Selecting unique records- Removing consecutive same data
HI,
am having a table where in some x,y,msg_date_info fields are there...here the data is in huge number...i need to fetch the data from this table subject to the following query conditions.
SELECT X longit,Y latit,MSG_DATE_INFO,row_number() over (order by MSG_DATE_INFO asc) SlNo FROM
(SELECT distinct x,y,MSG_DATE_INFO,row_number() over (order by MSG_DATE_INFO desc) r
FROM TRACKING_REPORT WHERE MSISDN='123456789') WHERE R between 1 and 20this works fine...
here one more thing i want to add up...this query results in 20 rows as expected and i want to filter the records if consecutive x and y values of these rows are same and give only unique values of x and y(condition that same x and y can be there somewhere in the order of data).
this example will show what is my requirement in detail....and this is the output of the above query
>
80.20550609 13.09469998 08-Mar-10 19:23:23 1
80.20550609 13.09469998 08-Mar-10 19:28:37 2
80.20087123 13.09437811 08-Mar-10 19:33:25 3
80.20550609 13.09469998 08-Mar-10 19:38:24 4
80.20550609 13.09469998 08-Mar-10 19:43:25 5
80.20550609 13.09469998 08-Mar-10 19:48:25 6
80.20087123 13.09437811 08-Mar-10 19:53:25 7
80.20087123 13.09437811 08-Mar-10 19:58:24 8
80.20550609 13.09469998 08-Mar-10 20:03:25 9
80.20087123 13.09437811 08-Mar-10 20:08:24 10
80.20550609 13.09469998 08-Mar-10 20:13:24 11
80.20087123 13.09437811 08-Mar-10 20:18:37 12
80.20550609 13.09469998 08-Mar-10 20:23:32 13
80.20550609 13.09469998 08-Mar-10 20:28:25 14
80.20550609 13.09469998 08-Mar-10 20:33:23 15
80.20550609 13.09469998 08-Mar-10 20:38:24 16
80.20550609 13.09469998 08-Mar-10 20:43:24 17
80.20550609 13.09469998 08-Mar-10 20:48:24 18
80.20550609 13.09469998 08-Mar-10 20:53:22 19
80.20550609 13.09469998 08-Mar-10 20:58:24 20
>
from this output i need to filter out CONSECUTIVE unique x and y values. and the output has to be like
>
80.20550609 13.09469998 08-03-10 19:23 1
80.20087123 13.09437811 08-03-10 19:33 3
80.20550609 13.09469998 08-03-10 19:48 6
80.20087123 13.09437811 08-03-10 19:53 7
80.20550609 13.09469998 08-03-10 20:03 9
80.20087123 13.09437811 08-03-10 20:08 10
80.20550609 13.09469998 08-03-10 20:13 11
80.20087123 13.09437811 08-03-10 20:18 12
80.20550609 13.09469998 08-03-10 20:58 20
>
how to go about this requirement?
Edited by: Aemunathan on Mar 9, 2010 5:45 PM
The following gives the same results on your test data but maybe it's more accurate because searches both for changes in x and in y:
SQL> with mytab as (
2 select 80.20550609 x, 13.09469998 y, '08-Mar-10 19:23:23' mydate, 1 rn from dual union
3 select 80.20550609,13.09469998, '08-Mar-10 19:28:37', 2 from dual union
4 select 80.20087123,13.09437811, '08-Mar-10 19:33:25', 3 from dual union
5 select 80.20550609,13.09469998, '08-Mar-10 19:38:24', 4 from dual union
6 select 80.20550609,13.09469998, '08-Mar-10 19:43:25', 5 from dual union
7 select 80.20550609, 13.09469998, '08-Mar-10 19:48:25', 6 from dual union
8 select 80.20087123, 13.09437811, '08-Mar-10 19:53:25', 7 from dual union
9 select 80.20087123, 13.09437811, '08-Mar-10 19:58:24', 8 from dual union
10 select 80.20550609, 13.09469998, '08-Mar-10 20:03:25', 9 from dual union
11 select 80.20087123, 13.09437811, '08-Mar-10 20:08:24', 10 from dual union
12 select 80.20550609,13.09469998, '08-Mar-10 20:13:24', 11 from dual union
13 select 80.20087123, 13.09437811, '08-Mar-10 20:18:37', 12 from dual union
14 select 80.20550609, 13.09469998, '08-Mar-10 20:23:32', 13 from dual union
15 select 80.20550609, 13.09469998, '08-Mar-10 20:28:25', 14 from dual union
16 select 80.20550609, 13.09469998, '08-Mar-10 20:33:23', 15 from dual union
17 select 80.20550609, 13.09469998, '08-Mar-10 20:38:24', 16 from dual union
18 select 80.20550609, 13.09469998, '08-Mar-10 20:43:24', 17 from dual union
19 select 80.20550609, 13.09469998, '08-Mar-10 20:48:24', 18 from dual union
20 select 80.20550609, 13.09469998, '08-Mar-10 20:53:22', 19 from dual union
21 select 80.20550609, 13.09469998, '08-Mar-10 20:58:24', 20 from dual
22 )
23 select x, y, mydate, rn from (
24 select x, y, mydate, rn, nvl(lead(x) over (order by rn),0) next_x
25 , nvl(lead(y) over (order by rn),0) next_y
26 from mytab
27 ) where next_x != x or next_y != y;
X Y MYDATE RN
80.20550609 13.09469998 08-Mar-10 19:28:37 2
80.20087123 13.09437811 08-Mar-10 19:33:25 3
80.20550609 13.09469998 08-Mar-10 19:48:25 6
80.20087123 13.09437811 08-Mar-10 19:58:24 8
80.20550609 13.09469998 08-Mar-10 20:03:25 9
