SharePoint - Created By Column

Hey all,
I was wondering if 1: Is it currently possible (or at least planned) to allow manual filtering of what data you retrieve from SharePoint so you don't import the entire list? and 2: I'm trying to retrieve the "created by" field from a SharePoint
list and ultimately filter a gallery based on how created a list item, is there a way to enable Siena to import that information?
Thanks!

This is interesting. We're looking into this. I can reproduce what you are saying about the Created By and Modified columns. I'm able to export the list to Excel where the columns do display.
Thanks for bringing this to our attention.
Please remember to click “Mark as Answer” on the post that helps you, and to click “Unmark as Answer” if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread. Regards, Harold Kless Microsoft
Online Community Support

Similar Messages

Created by column in sharepoint 2010

we have 5 different site list that uses the created by column to help us identify who created what. for some reasons one of the site list is showing system account in the created by column and not sure how it was changed to this?
all other list are showing the correct user who created each entry
any ideas?

Have you migrated one of the lists via the content and structure feature from elsewhere within the site collection?
This may have led to the creation of these items under the system account.
Steven Andrews
SharePoint Business Analyst: LiveNation Entertainment
Blog: baron72.wordpress.com
Twitter: Follow @backpackerd00d
My Wiki Articles:
CodePlex Corner Series
Please remember to mark your question as "answered" if this solves (or helps) your problem.
No

Sharepoint 2013 designer assign to task with created by column failing

We are getting below exception when we assign a task to created by column in sharepoint 2013 designer workflow.
It was working till last week.
RequestorId: c70d0b6d-a1c7-6825-5dec-3bc13f0713bf. Details: System.ArgumentNullException: Value cannot be null. Parameter name: Input at Microsoft.Activities.Expressions.SplitString.Execute(CodeActivityContext context) at System.Activities.CodeActivity`1.InternalExecute(ActivityInstance
instance, ActivityExecutor executor, BookmarkManager bookmarkManager) at System.Activities.Runtime.ActivityExecutor.ExecuteActivityWorkItem.ExecuteBody(ActivityExecutor executor, BookmarkManager bookmarkManager, Location resultLocation)
MCTS Sharepoint 2010, MCAD dotnet, MCPDEA, SharePoint Lead

Hi,
According to your post, my understanding is that you got exception when we assign a task to created by column in sharepoint 2013 designer workflow.
To troubleshoot the issue, I recommend to capture the created by field value in a variable.
You can add a "Set variable workflow" action and get the value of this field. Then, add a "Log on workflow history" action and log the value of the variable and see if it is capturing the right value. And in the task action, put the variable
on the user field and do some tests.
In addition, you need to make sure the variable return field as "string" or "Email Address”.
Here is a similar thread for you to take a look at:
http://sharepoint-community.net/forum/topics/sharepoint-2013-workflow-action-send-email-only-works-for-me?xg_source=activity
Best Regards,
Linda Li
Linda Li
TechNet Community Support

"Created By" Column is showing empty in SharePoint List

Hello All,
I have created a custom list and enabled the "Created By" and "Created" Column to be shown in the list.
All the users are able to see the "Created" Column populated, but the "Created By" column is blank, no value is populated to it.
But the Farm Administrator is able to see the values for "Created By" column in the List. I tried providing full control to the Users, provided all permissions, but still the users are unable to see this column populated. I have no clues what to
be done.
So I tried a workaround specified in the forum ie., by using a column with calculated value =[Me]. But this gives the login name and not the Proper name, which is not helpful for me. I just want a column which displays who created the item.
Please help me regarding this issue.
Thanks,
Shanky

Hi Alex,
Yes, I have checked them too.
1. This is happening with all lists, as I have modified the permission for the users to the lists only to :
Add Items
View Items
Open Items
View application Pages
View Pages
Open
This is to make sure that the users wont modify the list or delete it or its items.
2. This is happening with all the items in the list, not only for other people's items but also for current user's item as well.

Create Site Column and add it to two different list as dependent lookup column

I want to create two lookup lists that will have one common column. The common column values will vary depending on the list.
For ex: List A holds Countries (USA) and their Currency code (USD). List B holds States (New York) and their code (NY). The lists are completely independent of each other. I would like to create a common site column named "Code" of type
Text and use it across these two lists. Is it possible?
My solution so far -
a. created the site column (programmatically) which is pretty straight forward.
b. created list definition with two fields (Title and Code).
c. created list instance for Country list. Added data rows in the elements.xml. But not sure how to add Code field as dependent lookup.
If I remove the code field from the elements.xml, the solution deploys successfully creating the Country list with just the Title field. But I need both the fields. Any help is appreciated.
Here is a look at the elements.xml with data rows for Country list instance
<?xml version="1.0" encoding="utf-8"?>
<Elements xmlns="http://schemas.microsoft.com/sharepoint/">
<ListInstance Title="List Instance" OnQuickLaunch="TRUE" TemplateType="10001" Url="Lists/CountryList" Description="Country Values">
<Data>
<Rows>
<Row>
<Field Name="Title">USA</Field>
<Field Name="Code">USD</Field>
</Row>
<Row>
<Field Name="Title">Japan</Field>
<Field Name="Code">Yen</Field>
</Row>
<Row>
<Field Name="Title">Australia</Field>
<Field Name="Code">AUD</Field>
</Row>
</Rows>
</Data>
</ListInstance>
</Elements>

