Select top row in Single Query?

Hi
Can somebody help me to write a query to get the first row after order by clause using single query alone.
Example:
I can write following query to select first row
select * from (selec * from t order by col1) where rownum = 1;
But here I should not use inline view to get the result. Because my original requirement needs to use this query in select list and it needs to use a column (of a table from the FROM clause) in the where clause of inline query. Because there is restriction that we can not use the column (of a table from the FROM clause) more than one level of inline query.
Please help me.

Raghav.786 wrote:
Hi
Can somebody help me to write a query to get the first row after order by clause using single query alone.
Example:
I can write following query to select first row
select * from (selec * from t order by col1) where rownum = 1;
But here I should not use inline view to get the result. Because my original requirement needs to use this query in select list and it needs to use a column (of a table from the FROM clause) in the where clause of inline query. Because there is restriction that we can not use the column (of a table from the FROM clause) more than one level of inline query.
Please help me.
What Oracle version are you?
If you have 12c you can use
select col1,...
from t
order by col1
fetch first 1 row only;
If less than 12c, you have can't do it without a subquery.
What are you actually trying to do? Read Re: 2. How do I ask a question on the forums?
and follow the advice there by giving example create table and insert sample data statements and
explaining clearly what you are trying to do. Then we can help more.

Similar Messages

Need different rows from single query based on condition

Hi,
I have a table with 100 rows that holds employees and their roles.
I need to write a SQL(not a PL/SQL block) as below
1. When employee with role 'VP' logs in, the query should return all the 100 rows.
2. When employee with role 'MGR' logs in, the query should return only those rows whose MGR is the logged in employee.
3. When employee with role 'SALE_EXEC' logs in, it should return single rows corresponding to this SALE_EXEC.
My requirement here is to get these outputs from a single query.
Can anyone please help me with this.
Thanks,
Vivek.

