Setup for discoverer table for showing number of Rows and columns of Report

As oracle discoverer report show "Rows 1-25 of"(Total rows) and "Column 1-6 Of"(Total Column).
This total rows and columns information's is not appearing on our reports.
Kindly let us know its setting/setups .
This is very urgent to us, Any help will be highly appreciated.
Thanks, Avaneesh

Hmm, what version of Discoverer are you on? Do I understand you correctly that you are able to run a Discoverer report and see this rows and columns information? What software are you running when you do this - Viewer, Plus, or Desktop? Where is this showing up - the top of the report maybe? Or maybe the bottom of the report? The only thing I can think of to handle this is the Page Setup for a workbook, and looking at the Header and Footer sections of that setup. But I am on Discoverer 10.1.2.2 and I don't see anything I can insert on the header/footer that would show this kind of information. Desktop will let you do Page x of y pages (Plus does not), but that is not what you are seeing. You can maybe look at the page setup and see if there is something there not documented in the Discoverer guides.
John Dickey

Similar Messages

Setting number of rows and columns

How do I set the number of rows and columns of a table, say 2348 rows by 3 columns?
Then how do I quickly select the last row?
Also, if I enter a formula in row 1 column 2, how do I quickly copy that formula down to row 1435, or to the end of the column? Dragging seems slow and awkward.

