Syntax for linear gradient

I'm getting:
WARNING: com.sun.javafx.css.parser.CSSParser linearGradient Using deprecated syntax for linear gradient at <filename & line #>. Refer to the CSS Reference Guide.
But I'm copying the syntax from the only reference guide I can find (no reference is included in the JDK)
http://download.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html

The docs in the SDK have the correct reference. You can find the ref by following the link from the class doc for Node. Here is the relevant section.
Linear Gradients <linear-gradient>
linear-gradient( [ [from <point> to <point>] | [ to <side-or-corner>], ]? [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
where <side-or-corner> = [left | right] || [top | bottom]
Linear gradient creates a gradient going though all the stop colors along the line between the "from" <point> and the "to" <point>. If the points are percentages, then they are relative to the size of the area being filled. Percentage and length sizes can not be mixed in a single gradient function.
If neither repeat nor reflect are given, then the CycleMethod defaults "NO_CYCLE".
If neither [from <point> to <point>] nor [ to <side-or-corner> ] are given, then the gradient direction defaults to 'to bottom'.
Stops are per W3C color-stop syntax and are normalized accordingly.
This example will create a gradient from top left to bottom right of the filled area with red at the top left corner and black at the bottom right.
linear-gradient(to bottom right, red, black)
This is equivalent to:
linear-gradient(from 0% 0% to 100% 100%, red 0%, black 100%)
This more complex example will create a 50px high bar at the top with a 3 color gradient with white underneath for the rest of the filled area.
linear-gradient(from 0px 0px to 0px 50px, gray, darkgray 50%, dimgray 99%, white)
The following syntax for linear gradient does not conform to the CSS grammar and is deprecated in JavaFX 2.0. The JavaFX 2.0 CSS parser supports the syntax but this support may be removed in later releases.
linear (<size>, <size>) to (<size>, <size>) stops [ (<number>,<color>) ]+ [ repeat | reflect ]?
Radial Gradients <radial-gradient>
radial-gradient([ focus-angle <angle>, ]? [ focus-distance <percentage>, ]? [ center <point>, ]? radius [ <length> | <percentage> ] [ [ repeat | reflect ], ]? <color-stop>[, <color-stop>]+)
If neither repeat nor reflect are given, then the CycleMethod defaults "NO_CYCLE".
Stops are per W3C color-stop syntax and are normalized accordingly.
Following are examples of the use of radial-gradient:
radial-gradient(radius 100%, red, darkgray, black)
radial-gradient(focus-angle 45deg, focus-distance 20%, center 25% 25%, radius 50%, reflect, gray, darkgray 75%, dimgray)
The following syntax for radial gradient does not conform to the CSS grammar and is deprecated in JavaFX 2.0. The JavaFX 2.0 CSS parser supports the syntax but this support may be removed in later releases.
radial [focus-angle <number> | <number> ] ]? [ focus-distance <size> ]? [ center <size,size> ]? <size> stops [ ( <number>, <color> ) ]+ [ repeat | reflect ]?

Similar Messages

  • No "ANGLE" Option for Linear Gradients in Motion 4!

    Referring to the help section for Motion 4, there should be an "angle" tool for linear gradients, but there's not! I have a linear gradient that runs top to bottom and I want it to run left to right. Is there any other way to do this without having to rotate my entire shape object (which would require other modifications?)
    Thanks,
    ~Greg

    You can do it by the numbers in the Inspector by changing the start and end points, or you can right-click in the Canvas and choose Edit Gradient to adjust it interactively - assuming it's a shape with a gradient applied.