use vpd
New Policy Groups
When adding the policy to a table, view, or synonym, you can use the DBMS_RLS.ADD_GROUPED_POLICY interface to specify the group to which the policy belongs. To specify which policies will be effective, you add a driving context using the DBMS_RLS.ADD_POLICY_CONTEXT interface. If the driving context returns an unknown policy group, then an error is returned.
If the driving context is not defined, then all policies are executed. Likewise, if the driving context is NULL, then policies from all policy groups are enforced. In this way, an application accessing the data cannot bypass the security setup module (which sets up application context) to avoid any applicable policies.
You can apply multiple driving contexts to the same table, view, or synonym, and each of them will be processed individually. In this way, you can configure multiple active sets of policies to be enforced.
Consider, for example, a hosting company that hosts Benefits and Financial applications, which share some database objects. Both applications are striped for hosting using a SUBSCRIBER policy in the SYS_DEFAULT policy group. Data access is partitioned first by subscriber ID, then by whether the user is accessing the Benefits or Financial applications (determined by a driving context). Suppose that Company A, which uses the hosting services, wants to apply a custom policy which relates only to its own data access. You could add an additional driving context (such as COMPANY A SPECIAL) to ensure that the additional, special policy group is applied for data access for Company A only. You would not apply this under the SUBSCRIBER policy, because the policy relates only to Company A, and it is more efficient to segregate the basic hosting policy from other policies.
How to Implement Policy Groups
To create policy groups, the administrator must do two things:
Set up a driving context to identify the effective policy group.
Add policies to policy groups as required.
The following example shows how to perform these tasks.
Note:
You need to set up the following data structures for the examples in this section to work:
DROP USER finance CASCADE;
CREATE USER finance IDENTIFIED BY welcome2;
GRANT RESOURCE TO apps;
DROP TABLE apps.benefit;
CREATE TABLE apps.benefit (c NUMBER);
Step 1: Set Up a Driving Context
Begin by creating a namespace for the driving context. For example:
CREATE CONTEXT appsctx USING apps.apps_security_init;
Create the package that administers the driving context. For example:
CREATE OR REPLACE PACKAGE apps.apps_security_init IS
PROCEDURE setctx (policy_group VARCHAR2);
END;
CREATE OR REPLACE PACKAGE BODY apps.apps_security_init AS
PROCEDURE setctx ( policy_group varchar2 ) IS
BEGIN
REM Do some checking to determine the current application.
REM You can check the proxy if using the proxy authentication feature.
REM Then set the context to indicate the current application.
DBMS_SESSION.SET_CONTEXT('APPSCTX','ACTIVE_APPS', policy_group);
END;
END;
Define the driving context for the table APPS.BENEFIT.
BEGIN
DBMS_RLS.ADD_POLICY_CONTEXT('apps','benefit','APPSCTX','ACTIVE_APPS');
END;
Step 2: Add a Policy to the Default Policy Group.
Create a security function to return a predicate to divide the data by company.
CREATE OR REPLACE FUNCTION by_company (sch varchar2, tab varchar2)
RETURN VARCHAR2 AS
BEGIN
RETURN 'COMPANY = SYS_CONTEXT(''ID'',''MY_COMPANY'')';
END;
Because policies in SYS_DEFAULT are always executed (except for SYS, or users with the EXEMPT ACCESS POLICY system privilege), this security policy (named SECURITY_BY_COMPANY), will always be enforced regardless of the application running. This achieves the universal security requirement on the table: namely, that each company should see its own data regardless of the application that is running. The function APPS.APPS_SECURITY_INIT.BY_COMPANY returns the predicate to make sure that users can only see data related to their own company:
BEGIN
DBMS_RLS.ADD_GROUPED_POLICY('apps','benefit','SYS_DEFAULT',
'security_by_company',
'apps','by_company');
END;
Step 3: Add a Policy to the HR Policy Group
First, create the HR group:
CREATE OR REPLACE FUNCTION hr.security_policy
RETURN VARCHAR2
AS
BEGIN
RETURN 'SYS_CONTEXT(''ID'',''TITLE'') = ''MANAGER'' ';
END;
The following creates the policy group and adds a policy named HR_SECURITY to the HR policy group. The function HR.SECURITY_POLICY returns the predicate to enforce security on the APPS.BENEFIT table:
BEGIN
DBMS_RLS.CREATE_POLICY_GROUP('apps','benefit','HR');
DBMS_RLS.ADD_GROUPED_POLICY('apps','benefit','HR',
'hr_security','hr','security_policy');
END;
Step 4: Add a Policy to the FINANCE Policy Group
Create the FINANCE policy:
CREATE OR REPLACE FUNCTION finance.security_policy
RETURN VARCHAR2
AS
BEGIN
RETURN ('SYS_CONTEXT(''ID'',''DEPT'') = ''FINANCE'' ');
END;
Create a policy group named FINANCE and add the FINANCE policy to the FINANCE group:
BEGIN
DBMS_RLS.CREATE_POLICY_GROUP('apps','benefit','FINANCE');
DBMS_RLS.ADD_GROUPED_POLICY('apps','benefit','FINANCE',
'finance_security','finance', 'security_policy');
END;
As a result, when the database is accessed, the application initializes the driving context after authentication. For example, with the HR application:
execute apps.security_init.setctx('HR');
Validating the Application Used to Connect to the Database
The package implementing the driving context must correctly validate the application that is being used to connect to the database. Although the database always checks the call stack to ensure that the package implementing the driving context sets context attributes, inadequate validation can still occur within the package.
For example, in applications where database users or enterprise users are known to the database, the user needs the EXECUTE privilege on the package that sets the driving context. Consider a user who knows that:
The BENEFITS application allows more liberal access than the HR application
The setctx procedure (which sets the correct policy group within the driving context) does not perform any validation to determine which application is actually connecting. That is, the procedure does not check either the IP address of the incoming connection (for a three-tier system) or the proxy_user attribute of the user session.
Such a user could pass to the driving context package an argument setting the context to the more liberal BENEFITS policy group, and then access the HR application instead. Because the setctx does no further validation of the application, this user bypasses the normally more restrictive HR security policy.
By contrast, if you implement proxy authentication with VPD, then you can determine the identity of the middle tier (and the application) that is actually connecting to the database on behalf of a user. In this way, the correct policy will be applied for each application to mediate data access.
For example, a developer using the proxy authentication feature could determine that the application (the middle tier) connecting to the database is HRAPPSERVER. The package that implements the driving context can thus verify whether the proxy_user in the user session is HRAPPSERVER. If so, then it can set the driving context to use the HR policy group. If proxy_user is not HRAPPSERVER, then it can disallow access.
In this case, when the following query is executed
SELECT * FROM APPS.BENEFIT;
Oracle Database picks up policies from the default policy group (SYS_DEFAULT) and active namespace HR. The query is internally rewritten as follows:
SELECT * FROM APPS.BENEFIT WHERE COMPANY = SYS_CONTEXT('ID','MY_COMPANY') and SYS_CONTEXT('ID','TITLE') = 'MANAGER';
How to Add a Policy to a Table, View, or Synonym
The DBMS_RLS package enables you to administer security policies by using its procedures for adding, enabling, refreshing, or dropping policies, policy groups, or application contexts. You need to specify the table, view, or synonym to which you are adding a policy, as well as the data pertinent to that policy, such as the policy name. Such data also includes names for the policy group and the function implementing the policy. You can also specify the types of statements the policy controls (SELECT, INSERT, UPDATE, DELETE, CREATE INDEX, or ALTER INDEX).
for more you can refer to
http://download-west.oracle.com/docs/cd/B19306_01/network.102/b14266/apdvcntx.htm

