         6 BLAKE
         7 CLARK
         8 SCOTT      9999999999
         9 KING
        10 TURNER     9999999999
10 rows selected.But a simple outer join can give the result as above.
SQL> select e.empno, e.ename, p.phone_no
2    from emp e, phone p
3   where p.empno (+)= e.empno
4     and p.phone_type (+) = 'HOME';
     EMPNO ENAME        PHONE_NO
         1 SMITH      9999999999
         2 ALLEN      9999999999
         3 WARD       9999999999
         8 SCOTT      9999999999
        10 TURNER     9999999999
         5 MARTIN
         6 BLAKE
         7 CLARK
         4 JONES
         9 KING
10 rows selected.Thanks,
Karthick.

Condition on Mapping in Repeating Records

Hi,
This is my map file :
My input file is as follows:
<ns0:Root xmlns:ns0="http://schemas.microsoft.com/BizTalk/2003/aggschema">
<InputMessagePart_0>
<ns1:Response xmlns:ns1="http://Interplx_ndPhase.SourceSchema">
<Employees>
<Employee>
<EmpID>10</EmpID>
<EmpName>Prakash</EmpName>
</Employee>
<Employee>
<EmpID>20</EmpID>
<EmpName>EmpName_0</EmpName>
</Employee>
</Employees>
</ns1:Response>
</InputMessagePart_0>
<InputMessagePart_1>
<ns2:ResponseM xmlns:ns2="http://Interplx_ndPhase.ManagerSchema">
<Managers>
<Manager>
<ManagerID>30</ManagerID>
<Salary>Salary_0</Salary>
</Manager>
<Manager>
<ManagerID>20</ManagerID>
<Salary>1000000</Salary>
</Manager>
</Managers>
</ns2:ResponseM>
</InputMessagePart_1>
</ns0:Root>
I want to compare each EmpID with each Manager ID.If any EmpID and ManagerID is equal then simply transform with destination schema otherwise not.
How its is possible ??
Please suggest me some solution.
Prakash

For the given input instance, if you want map the employees who are managers (i.e. for the employee whose EmployeeID matches with the ManagerID) I created a output schema like the below to give an idea about the XSLT (which you can change it to
yours)
, in the map, If I use the XSLT like the following:
<?xml version="1.0" encoding="UTF-16"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s0" version="1.0" xmlns:s0="http://Interplx_ndPhase.ManagerSchema" xmlns:ns0="http://schemas.microsoft.com/BizTalk/2003/aggschema" xmlns:ns2="http://Interplx_ndPhase.SourceSchema">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />
<xsl:template match="/">
<xsl:apply-templates select="/ns0:Root" />
</xsl:template>
<xsl:template match="/ns0:Root">
<ns0:Root>
<OutputMessagePart_0>
<ns2:Response>
<Employees>
<xsl:for-each select="InputMessagePart_0/ns2:Response/Employees/Employee">
<Employee>
<xsl:call-template name="CheckMan">
<xsl:with-param name="empID" select="EmpID/text()" />
<xsl:with-param name="pos" select="position()" />
</xsl:call-template>
</Employee>
</xsl:for-each>
</Employees>
</ns2:Response>
</OutputMessagePart_0>
</ns0:Root>
</xsl:template>
<xsl:template name="CheckMan">
<xsl:param name="empID" />
<xsl:param name="pos" />
<xsl:for-each select="../../../../InputMessagePart_1/s0:ResponseM/Managers/Manager">
<xsl:if test="ManagerID/text() = $empID">
<EmpID>
<xsl:value-of select="../../../../InputMessagePart_0/ns2:Response/Employees/Employee[$pos]/EmpID/text()" />
</EmpID>
<EmpName>
<xsl:value-of select="../../../../InputMessagePart_0/ns2:Response/Employees/Employee[$pos]/EmpName/text()" />
</EmpName>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
You would get the desired output. As mentioned, you can change the output as per your need, and this XSLT which works for me for the above input & output schema can give an idea about how to achieve this requirement.
If this answers your question please mark it accordingly. If this post is helpful, please vote as helpful by clicking the upward arrow mark next to my reply.

