Searching two dimensional string arrays

Question

Hello, I'm very new to Java. I would like some advice on the code below. What I'm trying to do is: I want the user to enter a 9 digit number which is already stored in an two dimensional array. The array is to be searched and the 9 digit number and corresponding name is to be printed and stored for future reference. Something is wrong with my array checking. If I enter the nine digit number, the program errors and asks me again for the number. If I enter 0-4, I receive an output. I just don't know how to compare string array values. Could someone please help me with this?
import java.io.*;
import java.util.*;
public class SocialSn2
     public static void main(String args[]) throws Exception
          boolean validSSAN = false;
          Ssn(validSSAN);
          if (validSSAN)
               //Ssn(false);//write the code here to continue processing
     }//end main
     public static void Ssn(boolean Validated)
          String[][] employees =
               {{"333333333", "Jeff"},
               {"222222222", "Keith"},
               {"444444444", "Sally"},
               {"555555555", "Kaylen"},
               {"111111111", "Sheriden"}     };
          boolean found = false;
          while (!found)
               System.out.println("Enter the employee's Social Security number.");
               BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
               try
                    String line = in.readLine();
                    int input = Integer.parseInt(line); //added
                    found = false;
                    for(int j = 0; j < 5; j++)
                    if(input >= 0 && input <= employees.length)
                         //if(employees[j][0].equals(input))
                              //System.out.println(employees[input][0] + employees[input][1]);
                              found = true;
                         System.out.println(employees[input][0] + " " + employees[input][1]);
               catch (Exception exc)
                    System.out.println("error");
                    found = false;
          Validated = found;
     }//end Ssn
}//end class

Answer 1

There seems to be some problem with your loop for checking those values
if you had used System.err.println() in your catch block you would see that you were getting an ArrayIndexOutOfBoundsException
The following works for me.
import java.io.*;
import java.util.*;
public class SocialSn2
public static void main(String args[]) throws Exception
boolean validSSAN = false;
Ssn(validSSAN);
if (validSSAN)
//Ssn(false);//write the code here to continue processing
}//end main
public static void Ssn(boolean Validated)
String[][] employees =
{{"333333333", "Jeff"},
{"222222222", "Keith"},
{"444444444", "Sally"},
{"555555555", "Kaylen"},
{"111111111", "Sheriden"} };
boolean found = false;
System.out.println(employees.length);
System.out.println(employees[0].length);
while (!found)
System.out.println("Enter the employee's Social Security number.");
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
try
String line = in.readLine();
//int input = Integer.parseInt(line); //added
found = false;
for (int i=0; i< employees.length;i++)
     if(employees[0].equals(line))
     System.out.println(employees[i][0]+" "+employees[i][1]);
     found = true;
catch (Exception exc)
System.err.println(exc);
found = false;
Validated = found;
}//end Ssn
}//end class