Selecting top row after sorting

hi,
i have a table emp, whose primary key is empid(varchar2),
i want to sort the empid and select the top row after sorting,
i can sort the table using "select * from emp order by empid desc,
i can select the top row using "select * from emp where rownum=1"
i want a combination of the 2,
pls provide me the required query
Thanks and Regards,
Saurabh Jhunjhunwala

SEELCT *
   FROM ( SELECT e.*
                           , ROWNUM row_num
                   FROM emp e
                 ORDER BY empid desc
WHERE row_num = 1Regards
Arun

Update several rows with single query (easy question, I guess)

Hi all!
I have table with two columns - name and value.
I populate it with several sql queries:
insert into settings (name, value) values ('company_name', 'My Company');
insert into settings (name, value) values ('company_address', 'Company Address 12');
insert into settings (name, value) values ('company_city', 'South Park');
How can update rows with company_name and company_city in single query?
Thank you in advance!

How can update rows with company_name and company_city in single query?I guess something like this was meant:
update settings set value = ??? where name in ('company_name ', 'company_city');But it's still unclear to me what should be used instead of question marks... :)
Regards.

How do I select top 100 records in query

I would like to get only the first 100 or 200 records in a query. In Access query, it is TOP 100, is there an equal in Oracle sql?
Thanks!

select * from your_table
where rownum < 101;

How can I do for a row of a query be data provider for a variable?

Hi friends, I have a problem !
How can I do for a row of a query be data provider for a variable?
I need that a value of variable be stored when the user select a row in a query. At the BPS we can do this configuring the variable selector in WIB, and in a WAB how I can do this ?
Best regards,
Gustavo Liberado

In this case when I press the key to call other forms I need to wait for the response in the secondary form and then process the result.That is exactly what a "modal JDialog" (or JOptionPane) are used for.
Try it. Create a short demo program. All you need is a JFrame with a single button to show the modal dialog. All you modal dialog needs is a single button to close the dialog. After you show the modal dialog add a System.out.println(...) statement in your code and you will see that it is not executed until the dialog is closed.
Then once you understand the basics you add the code to your real program.
If you need further help then you need to create a [Short, Self Contained, Compilable and Executable, Example Program (SSCCE)|http://homepage1.nifty.com/algafield/sscce.html], that demonstrates the incorrect behaviour.
Don't forget to use the Code Formatting Tags so the posted code retains its original formatting. That is done by selecting the code and then clicking on the "Code" button above the question input area.