ORA-00904: "ATTRIBUTE20": invalid identifier (Human Resource)

Hi
Please anybody can tell me why the error (ORA-00904: "ATTRIBUTE20": invalid identifier) come. When I am trying to query in form "Human Resource Vision Enterprise > People > Salary Management"
Regards
Makshud

Hi Makshud,
In addition to above information, you can refer the following doc for the generic reason of this error,
[OERR: ORA-904 %s: invalid identifier / invalid column name|https://metalink2.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=18500.1]
This could be the reason for some invalid field entry as ORA-904 coming please verify.
This is just for the information of ORA - 904, reason can only me verified after you provide the information asked by Hussein.
Thanks,
Anchorage :)

Question on XMLTABLE related to XMLSEQUENCE

Hi Mark,
Easy one for you.
recently i tried XMLTABLE which i used as a replacement for TABLE(XMLSEQUENCE) which was used with versions lower than 10g R2.
here is the test.
SQL> create table xml(data clob)
2 /
Table created.
SQL>
SQL> insert into xml values (
2 '<DeptList>
3      <Dept id="1">
4            <name>XXX</name>
5            <EMP id="111">
6                 <name>XXX111</name>
7            </EMP>
8            <EMP id="112">
9                 <name>XXX112</name>
10            </EMP>
11      </Dept>
12      <Dept id="2">
13            <name>YYY</name>
14            <EMP id="222">
15                 <name>yyy222</name>
16            </EMP>
17            <EMP id="333">
18                 <name>yyy112</name>
19            </EMP>
20      </Dept>
21    </DeptList>')
22 /
1 row created.
SQL>
SQL> set linesize 150
SQL> column deptid format 9999
SQL> column dname format a20
SQL> column empid format 9999
SQL> column ename format a20
SQL>
SQL> select
2     cast(extractvalue(value(a), '/Dept/@id') as number )      deptid
3    ,cast(extractvalue(value(a), '/Dept/name') as varchar2(20)) dname
4    ,cast(extractvalue(value(b), '/EMP/@id') as number)         empid
5    ,cast(extractvalue(value(b), '/EMP/name') as varchar2(20)) ename
6 from xml
7 ,table(xmlsequence(extract(xmltype(data), '/DeptList/Dept'))) a
8 ,table(xmlsequence(extract(value(a), '/Dept/EMP'))) b
9 /
DEPTID DNAME                EMPID ENAME
     1 XXX                    111 XXX111
     1 XXX                    112 XXX112
     2 YYY                    222 yyy222
     2 YYY                    333 yyy112
SQL> Sofar good. Now i want to replace the TABLE(XMLSEQUENCE) with XMLTABLE operator. I got success with the usage of one XMLTABLE. But when i have requirement for 2, i.e collection within a collection i could not succeed.
here is the one i tried.
select
   deptid, dname, empid, ename
from xml
,xmltable('/DeptList/Dept' passing xmltype(data)
           columns
           deptid number        path   '/Dept/@id'
          ,dname   varchar2(20) path   '/Dept/name') a
,xmltable('/Dept/EMP' passing value(a)
           columns
           empid   number        path   '/EMP/@id'
          ,ename   varchar2(20) path   '/EMP/name')
/How can i make reference to the first collection output to pass it on to the next one.

