Shell script issue

Question

Hi All,
Am new to DB and unix....Trying to find the diskspace utilization of the filesystem so as to get an alert if it crosses limit.
Here is the code that i am trying to run but it doesn't seem to work. Need ur help on this
#!/bin/bash
#--To send a mail alert if the filesystem disk space is more than warning or critical limit--#
warning=85
high=90
i=`df -k |sed '1d'| awk '{print $7 }'`
while read $i
do
s=`df -k | awk '{ print $4}'|cut -d'%' -f1`
if [ $s -ge $high ]
then
echo "URGENT: limit for $7 is crossed"
break
fi
if [ $s -ge $warning ]
then
echo "WARNING: Low disk space for $7"
fi
done
Error that i get is as follows
+ read / /usr /var /tmp ......
d.sh[8]: /: This is not an identifier.

Answer 1

Hi
This will give you free space:
free_space=`df -m | grep "/orashare" | awk '{print $4}'`
Then to test:
if [ ${free_space} -lt $space_free_threshold ]; then...
To avoid getting multiple alerts, you may want to create a temporary file the first time the threshold has been reached, and then not send another message until the space problem has been resolved. At that stage remove the temp file again...
Sorry - didn't read your whole post - oops. Looks like you're getting the error because of extra spaces between directories:
/usr /var /tmp
Should work once you remove these...
Cheers,
A.
Edited by: Andreas Hess on Nov 24, 2009 2:13 PM