All selected 'n' consecutive rows in retrieved in a single query

hello,
I have table T with 50,000 rows
create table T
(student_id number,
class_id number,
quiz_id number,
marks number)
some sample rows like
INSERT INTO T VALUES (1,1, 1, 50);
INSERT INTO T VALUES (2,2, 2, 40);
INSERT INTO T VALUES (3,1, 3, 34);
INSERT INTO T VALUES (1,1, 4, 10);
INSERT INTO T VALUES (1,1, 5, 30);
INSERT INTO T VALUES (1,1, 6, 29);
INSERT INTO T VALUES (3,2, 7, 34);
INSERT INTO T VALUES (3,2, 8, 33);
INSERT INTO T VALUES (3,2, 9, 56);
INSERT INTO T VALUES (1,1, 7, 90);
INSERT INTO T VALUES (2,2, 8, 0,);
INSERT INTO T VALUES (1,1, 8, 80);
INSERT INTO T VALUES (2,2, 8, 65);
INSERT INTO T VALUES (1,1, 9, 34);
INSERT INTO T VALUES (2,2, 9, 11);each student belongs to one class_id. each student participates in many quizes. each quiz has its unique id. each student can appear once in a quiz_id
I am doing the below analysis and query:
1. with below query I am finding which student_id had most marks in any 3 successive quizes (see the 3-1 part below) in the query..
SELECT QUIZ_ID,
      STUDENT_ID,
SUM (MARKS) OVER (PARTITION BY STUDENT_ID ORDER BY QUIZ_ID1
RANGE BETWEEN CURRENT ROW AND (3-1) FOLLOWING) consecMARKS , MARKS   FROM
      (SELECT QUIZ_ID,
        STUDENT_ID,
        MARKS,
      ROW_NUMBER() OVER (PARTITION BY STUDENT_ID ORDER BY T.QUIZ_ID) QUIZ_ID1
      FROM T
      WHERE MARKS IS NOT NULL
      ORDER BY 1
    ORDER BY 3 DESC
SQL> /
   QUIZ_ID STUDENT_ID CONSECMARKS
         7          1         170
         6          1         166
         8          1         129
         5          1         106
         8          3          89
         8          2          76
         3          3          68
         7          3          67
         8          2          65
         1          1          60
         9          3          56
   QUIZ_ID STUDENT_ID CONSECMARKS
         9          1          49
         2          2          40
         4          1          40
         9          2          11
15 rows selected.With above query, I can play around and find for any 'n' number of consecutive quizes, like marks in 2 consecutives quizes, 3, 4 and so on but for each 'n' value I've to run a seperate query mentioning (2-1) or (3-1) or (4-1) and so on..
since my table is big and there are about 400 quizes so what I want to find out is for each 'n' consecutive quiz (from 1 to 400) which student had most marks for each consecutie 'n' quiz. Like in 1 (consecutive) quiz which student had the highest marks and then 2 conseuctive quiz who had most marks and then in 3 consecutive quiz who had most marks and so on till 400 consecutive quiz who had most marks... rather than running query for each 'n' value seperately i want a single query that can give me a summary of most marks in each n consecutive quizes...
my sample output is:
Nth consecutive quiz     student_id    sum(marks)
1                        1              90
2                        1              170
3                        1              246
4
100
200
300
400                      ?              ?   Is this possible to get the above output from one single query? If there are two or more students with equal most marks for any 'n' conseutive quizes then both should come in the summary.
Hope I have been able to put up my question clearly.
regards
Ramis

