Script for Linear Gradient Fill

I need a script to gradient fill - linear top to bottom - rectangles. Can someone help me with this?

Hi,
You may need to create the linear elements first if they have not been defined at design time, there is a sample of doing that here, http://forms.stefcameron.com/2008/03/14/field-background-color-fill/#comment-4423
Regards
Bruce

Similar Messages

Syntax for linear gradient

I'm getting:
WARNING: com.sun.javafx.css.parser.CSSParser linearGradient Using deprecated syntax for linear gradient at <filename & line #>. Refer to the CSS Reference Guide.
But I'm copying the syntax from the only reference guide I can find (no reference is included in the JDK)
http://download.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html

The docs in the SDK have the correct reference. You can find the ref by following the link from the class doc for Node. Here is the relevant section.
Linear Gradients <linear-gradient>
linear-gradient( [ [from <point> to <point>] | [ to <side-or-corner>], ]? [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
where <side-or-corner> = [left | right] || [top | bottom]
Linear gradient creates a gradient going though all the stop colors along the line between the "from" <point> and the "to" <point>. If the points are percentages, then they are relative to the size of the area being filled. Percentage and length sizes can not be mixed in a single gradient function.
If neither repeat nor reflect are given, then the CycleMethod defaults "NO_CYCLE".
If neither [from <point> to <point>] nor [ to <side-or-corner> ] are given, then the gradient direction defaults to 'to bottom'.
Stops are per W3C color-stop syntax and are normalized accordingly.
This example will create a gradient from top left to bottom right of the filled area with red at the top left corner and black at the bottom right.
linear-gradient(to bottom right, red, black)
This is equivalent to:
linear-gradient(from 0% 0% to 100% 100%, red 0%, black 100%)
This more complex example will create a 50px high bar at the top with a 3 color gradient with white underneath for the rest of the filled area.
linear-gradient(from 0px 0px to 0px 50px, gray, darkgray 50%, dimgray 99%, white)
The following syntax for linear gradient does not conform to the CSS grammar and is deprecated in JavaFX 2.0. The JavaFX 2.0 CSS parser supports the syntax but this support may be removed in later releases.
linear (<size>, <size>) to (<size>, <size>) stops [ (<number>,<color>) ]+ [ repeat | reflect ]?
Radial Gradients <radial-gradient>
radial-gradient([ focus-angle <angle>, ]? [ focus-distance <percentage>, ]? [ center <point>, ]? radius [ <length> | <percentage> ] [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
If neither repeat nor reflect are given, then the CycleMethod defaults "NO_CYCLE".
Stops are per W3C color-stop syntax and are normalized accordingly.
Following are examples of the use of radial-gradient:
radial-gradient(radius 100%, red, darkgray, black)
radial-gradient(focus-angle 45deg, focus-distance 20%, center 25% 25%, radius 50%, reflect, gray, darkgray 75%, dimgray)
The following syntax for radial gradient does not conform to the CSS grammar and is deprecated in JavaFX 2.0. The JavaFX 2.0 CSS parser supports the syntax but this support may be removed in later releases.
radial [focus-angle <number> | <number> ] ]? [ focus-distance <size> ]? [ center <size,size> ]? <size> stops [ ( <number>, <color> ) ]+ [ repeat | reflect ]?

No "ANGLE" Option for Linear Gradients in Motion 4!

Referring to the help section for Motion 4, there should be an "angle" tool for linear gradients, but there's not! I have a linear gradient that runs top to bottom and I want it to run left to right. Is there any other way to do this without having to rotate my entire shape object (which would require other modifications?)
Thanks,
~Greg

You can do it by the numbers in the Inspector by changing the start and end points, or you can right-click in the Canvas and choose Edit Gradient to adjust it interactively - assuming it's a shape with a gradient applied.