80.20087123 13.09437811 08-Mar-10 20:08:24 10
80.20550609 13.09469998 08-Mar-10 20:13:24 11
80.20087123 13.09437811 08-Mar-10 20:18:37 12
80.20550609 13.09469998 08-Mar-10 20:58:24 20
9 rows selected.Max
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Tnx!
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Go to Solution.For loop
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Sorry for my bad choice of discussion title, feel free to suggest me a more pertinent one
I've rewritten post for clarity and following the FAQ.
DB Version
I'm using Oracle Enterprise 10g 10.2.0.1.0 64bit
Tables involved
CREATE TABLE wrhwr (
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eq_id VARCHAR2(50) NULL,
date_completed DATE NULL,
status VARCHAR2(20) NOT NULL,
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description VARCHAR2(20) NULL);
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Query used
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OVER (PARTITION BY eq_id
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rn
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AND pmp_id LIKE 'VER-EX%'
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(SELECT eq_id,
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OVER (PARTITION BY eq_id
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rn
FROM wrhwr
WHERE status != 'S'
AND pmp_id LIKE 'VER-EX%'
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(SELECT eq_id,
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OVER (PARTITION BY eq_id
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rn
FROM wrhwr
WHERE status != 'S'
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ix = i-th ranking of tableX
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ThanksFrankKulash ha scritto:
About duplicate dates: I was most interested in what you wanted when 2 (or more) rows with the same eq_id and row type (e.g. 'Collaudo') had exactly the same completed_date.
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Why don't you want 'MI-EXT-0001' in the results? Is it realted to the non-unique date?
For all optimization questions, see the forum FAQ:https://forums.oracle.com/message/9362003
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About Duplicate dates: query must show ONLY one date_completed and ignore duplicated. Those records are "bad data". You can't have 2 collaudos with the same date completed.
Collaudo stands for equipment check. A craftperson does an equipment check once a day and, with a mobile app, update the work request related to equipment and procedure of preventive maintenance, so is impossibile that complete more than one check (Collaudo) in a day, by design.
In the new results, it's my fault: during digitation I've swapped columns
With "I don't want 'MI-EXT-0001'" I mean: "I don't want to show AGAIN MI-EXT-0001. In the previous post was correct the output including MI-EXT-0001.
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repetition of
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MIN (CASE WHEN r_type = THEN column_name END) IGNORE NULLS)
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I filter eq table for the specific equipment standard (eq_std column).
efm_eq_tablet table and where clause
AND e.eq_id = e2.eq_id
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NVL() and NVL2() functions are used in main query in order to impletement this.
The CASE/WHEN blocks inside main query implements the behavior of selecting the correct date based of the above conditions. -
Alternative to find unique records with 60 character in selection string.
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We have to find out the values from the Infoobject. When we try to display data from an master object, the maximum length of selection it accepts 45 characters only but we need to input data around 60 characters in selection.
Thing we tried:
1. Selecting complete data without any condition but it did not work due to large volume of data.
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Himanshu Panchal.This sounds a bit strange. Are you perhaps mistakenly storing text data incorrectly as the primary key of the master data? I can't think of any actual data that is that length to ensure usinqueness - even GUIDs are maximum 32 characters - but GUIDs don't count as actual "readable" data although you do need to be able to select it from time to time. Perhaps you have a super secure password hash or something like it ?
