Select data from tab 1 that are not in tab 2
hi,
i want to select data (mnr, date) from tab1, which are not in tab2!
what would be the best select-statement for this problem.
select mnr, date from tab1 where ...???
SELECT col1, col2 FROM tab1
MINUS
SELECT col1, col2 FROM tab2is one option. There are dozens of other approaches, some of which may perform better and some which may perform worse, but this is generally pretty efficient and pretty easy to understand.
Justin
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[svn:fx-trunk] 8417: Remove themes from the package that are not compiling cleanly
Revision: 8417
Author: [email protected]
Date: 2009-07-07 04:50:21 -0700 (Tue, 07 Jul 2009)
Log Message:
Remove themes from the package that are not compiling cleanly
bug: https://bugs.adobe.com/jira/browse/SDK-21144
qa: yes
doc:
checkintests: pass
Ticket Links:
http://bugs.adobe.com/jira/browse/SDK-21144
Modified Paths:
flex/sdk/trunk/build.xml -
Is there a way to retrieve pictures deleted from photo stream that are not yet on camera roll?
Is there any way to retrieve pictures deleted from photo stream that are not yet on camera roll? I used my iPhone for a camera and put pix on iPad through photo stream. But I didn't realize they were not on the iPad camera roll, and deleted them from the phone Photostream. Now they are gone. Any chance to find them in the cloud?
No, there is no re-cycling bin on the iPad. If you deleted them from the card, and you havn't yet re-used the card, then there may be recovery software that you can get for your computer that might be able to get them back.
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How do I delete items from menu bar that are not part of the OS
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Perhaps you could be more specific, as it is a little difficult to answer your question without any details. I can give you some general ideas though.
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So, my general advice would be that you need to identify the application that placed the item there, and remove it from your computer. If there is an uninstall program for that application, I would run that in the first instance.
If you don't actually wish to uninstall the application, you may need to click on the item or run the application and see if there is a setting to not show the menu bar item.
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You mean music that was not purchased from the iTunes Store?
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Music transferred from your computer can be removed the same way - via the iTunes sync process or you should be able to delete individual songs direct from the iPhone. -