SVG to CSS Help for Linear Gradient

Below is the linear gradient i created to skin the TabPane
SVG code
<linearGradient id="SVGID_1_" gradientUnits="userSpaceOnUse" x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292">
     <stop offset="0" style=stop-color:#C2B59B;stop-opacity:0.43"/>
     <stop offset="0" style=stop-color:#E2DBCE;stop-opacity:0.66"/>
     <stop offset="0.7939" style=stop-color:#C2B59B;stop-opacity:0.19"/>
     <stop offset="1" style=stop-color:#C2B59B;stop-opacity:0.02"/>
</linearGradient>
Css Code i used as
#tab-pane *.tab-header-background {
    -fx-background-color: linear-gradient(#c2b59b 40%, #e2dbce 60%, #c2b59b 19%, #c2b59b 2%);
}Now my question is how to specify theses thing in css
x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292" and offset of each stop ?
Edited by: Pugazhendhi on Apr 12, 2012 2:59 AM
Edited by: Pugazhendhi on Apr 12, 2012 2:59 AM

If you look at http://docs.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html#typepaint, you will see that you can give a "from <point> to <point>" in the linear-gradient.
Here is your SVG:
<linearGradient id="SVGID_1_" gradientUnits="userSpaceOnUse" x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292">
<stop offset="0" style="stop-color:#C2B59B;stop-opacity:0.43"/>
<stop offset="0" style="stop-color:#E2DBCE;stop-opacity:0.66"/>
<stop offset="0.7939" style="stop-color:#C2B59B;stop-opacity:0.19"/>
<stop offset="1" style="stop-color:#C2B59B;stop-opacity:0.02"/>
</linearGradient>The offsets in your SVG linear gradient are percentages, not absolute values. Here, then, would be the equivalent linear-gradient (I rounded .7939 to 80%):
linear-gradient(from 6.4492 95.292 to 1186.2246 95.292, #C2B59B 0%, #E3DBCE 0%, #C2B59B 80%, #C2B59B 100%)Having two color stops at 0% seems like a mistake.
I also doubt that you want the absolute x1,y1 and x2,y2 values. You need to ask yourself what direction you want the gradient to go. It looks to me like this is going "to right" (since y1==y2). So, it is more likely that you want:
linear-gradient(to right, #C2B59B 0%, #E3DBCE 0%, #C2B59B 80%, #C2B59B 100%)The thing I didn't do here is to include the opacity from the svg stops. There are a few things you can do to solve that but the easiest is to translate the stop-opacity into a hex two hex digits and add those to the color. Just multiply the opacity by 255 and convert to hex. For example, .19 * 255 = 0x30 so the third stop would be #C2B59B30. Note that standard CSS doesn't support this extra byte for opacity in a hex color, so you could translate the hex color and opacity to rgba - #C2B59B30 = rgba(194, 181, 155, .19)

In Adobe CC 2014 has the styling options been removed for gradient fills and inner shadows?

I was just setting up a simple button and can't seem to find the way to fill it with a gradient fill or apply an inner shadow to one of the states.

Hi Gary,
Here is the option for the gradient fill, http://prntscr.com/3woegn and here is the option for the inner glow, which can be used to create the effect of inner shadow, http://prntscr.com/3wofmd
- Abhishek Maurya

[svn] 4394: Adding last changes and comments on behalf of Kaushal for his radial and linear gradient transform calculations .

Revision: 4394
Author: [email protected]
Date: 2009-01-05 13:13:51 -0800 (Mon, 05 Jan 2009)
Log Message:
Adding last changes and comments on behalf of Kaushal for his radial and linear gradient transform calculations.
QE: Not yet.
Doc: No
Checkintests: Pass
Modified Paths:
flex/sdk/trunk/modules/fxgutils/src/java/flash/fxg/swf/AbstractFXGGraphics.java
flex/sdk/trunk/modules/fxgutils/src/java/flash/fxg/swf/TypeHelper.java

After posting I and lots of research I realized that I need to dive into
PaperVision 3D as way to get where I need to go.
However, if anyone has a solution to adding text to this code which rotates with the cube - let me know.
Thanks

Generate script for filling table

Hi all,
I've got table at test Oracle server table1 with columns ID, BTYPE, MYDESCRIPTION. Rows of this table have been inserted manually. Now my need is to write script for creating table (structure + data). I think about writing something like
CREATE TABLE table 1
AS
SELECT 1 AS ID, 'TYPE1' AS BTYPE, 'SOME TEXT' AS MYDESCRIPTION
UNION ALL
SELECT 2 AS ID, 'TYPE2' AS BTYPE, 'SOME TEXT 2' AS MYDESCRIPTION
But rows are too many to type... Could you please suggest some way of generating script for creating table at working server using existing table at test server? The problem is I don't have an access to working server.
Thanks ahead.