  • SVG to CSS Help for Linear Gradient

    Below is the linear gradient i created to skin the TabPane
    SVG code
    <linearGradient id="SVGID_1_" gradientUnits="userSpaceOnUse" x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292">
         <stop offset="0" style=stop-color:#C2B59B;stop-opacity:0.43"/>
         <stop offset="0" style=stop-color:#E2DBCE;stop-opacity:0.66"/>
         <stop offset="0.7939" style=stop-color:#C2B59B;stop-opacity:0.19"/>
         <stop offset="1" style=stop-color:#C2B59B;stop-opacity:0.02"/>
    </linearGradient>
    Css Code i used as
    #tab-pane *.tab-header-background {
        -fx-background-color: linear-gradient(#c2b59b 40%, #e2dbce 60%, #c2b59b 19%, #c2b59b 2%);
    }Now my question is how to specify theses thing in css
    x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292" and offset of each stop ?
    Edited by: Pugazhendhi on Apr 12, 2012 2:59 AM
    Edited by: Pugazhendhi on Apr 12, 2012 2:59 AM

    If you look at http://docs.oracle.com/javafx/2.0/api/javafx/scene/doc-files/cssref.html#typepaint, you will see that you can give a "from <point> to <point>" in the linear-gradient.
    Here is your SVG:
    <linearGradient id="SVGID_1_" gradientUnits="userSpaceOnUse" x1="6.4492" y1="95.292" x2="1186.2246" y2="95.292">
    <stop  offset="0" style="stop-color:#C2B59B;stop-opacity:0.43"/>
    <stop  offset="0" style="stop-color:#E2DBCE;stop-opacity:0.66"/>
    <stop  offset="0.7939" style="stop-color:#C2B59B;stop-opacity:0.19"/>
    <stop  offset="1" style="stop-color:#C2B59B;stop-opacity:0.02"/>
    </linearGradient>The offsets in your SVG linear gradient are percentages, not absolute values. Here, then, would be the equivalent linear-gradient (I rounded .7939 to 80%):
    linear-gradient(from 6.4492 95.292 to 1186.2246 95.292, #C2B59B 0%, #E3DBCE 0%, #C2B59B 80%, #C2B59B 100%)Having two color stops at 0% seems like a mistake.
    I also doubt that you want the absolute x1,y1 and x2,y2 values. You need to ask yourself what direction you want the gradient to go. It looks to me like this is going "to right" (since y1==y2). So, it is more likely that you want:
    linear-gradient(to right, #C2B59B 0%, #E3DBCE 0%, #C2B59B 80%, #C2B59B 100%)The thing I didn't do here is to include the opacity from the svg stops. There are a few things you can do to solve that but the easiest is to translate the stop-opacity into a hex two hex digits and add those to the color. Just multiply the opacity by 255 and convert to hex. For example, .19 * 255 = 0x30 so the third stop would be #C2B59B30. Note that standard CSS doesn't support this extra byte for opacity in a hex color, so you could translate the hex color and opacity to rgba - #C2B59B30 = rgba(194, 181, 155, .19)

  • Script for Linear Gradient Fill

    I need a script to gradient fill - linear top to bottom - rectangles. Can someone help me with this?

    Hi,
    You may need to create the linear elements first if they have not been defined at design time,  there is a sample of doing that here, http://forms.stefcameron.com/2008/03/14/field-background-color-fill/#comment-4423
    Regards
    Bruce

  • [svn] 4394: Adding last changes and comments on behalf of Kaushal for his radial and linear gradient transform calculations .

    Revision: 4394
    Author: [email protected]
    Date: 2009-01-05 13:13:51 -0800 (Mon, 05 Jan 2009)
    Log Message:
    Adding last changes and comments on behalf of Kaushal for his radial and linear gradient transform calculations.
    QE: Not yet.
    Doc: No
    Checkintests: Pass
    Modified Paths:
    flex/sdk/trunk/modules/fxgutils/src/java/flash/fxg/swf/AbstractFXGGraphics.java
    flex/sdk/trunk/modules/fxgutils/src/java/flash/fxg/swf/TypeHelper.java

    After posting I and lots of research I realized that I need to dive into
    PaperVision 3D as way to get where I need to go.
    However, if anyone has a solution to adding text to this code which rotates with the cube - let me know.
    Thanks

  • How do I apply a linear gradient to an S shape?

