Self Join in Discoverer Admin.

Hi,
We have a requirement in which we have to leave an option for self join for the users so that they should be able to change the join depending on their requirements.
So basically they want this option to be open for them in Disc Admin.
But i'm afraid as there is no such option for self join in Disc Admin...
So any work arounds for this??
Thanks in advance.

Hi,
I will try and explain, but I am not entirely sure what you actually want to do.
But suppose you have a folder F1 which maps to a table T1 and your users want to join T1 to itself but different users want to use different join conditions. Then you can create another complex folder F2 in the EUL and drag all the items from F1 into F2 to create another folder mapping on to T1. Then create a new item in the EUL in the F1 folder called join1 by just putting 1 in the calculation so that the join1 item always returns 1. Then in the same way create a join1 item in the F2 folder. This you will be able to create a join between join1 item in F1 and the join1 item in F2.
Your users will then be able to add items from both the F1 and F2 folders into a workbook. They will have to create the actual join between the folders by creating a condition in the workbook joining F1 columns to F2 columns.
Hope that is clear.
Rod West

Similar Messages

Creating cross-functional joins in Discoverer Admin

Hello
When creating cross-functional joins, say b/w Projects and Suppliers in Disco Admin, I import the Suppliers folder and then create the joins b/w Projects and Suppliers in the Projects Business Area.
However, the user needs access to both Projects and Accounts Payables (has Suppliers) to access the new cross-functional report. Is there a way by which the user needs to be granted rights to Projects only but would still be able to see the cross-functional report?
Thanks,
Sanjib Manna
Oracle Practice
IBM Business Consulting Services

Are you refering to "cross business area" joins? If so, you can have the same folder in multiple business areas. And by granting access to one business area, you grant access to all the folders in there.
So, if you put the folder "suppliers" in both BA's (do so by choosing "manage folders" from the menu), you only have to grant access to the projects BA.
Regards,
Sabine

Search feature for joins in Discoverer Admin

Hi,
In Discoverer Administrator, how do I search for all the joins? Is there a SQL available to do this?
Thanks.

Are you refering to "cross business area" joins? If so, you can have the same folder in multiple business areas. And by granting access to one business area, you grant access to all the folders in there.
So, if you put the folder "suppliers" in both BA's (do so by choosing "manage folders" from the menu), you only have to grant access to the projects BA.
Regards,
Sabine

Export workbooks in discoverer admin

hello
I am able to export workbooks from discoverer admin. in DEV env.
The file is in '.eex' format.
How can I import '.eex' file into Discoverer Desktop in Test env.
If i import the same .eex file into Discv Admin @ Test..How can i open it in Desktop@Test.
Appreciate any feedback
thanks
kp

Hi Tamir,
As i was having only discoverer plue in 11i i can only export using disc.admin.
Disc plus dont have options for this
THanks a lot for your tip..It worked
I selected
Refresh The Object
and "By Identifier"
I checked only take ownership if original owner can not be found
and it worked fine
I have few more clarifications
1)
When I click on =Refresh the object
there is a check box at the bottom says: Preserve Display Related Properties
Should I check it or not
2)
Also when I open the workbook under my name
workbook was opening only with this option->
Open the workbook in the current database account
If the workbook is asking if i need to substitute a join, I may need to do that right?
thanks
kp

Self join please help

I would be very grateful if someone would show me show to use the self join, I understand what is does but just don't know how to use it. I have a question from a exercise but no answer so I can't check it the question is - using temporary labels to abbreviate table names, find all the staff that earn more than 'SONG'.
here is the table
STAFFID SNAME JOB MGR STARTDATE SAL COMM BRANCHID
5963 SMITH ADMIN 5209 15-NOV-00 1600 20
5994 BATES ASSISTANT 5896 20-FEB-01 1800 100 30
5125 CHAN ASSISTANT 5896 22-FEB-02 1550 150 30
5665 JONES MANAGER 5938 02-MAR-01 3100 20
5465 WILSON ASSISTANT 5896 28-OCT-00 1250 140 30
5896 HAYAT MANAGER 5938 01-MAY-01 3100 30
5287 CLARK MANAGER 5938 09-JUL-02 3100 10
5887 COSTA BUYER 5665 18-APR-04 3150 20
5938 SHAW DIRECTOR 17-NOV-01 7000 10
5484 TURNER ASSISTANT 5896 08-OCT-01 1550 0 30
5678 KALIM ADMIN 5887 23-APR-04 1600 20
5009 JAMES ADMIN 5896 03-DEC-01 1600 30
5209 SONG BUYER 5665 03-JAN-02 3000 20
5439 SIMPSON ADMIN 5287 23-FEB-02 1600 10
Thanks in advanced :)
Edited by: user11093259 on 01-Dec-2010 10:19

