Save selected node in Tree control

I'm making this flex form for my school to add a new student
to the DB. When the admin clicks on a button it will open a Tree
control that displays the available courses and sections in the
following heirarchy:
Year>Semester>Course Name>Sections
Now I want that when he clicks on the button Select within
this new window showing the Tree, it will store the current
selected node and the full path to it, so that back in the original
form it will display the Year, Semester, Course name and section.
I've tried using the value and selecteditem methods from the tree
control but they are not working. Any ideas to figure out the full
path of the selected item?

You will need to climb back up the ancestor nodes to build
that path yourself.
"parent()" i believe returns the parent of the current node.
Tracy

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How to avoid multiple selection in ALV tree control?

Hi,
Experts,
I want to avoid multiple selections on Alv tree control after pressing control keyboard button(Ctrl). Even by pressing Ctrl keyword button i want to select only one row of a Alv tree control.i have used cl_salv_tree class for it is there any method to achieve this please pass some code/idea on it.
Thanks in advance,
Shabeer ahmed.

I haven't tried it before but it should help.
[https://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/cda3992d-0e01-0010-90b2-c4e1f899ac01|https://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/cda3992d-0e01-0010-90b2-c4e1f899ac01]

Tree control - How to get the full path of selected Item in tree control

I am Flex newbie. When the user clicks the particular item in
the tree control I just wanted to get it name along with it's full
parent.
Here is my XML
var dirXML:XML=<root basename="/home/tcegrid">
<Directories>
<Dir Name=".autosave" />
<Dir Name=".emacs.d" />
<Dir Name="AnsysDistributed">
<Dir Name="opt"/>
<Dir Name="root" />
</Dir>
<Dir Name="postgres"/>
<Dir Name="FineTurbo"/>
<Directories>
</root>
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user clicks the Dir Name called opt. I wanted it absolute path in
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Can any one tell me how to get this?

"Thamizhannal" <[email protected]> wrote in
message
news:gam9q8$4es$[email protected]..
>I am Flex newbie. When the user clicks the particular
item in the tree
>control
> I just wanted to get it name along with it's full
parent.
> Here is my XML
> var dirXML:XML=<root basename="/home/tcegrid">
> <Directories>
> <Dir Name=".autosave" />
> <Dir Name=".emacs.d" />
> <Dir Name="AnsysDistributed">
> <Dir Name="opt"/>
> <Dir Name="root" />
> </Dir>
> <Dir Name="postgres"/>
> <Dir Name="FineTurbo"/>
> <Directories>
> </root>
>
> The above XML is data provider for Tree control. When
the user clicks the
> Dir
> Name called opt. I wanted it absolute path in XML. say
> Directories.Dir.Dir.@Name is opt
> Can any one tell me how to get this?
loop until the parent() property of the XML node is empty.
HTH;
Amy

Auto scrolling to a selected node in Tree

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In my one of my flex application, i am selected nodes in a tree based on some input. However, if my tree is large and the selected node is at the bottom then i cant see what is selected until i scroll down. Is there any automatic way of scrolling to a node when that node is selected?
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write this statement
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But make sure you dont call this statement right after you set the dataProvider for the tree object. Instead wait for a second or two and then call this statement. This delay is allow the tree object ot call it validate functions.
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Right click select node in tree (for a standalone Air app)?

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Hi,
Duplicate thread of
http://swforum.sun.com/jive/thread.jspa?threadID=64518
MJ

Selecting node of tree

Hello thanks for anyone before..
I have a problem with selection of my Tree. my tree nodes contains of ItemFormat like :
class ItemFormat
private String code;
private String description;
..... mutator and accessor methods......
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thanks before....

Thanks Tony,
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Highlight selected node in tree