Performance issue in selecting data from a view because of not in condition
Hi experts,
I have a requirement to select data in a view which is not available in a fact with certain join conditions. but the fact table contains 2 crore rows of data. so this view is not working at all. it is running for long time. im pasting query here. please help me to tune it. whole query except prior to not in is executing in 15 minutes. but when i add not in condition it is running for so many hours as the second table has millions of records.
CREATE OR REPLACE FORCE VIEW EDWOWN.MEDW_V_GIEA_SERVICE_LEVEL11
SYS_ENT_ID,
SERVICE_LEVEL_NO,
CUSTOMER_NO,
BILL_TO_LOCATION,
PART_NO,
SRCE_SYS_ID,
BUS_AREA_ID,
CONTRACT,
WAREHOUSE,
ORDER_NO,
LINE_NO,
REL_NO,
REVISED_DUE_DATE,
REVISED_QTY_DUE,
QTY_RESERVED,
QTY_PICKED,
QTY_SHIPPED,
ABBREVIATION,
ACCT_WEEK,
ACCT_MONTH,
ACCT_YEAR,
UPDATED_FLAG,
CREATE_DATE,
RECORD_DATE,
BASE_WAREHOUSE,
EARLIEST_SHIP_DATE,
LATEST_SHIP_DATE,
SERVICE_DATE,
SHIP_PCT,
ALLOC_PCT,
WHSE_PCT,
ABC_CLASS,
LOCATION_ID,
RELEASE_COMP,
WAREHOUSE_DESC,
MAKE_TO_FLAG,
SOURCE_CREATE_DATE,
SOURCE_UPDATE_DATE,
SOURCE_CREATED_BY,
SOURCE_UPDATED_BY,
ENTITY_CODE,
RECORD_ID,
SRC_SYS_ENT_ID,
BSS_HIERARCHY_KEY,
SERVICE_LVL_FLAG
AS
SELECT SL.SYS_ENT_ID,
SL.ENTITY_CODE
|| '-'
|| SL.order_no
|| '-'
|| SL.LINE_NO
|| '-'
|| SL.REL_NO
SERVICE_LEVEL_NO,
SL.CUSTOMER_NO,
SL.BILL_TO_LOCATION,
SL.PART_NO,
SL.SRCE_SYS_ID,
SL.BUS_AREA_ID,
SL.CONTRACT,
SL.WAREHOUSE,
SL.ORDER_NO,
SL.LINE_NO,
SL.REL_NO,
SL.REVISED_DUE_DATE,
SL.REVISED_QTY_DUE,
NULL QTY_RESERVED,
NULL QTY_PICKED,
SL.QTY_SHIPPED,
SL.ABBREVIATION,
NULL ACCT_WEEK,
NULL ACCT_MONTH,
NULL ACCT_YEAR,
NULL UPDATED_FLAG,
SL.CREATE_DATE,
SL.RECORD_DATE,
SL.BASE_WAREHOUSE,
SL.EARLIEST_SHIP_DATE,
SL.LATEST_SHIP_DATE,
SL.SERVICE_DATE,
SL.SHIP_PCT,
0 ALLOC_PCT,
0 WHSE_PCT,
SL.ABC_CLASS,
SL.LOCATION_ID,
NULL RELEASE_COMP,
SL.WAREHOUSE_DESC,
SL.MAKE_TO_FLAG,
SL.source_create_date,
SL.source_update_date,
SL.source_created_by,
SL.source_updated_by,
SL.ENTITY_CODE,
SL.RECORD_ID,
SL.SRC_SYS_ENT_ID,
SL.BSS_HIERARCHY_KEY,
'Y' SERVICE_LVL_FLAG
FROM ( SELECT SL_INT.SYS_ENT_ID,
SL_INT.CUSTOMER_NO,
SL_INT.BILL_TO_LOCATION,
SL_INT.PART_NO,
SL_INT.SRCE_SYS_ID,
SL_INT.BUS_AREA_ID,
SL_INT.CONTRACT,
SL_INT.WAREHOUSE,
SL_INT.ORDER_NO,
SL_INT.LINE_NO,
MAX (SL_INT.REL_NO) REL_NO,
SL_INT.REVISED_DUE_DATE,
SUM (SL_INT.REVISED_QTY_DUE) REVISED_QTY_DUE,
SUM (SL_INT.QTY_SHIPPED) QTY_SHIPPED,
SL_INT.ABBREVIATION,
MAX (SL_INT.CREATE_DATE) CREATE_DATE,
MAX (SL_INT.RECORD_DATE) RECORD_DATE,
SL_INT.BASE_WAREHOUSE,
MAX (SL_INT.LAST_SHIPMENT_DATE) LAST_SHIPMENT_DATE,
MAX (SL_INT.EARLIEST_SHIP_DATE) EARLIEST_SHIP_DATE,