Hi,
Welcome to the forum!
Always post your best attempt at solving the problem. You'll get more specific replies that will help you learn more, and it often clarifies what you're trying to do.
Here's a typical self-join, using the scott.dept table (which you probably have avaialble).
SELECT     l.dname          AS lower_dname
,     h.dname          AS higher_dname
FROM     scott.dept     l
JOIN     scott.dept     h ON     l.dname     < h.dname
;Output:
LOWER_DNAME    HIGHER_DNAME
ACCOUNTING     OPERATIONS
ACCOUNTING     RESEARCH
ACCOUNTING     SALES
OPERATIONS     RESEARCH
OPERATIONS     SALES
RESEARCH       SALESAs you can see, this pairs every higher_dname with every dname that is less than it.
This is very similar to your problem. The main difference is, where the query above shows every possible higher_dname (and the lower_dnames related to it), you're interested in a single, specific higher value (and the rolws with lower values related to it). You can restrict the query to show only that one, specific higher values by adding a WHERE clause. Try it. If you get stuck, ask a more specific question, and, remember, post your code.

Discoverer Admin - Convert Db Object folders to custom SQL folders

Hi,
We are operating in a non-Apps EUL and have a large number of folders, with associated joins, reports etc, based directly on objects in the database (i.e. they were created using the 'new folder from database...' dialog).
We'd now like to add some SQL logic into these EUL folders - is it possible to convert these folders to Custom folders within Discoverer Admin? or will I have to recreate the folders, joins, reports etc from scratch?
Alternatively, is it possible to take an existing report and point it to the new Custom SQL folders without having to rebuild the report?
Any help much appreciated,
Ien Hien

Hi
Discoverer embeds the names of folders and joins into a workbook.
If you want to change a workbook from one folder to another you would have to do the following:
1. Examine the join names between the original folder and other folders
2. Change the name and identifier of the old workbook - try adding old to the end
3. Edit the joins and rename them and their identifiers too
4. Rename the new folder and identifier to match the old folder - these have to be exactly the same
5. Add joins between the new folder and the other folders, once again naming exactly the same as the old joins
6. Make sure all of the item names exist in the new folder
7. Hide the old folder so that the users see only one folder
8. Open your workbooks - they now should run
If workbooks still fail to run this means you have named a folder name or identifier wrong or named a join wrong.
Hope this helps
Regards
Michael

Importing PL/SQL function in Discoverer Admin

Gents
I'm trying to import a PL/SQL function. In fact this functions is in a package.
When I try to import in Discoverer Admin, I'm not able to see this package and the function.
It's possible import a function from a package in Discoverer?
Must a grant some privilege in package or create a synonym?
Regards
Honorio

Hey,
I have a similar problem.
I created a PL/SQL Function which i registered in my EUL. Bun when I'm using this function on an item in a custom folder, this custom folder disappeared from my Discoverer Plus list of folders? When I delete the item which uses this function the folder shows up in my Discoverer Plus list of folders.

Self join with fact table in Obie 10G

I am a newbie to obiee.I have a development requirement as follows-
I need to find supervisors designation with the existing star RPD design. explanation is below
                                                    DIM_Designation(Desig_Wid)
                                                  |(Row_wid)
                                                  |
DIM_EMPLOYEE--------WORKER_FACT------------DIM_Supervisor
(Row_Wid)-----------------(Employee_Wid)
                                  (Supervisor_Wid)------------(Row_Wid)
3 dimension is joined to fact to get employee, his supervisor and designation of employee. now i want to get the supervisor's designation? how is it possible? already employee and supervisor dimension is same W_employee_d table joined with fact as alias DIM_EMPLOYEE and DIM_SUPERVISOR. how to do self join with fact to get supervisor's designation. i do not have any supervisor_desig_wid in fact table. any help is deeply appreciated.

Yes,Duplicate the fact table create a primary key on the newly fact table alias dimension table.So you can ur data modelling as usual.