The following demonstrates using XMLTABLE with a Nested Collection
SQL> create or replace view DEPARTMENTS_XML of XMLType
2 with object id
3 (
4    'DEPARTEMENTS'
5 )
6 as
7 select xmlElement
8         (
9           "Departments",
10           xmlAgg
11           (
12             xmlElement
13             (
14               "Department",
15               xmlAttributes( d.DEPARTMENT_ID as "DepartmentId"),
16               xmlElement("Name", d.DEPARTMENT_NAME),
17               xmlElement
18               (
19                 "Location",
20                 xmlForest
21                 (
22                    STREET_ADDRESS as "Address", CITY as "City", STATE_PROVINCE as "State",
23                    POSTAL_CODE as "Zip",COUNTRY_NAME as "Country"
24                 )
25               ),
26               xmlElement
27               (
28                 "EmployeeList",
29                 (
30                   select xmlAgg
31                          (
32                            xmlElement
33                            (
34                              "Employee",
35                              xmlAttributes ( e.EMPLOYEE_ID as "employeeNumber" ),
36                              xmlForest
37                              (
38                                e.FIRST_NAME as "FirstName", e.LAST_NAME as "LastName", e.EMAIL as "EmailAddress",
39                                e.PHONE_NUMBER as "Telephone", e.HIRE_DATE as "StartDate", j.JOB_TITLE as "JobTitle",
40                                e.SALARY as "Salary", m.FIRST_NAME || ' ' || m.LAST_NAME as "Manager"
41                              ),
42                              xmlElement ( "Commission", e.COMMISSION_PCT )
43                            )
44                          )
45                     from HR.EMPLOYEES e, HR.EMPLOYEES m, HR.JOBS j
46                    where e.DEPARTMENT_ID = d.DEPARTMENT_ID
47                      and j.JOB_ID = e.JOB_ID
48                      and m.EMPLOYEE_ID = e.MANAGER_ID
49                 )
50               )
51             )
52           )
53         ) as XML
54    from HR.DEPARTMENTS d, HR.COUNTRIES c, HR.LOCATIONS l
55   where d.LOCATION_ID = l.LOCATION_ID
56     and l.COUNTRY_ID = c.COUNTRY_ID
57 /
View created.
SQL> set lines 140
SQL> set long 4000
SQL> --
SQL> select * from DEPARTMENTS_XML
2 /
SYS_NC_ROWINFO$
<Departments><Department DepartmentId="60"><Name>IT</Name><Location><Address>2014 Jabberwocky Rd</Address><City>Southlake</City><St
</State><Zip>26192</Zip><Country>United States of America</Country></Location><EmployeeList><Employee employeeNumber="103"><FirstNa
der</FirstName><LastName>Hunold</LastName><EmailAddress>AHUNOLD</EmailAddress><Telephone>590.423.4567</Telephone><StartDate>1990-01
tDate><JobTitle>Programmer</JobTitle><Salary>9000</Salary><Manager>Lex De Haan</Manager><Commission></Commission></Employee><Employ
eeNumber="105"><FirstName>David</FirstName><LastName>Austin</LastName><EmailAddress>DAUSTIN</EmailAddress><Telephone>590.423.4569</
<StartDate>1997-06-25</StartDate><JobTitle>Programmer</JobTitle><Salary>4800</Salary><Manager>Alexander Hunold</Manager><Commissio
ssion></Employee><Employee employeeNumber="106"><FirstName>Valli</FirstName><LastName>Pataballa</LastName><EmailAddress>VPATABAL</E
ss><Telephone>590.423.4560</Telephone><StartDate>1998-02-05</StartDate><JobTitle>Programmer</JobTitle><Salary>4800</Salary><Manager
r Hunold</Manager><Commission></Commission></Employee><Employee employeeNumber="107"><FirstName>Diana</FirstName><LastName>Lorentz<
<EmailAddress>DLORENTZ</EmailAddress><Telephone>590.423.5567</Telephone><StartDate>1999-02-07</StartDate><JobTitle>Programmer</Job
lary>4200</Salary><Manager>Alexander Hunold</Manager><Commission></Commission></Employee><Employee employeeNumber="104"><FirstName>
SYS_NC_ROWINFO$
rstName><LastName>Ernst</LastName><EmailAddress>BERNST</EmailAddress><Telephone>590.423.4568</Telephone><StartDate>1991-05-21</Star
bTitle>Programmer</JobTitle><Salary>6000</Salary><Manager>Alexander Hunold</Manager><Commission></Commission></Employee></EmployeeL
artment><Department DepartmentId="50"><Name>Shipping</Name><Location><Address>2011 Interiors Blvd</Address><City>South San Francisc
State>California</State><Zip>99236</Zip><Country>United States of America</Country></Location><EmployeeList><Employee employeeNumbe
FirstName>Matthew</FirstName><LastName>Weiss</LastName><EmailAddress>MWEISS</EmailAddress><Telephone>650.123.1234</Telephone><Start
-07-18</StartDate><JobTitle>Stock Manager</JobTitle><Salary>8000</Salary><Manager>Steven King</Manager><Commission></Commission></E
Employee employeeNumber="122"><FirstName>Payam</FirstName><LastName>Kaufling</LastName><EmailAddress>PKAUFLIN</EmailAddress><Teleph
23.3234</Telephone><StartDate>1995-05-01</StartDate><JobTitle>Stock Manager</JobTitle><Salary>7900</Salary><Manager>Steven King</Ma
mmission></Commission></Employee><Employee employeeNumber="121"><FirstName>Adam</FirstName><LastName>Fripp</LastName><EmailAddress>
mailAddress><Telephone>650.123.2234</Telephone><StartDate>1997-04-10</StartDate><JobTitle>Stock Manager</JobTitle><Salary>8200</Sal
ger>Steven King</Manager><Commission></Commission></Employee><Employee employeeNumber="124"><FirstName>Kevin</FirstName><LastName>M
SYS_NC_ROWINFO$
astName><EmailAddress>KMOURGOS</EmailAddress><Telephone>650.123.5234</Telephone><StartDate>1999-11-16</StartDate><JobTitle>Stock Ma
bTitle><Salary>5800</Salary><Manager>Steven King</Manager><Commission></Commission></Employee><Employee employeeNumber="123"><First
ta</FirstName><LastName>Vollman</LastName><EmailAddress>SVOLLMAN</EmailAddress><Telephone>650.123.4234</Telephone><StartDate>1997-1
rtDate><JobTitle>Stock Manager</JobTitle><Salary>6500</Salary><Manager>Steven King</Manager><Commission></Commission></Employee><Em
ployeeNumber="128"><FirstName>Steven</FirstName><LastName>Markle</LastName><EmailAddress>SMARKLE</EmailAddress><Telephone>650.124.1