I have a tree in the left, representing my companyÂ´s departments structure and in the right, when clicked, I show the employees that are subject to that department.
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Trees currently donât have a concept of a âcurrentâ node. You could try using lists instead; though they wonât be query based, they would have to have static values. And in the current 1.6 version you canât have hierarchical lists, though that will be added in 2.0.
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select case when connect_by_isleaf = 1 then 0
when level = 1 then 1
else -1
end as status,
level,
"NODE_LABEL" as title,
null as icon,
"SEQ_NBR" as value,
null as tooltip,
'f?p=&APP_ID.:900:'||:APP_SESSION||'::::P900_SELECTED_NODE:'||"SPECIES_QC_ID" as link
from "#OWNER#"."SPECIES_TREE"
where partner_id = :G_ISSUING_AGENCY and nvl("SPECIES_TREE"."DISPLAY_FLAG",'Y') <> 'N'
start with "NODE_PARENT" is null
connect by prior "SEQ_NBR" = "PID"
order siblings by "NODE_PARENT"
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Thanks Tony,
The application I have is a means of commercial seafood dealers recording what species they have purchased/landed. The page is designed with a tree listing all of the species and their sizes and then the tabular report of landings. The current application uses a collection to display the landings....I was trying to get rid of the collection and populate the table directly.
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Hi, i.m a novice for jdev 11.1.1.2,
i need to create a tree menu, but when i put the switcher + n°2 face whith link object, inside the tree and
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Gio
enclose xml for better clarification:
<?xml version='1.0' encoding='UTF-8'?>
<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="2.1"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:af="http://xmlns.oracle.com/adf/faces/rich">
<jsp:directive.page contentType="text/html;charset=UTF-8"/>
<f:view>
<af:document id="d1">
<af:messages id="m1"/>
<af:form id="f1">
<af:panelStretchLayout id="psl1">
<f:facet name="center">
<af:panelGroupLayout layout="scroll"
xmlns:af="http://xmlns.oracle.com/adf/faces/rich"
id="pgl4">
<af:panelSplitter id="ps1" splitterPosition="156"
inlineStyle="width:534px;">
<f:facet name="first">
<af:panelGroupLayout layout="scroll"
xmlns:af="http://xmlns.oracle.com/adf/faces/rich"
id="pgl3">
<af:panelHeader text="panelHeader 1" id="ph1">
<f:facet name="context"/>
<f:facet name="menuBar"/>
<f:facet name="toolbar"/>
<f:facet name="legend"/>
<f:facet name="info"/>
<af:tree value="#{bindings.DepartmentsViewTree.treeModel}"
selectionListener="#{bindings.DepartmentsViewTree.treeModel.makeCurrent}"
rowSelection="single" id="t1" var="node">
<f:facet name="nodeStamp">
<af:switcher id="s1"
facetName="#{node.hierType.viewDefName}">
<f:facet name="DepartmentsView">
<af:panelGroupLayout id="pgl1">
<af:commandLink text="#{node}"
action="#{MainPageBean.departmentRegionLayout}"
id="cl1">
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to="#{pageFlowScope.TreeKey}"/>
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<af:commandLink text=" (Edit)"
action="createEdit" id="cl2">
<af:setActionListener from="#{node.DepartmentId}"
to="#{pageFlowScope.DeptTreeKey}"/>
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</af:panelGroupLayout>
</f:facet>
<f:facet name="EmployeesView">
<af:commandLink text="#{node}"
action="#{MainPageBean.employeeRegionLayout}"
id="cl3">
<af:setActionListener from="#{node.EmployeeId}"
to="#{pageFlowScope.TreeKey}"/>
</af:commandLink>
</f:facet>
</af:switcher>
</f:facet>
</af:tree>
</af:panelHeader>
</af:panelGroupLayout>
</f:facet>
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<af:panelGroupLayout layout="scroll"
xmlns:af="http://xmlns.oracle.com/adf/faces/rich"
id="pgl2">
<af:region value="#{bindings.dynamicRegion1.regionModel}"
id="dynam1" partialTriggers="::t1"/>
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</f:facet>
</af:panelSplitter>
</af:panelGroupLayout>

</f:facet>
</af:panelStretchLayout>
</af:form>
</af:document>
</f:view>
</jsp:root>
Edited by: user595664 on 5-dic-2009 2.54
Edited by: user595664 on 5-dic-2009 2.57

Hi,
you need to provide the full naming for the facet names. So instead of DepartmentsView you provide mypackage.DepartmentsView where you replace mypackage with the package structure of the the ViewObject
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Selection screen within tree control model

Hello,
I am very new in ABAP OO, and have to make a module program for SD to handle the status of shipment.
I need to make a tree model of 3 parts that the first part has the selection screen.
There is a Sap standard model: program /DSD/SL_COCKPIT who has the same modle.
Is someone know how to do that ? which Class to use?
Any help would be appreciated...
Fariba

Hello Fariba
The target you have choosen to start with ABAP OO is not really the easiest one.
The three-parted screen in program /DSD/SL_COCKPIT is created using class <b>/DSD/SL_CL_FRAME_COCKPIT</b>. Simply display the class in the class builder (SE24), push F8 (<i>Test</i>) and create an instance of the class.
Perhaps this may be useful in starting you analyzing the details of this rather complex program and class.
Regards
Uwe

Change the selection of tree control with a right click

How is it possible to change the item selected in a tree control (LabVIEW7) with a mouse right click ?