Hi,
According to your post, my understanding is that you want to add lookup field to the list in elements.xml.
I recoment you to create lookup column as site column, then bind the lookup column to the contnet type, and then use the contnet type in the list.
For more information, you can refer to:
http://spcodes.blogspot.com/2013/02/create-custom-content-type-with-lookup.html
http://social.msdn.microsoft.com/Forums/office/en-US/d5ec08d5-cfa7-4bbb-9459-78d04674ee59/add-a-lookup-column-in-the-schemaxml?forum=sharepointcustomizationlegacy
http://www.justanothertechnologyguy.com/2013/01/how-to-create-and-connect-lookup-fields.html
Best Regards,
Linda Li
Linda Li
TechNet Community Support

How to have SharePoint search custom columns in a custom list?

Hello,
How can have SharePoint search custom columns in a custom list? I have a custom list for a directory with names, department, title and phone numbers. Department and titles are not searchable with the search box for the list.
How can I make these 2 custom columns searchable?
Thanks
Paul

Any text added to any property is searchable. If you have a Sales department search for "sales", but I think you are asking about doing a property search like "department=sales" or "department:sales".
2013 has a different way than 2007 and 2010 to create Managed Properties. You will need to create a Site Column and then a little configuration. The basic steps are:
Create a Site Column (as SP already has a Department column you will want to create one with a difference name such as CorpDept.)
Add the column to a list or library and add data. (won't be found otherwise)
Wait for the next content crawl. (or manually start a crawl)
Go to the tier where you want to define the managed property and go to the Schema page:
Central Admin, Search Service, Schema
your site, Settings (gear), Site Settings, Search Schema (in the Site Collection Admin section)
your site, Settings (gear), Site Settings, Schema (in the Search section)
Click Managed Properties and search for your column name. It might look like this: ows_q_TEXT_CorpDept.
Edit the Managed Property and give it a useful Alias, such as "CorpDept".
Test the search: CorpDept:Sales
Do a web search for "SharePoint 2013 Site Column Managed Properties" for examples.
Mike Smith TechTrainingNotes.blogspot.com
Books:
SharePoint 2007 2010 Customization for the Site Owner,
SharePoint 2010 Security for the Site Owner