    Hi
    I recently created an S shape with the pen tool that is quite large in my photoshop cs4.  I would like to know if there is a way for me to apply a linear gradient so that it follows the path of the S shape perfectly.
    The effect should cause one of the sides of the letter S to actually fade into black (the gradient is a transparent to black gradient colors).
    Is this even possible with my Photoshop cs4?
    Ricky

    Hi,
    Thanks for the response. I have found a way to accomplish exactly what I want.
    I use a stroke, set it to 'inner' style to the bottom most option, play with side and choose gradient
    I played aorund with these settings on here and got it working perfectly.
    Ricky

  • -webkit-linear-gradient not working with Adobe Air 3.0

    Hi -
    I recently downloaded Adobe Air 3.0 after reading that gradients are now supported (http://www.adobe.com/devnet/air/ajax/articles/air_and_webkit.html), but I have not been able to successfully implement them. For example, I have the following CSS class defined:
    .gradient_test {
         background-image: -webkit-linear-gradient(#68AB34, #3D721B);
         padding: 5px;
         color: #FFF;
    This should (and does in Chrome, Safari, etc) create a linear gradient going from light to dark green. But in Air it just appears as if no background has been applied to the selector. Am I missing some unique way to be able to apply gradients in Adobe Air 3.0?
    Thanks,
    Zach

    I don't know why this hasn't been addressed. I'm seeing the exact same problem. I've tried every permutation, but haven't been able to generate a gradient using any existing standard for webkit or otherwise (even though it's allegedly supported).
    -Matthew
    EDIT: I discovered that when the app is compiled, the gradients work fine. This one is driving my crazy, because I want to be able to test them. I get a mix of CSS support, depending on how the app is run.
    From Dreamweaver CS3 "Preview" - My CSS doesn't show gradients and shows embedded web fonts.
    From ADL - My CSS fails almost entirely, but some if it gets loaded.
    From the compiled AIR file: fortunately, everything seems to display correctly, but it's really a bad scenario for development / testing. Not sure what to do.

  • Trouble with Linear Gradients

    I am trying to use a horizontal linear gradient and when I
    preview my image in a browser, there are vertical bars or "slices"
    shown instead of a smooth gradient. Has anyone seen this or does
    anyone know how to remedy it?
    rory

    neillbaker wrote:
    > Thanks for the link nice looking site way,but to be fair
    i had nose and didn't
    > see anything helpful reguards getting rid of those lines
    on a aimating gif with
    > a gradient back ground ,looks fine in fireworks but as
    soon as i browse it bang
    > them bloody lines,
    > i have tryed blur more blur dittering all sorts, please
    there must be a way
    > many thanks
    The problem is with the GIF format. It isn't capable of
    displaying
    smooth gradients. Have you tried exporting the animation in
    SWF format?
    Linda Rathgeber [PVII] *Adobe Community Expert-Fireworks*
    http://www.projectseven.com
    Fireworks Newsgroup:
    news://forums.projectseven.com/fireworks/
    CSS Newsgroup: news://forums.projectseven.com/css/
    http://www.adobe.com/communities/experts/

  • Syntax for using a variable in an equation.

    Hi all,
    Simple question here.  What is tha appropriate syntax for using a variable in a calculation equation.  Specifically, I am taking an established curve fitting equation from my channels and trying to calculate it over a lineargenerated data set to extend the curve  beyond the original data sample.  Here is the small portion of script I have that will not work.  Thanks for any help.
    dim a,b,c
    a = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef1").Value
    b = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef2").Value
    c = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef3").Value
    Call Calculate("Ch(""[5]/Air Consumption LG"")= ""a"" + Ch(""[5]/LinearGenerated"")*""b""+""c""*ch(""[5]/LinearGenerated"")^2")

    Hi Gloorious,
    I am using diadem script.  In my example above, for the equation, if I substitue a,b,and c with numerical values, the script runs just fine and the formula executes as desired.  Is there a way to place the variables there instead as I have tried to do (I was hoping it was just a syntax issue) or do I have to approach it a completely different way?
    This script will execute just fine:
    Call Calculate("Ch(""[5]/Air Consumption LG"")= 4 + Ch(""[5]/LinearGenerated"")*5+6*ch(""[5]/LinearGenerated"")^2")
    but this will not:
    dim a,b,c
    a = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef1").Value
    b = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef2").Value
    c = Data.Root.ChannelGroups(5).Channels("air consumption formula").Properties("ResultApprAnsatzCoef3").Value
    Call Calculate("Ch(""[5]/Air Consumption LG"")= ""a"" + Ch(""[5]/LinearGenerated"")*""b""+""c""*ch(""[5]/LinearGenerated"")^2")

