SaveEntity, pass in a form structure.

Question

I've just started playing with ORM, and one thing I learned pretty quickly is that I need to completely rework the way I think of my data and how I work with it, so forgive me if these questions seem odd.
For years now, for each 'object', I have written my own methods.. one of these being save().  I can throw any structure at save() (e.g. a form) and it will work out how to handle it.
So I can submit a form to something like ...  saveForm = myObject.save(argumentcollection=form);  If I pass in the identifier for the record, it will do an update based on that identifier, if there is no identifier it will insert a new record.
I seem to be able create a new record with this appraoch using...  EntityNew('objName",formStruct) then EntitySave("objName") to create a new record, but does anyone know how I can upate an existing record using EntitySave() without having to pass each value into the setter for each property (e.g setName(form.name) ett....).
If the struct I pass into EntityNew has an identifier it throws an error that a 'set' method for that property doesn't exist...
So, to summarise.  Is there a way that I an update an existing record using ORM by just passing in a structure?
Thanks in advance, and apologies if this is sounding like a madmans rambles..
Jason

Answer 1

Hi,
If need generic assignmet use field symbols :
   PERFORM set_range TABLES r_gbstk USING 'BT' 'A' 'B'.
   FORM set_range TABLES t_range
                USING    p_option
                         p_low
                         p_high
  FIELD-SYMBOLS : <fs>.
  ASSIGN COMPONENT 'SIGN' OF STRUCTURE t_range TO <fs>.
  <fs> = 'I'.
  ASSIGN COMPONENT 'OPTION' OF STRUCTURE t_range TO <fs>.
  <fs> = p_option.
  ASSIGN COMPONENT 'LOW' OF STRUCTURE t_range TO <fs>.
  <fs> = p_low.
  ASSIGN COMPONENT 'HIGH' OF STRUCTURE t_range TO <fs>.
  <fs> = p_high.
  APPEND t_range.
ENDFORM.                    " SET_RANGE