phone><StartDate>2000-03-08</StartDate><JobTitle>Stock Clerk</JobTitle><Salary>2200</Salary><Manager>Matthew Weiss</Manager><Commis
mmission></Employee><Employee employeeNumber="127"><FirstName>James</FirstName><
SQL> select d.DEPARTMENT_ID, d.DEPARTMENT_NAME, e.*
2   from DEPARTMENTS_XML,
3        xmltable
4        (
5           '/Departments/Department'
6           passing object_value
7           columns
8           DEPARTMENT_ID   number(4)    path '@DepartmentId',
9           DEPARTMENT_NAME varchar2(32) path 'Name',
10           EMPLOYEES       xmlType      path 'EmployeeList/Employee'
11        ) d,
12        xmlTable
13        (
14          '/Employee'
15          passing d.EMPLOYEES
16          columns
17          EMPLOYEE_ID number path '@employeeNumber',
18          FIRST_NAME varchar2(32) path 'FirstName',
19          LAST_NANE   varchar2(32) path 'LastName'
20        ) e
21 /
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           60 IT                                       103 Alexander                        Hunold
           60 IT                                       105 David                            Austin
           60 IT                                       106 Valli                            Pataballa
           60 IT                                       107 Diana                            Lorentz
           60 IT                                       104 Bruce                            Ernst
           50 Shipping                                 120 Matthew                          Weiss
           50 Shipping                                 122 Payam                            Kaufling
           50 Shipping                                 121 Adam                             Fripp
           50 Shipping                                 124 Kevin                            Mourgos
           50 Shipping                                 123 Shanta                           Vollman
           50 Shipping                                 128 Steven                           Markle
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           50 Shipping                                 127 James                            Landry
           50 Shipping                                 126 Irene                            Mikkilineni
           50 Shipping                                 125 Julia                            Nayer
           50 Shipping                                 180 Winston                          Taylor
           50 Shipping                                 181 Jean                             Fleaur
           50 Shipping                                 182 Martha                           Sullivan
           50 Shipping                                 183 Girard                           Geoni
           50 Shipping                                 129 Laura                            Bissot
           50 Shipping                                 130 Mozhe                            Atkinson
           50 Shipping                                 131 James                            Marlow
           50 Shipping                                 132 TJ                               Olson
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           50 Shipping                                 184 Nandita                          Sarchand
           50 Shipping                                 185 Alexis                           Bull
           50 Shipping                                 186 Julia                            Dellinger
           50 Shipping                                 187 Anthony                          Cabrio
           50 Shipping                                 133 Jason                            Mallin
           50 Shipping                                 134 Michael                          Rogers
           50 Shipping                                 135 Ki                               Gee
           50 Shipping                                 136 Hazel                            Philtanker
           50 Shipping                                 188 Kelly                            Chung
           50 Shipping                                 189 Jennifer                         Dilly
           50 Shipping                                 190 Timothy                          Gates
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           50 Shipping                                 191 Randall                          Perkins
           50 Shipping                                 137 Renske                           Ladwig
           50 Shipping                                 140 Joshua                           Patel
           50 Shipping                                 139 John                             Seo
           50 Shipping                                 138 Stephen                          Stiles
           50 Shipping                                 192 Sarah                            Bell
           50 Shipping                                 193 Britney                          Everett
           50 Shipping                                 194 Samuel                           McCain
           50 Shipping                                 195 Vance                            Jones
           50 Shipping                                 144 Peter                            Vargas
           50 Shipping                                 143 Randall                          Matos
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           50 Shipping                                 142 Curtis                           Davies
           50 Shipping                                 141 Trenna                           Rajs
           50 Shipping                                 196 Alana                            Walsh
           50 Shipping                                 199 Douglas                          Grant