MAX (SL_INT.LATEST_SHIP_DATE) LATEST_SHIP_DATE,
MAX (
CASE
WHEN TRUNC (SL_INT.LAST_SHIPMENT_DATE) <=
TRUNC (SL_INT.LATEST_SHIP_DATE)
THEN
TRUNC (SL_INT.LAST_SHIPMENT_DATE)
ELSE
TRUNC (SL_INT.LATEST_SHIP_DATE)
END)
SERVICE_DATE,
MIN (
CASE
WHEN TRUNC (SL_INT.LAST_SHIPMENT_DATE) >=
TRUNC (SL_INT.EARLIEST_SHIP_DATE)
AND TRUNC (SL_INT.LAST_SHIPMENT_DATE) <=
TRUNC (SL_INT.LATEST_SHIP_DATE)
AND SL_INT.QTY_SHIPPED = SL_INT.REVISED_QTY_DUE
THEN
100
ELSE
0
END)
SHIP_PCT,
SL_INT.ABC_CLASS,
SL_INT.LOCATION_ID,
SL_INT.WAREHOUSE_DESC,
SL_INT.MAKE_TO_FLAG,
MAX (SL_INT.source_create_date) source_create_date,
MAX (SL_INT.source_update_date) source_update_date,
SL_INT.source_created_by,
SL_INT.source_updated_by,
SL_INT.ENTITY_CODE,
SL_INT.RECORD_ID,
SL_INT.SRC_SYS_ENT_ID,
SL_INT.BSS_HIERARCHY_KEY
FROM (SELECT SL_UNADJ.*,
DECODE (
TRIM (TIMA.DAY_DESC),
'saturday', SL_UNADJ.REVISED_DUE_DATE
- 1
- early_ship_days,
'sunday', SL_UNADJ.REVISED_DUE_DATE
- 2
- early_ship_days,
SL_UNADJ.REVISED_DUE_DATE - early_ship_days)
EARLIEST_SHIP_DATE,
DECODE (
TRIM (TIMB.DAY_DESC),
'saturday', SL_UNADJ.REVISED_DUE_DATE
+ 2
+ LATE_SHIP_DAYS,
'sunday', SL_UNADJ.REVISED_DUE_DATE
+ 1
+ LATE_SHIP_DAYS,
SL_UNADJ.REVISED_DUE_DATE + LATE_SHIP_DAYS)
LATEST_SHIP_DATE
FROM (SELECT NVL (s2.sys_ent_id, '00') SYS_ENT_ID,
cust.customer_no CUSTOMER_NO,
cust.bill_to_loc BILL_TO_LOCATION,
cust.early_ship_days,
CUST.LATE_SHIP_DAYS,
ord.PART_NO,
ord.SRCE_SYS_ID,
ord.BUS_AREA_ID,
ord.BUS_AREA_ID CONTRACT,
NVL (WAREHOUSE, ord.entity_code) WAREHOUSE,
ORDER_NO,
ORDER_LINE_NO LINE_NO,
ORDER_REL_NO REL_NO,
TRUNC (REVISED_DUE_DATE) REVISED_DUE_DATE,
REVISED_ORDER_QTY REVISED_QTY_DUE,
-- NULL QTY_RESERVED,
-- NULL QTY_PICKED,
SHIPPED_QTY QTY_SHIPPED,
sold_to_abbreviation ABBREVIATION,
-- NULL ACCT_WEEK,
-- NULL ACCT_MONTH,
-- NULL ACCT_YEAR,
-- NULL UPDATED_FLAG,
ord.CREATE_DATE CREATE_DATE,
ord.CREATE_DATE RECORD_DATE,
NVL (WAREHOUSE, ord.entity_code)
BASE_WAREHOUSE,
LAST_SHIPMENT_DATE,
TRUNC (REVISED_DUE_DATE)
- cust.early_ship_days
EARLIEST_SHIP_DATE_UnAdj,
TRUNC (REVISED_DUE_DATE)
+ CUST.LATE_SHIP_DAYS
LATEST_SHIP_DATE_UnAdj,
--0 ALLOC_PCT,
--0 WHSE_PCT,
ABC_CLASS,
NVL (LOCATION_ID, '000') LOCATION_ID,
--NULL RELEASE_COMP,
WAREHOUSE_DESC,
NVL (
DECODE (MAKE_TO_FLAG,
'S', 0,
'O', 1,
'', -1),
-1)
MAKE_TO_FLAG,
ord.CREATE_DATE source_create_date,
ord.UPDATE_DATE source_update_date,
ord.CREATED_BY source_created_by,
ord.UPDATED_BY source_updated_by,
ord.ENTITY_CODE,
ord.RECORD_ID,
src.SYS_ENT_ID SRC_SYS_ENT_ID,
ord.BSS_HIERARCHY_KEY
FROM EDW_DTL_ORDER_FACT ord,
edw_v_maxv_cust_dim cust,
edw_v_maxv_part_dim part,
EDW_WAREHOUSE_LKP war,
EDW_SOURCE_LKP src,
MEDW_PLANT_LKP s2,