Filippo,
Here is a popup menu toolkit, with an additional example for a listbox. If I
understand your problem, it shouldn't be hard to change it to a tree
control.
Regards,
Wiebe.
"Filippo" wrote in message
news:[email protected]..
> Sorry for my english ! If you can send me an example, it could be very
> useful for me.
> My e-mail is : [email protected]
> Thanks.
> Regards,
>
> Filippo
[Attachment Menu 042004.zip, see below]
Attachments:
Menu_042004.zip ‏175 KB

Exending SAME ALV tree control to different screens

Hi Experts,
I have to extend same ALV tree control to other different screens:
For exmaple:
I have screen 100 in that I have splitter control on Left ( say TREE_LEFT) which has ALV tree (ref to CL_GUI_ALV_TREE).
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Please suggest.
Regards,
Sathishkumar.V

Hi Sathish,
You are passing the Data to the Screen 100,200,..... by using ALV_GRID OO concept.so the screen is not a constant one.
It is possible to pass the Data (Based on the ALV_TREE user selection) and Modify the Screen dynamically by designing the Fieldcat.
So use only one screen may it 100 or 200 and then Pass data based on the user selection from the Tree control.
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Thanks,
Kanagaraja .L

Selected node in a tree table (via Data Controls and not managed bean)

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I have 3 POJO's,ex; Class AB which has a list of Class CD.And Class CD has a list of class EF. (Used for the tree table)
Now i have a java class, called MyDelegate.java which has a list of AB.I generated data controls off this MyDelegate class and have dropped the ABlist as a tree table (also displaying CD and EF in the tree table).
It displays fine with nodes of AB,CD (child of AB)and EF(child of CD)
The tree table is not bound to any managed bean.
For performing actions on the tree, i create a method - "doSomething() in the delegate class",generate data controls and drop it as a button.
Inside doSomething(), i need acess to the selected node in the tree (it can be a node of type AB or CD or EF).
The problem: I always get access to the node of type AB, and not the child nodes no matter what i click in the tree table.
doSomething(){
DCBindingContainer dcBindingContainer = (DCBindingContainer)ADFUtil.evaluateEL("#{bindings}");
DCIteratorBinding dcTreeIteratorBinding = dcBindingContainer.findIteratorBinding("lstABIterator");
RowSetIterator rowTreeSetIterator = dcTreeIteratorBinding.getRowSetIterator();
DCDataRow rowTree = (DCDataRow)rowTreeSetIterator.getCurrentRow();
if (rowTree.getDataProvider() instanceof AB) {
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} else if (rowTree.getDataProvider() instanceof CD){
          //do something
} else if (rowTree.getDataProvider() instanceof EF) {
          // do something
How do i access the "selected child node of the tree table" here in the delegate class method? Pls help.

Hi Frank,
Thanks for the response. In my case, i dont have a managed bean, so i am slightly unsure how to do it.
There is a mention "Note that another way to access the treeTable component at runtime is to search for it in JavaServer Faces UIViewRoot. This latter option allows you to write more generic code and does not require to create a page dependency to a managed bean"
How do i use this adf view root (without a managed bean) to get hold of the selected row in the tree table. Pls help.
Thanks.

How to binding incoming xml node list to the tree control as dataProvider

Recently, I faced into one issue: I want to binding incoming xml node (it's not avaliable at start) list to the tree control as a dataProvider.
Since the incoming xml node list is not avaliable at beginning but I needs to bind it to the tree, so I create one virtual one in the xml, and prepare to remove it before the tree is shown. (ready for the actual node adding). But It did not work.
Please see the presudo-code here:
1. Model layer(CsModel.as)
public class CsModel
        [Bindable]
        public var treeXML:XML=<nodes><car label="virtualOne" id="1">
                               </car></nodes>;
        (Here, I want to build binding relationship on the <car/> node,
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        public var treeData:XMLList =new XMLListCollection(treeXML.car);
2. view layer(treePage.mxml)
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        private function addNode():void
                var newNode:XML=<car/>;
                newNode.@label="newOne";
                newNode.@id=1;
                _model.treeXML.appendChild(newNode);
                         private function cleanData():void
                                 delete _model.treeXML.car;
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          creationComplete="cleanData()"
          dataProvider="{_model}"/>
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3. Top view layer (App.Mxml)
<mx:application>
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</mx:application>
For method: cleanData()，It's expected that when the treePage is shown, we first delete the virutalOne to provide one 'clear' tree since we don't want show virtualOne to the user. The virutalOne node just for building the relationship between treeData and treeXML at beginning. But the side effect of this method, I found, is that the relationship between treeXML and treeData was cut off. And this leads to that when I added new node (by click the 'addNode' button) to the xmlXML, the xmlData was not affected at all !
So Is there any other way to solve this issue or bind the incoming xml node list to the xmlListCollection which will be used as Tree control's dataProvider ?

If u want to display the name : value then u can do like this
<xsl:eval>this.selectSingleNode("name").nodeName</xsl:eval> : <xsl:value-of select="name" />

Save selected node in Tree control

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