           50 Shipping                                 197 Kevin                            Feeney
           50 Shipping                                 198 Donald                           OConnell
           10 Administration                           200 Jennifer                         Whalen
           30 Purchasing                               114 Den                              Raphaely
           30 Purchasing                               118 Guy                              Himuro
           30 Purchasing                               117 Sigal                            Tobias
           30 Purchasing                               119 Karen                            Colmenares
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           30 Purchasing                               115 Alexander                        Khoo
           30 Purchasing                               116 Shelli                           Baida
           90 Executive                                101 Neena                            Kochhar
           90 Executive                                102 Lex                              De Haan
          100 Finance                                  108 Nancy                            Greenberg
          100 Finance                                  112 Jose Manuel                      Urman
          100 Finance                                  111 Ismael                           Sciarra
          100 Finance                                  113 Luis                             Popp
          100 Finance                                  109 Daniel                           Faviet
          100 Finance                                  110 John                             Chen
          110 Accounting                               206 William                          Gietz
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
          110 Accounting                               205 Shelley                          Higgins
           20 Marketing                                202 Pat                              Fay
           20 Marketing                                201 Michael                          Hartstein
           40 Human Resources                          203 Susan                            Mavris
           80 Sales                                    148 Gerald                           Cambrault
           80 Sales                                    149 Eleni                            Zlotkey
           80 Sales                                    145 John                             Russell
           80 Sales                                    146 Karen                            Partners
           80 Sales                                    147 Alberto                          Errazuriz
           80 Sales                                    150 Peter                            Tucker
           80 Sales                                    151 David                            Bernstein
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           80 Sales                                    152 Peter                            Hall
           80 Sales                                    153 Christopher                      Olsen
           80 Sales                                    154 Nanette                          Cambrault
           80 Sales                                    155 Oliver                           Tuvault
           80 Sales                                    161 Sarath                           Sewall
           80 Sales                                    160 Louise                           Doran
           80 Sales                                    159 Lindsey                          Smith
           80 Sales                                    158 Allan                            McEwen
           80 Sales                                    157 Patrick                          Sully
           80 Sales                                    156 Janette                          King
           80 Sales                                    167 Amit                             Banda
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           80 Sales                                    166 Sundar                           Ande
           80 Sales                                    165 David                            Lee
           80 Sales                                    164 Mattea                           Marvins
           80 Sales                                    163 Danielle                         Greene
           80 Sales                                    162 Clara                            Vishney
           80 Sales                                    173 Sundita                          Kumar
           80 Sales                                    172 Elizabeth                        Bates
           80 Sales                                    171 William                          Smith
           80 Sales                                    170 Tayler                           Fox
           80 Sales                                    169 Harrison                         Bloom
           80 Sales                                    168 Lisa                             Ozer
DEPARTMENT_ID DEPARTMENT_NAME                  EMPLOYEE_ID FIRST_NAME                       LAST_NANE
           80 Sales                                    177 Jack                             Livingston
           80 Sales                                    176 Jonathon                         Taylor
           80 Sales                                    175 Alyssa                           Hutton
           80 Sales                                    174 Ellen                            Abel
           80 Sales                                    179 Charles                          Johnson
           70 Public Relations                         204 Hermann                          Baer
105 rows selected.
SQL>