edw_v_incr_refresh_ctl incr
WHERE ord.BSS_HIERARCHY_KEY =
cust.BSS_HIERARCHY_KEY(+)
AND ord.record_id = part.record_id(+)
AND ord.part_no = part.part_no(+)
AND NVL (ord.WAREHOUSE, ord.entity_code) =
war.WAREHOUSE_code(+)
AND ord.entity_code = war.entity_code(+)
AND ord.record_id = src.record_id
AND src.calculate_back_order_flag = 'Y'
AND NVL (cancel_order_flag, 'N') != 'Y'
AND UPPER (part.source_plant) =
UPPER (s2.location_code1(+))
AND mapping_name = 'MEDW_MAP_GIEA_MTOS_STG'
-- AND NVL (ord.UPDATE_DATE, SYSDATE) >=
-- MAX_SOURCE_UPDATE_DATE
AND UPPER (
NVL (ord.order_status, 'BOOKED')) NOT IN
('ENTERED', 'CANCELLED')
AND TRUNC (REVISED_DUE_DATE) <= SYSDATE) SL_UNADJ,
EDW_TIME_DIM TIMA,
EDW_TIME_DIM TIMB
WHERE TRUNC (SL_UNADJ.EARLIEST_SHIP_DATE_UnAdj) =
TIMA.ACCOUNT_DATE
AND TRUNC (SL_UNADJ.LATEST_SHIP_DATE_Unadj) =
TIMB.ACCOUNT_DATE) SL_INT
WHERE TRUNC (LATEST_SHIP_DATE) <= TRUNC (SYSDATE)
GROUP BY SL_INT.SYS_ENT_ID,
SL_INT.CUSTOMER_NO,
SL_INT.BILL_TO_LOCATION,
SL_INT.PART_NO,
SL_INT.SRCE_SYS_ID,
SL_INT.BUS_AREA_ID,
SL_INT.CONTRACT,
SL_INT.WAREHOUSE,
SL_INT.ORDER_NO,
SL_INT.LINE_NO,
SL_INT.REVISED_DUE_DATE,
SL_INT.ABBREVIATION,
SL_INT.BASE_WAREHOUSE,
SL_INT.ABC_CLASS,
SL_INT.LOCATION_ID,
SL_INT.WAREHOUSE_DESC,
SL_INT.MAKE_TO_FLAG,
SL_INT.source_created_by,
SL_INT.source_updated_by,
SL_INT.ENTITY_CODE,
SL_INT.RECORD_ID,
SL_INT.SRC_SYS_ENT_ID,
SL_INT.BSS_HIERARCHY_KEY) SL
WHERE (SL.BSS_HIERARCHY_KEY,
SL.ORDER_NO,
Sl.line_no,
sl.Revised_due_date,
SL.PART_NO,
sl.sys_ent_id) NOT IN
(SELECT BSS_HIERARCHY_KEY,
ORDER_NO,
line_no,
revised_due_date,
part_no,
src_sys_ent_id
FROM MEDW_MTOS_DTL_FACT
WHERE service_lvl_flag = 'Y');
thanks
asnAlso 'NOT IN' + nullable columns can be an expensive combination - and may not give the expected results. For example, compare these:
with test1 as ( select 1 as key1 from dual )
, test2 as ( select null as key2 from dual )
select * from test1
where key1 not in
( select key2 from test2 );
no rows selected
with test1 as ( select 1 as key1 from dual )
, test2 as ( select null as key2 from dual )
select * from test1
where key1 not in
( select key2 from test2
where key2 is not null );
KEY1
1
1 row selected.Even if the columns do contain values, if they are nullable Oracle has to perform a resource-intensive filter operation in case they are null. An EXISTS construction is not concerned with null values and can therefore use a more efficient execution plan, leading people to think it is inherently faster in general. -
I just purchased a mac mini and wondered if it's safe to download from the internet (such as Kobo) that are not available on the app store. It asked me if I was sure it was safe, so it's got me worried.