How to achieve parent-child relationship using self join?

my table structure is as follows
parent child name
-1     1     A1
1     2     A2
1     3     A3
how to achieve the hierarchy model using self join. this can be easily achieved using "connect by prior". but how to achieve the same using self join?

Hi,
Yes, that's definitely possible. If you only need to display two levels from the hierarchy, a self-join is a good option. Make it an outer join if you need to show everyone on one level, regardless of whether they have a match on the other level or not; for example, if you want the output:
child_name     child_id     parent_name     parent_id
A1          1
A2          2          A1          1
A3          3          A1          1It's good that you posted some sample data. Now post the results you want from that data, and your query (what you think is the best attempt you've made so far). If you haven't tried anything so far, then look at some other simple self-join to get ideas.

Problem writing a XSLT to convert XML in desired format from a table having self join

Hello,
I have to write a style sheet to convert XML generated from XSQL into a different format. The query that I have is as follows.
select LEVEL depth,
'H' || hierarchy_id id,
name,
nvl2(parent_id, 'H' || parent_id, 0) parent_id,
CURSOR(select LEVEL depth,
'H' || hierarchy_id hid,
name hname,
nvl2(parent_id, 'H' || parent_id, 0) hparent_id,
decode(system_id, NULL, '0', 'S' || system_id) formatted_system_id,
system_id
from hierarchy
where parent_id = h.hierarchy_id
and system_id is not null
) as systems
from hierarchy h
where system_id is null
start with parent_id is null
connect by prior hierarchy_id = parent_id
The hierarchy table has a self join to itself. The selfjoin is on the hierarchyid and the parentid fields which is evident from the query.
Here the hierarchy table contains the parent system and also the child systems underneath. The problem is that the no. of levels that it can go deep is not fixed. The output of this in sqlplus is as follows.
Depth Hierarchyid, name parentid
1 h1 xxx <null>
2 h2 bbb h1
3 h3 ccc h2
<Cursor for systems>
hid hname hparentid formatted_system_id systemid
h4 ccc h2 s1 1
h5 ccc h2 s2 2
<Back to original data>
Depth Hierarchyid, name parentid
2 h6 ddd h1
2 h7 eee h1
The desired output required from the stylesheet is as follows
<h id=h1 name=xxx>
<h id=h2 name=bbb parentid=h1>
<h id=h3 name=ccc parentid=h2>
<h id=h4 name=fff parentid=h3 systemid=s1>
<h id=h5 name=ggg parentid=h3 systemid=s2>
</h>
</h>
<h id=h6 name=ddd parentid=h1/>
<h id=h7 name=eee parentid=h1/>
</h>
Could some one guide me as to how to get this. I did write a stylesheet which gives me the following output.
<h id=h1 name=xxx>
<h id=h2 name=bbb parentid=h1/>
<h id=h3 name=ccc parentid=h2/>
<h id=h4 name=fff parentid=h3 systemid=s1>
<h id=h5 name=ggg parentid=h3 systemid=s2>
</h>
<h id=h6 name=ddd parentid=h1/>
<h id=h7 name=eee parentid=h1/>
</h>
As you can see I am missing the closing of the tag on the 7th line in the desired format. I have written the following stylesheet.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="HIERARCHY">
<HIERARCHY><xsl:apply-templates/></HIERARCHY>
</xsl:template>

<xsl:template match="HELEMENT">
<xsl:choose>
<xsl:when test="PARENT_ID=0">
<helement id="{ID}" name="{NAME}" parentid="{PARENT_ID}"/>
</xsl:when>
<xsl:when test="PARENT_ID!='0'">
<helement2 id="{ID}" name="{NAME}" parentid="{PARENT_ID}">
<xsl:for-each select="SYSTEMS/SYSTEMS_ROW">
<helement3 id="{HID}" name="{HNAME}" parentid="{HPARENT_ID}" systemid="{FORMATTED_SYSTEM_ID}">
</helement3>
</xsl:for-each>
</helement2>
</xsl:when>
<xsl:otherwise>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Is there any way of achieving this. Any help would be appreciated. I am using XSQL to generate first the basic XML output and then applying stylesheet to achieve the desired output.
Sincerely,
D