HRMS apps 11i help

Hi all
I am new to apps 11i,my boss just came with a requirement of creating employment certificates in erp,
Can someone guide me to create an offer letter for each employee with the company header
Kindly let me know if any details are needed as i am new to apps
thanking in advance
regards
oracleuser

hi
i did ctrl+L ,a small pop up box comes asking to type the interent address of the document we wish to search for
these are things i view when i got to hrms responsibility
abc HRMS Manager
Flex Values
Payment Invoice(PY)
People
Enter and Maintain
Salary Management
Events and Bookings
Delete Personal Records
Manage Contracts
People : Maintain Using Templates
Hiring Applicants
Entering Employees
Maintaining Employees
Entering Contingent Workers
Maintaining Contingent Workers
People : Total Comp Participation
Person Benefits Balances
Person Benefits Assignments
People : Total Comp Enrollment : Benefits Enrollment
View Enrollment Results
Non-flex Program
Savings Plan
Miscellaneous Plan
Enrollment Override
Dependent/Beneficiary Designation
Person Primary Care Provider
Person Life Events
People : Total Comp Contribution
Record Continuing Benefits Payment
Monthly Participant Premium
Monthly Premiums
Manual Payments
People : Mass Updates for Person
Mass Update of Applicant Assignments
Mass Update of Employee Assignments
Mass Update of Assignments
Fast Path
Address
Picture
Special Information
Contact Information
Event for Person
Phone Numbers
Absence Information
Application
End Application
Assignment
Assignment Costing
Assign. Budget Values
Grade Step Placement
Secondary Status
Pay Method
End Employment
Employee Review
Salary Review
Salary History
Element Entry
Accruals
Tax Statement
Statement of Earnings
P45 Form
Adjust Balances
QuickPay
Reverse Payroll Run
Extern./Manual Payments
Person Type Usage
School/College Attendance
Assignment Rates
Element Entry
End Placement
Work Structures
Location
Status
Recruitment Letter Type
Contract Letter Type
Elections
Assignment Rate Types
Collective Agreements
Collective Agreements and Grade Structures
Work Structures : Collective Agreement
Define Entitlement Item
Define Collective Agreement
Define Collective Agreement Grades
Define Eligibility Profiles
Define Derived Factors
Work Structures : Organization
Description
Organization Manager
Hierarchy
Diagrammer
Work Structures : Job
Description
Path Name
Career Path
Job Groups
Work Structures : Position
Description
Hierarchy
Mass Move
Diagrammer
Position Transaction
Position Copy
Mass Position Update
Work Structures : Grade
Description
Grade Rate
Pay Scale
Point Values
Grade Steps and Points
Progression Approval
Work Structures : Budget
Budget Worksheet
Budget Details
Budget Reallocation
Budget Calendar
Budget Set
Budget Characteristics
Budget Migration
Payroll
Description
Consolidation
Payment Methods
GL Flexfield Map
Update Payroll Run
Assignment Set
Element Set
RetroPay Set
GL Daily Rates
Conversion Rate Types
Monetary Units
Balance Sets
View
Vacancies
Grade Comparatio
Employee Accruals
Payroll Process Results
Assignment Process Results
System Messages
View : Histories
Worker Assignment
Absence
Run Results
Salary
Entries
View : Lists
People Folder
Assignment Folder
People by Assignment
Assignments
Workforce by Organization
Workforce by Position
Workforce by Position Hierarchy
Employees by Element
Employees by Absence Type
People by Special Information
Processes and Reports
Submit Processes and Reports
View Requests
View Reports
Workflow Notifications
Define a QuickPaint Report
Run a QuickPaint Report
Submit Custom Reports
Process Log
Batch Process Parameters
Monitor Batch Processes
Mass Information eXchange: MIX
Batch Element Entry
BEE Summary
Mass Information eXchange: MIX : System Extract
Layout Definition
Criteria Definition
Extract Definition
Extract Results
Change Event Log
Other Definitions
Person Types
Application Utilities Lookups
Special Information Types
Table Structure
Table Values
Time Periods
User Profile Options
Formula Functions
User Types and Statuses
Dynamic Trigger Definition
Dynamic Trigger Functional Area Grouping
Table Event Updates
Other Definitions : Payroll Exception Reporting : Payroll Exception Reports and Groups
Reports
Groups
Security
Profile
Assign Security Profiles
CustomForm
Information Types Security
Report Sets
Task Flow Nodes
Task Flow Definitions
Forms Configurator
Contexts
Transaction Status
Task Flow Unit kindly help me
thanking in advance
regards
oracleuser

Reg restriction on employees in the organziation

Salary Management screen contains employees with info and approve button at bottom.
We have severeal organizations. We restricted employees based on organization. But still I am able to see few employees in other organization.
i.e., Org A and Org B contains 30 and 40 employees respectively.
When I login in Salary Management screen in custom responsibilty of org A,
I am able to see few org B people along with the Org A.
I have verified sexurity profile.It is fine and I ran security list maintenance program too.
But still able to see people from different organziation

Even I chekched the box, I am able to see other deprtment employees.
Note: I am seeing only one extra organization employees(only 4 employees not all empl in the organziation), not all organization employees.