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MS_AV16850------04/01/2006-----------8719618----------------51.82
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MS_AV16850------30/05/2007-----------10689899----------------189.29
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It should not get
MS_AV16850------16/04/2007-----------10353759----------------189.29
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because inv_number 10866311 has a prvevious inv_amount of 65.49.
and not get this
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MS_AV16850------04/01/2006-----------8719618----------------51.82
because they are not the most recent purchase date even if they have the same inv_amount.
Thanks in advance.Hi,
You're right; thanks for catching my mistake.
I changed the WHERE clause of the main query (including subquery there) to deal with that situation:
WITH got_grp AS
SELECT x.*
, ROW_NUMBER () OVER ( ORDER BY purchase_date )
- ROW_NUMBER () OVER ( PARTITION BY inv_amt
ORDER BY purchase_date ) AS grp
-- , ROW_NUMBER () OVER ( ORDER BY purchase_date ) AS r1
-- , ROW_NUMBER () OVER ( PARTITION BY inv_amt
-- ORDER BY purchase_date ) AS r2
FROM table_x x
SELECT * -- Or list all columns except grp
FROM got_grp
WHERE (inv_amt, grp) IN (
SELECT MAX (inv_amt) KEEP (DENSE_RANK LAST ORDER BY MAX (purchase_date))
, MAX (MAX (grp))
FROM got_grp
GROUP BY grp
, inv_amt
HAVING COUNT (*) > 1
;Thanks, too, for posting the sample data. Apparantly, you're more interested in solving this problem than OP is.
Edited by: Frank Kulash on Nov 22, 2010 1:36 PM
The r1 and r2 columns are not needed for the solution. You may want to display them, just to help see how the query works. -
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I have a set of records with same company code, same contract same delivery leg and different pricing leg.
If delivery leg and pricing leg is 1 then I want to add one line of record.
There will be several records with the same company code contract delivery leg and pricing leg. In the extraction logic I will extract with the following command i_t_data [] = c_t_data [], then sort with company code, contract delivery and pricing leg. then Delete duplicate with adjustcent..command...to get one record, based on this record with some condition I will populate a new line of record what my business neeeds.
My concern is
if the same set of records over shoot the datapackage size how to handle this. Is there any option.
My data package size is 50,000. Suppose I get a same set of records ie same company code, contract delivery leg and pricing leg as 49999 th record. Suppose there are 10 records with the same characteristics the extraction will hapen in 2 data packages then delete dplicate and the above logic will get wrong. How I can handle this secnaio. Whether Delta enabled function module help me to tackle this. I want to do it only in Extraction. as Data source enhancement.
Anil.
Edited by: Anil on Aug 29, 2010 5:56 AMHi,
You will have to do the enhancement of the data source.
Please follow the below link.
You can write your logic to add the additional records in the case statement for your data source.
http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/c035c402-3d1a-2d10-4380-af8f26b5026f?quicklink=index&overridelayout=true
Hope this will solve your issue. -
I imported a bunch of photos taken at different dates that i wanted to group together in the same album but they are not in the "last import" album and are all just mixed in with "all photos" according to the dates they were taken and it's impossible to sift through them all to select the ones i wanted.
Sorry I'm terrible at explaining and even using my macbook haha. Let me try again. I imported some photos that I wanted to group together into an album. I forgot to create the album before importing a new set of photos which then took the place of the previous ones in the "last import" album. Is there anywhere or any way I can easily find the selection of photos I forgot to put into an album together without having to select them one by one from the "all photos" section? These would be the only pictures in my Photos application that haven't been organized into an album yet if that helps; however, these photos were not taken on the same date.
-
I want to upgrade iOS from 5 to 6, but when I go to synch everything in preparation, it tells me I will lose all my stuff on the iPhone and iPad which is/are unique. How can I backup or do a "real synch" (both sides have same data at end of process) and then upgrade?
You should really read the manual.
"How do you restore from backup? "
Restore. When given the choice, choose to use backup.
"And how can I check to see if the pics and videos are on my computer somewhere first??"
They would only be where you put them. What program did you use to import them? Pics/vids taken with ipod are not part of the sync process at all. You should be importing them just as you would with any digital camera.
If you did not import them, then they are not on your computer. -
"record enable" buttons not showing up in Garage Band 10.0.3 (I have selected "show record enable"- a space in the track header opens up, but the button is not present. Same with "input monitor".
Look at all the posts in the forum from users with similar problems, it happened with the last Logic update.
-
Hi Developer,
i have issues that i need stop or restrict the same entries provided in the selection screen parameters it should no display that data but it should give an alert message by saying the data all ready viewed or displayed.
example: organisation :getha pvt.td.
name :ramesh.
start date:10.2.2013.
these are parameter which has been displayed by clicking execute ,if provide the same value to display again it should give waring message.