I wish to add a few words to Jerrold responce.
gjf12 wrote:
How do I set the number of rows and columns of a table, say 2348 rows by 3 columns?
Then how do I quickly select the last row?
Also, if I enter a formula in row 1 column 2, how do I quickly copy that formula down to row 1435, or to the end of the column? Dragging seems slow and awkward.
The process that you describe is inefficient.
The efficient one is :
create a table
enter the formulas in a single row
delete the rows below.
Now, each newly inserted row will contain the formulas.
From my point of view, it's when this is done that it will be interesting to apply a script adding rows.
Here is a script inserting rows.
--[SCRIPT insertRows]
Enregistrer le script en tant que Script : insertRows.scpt
déplacer le fichier ainsi créé dans le dossier
<VolumeDeDémarrage>:Users:<votreCompte>:Library:Scripts:Applications:Numbers:
Il vous faudra peut-être créer le dossier Numbers et peut-être même le dossier Applications.
Sélectionner une cellule au-dessous de laquelle vous voulez insérer des lignes.
menu Scripts > Numbers > insertRows
Le script vous demande le nombre de lignes désiré puit insère celles-ci.
--=====
L'aide du Finder explique:
L'Utilitaire AppleScript permet d'activer le Menu des scripts :
Ouvrez l'Utilitaire AppleScript situé dans le dossier Applications/AppleScript.
Cochez la case "Afficher le menu des scripts dans la barre de menus".
--=====
Save the script as a Script: insertRows.scpt
Move the newly created file into the folder:
<startup Volume>:Users:<yourAccount>:Library:Scripts:Applications:Numbers:
Maybe you would have to create the folder Numbers and even the folder Applications by yourself.
Select a cell below which you want to insert rows.
menu Scripts > Numbers > insertRows
The script ask you the number of rows to insert then it does the required insertion.
--=====
The Finder's Help explains:
To make the Script menu appear:
Open the AppleScript utility located in Applications/AppleScript.
Select the "Show Script Menu in menu bar" checkbox.
Save this script as a … Script in the "Folder Actions Scripts" folder
<startupVolume>:Library:Scripts:Folder Action Scripts:
--=====
Yvan KOENIG (VALLAURIS, France)
2010/01/13
--=====
on run
set defaultValue to 100
if my parleAnglais() then
set myInteger to my askAnumber("Insert how many rows ?", defaultValue, "i")
else
set myInteger to my askAnumber("Combien de lignes voulez-vous insérer ?", defaultValue, "i")
end if
set {dName, sName, tName, rname, rowNum1, colNum1, rowNum2, colNum2} to my getSelParams()
tell application "Numbers" to tell document dName to tell sheet sName to tell table tName
repeat myInteger times
add row below row rowNum2
end repeat
end tell
end run
--=====
on getSelParams()
local r_Name, t_Name, s_Name, d_Name, col_Num1, row_Num1, col_Num2, row_Num2
set {d_Name, s_Name, t_Name, r_Name} to my getSelection()
if r_Name is missing value then
if my parleAnglais() then
error "No selected cells"
else
error "Il n'y a pas de cellule sélectionnée !"
end if
end if
set two_Names to my decoupe(r_Name, ":")
set {row_Num1, col_Num1} to my decipher(item 1 of two_Names, d_Name, s_Name, t_Name)
if item 2 of two_Names = item 1 of two_Names then
set {row_Num2, col_Num2} to {row_Num1, col_Num1}
else
set {row_Num2, col_Num2} to my decipher(item 2 of two_Names, d_Name, s_Name, t_Name)
end if
return {d_Name, s_Name, t_Name, r_Name, row_Num1, col_Num1, row_Num2, col_Num2}
end getSelParams
--=====
set {rowNumber, columnNumber} to my decipher(cellRef,docName,sheetName,tableName)
apply to named row or named column !
on decipher(n, d, s, t)
tell application "Numbers" to tell document d to tell sheet s to tell table t to return {address of row of cell n, address of column of cell n}
end decipher
--=====
set { d_Name, s_Name, t_Name, r_Name} to my getSelection()
on getSelection()
local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
tell application "Numbers" to tell document 1
repeat with i from 1 to the count of sheets
tell sheet i
set x to the count of tables
if x > 0 then
repeat with y from 1 to x
try
(selection range of table y) as text
on error errMsg number errNum
set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
return {theDoc, theSheet, theTable, theRange}
end try
end repeat -- y
end if -- x>0
end tell -- sheet
end repeat -- i
end tell -- document
return {missing value, missing value, missing value, missing value}
end getSelection
--=====
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d
set l to text items of t
set AppleScript's text item delimiters to ""
return l
end decoupe
--=====
Asks for an entry and checks that it is an floating number
set myInteger to my askAnumber(Prompt, DefaultValue, "i")
set myFloating to my askAnumber(Prompt, DefaultValue, "f")
on askAnumber(lPrompt, lDefault, ForI)
local lPrompt, lDefault, n
tell application (path to frontmost application as string)
if ForI is "f" then
set n to text returned of (display dialog lPrompt & " (" & (1.2 as text) & ")" default answer lDefault as text)
try
set n to n as number (* try to convert the value as an number *)
return n
on error
if my parleAnglais() then
display alert "The value needs to be a floating number." & return & "Please try again."
else
display alert "La valeur saisie doit être un nombre décimal." & return & "Veuillez recommencer."
end if
end try
else
set n to text returned of (display dialog lPrompt default answer lDefault as text)
try
set n to n as integer (* try to convert the value as an integer *)
return n
on error
if my parleAnglais() then
display alert "The value needs to be an integer." & return & "Please try again."
else
display alert "La valeur saisie doit être un nombre entier." & return & "Veuillez recommencer."
end if
end try -- 1st attempt
end if -- ForI…
end tell -- application
Here if the first entry was not of the wanted class
second attempt *)
tell application (path to frontmost application as string)
if ForI is "f" then
set n to text returned of (display dialog lPrompt & " (" & (1.2 as text) & ")" default answer lDefault as text)
try
set n to n as number (* try to convert the value as an number *)
return n
on error
end try
else
set n to text returned of (display dialog lPrompt default answer lDefault as text)
try
set n to n as integer (* try to convert the value as an integer *)
return n
on error
end try -- 1st attempt
end if -- ForI…
end tell -- application
if my parleAnglais() then
error "The value you entered was not numerical !" & return & "Goodbye !"
else
error "La valeur saisie n’est pas numérique !" & return & "Au revoir !"
end if
end askAnumber
--=====
on parleAnglais()
local z
try
tell application "Numbers" to set z to localized string "Cancel"
on error
set z to "Cancel"
end try
return (z is not "Annuler")
end parleAnglais
--=====
--[/SCRIPT]
Yvan KOENIG (VALLAURIS, France) mercredi 13 janvier 2010 12:43:34

How to get number of rows and columns in a two dimensional array ?

Hello,
What would be the simplest way to get number of rows and columns in a two dimensional array represented as integers ?
I'm looking for another solution as For...Each loop in case of large arrays.
Regards,
Petri

Hi Petri,
See a attached txt file for obtaining two arrays with upper and lower index values
Regards
Ray
Regards
Ray Farmer
Attachments:
Get2DArrayIndex.txt ‏2 KB

Maximum number of rows and columns in data form

Hi,
I wanted to know if there is a limitation to the number of rows and columns that can be displayed in a data form, in Hyperion planning 11.1.2.1 ?
And what would be the most appropriate number of rows and columns to be included for optimum performance.
Thanks.

