Set up the classpath for tomcat 5.0 to compile servlet

Question

I am totally confused how do you set up the class path, i use this command:
c:\set CLASSPATH=.;C:\tomcat5.0\common\lib\servlet-api.jar;%CLASSPATH%
and I compile my file which i put in j2sdk1.4.2_10\bin
here is the command line:
c:\j2sdk1.4.2_10\bin\servletexercise1.java
and it gives me the error message to say that it can't find the servelt, javax.servlet.
Please help! thanks in advance!

Answer 1

I am totally confused how do you set up the class
path, i use this command:
c:\set
CLASSPATH=.;C:\tomcat5.0\common\lib\servlet-api.jar;%C
LASSPATH%I don't have a CLASSPATH environment variable on any machine that I work with.
and I compile my file which i put in j2sdk1.4.2_10\binThat's a pretty stoopid place to put a Java source file. You shouldn't be putting any files in that directory.
The right thing to do is to add the Java /bin directory to your PATH environment variable. When you do, make sure there are no spaces in the path name. (e.g., don't install Java to the "Program Files" directory) OR replace it with its 8-char DOS equivalent (e.g., c:\Progra~1).
here is the command line:
c:\j2sdk1.4.2_10\bin\servletexercise1.javaSorry, I don't see where you execute javac.exe.
and it gives me the error message to say that it
can't find the servelt, javax.servlet.
Please help! thanks in advance!What is this telling you? That the javac.exe totally ignores the CLASSPATH that you set? (Hint: Right answer.)
The correct way to do it is to use the -classpath option on javac.exe.
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