Something like:
SELECT N,
        QUIZ_ID,
        STUDENT_ID,
        SUM(MARKS) OVER (PARTITION BY N,STUDENT_ID ORDER BY QUIZ_ID1 RANGE BETWEEN CURRENT ROW AND (N-1) FOLLOWING) consecMARKS,
        MARKS
FROM (SELECT QUIZ_ID,
                 STUDENT_ID,
                 MARKS,
                 ROW_NUMBER() OVER (PARTITION BY STUDENT_ID ORDER BY T.QUIZ_ID) QUIZ_ID1
           FROM T
           WHERE MARKS IS NOT NULL
         SELECT LEVEL N
           FROM DUAL
           CONNECT BY LEVEL <= (
                                SELECT COUNT(DISTINCT QUIZ_ID)
                                  FROM T
    ORDER BY N,
             consecMARKS DESC
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         1          7          1          90         90
         1          8          1          80         80
         1          8          2          65         65
         1          9          3          56         56
         1          1          1          50         50
         1          2          2          40         40
         1          9          1          34         34
         1          7          3          34         34
         1          3          3          34         34
         1          8          3          33         33
         1          5          1          30         30
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         1          6          1          29         29
         1          9          2          11         11
         1          4          1          10         10
         1          8          2           0          0
         2          7          1         170         90
         2          6          1         119         29
         2          8          1         114         80
         2          8          3          89         33
         2          8          2          76         65
         2          3          3          68         34
         2          7          3          67         34
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         2          8          2          65          0
         2          1          1          60         50
         2          5          1          59         30
         2          9          3          56         56
         2          2          2          40         40
         2          4          1          40         10
         2          9          1          34         34
         2          9          2          11         11
         3          7          1         204         90
         3          6          1         199         29
         3          5          1         149         30
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         3          7          3         123         34
         3          8          1         114         80
         3          2          2         105         40
         3          3          3         101         34
         3          1          1          90         50
         3          8          3          89         33
         3          8          2          76         65
         3          8          2          76          0
         3          4          1          69         10
         3          9          3          56         56
         3          9          1          34         34
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         3          9          2          11         11
         4          6          1         233         29
         4          5          1         229         30
         4          7          1         204         90
         4          4          1         159         10
         4          3          3         157         34
         4          7          3         123         34
         4          1          1         119         50
         4          2          2         116         40
         4          8          1         114         80
         4          8          3          89         33
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         4          8          2          76          0
         4          8          2          76         65
         4          9          3          56         56
         4          9          1          34         34
         4          9          2          11         11
         5          5          1         263         30
         5          4          1         239         10
         5          6          1         233         29
         5          1          1         209         50
         5          7          1         204         90
         5          3          3         157         34
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         5          7          3         123         34
         5          2          2         116         40
         5          8          1         114         80
         5          8          3          89         33
         5          8          2          76          0
         5          8          2          76         65
         5          9          3          56         56
         5          9          1          34         34
         5          9          2          11         11
         6          1          1         289         50
         6          4          1         273         10
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         6          5          1         263         30
         6          6          1         233         29
         6          7          1         204         90
         6          3          3         157         34
         6          7          3         123         34
         6          2          2         116         40
         6          8          1         114         80
         6          8          3          89         33
         6          8          2          76          0
         6          8          2          76         65
         6          9          3          56         56
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         6          9          1          34         34
         6          9          2          11         11
         7          1          1         323         50
         7          4          1         273         10
         7          5          1         263         30
         7          6          1         233         29
         7          7          1         204         90
         7          3          3         157         34
         7          7          3         123         34
         7          2          2         116         40
         7          8          1         114         80
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         7          8          3          89         33
         7          8          2          76          0
         7          8          2          76         65
         7          9          3          56         56
         7          9          1          34         34
         7          9          2          11         11
         8          1          1         323         50
         8          4          1         273         10
         8          5          1         263         30
         8          6          1         233         29
         8          7          1         204         90
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         8          3          3         157         34
         8          7          3         123         34
         8          2          2         116         40
         8          8          1         114         80
         8          8          3          89         33
         8          8          2          76          0
         8          8          2          76         65
         8          9          3          56         56
         8          9          1          34         34
         8          9          2          11         11
         9          1          1         323         50
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         9          4          1         273         10
         9          5          1         263         30
         9          6          1         233         29
         9          7          1         204         90
         9          3          3         157         34
         9          7          3         123         34
         9          2          2         116         40
         9          8          1         114         80
         9          8          3          89         33
         9          8          2          76          0
         9          8          2          76         65
         N    QUIZ_ID STUDENT_ID CONSECMARKS      MARKS
         9          9          3          56         56
         9          9          1          34         34
         9          9          2          11         11
135 rows selected.
SQL> SY.

Selecting data from single table with different condition in single query

Hi everybody...
I have one table with col1, col2, col3, col4, col5... as columns.
I want to select col1, col2, col3 with condition (x=y and a=b and c=d)
I want to select col4, col5 with condition (x=y and a=b and m=n )
in single query...
Thanx for ur help

Given this data set...
SQL> select * from oddity
2 /
      COL1       COL2       COL3       COL4       COL5 A X C M
         1          2          3          4          5 B Y   M
         1          2          3          4          5 A Y C N
         1          2          3          4          5 A Y D M
         1          2          3          4          5 A Y D N
         1          2          3          4          5 B Y D N
         1          2          3          4          5 B Y D U
6 rows selected.
SQL>The following query meets the requirements. Of course, the requirements as stated are incomplete. I ahave assumed that we select all five columns if C=D andM=N.
SQL> SELECT decode(c, 'D', col1, '0') AS col1
2         , decode(c, 'D', col2, '0') AS col2
3         , decode(c, 'D', col3, '0') AS col3
4          , decode(m, 'N', col4, '-8') AS col4
5           , decode(m, 'N', col5, '-8') AS col5
6 FROM oddity
7 WHERE a = 'B'
8 AND x = 'Y'
9 /
      COL1       COL2       COL3       COL4       COL5
         0          0          0         -8         -8
         1          2          3          4          5
         1          2          3         -8         -8
SQL> Cheers, APC

