Selecting duplicate rows based on a combination of columns as key

Question

Hi ,
I have a table with 5 columns.
Code ID S_DATE E_DATE Name
1 23 01012001 null ABC
1 09 01012001 null XYZ
2 81 04022007 null TVU
1 43 03092008 null XXX
Now, I need write a select query to fetch the duplicate rows from the above table having the combination of (Code, S_DATE,E_DATE) as the key.
So from the above example, I need to get Row1 and Row2 as output (but not Row3 as it has a different S_DATE)
Thanks in advance for your suggestions.
Thanks
Edited by: thotaramesh on Mar 9, 2009 4:54 PM

Answer 1

On XE;
WITH sample_data AS (
   SELECT 1  code,23 ID, '01012001' s_date, null e_date, 'ABC' NAME FROM dual UNION ALL
   SELECT 1, 09, '01012001', null, 'XYZ' FROM dual UNION ALL
   SELECT 2, 81, '04022007', null, 'TVU' FROM dual UNION ALL
   SELECT 1, 43, '03092008', null, 'XXX' FROM dual)
SELECT code, ID, s_date, e_date, NAME
FROM (
   SELECT
      sample_data.*,
      COUNT(*) over (PARTITION BY code, s_date, e_date) dups
   FROM sample_data)
WHERE dups > 1;
      CODE         ID S_DATE   E_DATE NAME
         1         23 01012001        ABC
         1          9 01012001        XYZ