Error while creating a column in master

Hi all,
I am using the sap business one 8.8 version.
I am getting an error while creating a user defined column for a master table.
The error code is -104.
The method I had used for creating a master table is as follows.
*#region Create Table*
        public static bool CreateTable(string TableName, string TableDescription, SAPbobsCOM.BoUTBTableType TableType, SAPbouiCOM.Application oApplication, SAPbobsCOM.Company oCompany)
            SAPbobsCOM.UserTablesMD oUserTableMD;
            int intRecCode;
            bool boolResult = false;
            oUserTableMD = (SAPbobsCOM.UserTablesMD)oCompany.GetBusinessObject(SAPbobsCOM.BoObjectTypes.oUserTables);
            try
                if (!oUserTableMD.GetByKey(TableName))
                    oUserTableMD.TableName = TableName;
                    oUserTableMD.TableDescription = TableDescription;
                    oUserTableMD.TableType = TableType;
                    intRecCode = oUserTableMD.Add();
                    if (intRecCode == 0)
                        boolResult = true;
            catch (Exception e)
                oApplication.MessageBox(e.Message, 1, "Ok", "", "");
            finally
                System.Runtime.InteropServices.Marshal.ReleaseComObject(oUserTableMD);
                GC.Collect();
            return boolResult;
        #endregion
==================================
The following is the code for creating a column in the above master
private static void AddField(string TableName, string ColumnName, string ColDescription, SAPbobsCOM.BoFieldTypes FieldType, int Size, SAPbobsCOM.BoFldSubTypes SubType, string ValidValues, string ValidDescription, string
SetValidValues, SAPbouiCOM.Application oApplication, SAPbobsCOM.Company oCompany)
int intLoop;
            string[] strValue, strDesc;
            SAPbobsCOM.UserFieldsMD oUserFieldsMD;
            SAPbobsCOM.Recordset oRecordSet;
            oUserFieldsMD = (SAPbobsCOM.UserFieldsMD)oCompany.GetBusinessObject(SAPbobsCOM.BoObjectTypes.oUserFields);
            oRecordSet = (SAPbobsCOM.Recordset)oCompany.GetBusinessObject(SAPbobsCOM.BoObjectTypes.BoRecordset);
            try
                oRecordSet.DoQuery("SELECT COUNT(*) FROM CUFD WHERE TableID = '" + TableName + "' AND AliasID = '" + ColumnName + "'");
                if (Convert.ToInt16(oRecordSet.Fields.Item(0).Value) == 0)
                    System.Runtime.InteropServices.Marshal.ReleaseComObject(oRecordSet);
                    oRecordSet = null;
                    strValue = ValidValues.Split(Convert.ToChar(","));
                    strDesc = ValidDescription.Split(Convert.ToChar(","));
                    if (strValue.GetLength(0) != strDesc.GetLength(0))
                        throw new Exception("Invalid Values");
                    oUserFieldsMD.TableName = TableName;
                    oUserFieldsMD.Name = ColumnName;
                    oUserFieldsMD.Description = ColDescription;
                    oUserFieldsMD.Type = FieldType;
                    if (FieldType != SAPbobsCOM.BoFieldTypes.db_Numeric)
                        oUserFieldsMD.Size = Size;
                    else
                        oUserFieldsMD.EditSize = Size;
                    oUserFieldsMD.SubType = SubType;
                    oUserFieldsMD.DefaultValue = SetValidValues;
                    for (intLoop = 0; intLoop <= strValue.GetLength(0) - 1; intLoop++)
                        oUserFieldsMD.ValidValues.Value = strValue[intLoop];
                        oUserFieldsMD.ValidValues.Description = strDesc[intLoop];
                        oUserFieldsMD.ValidValues.Add();
                    if (oUserFieldsMD.Add() != 0)
                        UpdateLastErrorDetails(-104, oCompany);
            catch (Exception e)
            { oApplication.MessageBox(e.Message, 1, "Ok", "", ""); }
            finally
                if (oRecordSet != null)
                    System.Runtime.InteropServices.Marshal.ReleaseComObject(oRecordSet);
                    oRecordSet = null;
                System.Runtime.InteropServices.Marshal.ReleaseComObject(oUserFieldsMD);
                GC.Collect();

Hi,
I am newly using BI publisher . I am using 10.1.3.4.0 . I am just trying to create a report in test name. that is the first step to create a report where i am getting error. I am using default RPD paint , where all the user and Groups are defined .

How do I create multiple columns with bullets in pages

I'm trying to figure out how to create multiple columns within a document in which I bullet information...

At the point you wish to change to two columns, Insert > Columns and then in the Layout Inspector, select the number of columns. After the insertion point, you will also need to insert another Column Change to return the following paragraphs to single column.
Then Select the text to be bulleted and in the Text Inspector > List tab select the type of bullets.
Note: This creates two columns that flow together. This can be tricky if you add any text later.
If you wish to ensure alignment, create a two column text table and remove the lines with the Graphic Inspector > Lines > No Lines option and insert your text in each column and apply the bullets as above.
This will create a text box - you then need to ensure it moves with the text by electing "Object Moves With Text" in the Wrpa Inspector.
Message was edited by: bwfromspring hill

How can I create a column to numerically order all the items?

As a first time user of Numbers, I created a table of info which I imported from Address book.
Everything looks good.
I would like to be able to see how many addresses I have on the table.
I looked at the Numbers 08 manual, and went to Preferences, then Auto correction, then -automatically detect lists.
The manual says to choose something on Table Inspector- but I couldn't find it.
I did choose - have Press Return to automatically move to next cell.
I created a column before the first column on my table ( which was last name) and typed 1.
I thought that when I pressed return it would automatically type in 2 and 3 and so on.
But I guess I missed a step.
Any suggestion?

Hi Rosie,
It's not clear whether you want to Number the names or Count the names. I'll give you the solution for each.
To number the entries, begin as you have done, typing a "1" in the first cell, and hitting Return. Then type a "2" in the second cell. Now select both cells and grab the little circle in the lower right corner of the selection rectangle, pulling it down to continue the sequence that you have begun typing.
To count the number of entries without numbing them, here is one pretty easy way...
Click on the column label over the last names, which will select the entire column. Then click on the Function Icon on the Toolbar and select Count. This will insert a Footer Row in your Table, and will display the number "0". The zero count is because you have no numbers values in the column. To edit the function to display the count of text items, Names, we need to edit the Function from COUNT to COUNTA. Just click on the footer cell to select it, then click in the Formula Bar, just above the Column Labels, and place your text cursor behind the "T" in COUNT and type an "A". Then hit Return. Now your new footer cell will show your count of names.
Post back if you have questions.
Jerry

Is it possible to create a Column with Conditional Mandatory with another Column?