Selecting top five rows

hi,
pls I have this issue that needs to be resolved. I need to select top five rows from a table depending on the values of a column stock_value. pls I will appreciate if someone can help me out, Francois pls try and help
This is the senerio:
I have a table stock, on the table I have company_name, stock_value, sector.
Now I want to get top five rows from this table depending on the five highest value of stock_value and for each sector.
lets try and write a query that will retrive the records after that I will put it in a procedure.
I know am suppose to ask this on mssql forum but most mssql forums takes time to reply and this is very urgent cos I have to deliver in 45 minutes time
thank you very much
jideofor

hy,
try out:
select s.name, sp. sp_sales total_sales
from salesperson s,
(select salesperson_id,sum(tot_sales) sp_sales
RANK() OVER (ORDER BY SUM(tot_SALES) desc) SALES_RANK
FROM ORDERS
WHERE YEAR = 2006
group by salesperson_id) sp
where sp.sales_rank <= 5 (...n)
and sp.salesperson_id = s.salesperson_id
order by sq.sales_rank;
give result in:
name total_sales
a 100
b 90
c 80
d 70
e 60
hope help you
regards

Single Query for getting total no of records N getting records from a selected range

Hi,
Got the below query:
SELECT a.*, rowid FROM (SELECT name, postcode FROM Tbl ORDER BY name asc)a WHERE ROWNUM <=30
MINUS
SELECT b.*, rowid FROM (SELECT name, postcode FROM Tbl ORDER BY name asc) b WHERE ROWNUM <= 10
Though I got the results right, I also want to know the total no of records from "SELECT name, postcode FROM Tbl ORDER BY name asc". Does anyone knows how to do it in a single query?
Thanks.

hi Carol
The following output may help you.
SQL> l
1 select * from emp where (rowid,0) in (select rowid,mod(rownum,10)-rownum from emp)
2 minus
3* select * from emp where (rowid,0) in (select rowid,mod(rownum,6)-rownum from emp)
SQL> /
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7839 KING PRESIDENT 17-NOV-81 5000 10
7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30
7876 ADAMS CLERK 7788 12-JAN-83 1100 20
7900 JAMES CLERK 7698 03-DEC-81 950 30
The above query fetches the 6,7,8,9th records only.
Well my suggestion would be not to use ROWNUM directly in where clause since it changes dynamically. it is not a fixed value. for example pls see the result.
SQL> select rownum,empno,ename,sal,job from emp where sal > 3000;
ROWNUM EMPNO ENAME SAL JOB
1 7839 KING 5000 PRESIDENT
SQL> select rownum,empno,ename,sal,job from emp where sal > 1000;
ROWNUM EMPNO ENAME SAL JOB
1 7566 JONES 2975 MANAGER
2 7654 MARTIN 1250 SALESMAN
3 7698 BLAKE 2850 MANAGER
4 7782 CLARK 2450 MANAGER
5 7788 SCOTT 3000 ANALYST
6 7839 KING 5000 PRESIDENT
7 7844 TURNER 1500 SALESMAN
8 7876 ADAMS 1100 CLERK
9 7902 FORD 3000 ANALYST
10 7934 MILLER 1300 CLERK
10 rows selected.
SQL> select * from emp where rownum = 1;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7566 JONES MANAGER 7839 02-APR-81 2975 20
The record of employee KING is getting the rownum differently.
My understanding (out of my little knowledge) is the rownum values are assigned to the records only after the records are read physically and after applying the conditions(without rownum). Then the row numbers (rownum) is assigned to the records. Hence the rownum is not constant to a record since it is a dynamic value.
Well i would like to know the suggestions of the ORACLE EXPERTS here in the discussion forum.
If my finding is correct then OK if not Pls excuse me and pls give the correct solution
Regards
Prakash Eranki
[email protected]

Single row from this query without create a group by

Can I have a single row from this query without create a group by on tipo (TIPO can have only 2 value (A,D)
SELECT
CASE TIPO
WHEN 'D' THEN SUM(IMPORTO) ELSE 0 END DIMPORTO,
CASE TIPO
WHEN 'A' THEN SUM(IMPORTO) ELSE 0 END AIMPORTO
FROM MGIORNALE
WHERE K_CONTO = '100001' --CONTO
AND DECODE(T_MOVIM,'MRAP',TO_DATE('31/12/'||to_char(a_competenza),'DD/MM/YYYY'),DATA_RG)
-- BETWEEN DATAA AND DATAB
BETWEEN '01/01/2006' AND '31/12/2006'
--GROUP BY TIPO
--AND TIPO = COL_conto
Thanks in advance

Is like this?
sum (CASE TIPO
WHEN 'D' THEN IMPORTO ELSE 0 END) DIMPORTO,

How to select a row in a single-select table view?