Please guide me in solve the problem.
thanks.
ravi.Hi Somendra,
Thanks for your response sir , i have provided the according to your provided information sir but it was not displaying the data first time also its giving message which i have provided ,my issues is if i provide data from time should display if i provide same data next time then only it should restrict the data and give a message.
example:
types:BEGIN OF str1,
ROOMNO type zROOMNO,
NAME TYPE zname3,
BRANCH type zBRANCH,
PHONENUMBER type zPHONENUMBER,
END OF str1.
data:it_str1 type TABLE OF str1,
wa_str1 type str1.
SELECTION-SCREEN BEGIN OF BLOCK b1 WITH FRAME .
skip.
PARAMETERS:s_roomno type ZTABLE_2-roomno.
skip.
parameters:s_name type ztable_2-name.
skip.
PARAMETERS:s_branch type ztable_2-branch.
skip.
PARAMETERS:s_pho type ztable_2-phonenumber.
SELECTION-SCREEN END OF BLOCK b1.
AT SELECTION-SCREEN.
SELECT roomno
name
branch
phonenumber from ztable_2 into TABLE it_str1
WHERE roomno eq s_roomno and name eq s_name and branch eq s_branch and phonenumber eq s_pho.
READ TABLE it_str1 INTO wa_str1 with KEY roomno = s_roomno name = s_name branch = s_branch phonenumber = s_pho.
if sy-subrc eq 0.
MESSAGE 'THE DATA IS ALL READY VIEWED' TYPE 'E'.
RETURN.
ENDIF.
START-OF-SELECTION.
SELECT roomno
name
branch
phonenumber from ztable_2 into TABLE it_str1
WHERE roomno eq s_roomno and name eq s_name and branch eq s_branch and phonenumber eq s_pho.
loop at it_str1 into wa_str1.
WRITE:/1 wa_str1-roomno,
10 wa_str1-name,
30 wa_str1-branch,
60 wa_str1-phonenumber.
ENDLOOP.
please guide me in solving the issue sir.
thanks,
Ravi -
Select Expert Record. Last 6 months and week start date on Monday
Hello,
i am trying to use the select expert record to grab the last 6 months worth of data. I require the week start day to be a monday and end on a sunday.
Can someone please provide some advice the best way to do this
kind regards
davidHello Abhilash,
Once again thanks for your reply.
Yes this is correct, when it goes back 6 months i need it to skip the days prior and begin on a monday as we are reporting on a mon-sunday basis.
I have tried your formula Date field >= dateadd('m',-6,currentdate) and it seems to grab 6 months of data, but the group weeks are not grouping from Monday to Sunday...
kind regards
david
Edited by: davitali on Dec 2, 2011 9:35 AM -
Select record having most recent date
Table: Order
Code ImportId EntryDate
1 100
10/11/2014
1 101
10/14/2014
1 102
10/10/2014
2 103 10/11/2014
2 104 10/15/2014
I want to select the record having the most recent EntryDate grouped by Code. In the select, i need to return the ImportId.
AnonymousPlease post DDL, so that people do not have to guess what the keys, constraints, Declarative Referential Integrity, data types, etc. in your schema are. Learn how to follow ISO-11179 data element naming conventions and formatting rules. Nothing you posted
was right. Temporal data should use ISO-8601 formats. This is the only format allowed in the ANSI-ISO SQL Standards and it is the most common IT standard on Earth; but you do not know it!
Code should be in Standard SQL as much as possible and not local dialect. There is no such crap as a generic “code” in RDBMS. Table have keys, so you have no table! Rows are not records; this is a basic concept.
This is minimal polite behavior on SQL forums. Here is my guess at what a polite, competent person might have posted.
CREATE TABLE Import_Orders
(order_type INTEGER NOT NULL
CHECK(order_type IN (1,2)),
import_id CHAR(3) NOT NULL PRIMARY KEY,
entry_date DATE NOT NULL);
INSERT INTO Import_Orders
VALUES
(1, 100, '2014-10-11'),
(1, 101, '2014-10-14'),
(1, 102, '2014-10-10'),
(2, 103, '2014-10-11'),
(2, 104, '2014-10-15');
I want to select the record [sic] having the most recent entry_date grouped by order_type. In the select, I need to return the import_id.
If you return only the import_id, then the most recent entry_date does not matter! Think about it! Did you want the whole row with the most recent entry_date? Here is a common idiom.
WITH X (import_id, order_type, entry_date, entry_date_max)
AS
(SELECT import_id, order_type, entry_date,
MAX(entry_date) OVER (PARTITION BY order_type)
FROM Import_Orders)
SELECT import_id, order_type, entry_date
FROM X
WHERE entry_date = entry_date_max;
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL
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