Use the view user_tab_cols
say
declare
cursor c1 is
select 'e_'||column_name ||' '||data_type||' ('||data_length||') ' col
from user_tab_cols
where table_name = 'DEPARTMENTS'
union
select 'd_'||column_name ||' '||data_type||' ('||data_length||') ' col
from user_tab_cols
where table_name = 'EMPLOYEES';
v1 varchar2(500);
begin
v1 := 'create table new_tabl (';
for i in c1 loop
v1 := v1||i.col||',';
end loop;
v1 := substr(v1,1,length(v1)-1);
dbms_output.put_line(v1||')');
end;
/i am using employees and departments table of hr schema.
now as both the tables have some column column so i have used e for employees and d for departments
just do one thing remove the length for date data type in o/p i dont know why it is not working.
this will give you structure for data use any sql stmt
Edited by: 810345 on Jun 9, 2011 9:58 PM

Creating Gradient-filled shapes via JSFL CS5.5?

I'm trying to use JSFL to create a number of oval shapes on a layer, that have a gradient fill applied to them. I've stripped down the JSFL to very bare bones which I will post here:
var flashDoc = fl.getDocumentDOM();
var flashLib = flashDoc.library;
var flashTimeline = flashDoc.getTimeline();
// Set fill color for all shapes
var fill = flashDoc.getCustomFill();
fill.style = "radialGradient";
fill.color = "#FFFFFF";    // For some reason if I don't assign at least *something* here, the color array doesn't work and I get fully black shapes
fill.colorArray = ["#0033CC", "#FFFFFF"];
fill.posArray = [0, 255];
fill.focalPoint = 0;
fill.linearRGB = true;
flashDoc.setCustomFill( fill );
for( var i = 0; i < 10; ++i )
    var x = Math.random() * 500;
    var y = Math.random() * 400;
    var radius = Math.random() * 25 + 25;
    var left = x - radius;
    var top = y - radius;
    var right = x + radius;
    var bottom = y + radius;
    flashDoc.addNewOval( {left:left, top:top, right:right, bottom:bottom}, false, true );
When I run this script I do not get the results I'm expecting. I get a number of oval shapes that all share the same gradient transform, i.e., each shape only gets part of the gradient. The documentation says this function should be equivalent to using the draw oval tool, yet when you use that tool each oval you draw is associated with its own gradient transform.
My Questions:
1. Am I missing a piece here to create shapes each with their own gradient transform?
2. Is it a bug that I have to set something into fill.color, even though I'm supplying a color array? If I set nothing there, all the shapes will draw in full black.
3. Is there a way to specify gradient colors that include alpha?
Thanks for your time.

Yep, that made the rest of my whole day!! Works excelllent in the demo, and i'm just replacing all the Image<->Triangle commands. Wonderfulll & thanks a lot, LitDev. (enjoint the sb sample in your Test-DL :-))
PS:
Controls.SetTextBoxText(Controls.AddTextBox(10,10), "Enter your name here...")
Controls.AddButton(".. then press the Button", 180,10)
LDGraphicsWindow.Capture("","")
GraphicsWindow.Clear()
GraphicsWindow.DrawImage("ImageList1", 0,0)