If you know the sites are OK, then download away.
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HT4910 how do you remove pics from my ipad that are not in camera roll?
I have a couple thousand pics on my ipad that I put on from my laptop a long time ago. they are not on the camera roll. I can delete those but can't figure out haw to remove the rest. I updated I tunes and can't find were it shows the files on my device. can anyone help?
If you want to remove all of your synced photos .....
Connect your iPad to your computer and launch iTunes.
Select your iPad under the devices tab in the upper right or in the left sidebar, if you have the sidebar enabled.
Click on Photos at the top of the iTunes window on the right.
Uncheck the "Sync Photos From" heading
Click on Apply in the lower right corner of iTunes.
IF that doesn't work, create an empty folder on your desktop and call it "Empty Folder". Select that folder in the "Sync Photos From" heading in the photos tab of iTunes and then click on Apply. That will also remove all synced photos. -
My phone was stolen. I first backe up from the icloud but then synced with my computer and lost some pictures that are backed up on the cloud. How do I get pics from my old phone which are backed up on the cloud but are not in my photostream?
If you have an iCloud backup, restore it to your phone as explained here: https://support.apple.com/kb/ph12521. If you have a backup on your computer instead, restore it to your phone by connecting your phone to your computer, opening iTunes and going to File>Devices>Restore from Backup.
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How to retrieve data from a dimension that is not directly joined to a fact
Hi,
In my case I have 2 dimensions and one fact. I need to runa report collecting data from all the three tables.
I need to do the following.
DIMA DIMB FACT1
FACT1 is joined with DIMA
DIMA is joined with DIMB
FACT1 is not Joined with DIMB.
My report should still retrieve information from DIMB by connecting FACT1 with DIMA and retrieve corresponding data from DIMB.
Please suggest how can I do this .
I am using 10.1.3 version of OBIEE
You help will be much appreciated.Hi,
I think your data model is snow-flake schema,we can get the data from snow-flake schema also.Pull the columns from both fact and DIMB into criteria.It will display the result.
mark if helpful/correct...
thanks,
prassu -
Hi there. can someone please tell me there is a way of doing this because I was on the phone to 121 for two hours and they couldn't help in the way I wanted.
I have a customer who took his iPad on holiday and with a cable adapter used it to back up the photos from his campact camera.
Whilst he was out there he took the time to separate all the photos into albums using the standard iPad 'Photos' app. There must be 50 or so albums in there.
So now he wants to get those photos off but keep the organisation the app has allowed him to do but if we plug it up to either his Macbook pro or Windows neither the hundreds of photos or thier albums are nowhere to be seen.
The only way I can find to get them out using Macbook or Windows is to transfer photos back into the camera roll or to share them via the cloud but both ways lose the album organisation.
Obviously if there is no way to do this (which seems bonkers for a modern device) then we shall have to painstakingly do just that. It would be nice not to have to endure the hours of work is all.
Thanks in advance!!!How to Transfer Photos from an iPad to a Computer
http://www.wikihow.com/Transfer-Photos-from-an-iPad-to-a-Computer
Importing Personal Photos and videos from your iOS device to your computer.
http://support.apple.com/kb/HT4083
iTunes: Frequently asked questions about viewing and syncing videos
http://support.apple.com/kb/HT2729
Also check out the Photo Manager Pro app.
https://itunes.apple.com/us/app/photo-manager-pro/id393858562
Check out the Feem WiFi File Transfer app
https://itunes.apple.com/us/app/feem-wifi-file-transfer-free/id596378699?mt=8
Cheers, Tom -
How do I import photos from my ipad that are not in the saved photos folder
I do have a saved photos album and was able to import those. However, I have several other folders and I can't figure out how to get the photos from my iPad to my new iMac. Or for that matter, into the saved photos folder. This is my first experience with iPhoto. Any help? Thanks!