Hello folks,
I have a table view with a 'details' button. When a row is selected and 'details' is pressed, the table view disappears and a form view is displayed (like the toggle button in PCUI). I have implemented this using a navigation link. When I press 'cancel' in the form view, another navigation link takes the user back to the table view.
My problem is, when the table view reappears, there is no row selected (the row that was selected previously, is de-selected). How do I make sure that the row remains selected?
I tried using the collection_wrapper->mark() method in the inbound plug of the table view, but it works only for multi-select table.

Hi Masood,
Thanks for your reply.
I had already tried using MARK ( iv_index = lv_index ), but it did not work because the first statement in the MARK method is
check ME->MULTI_SELECT = ABAP_TRUE.
Mine is a single-select table. So, using the MARK of the iterator object, with either the IV_BO or the IV_INDEX parameter also does not work. Is there any other way for a table with single row selection?
Thanks!!!
Rohan.

Different selection in a single query according to an ID

Hi
I'm looking for a way to perform different selections in a single query according to a specific value:
Here is the first selection:
select g.*,gf.*,gs.*
FROM graphs g
LEFT JOIN graph_frames gf on g.graph_id = gf.graph_id
LEFT JOIN graph_sets gs on gf.frame_id = gs.frame_id
WHERE g.graph_id = :IDHere is the second selection:
SELECT gg.graph_id, gg.graph_name
FROM generic_graphs gg
INNER JOIN generic_graph_frames ggf on gg.graph_id = ggf.graph_id
INNER JOIN generic_graph_sets ggs on ggf.frame_id = ggs.frame_id
WHERE gg.graph_id = :IDNow, the ID cannot be in both the tables and I want to perform that in a single query, UNION cannot be applied since the tables are different.
Any ideas?
Edited by: BluShadow on 14-Sep-2011 09:09
added {noformat}{noformat} tags. Please read {message:id=9360002} and learn to do this yourself.

Example of consolidating the columns...
SQL> ed
Wrote file afiedt.buf
1 with t as (select &id as id from dual)
2 select e.empno, e.ename, e.job, e.mgr, d.deptno, d.dname, d.loc
3 from   (select * from emp cross join t where empno = t.id) e
4         full outer join
5         (select * from dept cross join t where deptno = t.id) d
6*        on (1=1)
SQL> /
Enter value for id: 7521
old   1: with t as (select &id as id from dual)
new   1: with t as (select 7521 as id from dual)
     EMPNO ENAME      JOB              MGR     DEPTNO DNAME          LOC
      7521 WARD       SALESMAN        7698
SQL> /
Enter value for id: 10
old   1: with t as (select &id as id from dual)
new   1: with t as (select 10 as id from dual)
     EMPNO ENAME      JOB              MGR     DEPTNO DNAME          LOC
                                                   10 ACCOUNTING     NEW YORK
SQL>Though, this would be considered poor design because you are trying to query two disperate things, so they should be treated differently. i.e. in my example, I should already know if I'm querying an employee or a department beforehand.

If I add artwork by dragging a jpg to the artwork area after selecting several rows, in some instances a single icon is created in the flipper; in others one is created for each song. Why? How can I get one image per album every time?

If I add artwork by dragging a jpg to the artwork area after selecting several rows, in some instances a single icon is created in the flipper; in others one is created for each song. Why? How can I get one image per album every time?

If I add artwork by dragging a jpg to the artwork area after selecting several rows, in some instances a single icon is created in the flipper; in others one is created for each song. Why? How can I get one image per album every time?

SELECT TOP query in HANA

Hi,
Can somebody give me the HANA equivalent of the following SQL query:
SELECT TOP (731-624+1) COLUMNNAME FROM TABLENAME
In case of HANA, it gives syntax error near "(".

Hi Yash,
As per the HANA SQL syntax supported case is
<select_clause> ::= SELECT [TOP <unsigned_integer>] [ ALL | DISTINCT ]
<select_list>
After Top only an unsigned intger is expected and cannot handle an <expression> like in your example.
Hope this is useful.
Best Regards,
Ranjit

Select top row in Single Query?

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