Trying to make sense of AS2 gradient fill matrices

This one will likely interest kglad, but I'm all ears for
insight from
anyone who digs math.
I've been working with gradient fills lately in AS2, which
means I've
been reading through related entries in the ActionScript 2.0
Language
Reference. Here's a quick example right out of the docs
(slightly revised
to boil it down to the essentials). The Drawing API draws a
square and
fills it with a linear gradient that goes from red (upper
left) to blue
(lower right).
this.createEmptyMovieClip("gradient_mc",this.getNextHighestDepth());
with (gradient_mc) {
colors = [0xFF0000, 0x0000FF];
fillType = "linear";
alphas = [100, 100];
ratios = [0, 0xFF];
matrix = {matrixType:"box", x:100, y:100, w:200, h:200,
r:(45/180)*Math.PI};
beginGradientFill(fillType,colors,alphas,ratios,matrix);
moveTo(100,100);
lineTo(100,300);
lineTo(300,300);
lineTo(300,100);
lineTo(100,100);
endFill();
The point of interest, to me, is that generic Object
instance, matrix,
with properies x, y, w, h, r, and matrixType. The x and y are
for position
and correspond to the moveTo(100,100) call. The w and h
represent width and
height. The r is rotation in radians. The matrixType is
arbitrary (I
guess), because the same matrix can be used for a radial
gradient -- never
mind that for now.
The properties shown, arbitrary or not, are the ones
demonstrated in the
docs. That snippet does draw a 45deg red to blue gradient.
The docs recommend a slightly different approach for Flash
Payer 8 and
higher; namely, the native Matrix class. Everything in the
above sample
remains except that the existing matrix line changes to these
two lines:
matrix = new Matrix();
matrix.createGradientBox(200, 200, (45/180)*Math.PI, 100,
100);
Pretty obvious to see where they overlap. The matrixType
property is
gone, but hey ... everything works, so I'm not going to go
looking for
trouble.
Here's the punch line. The docs *also* show an alternative
Object
approach, one in which the properties describe a 3x3 matrix
whose properties
are a, b, c, d, e, f, g, h, and i. After toying with this
a-through-i
example, I noticed a pattern in the values: c, f, and i are
0, 0, and 1
respectively. That seems to correspond to the conventional
graphics matrix
a b u
c d v
tx ty w
... where u, v, and x are 0, 0, and 1. Seems fairly clear
that tx and ty
would correspond to x and y. After tracing the properties of
the matrix
variable (after the createGradientBox() call) it seemed
reasonable to me to
make the following mapping:
a:a b:b c:0
d:c e:d f:0
g:tx g:ty i:1
... which led me to replace the original matrix declaration
with this (back
to a single line):
matrix = {
a:0.086316745750311,
b:0.086316745750311,
c:0,
d:-0.086316745750311,
e:0.086316745750311,
f:0,
g:200,
h:200,
i:1
Those values, by the way, come from my tracing the
properties of this
matrix.createGradientBox(200, 200, (45/180)*Math.PI, 100,
100);
The weird part is, that still gives a 45deg angled gradient,
but it's
super-heavily banded. Not really a gradient at all, but more
like four
colored stripes -- red, blue, red, blue -- from upper left to
lower right.
Can anyone explain to me why?
David Stiller
Adobe Community Expert
Dev blog,
http://www.quip.net/blog/
"Luck is the residue of good design."

GWD,
> I couldn't leave it alone. I came back to it.
Ha! I know that feeling. :)
> matrix = { a:200, b:-100, c:0, d:-100, e:200, f:0,
g:200, h:200, i:1 };
>
> gets close, but its still not quite right. I think the
difference here is
> that skew is expressed differently.
That makes sense. And yes, that comes pretty close.
> I found a better explanation here:
>
http://www.flashdevils.com/tutorials.php?id=142
Thanks, GWD! That helps a lot.
> [I would be inclined to use the other approaches if I
could get
> away with it.]
Yeah, I definitely agree. I find it odd that the docs even
mention it,
but since they do, I found myself elbow deep in wondering
why. Thanks for
input!
David Stiller
Adobe Community Expert
Dev blog,
http://www.quip.net/blog/
"Luck is the residue of good design."

Change the blending mode on the gradient fill within a shape layer?

I can't seem to figure out how to do this, if it is possible. I have a shape layer with a gradient fill, that gradient fill layer needs to be set to multiply, by default its normal. can the be done with scripting?

