Search an ID in concatenated by stragg

Question

Hi there,
Oracle Database 11g Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
Sample data
with person as(
select 1 as pid, 'person1' as name from dual union all
select 2 as pid, 'person2' as name from dual union all
select 3 as pid, 'person3' as name from dual union all
select 4 as pid, 'person4' as name from dual union all
select 5 as pid, 'person5' as name from dual union all
select 6 as pid, 'person6' as name from dual
function_type as (
select 1 as ftid, 'function1' as name from dual union all
select 2 as ftid, 'function2' as name from dual union all
select 3 as ftid, 'function3' as name from dual union all
select 4 as ftid, 'function4' as name from dual union all
select 5 as ftid, 'function5' as name from dual union all
select 11 as ftid, 'function11' as name from dual
person_function_types as(
select 1 as pid, 1 as ftid from dual union all
select 1 as pid, 2 as ftid from dual union all
select 1 as pid, 3 as ftid from dual union all
select 2 as pid, 1 as ftid from dual union all
select 2 as pid, 5 as ftid from dual union all
select 3 as pid, 2 as ftid from dual union all
select 3 as pid, 3 as ftid from dual union all
select 3 as pid, 4 as ftid from dual union all
select 4 as pid, 5 as ftid from dual union all
select 5 as pid, 1 as ftid from dual union all
select 6 as pid, 11 as ftid from dual
person_function_view as(
select p.pid,
       p.name,
       stragg(distinct ft.ftid) as function_ids,
       stragg(distinct ft.name) as function_types
from   person_function_types pft
  left join person p
    on p.pid = pft.pid
  left join function_type ft
    on ft.ftid = pft.ftid
group by p.name
select pfv.name,
       pfv.function_types
from   person_function_view pfv
where  pfv.function_ids like '%1%'
Problem
The result of this query should be person all persons with function_ids containing 1.
How ever the result of this query returns person6 containing function_id 11.
Understandable that 11 is like %1% ... how can I avoid this?
Thanks in advance!
Kind regards,
Metroickha

Answer 1

Hi,
you can use regular expression.
Actually I could not test completely your query as I don't have STRAGG in my DB. There are several new alternatives to STRAGG. On 11g you can use LISTAGG.
Anyway assuming that using STRAGG after the comma you have one space you can do in this way:
select pfv.name,
       pfv.function_types
from   person_function_view pfv
where  regexp_like(pfv.function_ids ,'(^|, )1(,|$)');If STRAGG don't put a space after the comma then remove the space after the comma in the regular expression pattern:
where  regexp_like(pfv.function_ids ,'(^|,)1(,|$)');Regards.
Al