Hello,
I have to write a style sheet to convert XML generated from XSQL into a different format. The query that I have is as follows.
select LEVEL depth,
'H' || hierarchy_id id,
name,
nvl2(parent_id, 'H' || parent_id, 0) parent_id,
CURSOR(select LEVEL depth,
'H' || hierarchy_id hid,
name hname,
nvl2(parent_id, 'H' || parent_id, 0) hparent_id,
decode(system_id, NULL, '0', 'S' || system_id) formatted_system_id,
system_id
from hierarchy
where parent_id = h.hierarchy_id
and system_id is not null
) as systems
from hierarchy h
where system_id is null
start with parent_id is null
connect by prior hierarchy_id = parent_id
The hierarchy table has a self join to itself. The selfjoin is on the hierarchyid and the parentid fields which is evident from the query.
Here the hierarchy table contains the parent system and also the child systems underneath. The problem is that the no. of levels that it can go deep is not fixed. The output of this in sqlplus is as follows.
Depth Hierarchyid, name parentid
1 h1 xxx <null>
2 h2 bbb h1
3 h3 ccc h2
<Cursor for systems>
hid hname hparentid formatted_system_id systemid
h4 ccc h2 s1 1
h5 ccc h2 s2 2
<Back to original data>
Depth Hierarchyid, name parentid
2 h6 ddd h1
2 h7 eee h1
The desired output required from the stylesheet is as follows
<h id=h1 name=xxx>
<h id=h2 name=bbb parentid=h1>
<h id=h3 name=ccc parentid=h2>
<h id=h4 name=fff parentid=h3 systemid=s1>
<h id=h5 name=ggg parentid=h3 systemid=s2>
</h>
</h>
<h id=h6 name=ddd parentid=h1/>
<h id=h7 name=eee parentid=h1/>
</h>
Could some one guide me as to how to get this. I did write a stylesheet which gives me the following output.
<h id=h1 name=xxx>
<h id=h2 name=bbb parentid=h1/>
<h id=h3 name=ccc parentid=h2/>
<h id=h4 name=fff parentid=h3 systemid=s1>
<h id=h5 name=ggg parentid=h3 systemid=s2>
</h>
<h id=h6 name=ddd parentid=h1/>
<h id=h7 name=eee parentid=h1/>
</h>
As you can see I am missing the closing of the tag on the 7th line in the desired format. I have written the following stylesheet.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="HIERARCHY">
<HIERARCHY><xsl:apply-templates/></HIERARCHY>
</xsl:template>

<xsl:template match="HELEMENT">
<xsl:choose>
<xsl:when test="PARENT_ID=0">
<helement id="{ID}" name="{NAME}" parentid="{PARENT_ID}"/>
</xsl:when>
<xsl:when test="PARENT_ID!='0'">
<helement2 id="{ID}" name="{NAME}" parentid="{PARENT_ID}">
<xsl:for-each select="SYSTEMS/SYSTEMS_ROW">
<helement3 id="{HID}" name="{HNAME}" parentid="{HPARENT_ID}" systemid="{FORMATTED_SYSTEM_ID}">
</helement3>
</xsl:for-each>
</helement2>
</xsl:when>
<xsl:otherwise>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Is there any way of achieving this. Any help would be appreciated. I am using XSQL to generate first the basic XML output and then applying stylesheet to achieve the desired output.
Sincerely,
D

Unable to connect Oracle Application Database using Discoverer Admin 10g

Hi,
I have installed oracle Admin 10g on my machine and trying to connect oracle application database but every time i am getting error like "Unable to connect to: user@hostname Failed to connect to database Unable to connect to Oracle Application Database. Invalid username/password".
Installed BI Discoverer Admin 10.1.2.1
Discoverer Admin Client 10.1.2.48.18
Database 9i
I have done following steps:
1. Selected radio button for Connect to Application EUL's.
2.Gateway User ID (GWYUID)/Password :APPLSYSPUB/PUB
3.FNDNAME:APPS
I able to connect discoverer plus.
Thanks
Ravi

Hi Ravi
Glad to hear you solved this. It is very gratifying when one solves it alone, don't you think?
Best wishes
Michael