If you want to remove all of your synced photos .....
Connect your iPad to your computer and launch iTunes.
Select your iPad under the devices tab in the upper right or in the left sidebar, if you have the sidebar enabled.
Click on Photos at the top of the iTunes window on the right.
Uncheck the "Sync Photos From" heading
Click on Apply in the lower right corner of iTunes.
IF that doesn't work, create an empty folder on your desktop and call it "Empty Folder". Select that folder in the "Sync Photos From" heading in the photos tab of iTunes and then click on Apply. That will also remove all synced photos. -
i have been trying to get photo from my phone onto my new computer because i lost everything. i have got all the photos from my camera roll onto it but i can get the one that i put on there from my old computer. i did try download iexplorer but you have to pay for it in dollars im in the UK. i have noticed to that if i edit few they go into the camera roll after but then how do i delete the orignals. please someone help its really frustrating me!!!!!
The photo sync is one way - computer to iphone. As the photos came from your computer in the first place, then they should still be there and should have been included in your regular backup copy of your computer.
You can e-mail them to yourself. they will not be of the original quality.
The iphone is not a storage/backup device. It simply mirrors the selected content of your computer/cloud service. -
Charges from itunes store that are not mine
WARNING to all you itunes users out there!! . I woke up this morning to several fraudulent charges charged to me by itunes All were in Chinese!!! Trying to resolve these, I discovered the ONLY way to contact itunes is via email----- and it appears that itunes has no FRAUD division, It looks like the only way to fight fraudulent charges is through your credit card, paypal or whatever form of paymeent you use. It is amazing to me what suckers we are, In order to use an iphone, ipod or ipad, apple requires us to have an itunes account . they willingly take our money for purchases but have absolutely no viable support system in place for us if things go wrong. Surely, apple is doing well enough financially to afford us a liittle support!! Please let me know if I am wrong and if there is a fraud division for iuines that has a phone number I can call! Thsi may noyt be big to itines buit it is to me!! I am a single mom and now have no money in my bank account which means no gas to get ny kids to school ., etc, etc thanks!!
You credit card company would handle any reimbursement.
Change your password so that your account canot be accessed again. -
Select data from table not in another table
Hi,
I want to select data from table A which is not in table B.
Currently I am doing:
select
snoA,
nameA,
dobA
from A
where snoA not in
(select snoB from A, B
where snoA = snoB
and nameA = nameB)
But above is very slow.
Can I do something like:
select
snoA,
nameA,
dobA
from A, B
where
EXCLUDE ( snoA = snoB and nameA = nameB)
Please note that I need the where condition on both the columns.
any help will be appreciated.
-- HarveyWhat are the approximate data volumes in A and B?
What is "very slow"?
What version of Oracle?
What is the query plan?
Without knowing anything about your system, my first thought would be to see if a NOT EXISTS happened to be faster for your data
SELECT snoA,
nameA,
dobA
FROM a
WHERE NOT EXISTS (
SELECT 1
FROM b
WHERE a.snoA = b.snoB
AND a.nameA = b.nameB )Of course, I'm not sure why you are joining A & B in your NOT IN subquery. It would seem like you would just need a correlated subquery, i.e.
SELECT snoA,
nameA,
dobA
FROM a
WHERE snoA NOT IN (
SELECT snoB
FROM b
WHERE a.snoA = b.snoB
AND a.nameA = b.nameB )That should be more efficient than the original query. The NOT EXISTS version may or may not be more efficient than the NOT IN depending on data volumes.
Justin
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