  • Syntax for Evaluate function in OBIEE

    Hi
    I have browsed through the docs but couldn't find syntax for Evaluate function. Could someone pass me the full syntax and if possible a helpful example against essbase.
    Thanks

    Hi
    definitely
    syntax:- EVAULATE('your db function(%1,%2)', parameter list)
    here %1 and %2 are the no.of parameters (columns or may constant values) to be passed for the db-function
    if you have 3 parameters then you need to use %3 also.. means the columns to be passed.
    following exapmples are for ORACLE db,
    ex1: EVALUATE('upper(%1)', 'kishore kumar') gives the result as -> KISHORE KUMAR
    ex2: EVALUATE('upper(%1)', 'Markets.Region') here Markets.Region is column.
    you also can call the user-defined functions through evaulate
    EVALUATE('functioname(%1,%2), column1, column2)
    the above function has 2 parameters to be inputted
    Thanks & Regards
    Kishore Guggilla
    Edited by: Kishore Guggilla on Jan 16, 2009 11:00 PM

  • SQL Syntax for hour/date range in Query

    Hi
    I am trying to set up an query for sales order documents procesed in the last 30 minutes to be set as an alert to be run every 30 minutes to the sales manager.  I am having difficulty getting the syntax for the last 30 minutes
    Any suggestions?
    David

    hi,
    I'm not sure query is correct,but u can modify it futher to get correct one.
    SELECT T0.DocNum, T0.DocDate, T0.CardName, T0.DocTotal FROM ORDR T0 WHERE DateDiff(dd, T0.DocDate ,getdate()) = 0 and
    DateDiff(Minute,T0.DocTime,' ') <= 30
    Jeyakanthan

  • FAGLL03 : Submit syntax for dynamic selections

    Hi Experts,
    My z report contains following fields in selction screen.
    1 . G/ L account
    2. Comapny code
    3. posting date
    4. document type
    5. layout
    In my z report i used following syntax for passing selection screen values to standard program and getting data.
    SUBMIT FAGL_ACCOUNT_ITEMS_GL
                      WITH SD_SAKNR   IN S_SAKNR
                      WITH SD_BUKRS   IN S_BUKRS
                      WITH X_OPSEL    EQ ' '
                      WITH X_CLSEL    EQ ' '
                      WITH X_AISEL    EQ 'X'
                      WITH SO_BUDAT   IN S_BUDAT
                      WITH PA_VARI    EQ P_VAR
                      EXPORTING LIST TO MEMORY
                     AND RETURN. 
    The above syntax is not working for dynamic selection field ( document type ), entire document types data is fetching from standard program. I want to fetch document type data based on my z report selection values for document type field.
    Expect for document type field , submit syntax is working.
    kindly provide submit syntax for my above requirement .
    Any suggestions from experts....
    thanks & regards,
    Hari priya
    Edited by: Hari  Priya on Aug 24, 2009 4:33 PM

    Hi,
    Try like this.
    call function 'RS_REFRESH_FROM_SELECTOPTIONS'
      exporting
        curr_report = 'FAGL_ACCOUNT_ITEMS_GL'
      tables
        selection_table = i_sel[].
    Fill your profit center values in i_sel
    Submit FAGL_ACCOUNT_ITEMS_GL with selection-table i_sel and return
    WITH FREE SELECTIONS TEXPR AND RETURN
    Regards,
    Shamma

  • Syntax for how to call method of one comp in other comp     wd java.