Hi,
While its a fun fact to determine how much one can stuff into a web form, the reality is: how much can a user reasonably consume in a web form?
And what would be the most appropriate number of rows and columns to be included for optimum performance
You will find that the answer to this is by "what design makes a web form most usable?" And no, the users don't really know what they want from a design perspective, they see it in their head, but usually what they ask for is something that would look entirely different (huge).
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If your question is a bit more technical, then consider this (somewhat oversimplified): Web forms are constructed by a process on the server. Objects are created based on the form's definition and used by the process that builds the form. The process uses Cartesian looping (lots of iterations) to construct the form cell by cell, starting at the top left and finishing up in the bottom right. If the form has a million cells on it, then the loop and all the code within it runs a million times. The capability of the server has a lot to do with how well it can handle this request, and how many it can handle at one time.
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And that's just rendering the page for use.
Now it has to be interacted with on the client machine, and changes parsed, packaged, and sent back to the server.
So the technical answer is, there can be many limitations to how many rows and columns a data form can have - none of which can truly be anticipated by anyone. This is why I put the part about usability first in this post.
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Web Form :Number of rows and columns

Hi All,
I have a web form with many rows and columns . Is it possible for a user to view only a limited rows in the form ? Not using Adhoc/Analyze option . since there are formula rows which wont appear in Analyze grid.
The user want to see only 5 to 10 random rows in the form ? How to do this ?
Please help.

I remember an option in 11.1 which allows users to dynamically add rows and I cannot find that in 11.1.2.2
I think the user will have to always update the user variable to what he want to see.
Regards
Celvin
http://www.orahyplabs.com
http://docs.oracle.com/cd/E17236_01/epm.1112/planning_admin_11122300/frameset.htm?launch.html

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How do I reset my security questions? Normally people are saying something about a rescue email or a thing that will show where your password and security are for me it just shows my two questions and that is it.- Help

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To divide the table based on number of rows

Hello,
I am trying to divide a table based on the number of rows and then to process it.
Say i have a table TEST_XXX which contains 50 rows, what i would like to do is,
to access rows in multiple of 10. How can we do this ?
What i was thinking is, once the table gets created and row are filled in,
add a new column to the table and run a procedure which inserts 1 to first 10 rows
and 2 to next 10 rows and 3 to next 10 row ...etc. Based on this we can process
the first set of rows then next set or rows etc ....
is there a better way to do this ?
Code to create the table :
CREATE TABLE TEST_XXX
A_ID   VARCHAR2(10),
B_ID   NUMBER,
c_ID   VARCHAR2(10),
D_ID   NUMBER
)Code to add rows:
DECLARE
BEGIN
FOR I IN 1..50
LOOP
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END LOOP;
COMMIT;
END;The original problem is, i do have a huge table, and i write a sql query to process it,
when i process it selecting all values from table, it is very slow.
But when i process it in small chuks(say 100 rows) it works fine.
Thats how i was the above approach in mind.

The original problem is, i do have a huge table, and i write a sql query to process it,
when i process it selecting all values from table, it is very slow.Did you trace both the implementations and see why it is taking longer?

Need help setting up rows and columns for a shop page in DW

I sell my books and design tees on my site. I'm trying to set up a new page for a new site.
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Use a table for your product catalog.
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I need to take elements from within 2 nested for loops and place them in an array at the specific row and column that I need.

I have tried intializing an array and replacing elements by specifying a particular row, and column, but in the end I get an array with only one element replaced, and I suspect that it is because as the for loops are running through their iterations each time the array is re-initializing. I have a simple vi that I will post below, it is not the exact situation that I have but is a good place for me to get some understanding. I have the row and column indexes being driven by the inner and outer loop iterations, which gives me the pattern I need. I am using the inner iterations as array elements. How do I set this up so that it works and d
oes keep re-initializing my array.
Attachments:
Untitled.vi ‏26 KB

I have fixed a number of things in your vi.
You were right in thinking that the array was continuously re-initialized. To avoid this, use a shift register (right-click the loop border), which will pass the updated array into the next iteration.
Chilly Charly (aka CC)
E-List Master - Kudos glutton - Press the yellow button on the left...
Attachments:
your_vi.vi.zip ‏13 KB

How to find accurate number of Rows, and size of all the tables of a Schema

HI,
How to find the accurate number of Rows, and size of all the tables of a Schema ????
Thanks.

