Show date list

Question

Hi I am trying to show a date list in column. I have got a count of jobs opened, however all of the jobs are grouped into one count. I need a count of the 1st then the 2nd etc.
EG I am getting..
Opened Closed Movement
3 0 -3
I need
Date Opened Closed Movement
01/Sep/2006 1 1 1
02/Sep/2006 2 1 -1
03/sep/2006 5 5 5
etc...
Can anyone help?

Answer 1

Hi Dave
You first of all have to start out with deciding how many result sets you need and which function, CASE or DECODE, you want to use. In your case let's say we have decided on four buckets.
The first part of the answer is to produce a calculation that determines the number of days. In your case you need to either build a calculation or use an existing database item. So let's call the result of this DAYS.
Now look at this:
IF DAYS LESS THAN OR EQUAL TO 7 THEN 'a) 1 - 7 days'
ELSE IF DAYS LESS THAN OR EQUAL TO 15 THEN 'b) 8 - 15 days'
ELSE IF DAYS LESS THAN OR EQUAL TO 21 THEN 'c) 16 - 22 days'
ELSE ELSE 'd) More than 22'
Converting this to a CASE you get:
CASE WHEN DAYS <= 7 THEN 'a) 1 - 7 days'
WHEN DAYS <= 15 THEN 'b) 8 - 15 days'
WHEN DAYS <= 22 THEN 'c) 16 - 22 days'
ELSE 'd) More than 22 Days' END
Converting to a DECODE is more difficult but not impossible due to the fact that DECODE only works with equality. However, with the use of the LEAST function we can do the same thing:
DECODE(LEAST(DAYS,7),DAYS,'a) 1 - 7 days',LEAST(DAYS,15),DAYS,'b) 8 - 15 days',LEAST(DAYS,22),DAYS,'c) 16 - 22 Days',d) More than 22 Days')
Best wishes
Michael