Is it possible to create a Column with Conditional Mandatory with another Column?
For example
In a Table we have column A, B, C.
A is Primary Column.
B is Optional
C is Conditional Mandatory.
A B
C
12345 ABC
OK
12346 NULL
NULL
12347 ABC
OK
Only if the B Column has the value then only C column should be mandatory

I guess you can't create a condtional mandatory column directly. However, you can use check constraint to on the column
create table YourTable
A int primary key,
B char(3),
C int,
constraint ch_con check(
B
is not null
or C is null

How to create some columns dynamically in the report designer depending upon the input selection

Post Author: ekta
CA Forum: Crystal Reports
how to create some columns dynamically in the report designer depending upon the input selection
how export this dynamic report in (pdf , xls,doc and rtf format)
report format is as below:
Element Codes
1
16
14
11
19
10
2
3
Employee nos.
Employee Name
Normal
RDO
WC
Breveavement
LWOP
Sick
Carers leave
AL
O/T 1.5
O/T 2.0
Total Hours
000004
PHAN , Hanh Huynh
68.40
7.60
76.00
000010
I , Jungue
68.40
7.60
2.00
5.00
76.00
000022
GARFINKEL , Hersch
66.30
7.60
2.10
76.00
In the above report first column and the last columns are fixed and the other columns are dynamic depending upon the input selection:
if input selection is Normal and RDO then only 2 columns w'd be created and the other 2 fixed columns.
Can anybody help me how do I design such report....
Thanks

Hi Developer life,
According to your description that you want to dynamically increase and decrease the numbers of the columns in the table, right?
As Jason A Long mentioned that we can use the matrix to do this and put the year field in the column group, amount fields(Numric values) in the details, add an filter to filter the data base on this column group, but if
the data in the DB not suitable to add to the matrix directly, you can use the unpivot function to turn the column name of year to a single row and then you can add it in the column group.
If there are too many columns in the column group, it will fit the page size automatically and display the extra columns in the next page.
Similar threads with details steps for your reference:
https://social.technet.microsoft.com/Forums/en-US/339965a1-8cca-41d8-83ef-c2548050799a/ssrs-dataset-column-metadata-dynamic-update?forum=sqlreportings
If your still have any problem, please try to provide us more details information, such as the data structure in the DB and the table structure you are currently designing.
Any question, please feel free to let me know.
Best Regards
Vicky Liu

Created by column value is not showing in XSLT List View After Migration To 2013

Hello All,
In my XSLT Created By Column value is not showing. Please help me with this problem. My code is simple I have custom column in XSLT name as 'Reported By' in which I want to show 'Created By' column value. but it is not showing. please help me with that.
Thanks in advance

hi
is anyone has answer for this question.
thanks...!!!!

'Created by' column in SM37 contains inactive users - audit issue?

Hi,
Most of the jobs in sm37 in our systems have been created by staff who had already left. So under the 'created by' column in SM37 we can see jobs running under users who have been locked/deleted. But it's only the 'created by' column. All the 'steps' run under a system user called 'BATCHUSER', that's why the jobs run fine.
Is it a problem to have inactive users under the 'created by' column in SM37? Is it an audit issue? I've thought that as long as the steps run as a system user then it shouldn't be an audit issue but having discussing about it in my team.
Any comments will be very welcome!
Thank you
Marcia

Yes,
This is purely depends on your org understandness, As in system there won't be any issue as long as the jobs run.
In SAP there is no such way to change the owner (Created by) of background job, we only can change the step owner.
If you feel that there will be an issue, my suggestion is to copy the jobs to BATCHUSER and delete all old jobs created by inactive users.
Regards,
Nick Loy

Is it possible to create a column in runtime?

Hi,
I created a application that connect with Access database. I just wonder is it possible for user to create a column in runtime, because the application need this kind of interaction.
Many thanks,
Ann

Here's code to do that
     static void addColumn(Connection dbConn, String cname)
          Statement ins;
          String sql = "ALTER TABLE TestTable ADD "+cname+" CHAR(20)";
          try
               ins = dbConn.createStatement();
               ins.executeUpdate(sql);
               ins.close();
          catch (SQLException se){fail(se);}
     }The rest of my TestODBC example can be found at
http://forum.java.sun.com/thread.jsp?forum=31&thread=453376

Is it possible to create a column in the runtime?

Hi,
I created a application that connect with Access database. I just wonder is it possible for user to create a column in runtime, because the application need this kind of interaction.
Many thanks,
Ann

Cross-post:
http://forum.java.sun.com/thread.jsp?
forum=31&thread=453860&start=0&range=15#2066833

SharePoint - Created By Column

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