Need sql query for all employees list which are having lessthan maximum salary of manager in same departmnet;

HI
I want a sql query i.e., all employees list which are having lessthan maximum salary of manager in same departmnet;
my table is like this
employees
EMPLOYEE_ID                               NOT NULL NUMBER(6)
FIRST_NAME                                                   VARCHAR2(20)
LAST_NAME                                 NOT NULL    VARCHAR2(25)
EMAIL                                     NOT NULL          VARCHAR2(25)
PHONE_NUMBER                                              VARCHAR2(20)
HIRE_DATE                                 NOT NULL        DATE
JOB_ID                                    NOT NULL           VARCHAR2(10)
SALARY                                                           NUMBER(8,2)
COMMISSION_PCT                                          NUMBER(2,2)
MANAGER_ID                                                  NUMBER(6)
DEPARTMENT_ID                                             NUMBER(4)
if need the department table
departments:
DEPARTMENT_ID
NOT NULL NUMBER(4)
DEPARTMENT_NAME
NOT NULL VARCHAR2(30)
MANAGER_ID
NUMBER(6)
LOCATION_ID
NUMBER(4)

Try this:
select
   employees.last_name || ', ' || employees.first_name “Employee”,
   employees.salary “Emp Salary”,
   sub.salary “Mgr Salary”,
   employees.department_id “Department”
from
   employees,
   ( select
      mgr.department_id dept,
      max(mgr.salary) salary
   from
      employees,
      employees mgr
   where
      employees.mgr = mgr.employee_id
   group by
      mgr.department_id) sub
where
   employees.department_id = sub.dept
   and employees.salary < sub.salary
Jeff

SAP ERP 6.0 Enterprise Compensation Management-Salary structure adjustment

Using the sap portal functionality, for the Salary survey and benchmarking -> Salary strucuture adjustment, the portal displays the folllowing situation:
- tab current salary structure : the values are correctly filled automatically using the related back end configuration table
- tab market data = the system displays "market minimum"= "market average" = "market maximum", once selected the composite result to be used
- tab planned salary structure : once click on "Create from market data", the system displays "planned minimum" = "planned reference" = "planned maximum" as consequence of what uploaded in tab "market data".
someone can help me to understand why the market minimum = market maximum = market average, because the uploaded survey job catalogues and survey market have minumum not equal to average not equal to maximum.
Many Thanks
Leandro

Hi Kevin,
As you noted the IT0759 is created, but this is actually good history! How could you refute an employee who says "My boss said I was getting a Special Adjustment and it is not on my paycheck!". You want that "$0.00" record in the IT0759. You do not want any change to IT0008 or IT0015 if there is no adjustment entered and none is created upon activation. But you do want the IT0759 for proof as to what the manager did enter - no increase.
We have used ECM for the past two years. We maintain the IT0759 as history and also have three types of increases - Merit, Market and Lump Sum. Most people will get a merit, some a market adjustment and a few a lump sum amount or they may receive more than one. But even if no entry is made, we want to make sure the manager has "Submitted" the $0.00 record. This way we can verify the manager has consider each employee - $0.00 can be a valid amount if no increase is given! Also, this is referenced when you do a history view of the employee's salary in ECM. Thus, the $0.00 amount record is a valid record and should be maintained.
Paul

Salary of employees of respective manager

i have manager_id,last_name,salary from employees table i need to print the managers name and the lowest salry of the respective employee working under the manager

think about it. You want the lowest salary of an employee with this manager. Do we have a function that returns the lowest value? Why yes, it's MIN.
So we want our where clause to include
and a.salary = (SELECT min(salary) from employees c from this manager (a))
I leave you to do the simple join from c to a.