Indeed it is not that easy to modify the blending mode.
The blending mode is property(1), or property("ADBE Vector Blend Mode"), of the gradient fill.
Normally the blending modes are listed in the BlendingMode object, and mutliply corresponds to BlendingMode.MULTIPLY
But it doesnt work for shape graphics: if you try myGradientFill.property(1).setValue(blendingMode.MULTIPLY); you are out of range.
The value to enter is actually the occurrence of the mode in the dropdownmenu, counting separators...
so
myGradientFill.property(1).setValue(4);
Xavier

[AS] Set Gradient Fill Angle

I am using XTags to build a document in ID, but for some reason all my gradient fills have a 0degree angle and they all need changing to 90deg.
I can change a single box successfully, so I know the 'core' line of script works. My problem is finding a loop that does the job. The results are erratic. If the boxes with the fills are part of a group they don't change. If I ungroup everything (which I don't want to do as each group is a product image, description, price and need to move together), then a change happens - but although the gradient box shows 90deg, the boxes all look to be filled with solid red (instead of light to dark red as they should be).
This is the sort of thing I'm playing with:
tell application "Adobe InDesign CS5"
tell document 1
set gradboxes to object reference of every text frame whose name of fill color is "PromotionTypeGradient"
repeat with i in gradboxes
tell i
set gradient fill angle to 90
end tell
end repeat
end tell
end tell
I tried doing this with find/change, but got the same result - the fill seems to be solid red.
Any suggestions? Is my approach fundamentally wrong?
Thanks
Emma

Aha! Yes it was the grouped items. I still have a problem where the colour seems to go solid, but I think that's just my monitor. When I redefine the gradient with contrasting colours (as opposed to 2 shades of red as it should be) it all works, so I will try this at work tomorrow and fingers crossed a lot of time will be saved.
Thanks!

How can I get "distorted" gradient fills to copy & paste properly?

Here's the situation simplified: I create a document and draw a circle and fill it with a circular gradient fill. I then copy and paste that circle into a new document. It looks exactly the same, and importantly, the gradient fill is still editable, so I can change the colours making up the gradient, their positions on the gradient-slider, etc.
However, if I draw the circle in the first document, fill it with a circular gradient fill, and then I "distort" the gradient's shape to an oval shape, using the gradient tool — still keeping the circle itself as a circular shape (only the fill has changed shape) — and I then copy and paste this circle into a document, it does not get copied across properly as a "true" gradient fill.
At first glance, it looks the same. However, viewing the circle in Outline mode shows that the gradient fill has been expanded into 100s and 100s of flat solid coloured objects, each one laid on top of another, getting progressively smaller and smaller, and all masked in the original circle shape.
And of course, as the gradient fill has been expanded, it is no longer "live" and no longer editable, so I now can not edit its colours or positions on the gradient-slider, etc.
So, how can I make it so that Illustrator maintains and keeps the correct gradient fill when copying and pasting between documents? I've tried editing all the settings under Preferences > File Handling & Clipboard, but all without success.
At the moment, to overcome this "bug", I have to separate the two document windows by dragging its tab out of the main Illustrator window, so I now have two floating windows, rather than all windows tabbed in the one environment, and I then have to drag and drop the object from one window to the other. Slightly inconvenient, but it does get the job done.
Strangely enough, dragging and dropping DOES work, whereas copying and pasting does NOT. Weird.
However this slight inconvenience soon adds up when I have to do it many many many times over.
And it gets progressively worse, because dragging and dropping does not allow me to place the object in the position I want it, whereas with copying and pasting, I could ordinarily choose to "Paste In Front" to place my object exactly in the same position between the two documents.
In order to overcome this, I have to drag and drop to get the gradient fill across correctly, and then I have to copy and paste a non-filled duplicate version of the object to get it in precisely the same place, and then I have to use the alignment tools to get the two objects to line up. This = major inconvenience.
And all this becomes even worse when attempting to copy an Illustrator object into Photoshop as a Smart Object, because when I then double-click the Smart Object in Photoshop to edit it, the gradient fill has been expanded — because, obviously, the object had to have been copied and pasted to get it from Illustrator into Photoshop, and this is the problem that Illustrator seems to be having.