Cannot See Database Tables in BI Discoverer Admin

Hello All -
My organization recently upgraded to Discoverer 10g from Discoverer 4i. In 10g the EUL is called BIEUL and in 4i it was called V9EUL. During the upgrade, all the Business Areas belonging to V9EUL in 4i were assigned to BIEUL in 10g. I'm not sure how our DBA accomplished this part of the upgrade.
When I'm logged into BI Discoverer Admin (version 10.1.2.00.00) I am unable to see the database tables in order to create folders from them. For instance, today I want to create a brand new Business Area so I click on File...New to start the Load Wizard then I click on "Create a new business area" then I specify to load the meta-data from the on-line dictionary and click the "Next"button. In the next window (Load Wizard: Step 2) I can see all the available users as I expect so I check the user I want and click 'Next".
Here's the point where the problem arises. In the window "Load Wizard: Step 3" I see the user I chose in the "Available" list on the left, but when I click on + to see the tables owned by the user it does not expand and I cannot go any further.
I experienced the same thing when I try to add a "New Folder from Database" to an already-existing Business Area.
Many Thanks in Advance,
Patrick

At first it sounds like it's a simple matter as the EUL owner not having the rights to see the tables / views pointed to by the EUL (grants).
However, the part about the DBA where you say all BAs belonging to V9EUL in 4i wre assigned to BIEUL in 10g, I hope the DBA didn't do anything fancy. All the EUL manager should have to do is fire up the new version of Disco Admin 10g and it will see that the existing EUL is a version 4 one and will ask if you want to upgrade. Saying yes, you will get an entirely new EUL, tables, etc. created pointing to the same database tables / views as your still existing v4 EUL is.
So you'll have 2 EULs - a v4 one and a v10 one as it's not a destructive upgrade.
Is it possible the DBA hacked something? - or just a grants problem to the new EUL owner?
Russ

Oracle query with out using self join

hi friends,
i have one table for exeample PERSTATUS
pk/fK STUDENT NUMBER SUBJECT MARKS STATUS
1 ACCOUNTS 15 RED
1 MATHS 35 YELLOW
1 SCINECE 45 GREEN
2 ACCOUNTS 55 BROWN
2 MATHS 35 YELLOW
2 SCINECE 45 GREEN
3 ACCOUNTS 15 RED
3 MATHS 35 YELLOW
3 SCINECE 45 GREEN
i want students how status is both red and yellow so i am using self join
i want students status is both red and yellow so i am using self join
SELECT PS.STUDENTNUMBER,PS.STATUS,PS.STATUS1 FROM PERSTATUS PS ,PERSTATUS PS1
WHERE PS.STUDENTNUMBER-PS1.STUDENTNUMER
PS.STATUS='RED' AND PS1.STAUTS='YELLOW'
i want students status is both RD and YELLOW AND GREEN so i am using self join( two self joinS}
SELECT PS.STUDENTNUMBER,PS.STATUS,PS.STATUS,PS2.STATUS FROM PERSTATUS PS ,PERSTATUS PS1,PERSTATUS PS2
WHERE PS.STUDENTNUMBER-PS1.STUDENTNUMER AND PS.STUDENTNUMBER-PS2.STUDENTNUMBER
PS.STATUS='RED' AND PS1.STAUTS='YELLOW' AND PS2.STAUTUS='GREEN'
if i require MORE STATUS then more self joins required, is there any alternative to achive this
and if results comes in multiple rows are accepted (since with the above query result will come in single row)
i tried to use group by (studentnumber,status) with status='red' and status='yellow'
but it is not possible could you povidet he solution