    Let us assume,
    there is method1 in view1 comp1.
    tell me syntax for calling method 1 in view2 comp2
    thanks in advance.
    Edited by: madhu1011 on Nov 9, 2011 11:31 AM

    Hi Madhu,
    This is the situation:
    comp1-> method 1 , view1
    comp2-> view2
    You need to access method1  in view2 of comp2.
    For that, do the following steps:
    1.) First create a method (for eg: method1) in comp1 (under implementation of view1).
            eg: public void method1(){
                    <......some logic...>
    2.)Save the meta data.
    3.) In comp2, you will find an option called used components. In that right click and add the component comp2. (Carefully select comp1 itslef).
    4.)Save the meta data.
    5.) Then go to view2 of comp2 and take implementaion part and right the following logic in wddoinit() (or any other standard or custom method).
    wdThis.wdGetComp2Interface().getMethod("method1"); 
    By this way, we can access the method1 of comp1 in comp2.
    Regards,
    Jithin

  • Authentication syntax for HTTP GET method using TCP functions in Labview on linux

    Hi,
    Currently, I am trying to communicate to web server. I have Labview installed on a Linux machine. The HTTP function blocks and other labview functions do not work. Hence, I am building a HTTP code string using TCP functions (port 80) to talk to the web server. I am successfully able to fetch a response from web sites (example www.ni.com) from my vi. However, when I try to communicate to my web server, it does not work. It requires an authentication. I am able to open http://ipaddress in my browser from my machine using username and password. Can someone help with Authentication string requirement for GET method?
    so far the string is:
    GET /index/ HTTP/1.1
    Host: http://xx.xx.xx.xx

    An easy option would be to try http://userassword@server syntax for the URL.
    Else I posted a Twitter fetcher once (won't work anymore since Twitter moved to Oauth authentication) at LAVA. Based on code from @cloew.
    The code is part of this LLB.
    Ton
    Free Code Capture Tool! Version 2.1.3 with comments, web-upload, back-save and snippets!
    Nederlandse LabVIEW user groep www.lvug.nl
    My LabVIEW Ideas
    LabVIEW, programming like it should be!

  • "unsupported syntax for refreshRow  ()"

    Hi everybody!
    I've got a problem with a JDBC-Application I wrote for Oracle 8i. Since migrating to Oracle 9i, it displays after the 10th call to ResultSet.next() an error message "unsupported syntax for refreshRow ()" and it seems to end the connection. Any further requests to the database result in "No more data can be read from socket". I need to logon to the database again to fix this.
    I suspect that only 10 lines are cached in the ResultSet. But shouldn't the Oracle thin driver by itself realize if an underrun in the cache appears and rather try to get more lines from the database than display an error message?
    I could set the lines fetched at the first attempt to a higher value than 10, but that would only shift the problem.
    Any answer is appreciated.
    Thanks and regards,
    Torsten

    my solution was, to change my scrollable result set from sensitive to insensitive type ...

Maybe you are looking for

  • Questions on BDC program statements.....

    Hi, Currently i am checking below BDC program for packing material use. But there is a statement that i am not very clear what it is for...     PERFORM bdc_field       USING 'BDC_CURSOR'                                   'V51VE-EXIDV(01)'. For the  '

  • Itunes 11.1.3.8 not seeing my iphone 4 over wifi

    I have a new laptop and have installed itunes. I wan to sync my contacts and calendar from Outlook. itunes is not recognizing my iphone or my ipad over wifi. It syncs fine with a usb cable but I want to sync with wifi.

  • Displaying the sorted acct number as the first element

    Hi, I have list of account numbers , say 5 account numbers (2300,5200,7689,1234,4566) from which I found which is the parent acct number by invoking a query. Here the parent acct number is say "1234". Now i need to make sure that parent acct number r

  • Pacman -- hard drive prob

    When I use pacman to search or upgrade packages, my laptop's hard drive makes a strange noise (a squeal). The noise is completely different from normal operation (ie: using slocate, loading programs). It doesn't sound healthy. Is it a problem with th

  • Client Agent behaviour after device deletion

    Hi experts, quick question on client behaviour: I've installed a client successfully and the client has registered as active in ConfigMgr (2012 SP1 CU2). Now someone went ahead and deleted the device from ConfigMgr. On the client, I can still retriev