Thanks for the continuing answers guys, mucho appreciado.
However, to go through what's been said since my last post...
I tried launching Illustrator in another user account on this machine, but it wouldn't even launch! I got some error number (which I don't recall offhand, but I can re-check it later).
To clarify, this is an official install of CS4 (so no pirating here!), and Illustrator was not running in my other main user account.
And the InDesign thing wouldn't apply to me, as I don't use that app at all. I do invariably have a couple of other CS4 apps running though, usually always Photoshop and Bridge.
I CAN understand how copying and pasting from Illustrator to InDesign would cause this though, because InDesign doesn't support live editable gradients to the same advanced degree that Illustrator does, so it has to expand it when doing so, thereby losing its editability.
Copying and pasting whilst staying completely within Illustrator though is a different story.
You know what — I just had a thought... What if this is nothing to do with Illustrator, but is instead something to do with my Mac OS's system-level clipboard?
I actually had a 3rd-party multiple-item clipboard item installed some time ago, but then never used it. Maybe there's still remnants of that floating around and that's interfering with it somehow?
I'll see if I can clear out all traces of it and see if it makes a difference... Fingers crossed!

How do I apply a linear gradient to an S shape?

Hi
I recently created an S shape with the pen tool that is quite large in my photoshop cs4. I would like to know if there is a way for me to apply a linear gradient so that it follows the path of the S shape perfectly.
The effect should cause one of the sides of the letter S to actually fade into black (the gradient is a transparent to black gradient colors).
Is this even possible with my Photoshop cs4?
Ricky

Hi,
Thanks for the response. I have found a way to accomplish exactly what I want.
I use a stroke, set it to 'inner' style to the bottom most option, play with side and choose gradient
I played aorund with these settings on here and got it working perfectly.
Ricky

Gradient filled background is not showing up in Internet Explorer on a PC.

My gradient filled background is not showing up in Internet Explorer on a PC.
I'm working on a MAC, so I don't know of anyway to preview a new MUSE Site in I.E. since it's no longer supported on a Mac.
When the Home Page is viewed, my blue sky gradient background shows up as a white box?? I need a fix for this please.
Here is my url: www.ThanksSanta.org

Hello,
We might have to look into your .muse file to have a better look into the issue.
I tried it on a sample file but it worked fine for me.
Could you please e-mail your .muse file on [email protected] You can use Adobe SendNow service (https://sendnow.acrobat.com/) to send your file in case it is larger than 20MB.
Please do not forget to mention the link to this forum in your e-mail.
Regards,
Sachin

-webkit-linear-gradient not working with Adobe Air 3.0

Hi -
I recently downloaded Adobe Air 3.0 after reading that gradients are now supported (http://www.adobe.com/devnet/air/ajax/articles/air_and_webkit.html), but I have not been able to successfully implement them. For example, I have the following CSS class defined:
.gradient_test {
     background-image: -webkit-linear-gradient(#68AB34, #3D721B);
     padding: 5px;
     color: #FFF;
This should (and does in Chrome, Safari, etc) create a linear gradient going from light to dark green. But in Air it just appears as if no background has been applied to the selector. Am I missing some unique way to be able to apply gradients in Adobe Air 3.0?
Thanks,
Zach

I don't know why this hasn't been addressed. I'm seeing the exact same problem. I've tried every permutation, but haven't been able to generate a gradient using any existing standard for webkit or otherwise (even though it's allegedly supported).
-Matthew
EDIT: I discovered that when the app is compiled, the gradients work fine. This one is driving my crazy, because I want to be able to test them. I get a mix of CSS support, depending on how the app is run.
From Dreamweaver CS3 "Preview" - My CSS doesn't show gradients and shows embedded web fonts.
From ADL - My CSS fails almost entirely, but some if it gets loaded.
From the compiled AIR file: fortunately, everything seems to display correctly, but it's really a bad scenario for development / testing. Not sure what to do.

Script for Linear Gradient Fill

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