Hi,
Whenever you have a problem, please post CREATE TABLE and INSERT statements for your sample data, and the exact results you want from that data. Explain how you get those results from that data.
See the forum FAQ {message:id=9360002}
Here's an example of how to post the sample data:
CREATE TABLE     perstatus
(       studentnumber     NUMBER
,     subject          VARCHAR2 (10)
,     marks          NUMBER
,     status          VARCHAR2 (10)
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (1,           'ACCOUNTS', 15,       'RED');
INSERT INTO perstatus (studentnumber, subject , marks, status)
       VALUES           (1,           'MATHS',        35,       'YELLOW');
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (1,           'SCINECE', 45,       'GREEN');
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (2,           'ACCOUNTS', 55,       'BROWN');
INSERT INTO perstatus (studentnumber, subject , marks, status)
       VALUES           (2,           'MATHS',        35,       'YELLOW');
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (2,           'SCINECE', 45,       'GREEN');
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (3,           'ACCOUNTS', 15,       'RED');
INSERT INTO perstatus (studentnumber, subject , marks, status)
       VALUES           (3,           'MATHS',        35,       'YELLOW');
INSERT INTO perstatus (studentnumber, subject,    marks, status)
       VALUES           (3,           'SCINECE', 45,       'GREEN');You were on the right track, thinking about GROUP BY. You're interested in something about the whole group of rows that has the same studentnumber. Looking at any individual row won't tell you if that row is part of the group you're interested in or not.
If you want to see information about the group as a whole, you can do the whole job with GROUP BY. In this case, studnetnumber is the only thing that an entire group has in common. If you wanted to see the studentnumbers that had both RED and YELLOW, that is:
STUDENTNUMBER
            1
            3here's one way you could do it:
SELECT       studentnumber
FROM       perstatus
WHERE       status     IN ('RED', 'YELLOW')
GROUP BY studentnumber
HAVING       COUNT (DISTINCT status) = 2 -- That is, both RED and YELLOW
ORDER BY studentnumber
;But say you wanted to see details about individuals in the group; for example, say we want to see all the columns for students that have all 3 of RED, YELLOW and GREEN, like this:
STUDENTNUMBER SUBJECT         MARKS STATUS
            1 SCINECE            45 GREEN
            1 ACCOUNTS           15 RED
            1 MATHS              35 YELLOW
            3 SCINECE            45 GREEN
            3 ACCOUNTS           15 RED
            3 MATHS              35 YELLOWWe used the aggregate COUNT function earlier, but aggregate functions require collapsing the results down to one row per group.
However, most of the aggregate functions, like COUNT, have analytic counterparts, that can give the same results without collapsing the result set. Here's one way to get the results above, using the analytic COUNT function:
WITH     got_cnt          AS
     SELECT studentnumber, subject, marks, status
     ,     COUNT ( DISTINCT CASE
                               WHEN status IN ('RED', 'YELLOW', 'GREEN')
                         THEN status
                           END
                ) OVER (PARTITION BY studentnumber)     AS cnt
     FROM    perstatus
SELECT    studentnumber, subject, marks, status
FROM       got_cnt
WHERE       cnt = 3
ORDER BY studentnumber
,            status
;

Oracle doc inconsistent on materialize view with union all and self joins

First of all, I can't seem to create a materialized view containing self-joins AND union all. Is it possible?
I checked Oracle 9i (my version: PL/SQL Release 9.2.0.4.0 - Production) documentation and I get different answers (or so it seems to me).
First I saw this: "The COMPATIBILITY parameter must be set to 9.0 if the materialized aggregate view has inline views, outer joins, self joins or grouping sets and FAST REFRESH is specified during creation..."
Did you see the part about 'self joins' in there? I did and I was pumped because that seems to say that you CAN have 'self joins' (and my compatibility is 9.2...)
BUT
In the very same document I also found "Oracle does not allow self-joins in materialized join views." (rage)
You can see the document I am speaking of here: http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96520/mv.htm#574889
Whenever I try to create the mview I get the following error. (
In any caseORA-01446 cannot select ROWID from view with DISTINCT, GROUP BY, etc.

First of all, I can't seem to create a materialized view containing self-joins AND union all. Is it possible?
I checked Oracle 9i (my version: PL/SQL Release 9.2.0.4.0 - Production) documentation and I get different answers (or so it seems to me).
First I saw this: "The COMPATIBILITY parameter must be set to 9.0 if the materialized aggregate view has inline views, outer joins, self joins or grouping sets and FAST REFRESH is specified during creation..."
Did you see the part about 'self joins' in there? I did and I was pumped because that seems to say that you CAN have 'self joins' (and my compatibility is 9.2...)
BUT
In the very same document I also found "Oracle does not allow self-joins in materialized join views." (rage)
You can see the document I am speaking of here: http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96520/mv.htm#574889
Whenever I try to create the mview I get the following error. (
In any caseORA-01446 cannot select ROWID from view with DISTINCT, GROUP BY, etc.

How to resolve Self Joins in OBIEE

Hi All
Could any one help how to resolve the Self Join relations in OBIEE (ex. "SCOTT.EMP" table has "EMPNO" column which is referenced by "MGR" column in the same table.
Request:
Need to drill down from the Top manager to his employees and so on
Another example can be applied for reporting the Organisation Chart

This is a great article that shows ho to do the Alias:
Adding an Alias table within the BI physical layer using Oracle BI Administration Tool
http://www.mandsconsulting.com/adding-an-alias-table-within-oracle-bi-administration-tool
Thanks
Subra

Self Join in Discoverer Admin.

Similar Messages

Maybe you are looking for