SELECT t.table_name AS "Table Name",
t.num_rows AS "Rows",
t.avg_row_len AS "Avg Row Len",
Trunc((t.blocks * p.value)/1024) AS "Size KB",
t.last_analyzed AS "Last Analyzed"
FROM dba_tables t,
v$parameter p
WHERE t.owner = Decode(Upper('&1'), 'ALL', t.owner, Upper('&1'))
AND p.name = 'db_block_size'
ORDER by 4 desc nulls last;
## Gather schema stats
begin
dbms_stats.gather_schema_stats(ownname=>'SYSLOG');
end;
## Gather a particular table stats of a schema
begin
DBMS_STATS.gather_table_stats(ownname=>'syslog',tabname=>'logs');
end;
http://www.oradev.com/create_statistics.jsp
Hope this will work.
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Asif Kabir
-- Mark the answer as correct/helpful

How Calculate more than one value and store it into to different rows and column for each input?

thx guys.....i have a progress now in LV
But now i have new trouble here. Ok i attached my LV file (LV 7.0.1/7.1) and excel form. I just could'nt calculate more than one input value. I want a different result for each value that i enter ... and store it into different rows and column. But it just store at one row.
Attachments:
My Project.vi ‏31 KB
rumus motor bakar.xls ‏14 KB

duplicate post

Hi, how can i break the value for a row and column once i have converted the image to the array???????

Hi, I would like to know how can i break the value for a row and column once i have converted the image to the array. I wanted to make some modification on the element of the array at a certain position. how can i do that?
At the moment (as per attachhment), the value of the new row and column will be inserted by the user. But now, I want to do some coding that will automatically insert the new value of the row and the column ( I will use the formula node for the programming). But the question now, I don't know how to split the row and the column. Is it the value of i in the 'for loop'? I've tried to link the 'i' to the input of the 'replace subset array icon' , but i'm unable to do it as i got some error.
Please help me!
For your information, I'm using LABView 7.0.

Hi,
Thanks for your reply.Sorry for the confusion.
I manage to change the array element by changing the row and column value. But, what i want is to allow the program to change the array element at a specified row and column value, where the new value is generated automatically by the program.
Atatched is the diagram. I've detailed out the program . you may refer to the comments in the formula node. There are 2 arrays going into the loop. If a >3, then the program will switch to b, where if b =0, then the program will check on the value of the next element which is in the same row with b but in the next column. But if b =45, another set of checking will be done at a dufferent value of row and column.
I hope that I have made the problem clear. Sorry if it is still confusing.
Hope you can help me. Thank you!!!!
Attachments:
arrayrowncolumn2.JPG ‏64 KB

Search row and column for return value

Dear Sir/Madam,
                           I have a problem for searching spreadsheet and hope you can help me out a bit. Im pretty new to Labview and Im currently using Labview 8.0. My task is to search the spreadsheet I have attached in row and column-wise, then return the corresponding value out. I had an attempt in doing this as you can see from the vi that i have attached. I try inputting the 'read from measurement file' into an array and using delete, index and search array I will be able to find the index value for the relevant row and column that i searched for by inputting them into an index array with the orginal array from the 'read from measurement file'.
                          So ultimately, when i enter a row value of 0.5 and a column value of 0.3, my output will be 1.688.
                          I can't see any mistakes in my logic but I getting really strange results, like I can read my data has been entered into an array but when i try deleting the first column and put it into another array, the orginal array with nothing deleted is outputted hence making my search to give out -1 value. So could you take a look please and give me any suggestion that can solve my problem or enhance the code a bit. Thank you for your time.
Best Regards,
Coato
P.s for some reason i can't attached the .lvm file of my data hence i have attached the excel version but i think you need to convert it back to .lvm for the 'read from measurement file' function to work.
Attachments:
Backswing compensation.csv ‏10 KB
Backswing comnpensation2.vi ‏109 KB

Your VI makes absolutely no sense to me, but maybe I don't understand what you are trying to do.
You seem to have dynamic data with 6 signals and 48 points/channel. Now you reshape this into an array of dynamic data with 4x13 elements from which you slice out one row or column, resp. "delete from array" is NOT the correct tool to do this, use "Index array" with one index unwired to get a row or column as 1D array.
So you end up with two 1D arrays of dynamic data that you search for DBL. It is difficult to understand how you want to search for an array element that corresponds to a scalar DBL value of 0.1. Your array elements are NOT DBLs but dynamic data, each containing many signals!
There are two elements on all your data that are "3", the rest are zero. You will never find anything that is 0.1.
Maybe you can convert your original dynamic data to a 2D array with "rows are signals" using "convert from dynamic data", then operate on the 2D array.
Coato wrote:
                          So ultimately, when i enter a row value of 0.5 and a column value of 0.3, my output will be 1.688.
Sorry, Please explain.
Please make a VI containing a simple 2D aray as diagram constant that contains e.g. 5x5 typical values. Let us know what kind of result you expect from your algorithm..
LabVIEW Champion . Do more with less code and in less time .

Setup for discoverer table for showing number of Rows and columns of Report

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