Setting a default servlet

          i need to do considerable pre-processing of requests and would like
          to isolate all the pre-processing logic to one servlet. the default
          servlet ( as far as I understand ) is served when a resource cannot
          be found therefore weblogic serves the default. what i need is
          to specify all request come through a single 'preprocessor' servlet
          which does all request preprocessing then forwards the request
          to the requested URI. How can i achieve this ?
          thanks in advance.

Hi,
 You can make use of FileServlet which is the default servlet in
 Weblogic. You can do any number of pre processing. You can achieve
 this by extending the FileServlet class and overridding the appropriate
 methods.
 Regards
 Ganesh
 "derrick" <[email protected]> wrote:
 >
 >i need to do considerable pre-processing of requests and
 >would like
 >to isolate all the pre-processing logic to one servlet.
 >the default
 >servlet ( as far as I understand ) is served when a resource
 >cannot
 >be found therefore weblogic serves the default. what i
 >need is
 >to specify all request come through a single 'preprocessor'
 >servlet
 >which does all request preprocessing then forwards the
 >request
 >to the requested URI. How can i achieve this ?
 >
 >thanks in advance.

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"Pan YangBin" <[email protected]> wrote in message
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Dimitri Rakitine <[email protected]> wrote in message
news:[email protected]...
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Dimitri Rakitine <[email protected]> wrote in message
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Locale.setDefault(new Locale(...)) ?
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Hi,
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 > "Huy Pham" <[email protected]> wrote:
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 >>weblogic.httpd.servlet.SingleThreadedModelPoolSize. I tried to set this property in WL 5.1, and get an "Found undeclared property..." message when booting WL. Is this feature still supported in WL 5.1? If so, how do I set it?
 >>
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Setting a default servlet

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