Set operators over ore.frame

Question

Is there a way to make set operators work with ore.objects without ore.pull?
EXAMPLE:
> df1 <- data.frame(ID=c(1:3),A=rep(1,3))
> df2 <- data.frame(ID=c(2:4),B=rep(1,3))
> class(df1)
[1] "data.frame"
> # Union
> union(df1$ID,df2$ID)
[1] 1 2 3 4
> # Minus
> setdiff(df1$ID,df2$ID)
[1] 1
> #Intersect
> intersect(df1$ID,df2$ID)
[1] 2 3
> #-------------------------------------------------
> of1 <- ore.push(df1)
> of2 <- ore.push(df2)
> class(of1)
[1] "ore.frame"
attr(,"package")
[1] "OREbase"
> # Union
> union(of1$ID,of2$ID)
integer(0)
> # Minus
> setdiff(of1$ID,of2$ID)
integer(0)
> #Intersect
> intersect(of1$ID,of2$ID)
integer(0)
> #-------------------------------------------------
> vec1 <- ore.push(df1$ID)
> vec2 <- ore.push(df2$ID)
> class(vec1)
[1] "ore.integer"
attr(,"package")
[1] "OREbase"
> union(vec1,vec2)
integer(0)

Answer 1

Many of the commonly used base R functions are overloaded in the Oracle R Enterprise transparency layer to work with ore.frame objects.  These functions are located in the OREbase and OREstats packages.
For example, to get the union, use merge, as it has been overloaded to operate on ore.frame objects:
R> find("merge")
[1] "package:OREbase" "package:base"  
merge(x = of1, y = df2, all = TRUE)
R> merge(x = of1, y = of2, all = TRUE)
ID  A  B
1|NA  1  1 NA
2|1   2  1  1
3|2   3  1  1
NA|3  4 NA  1
to subtract:
R> find("Arith")
[1] "package:OREbase" "package:methods"
of1$A - of2$B
R> of1$A - of2$B
[1] 0 0 0
There is no need to pull the data if the function is overloaded to work with ore.frame objects.  More examples can be found in the ORE 1.4 Training Materials: Oracle R Enterprise 1.4 Transparency Layer: http://www.oracle.com/technetwork/database/database-technologies/r/r-enterprise/learnmore/ore-1-4-transparency-layer-215…
You can view the functions in the OREbase and OREstats packages by typing:
ls("package:OREbase")
ls("package:OREstats")
Sherry