UNABLE TO GET SALARY BASED ON HOURS ( POSITVE TIME MANAGMENT )

Hi Vivek,
Your document was great.
I am implementing positive time management and at present i am entering the clock in and clock-out in IT-2011 manually for testing and when i run PT60 using TM00 schema it was not showing any errors but data in 'ZL' it was showing as no entries.
And to cross check i have executed 'PC00_M40_CALC' but the payroll was caluclated based on no. of days( negative tm).
I am new to TM concept please help me out.
Thanks,
Saikrishna.

Hi,
Here are some answers/comments to your question above.
1. You should not make any changes in schema TM00 (Standard SAP Schema) - copy this to a custom schema (ZM00) in transaction PE01 and add logic/make changes in this custom schema.
2. Entries will not automatically be created in the ZL table just because you have IT2011 (Table TEVEN) entries. ZL entries are created either through PCR logic, or via table T510S (Wage type generation) entries. These are both very complex Time Management concepts that require a lot of studying and understanding in order to take raw data and generate the appropriate wage types at the appropriate time. This is important because based upon raw clock in and clock out's alone the system does not know if it should generate regular hours, overtime, double time, holiday pay etc - you have to do the configuration to tell the system what to generate and when to generate it.
3. As far as your issue within the payroll driver (Basic Salary being created on the basis of number of date) - I believe this could be based upon either wage type setup or your Pay Scale configuration and this associate's Infotype 8. You probably have him setup like a salaried associate. Check the following area in the IMG Personnel Management --> Personnel Administration --> Payroll Data --> Basic Pay
Good luck on your journey to learning SAP Time Management/SAP Payroll.
Thanks,
Imran

Compensation Management- Planning page in portal - Salary development iview

Hi Experts
I am working on Enterprise compensation Management Planning by manger in protal.
In that portal page there is a a link for employee data on the employee name. clicking this link takes you to another screen where it display the employee data, compensation history data, Eligibiltiy, guidline, employee salary data and guidline values etc.
In this screen there is an iview called "Salary Development". But this iveiw does not display any info, It always says no data found. What data it will display here?
Can you one explain this iveiw with some example?
Thanks and regards
Dhina Varadhan

Hi,
Column EC_APPRAISAL used standard function module HR_ECM_UI_DISP_APPRAISAL (unless you have replaced this with your own) to display the appraisal ratings. The view name is V_TWPC_COL_ERP. Please check it through transaction SM30/SM31.
For your issue, can you check if OSS note 1522746 is relevant?
Hope this helps.
Donnie

Employees Salary without Time Management sub-module?

Dear Consultants,
Where to record employees attendance/absences (time related information) inorder to pay the salary through SAP-HR Payroll? We are implementing PA and Payroll (International). Time Management is not in the scope of the project.
Could you please let me know, how can we handle this without Time Management. What would be the limitations without Time Management sub-module.
Thank you all for your efforts.
Edited by: Business Analyst - HCM on May 20, 2009 2:20 PM

You have to create atleast the work schedule which will consist of DWS and PSW and then work scheedule rule. Also I think you will require to configure feature SCHKZ to default work schedule rule in IT0007.
After doing this configuration you can create wagetypes related to ur time and you can pay these wage types through IT2010 ee remuneration info
if the wt will have rate then that rate you can maintain in T510 and may be to meet the complete requirement you need to write little bit code in CATS exit.
otherwise you will be able to pay through 2010 and you can enter the data thru CAT2 tcode. Just you need to create a profile and set the view for entering the data like single entry or mass entry.
SPRO->IMG->Cross-Application Components->Time Sheet->Specific Settings for CATS Regular->CATS Regular->Record Working Time
hope this will help
guds

TEM and FI/CO (Training and Event Management)

Hi All,
I wish to track actual cost per event in PE (TEM - Training and Event Management). Was considering having a Internal order per Instance of event. Have any Idea on how to set up something like this?
Appreciate all ideas,
LB

Hi Dean,
using internal orders you have to consider that sending and receiving cost center have to in the same company code.
If you do not want to distribute the costs to FI/CO but only report them, you can use the cost items provided by TEM. We have set up something similar for our plants in South Europe.
We have created some cost items and fill them manually with the training costs. Additionally we have created a report that evaluated this costs and combines them with the employee costs (derived from salary).
Best regards
Michael

Salary Management

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