Show file content in jsp

i want to get an xml file and give the client user.maybe in the jsp i write the XML content to notepad.But i don't know how can i open notepad and write the content to it.
pls tell me the the right way! thanks a lot a lot!

Why don't you use Java Script to reference the xml file and open it in a new window from your JSP?
String browserFilePath = request.getContextPath() + "/some_directory/myfile.xml";
then in your jsp
<% if (...???) { %>
<Script>window.open('<%=browserFilePath%>')</Script>
{% } %>

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Reading RTF file content from JSP which stored in database as image format

<%@page import="java.sql.*" %>
<%@page import="java.net.*" %>
<%@page import="java.io.*" %>
<%@page import="java.*" %>
<%@page import="javax.swing.*" %>
<%@page import="javax.swing.text.*" %>
<%@page import="javax.swing.text.rtf.*" %>
<%
     Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
Connection con=DriverManager.getConnection("jdbc:sqlserver://local:1433;databaseName=database;user=sa");
     Statement st=con.createStatement();
     ResultSet rs=st.executeQuery("select Document from docrev where UniqeId ='199207' ");//("select data from rtfdata");227317
     rs.next();
     byte bt[]=rs.getBytes(1);
     InputStream fi = new ByteArrayInputStream( bt );
     RTFEditorKit rtf = new RTFEditorKit();
     JEditorPane editor = new JEditorPane();
     editor.setEditorKit( rtf );
     rtf.read( fi, editor.getDocument(), 0 );
     Document d=editor.getDocument();
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%>
<html>
<body>
<p><textarea name=myarea style="background:#FFCC99" cols=100 rows=50><%=str%></textarea>
</body>
</html>
Edited by: Santhu538 on Oct 23, 2007 10:16 PM
Edited by: Santhu538 on Oct 23, 2007 10:25 PM
Edited by: Santhu538 on Oct 23, 2007 10:26 PM

Please use code tags while posting code. See the code button above the text area?
It's a good practise not to mix jdbc code in your jsp (mvc and all that you see)
Finally you'll have to quickly decide on your front end - jsp or swing. It looks like the former, but then with the code you have posted, the server is apt to pop up some windows prompting the user who has logged on (to the server) to choose the files for the client :)
ram.

How to display an xml file contents in jsp as tree view

hi,
Iam trying to read an xml file and display the structure in jsp as tree view, can any one help me

Use a [XML or DOM parser|http://java-source.net/open-source/xml-parsers] to read a XML file into a tree structure of Java objects.
Use the [Collections API|http://java.sun.com/docs/books/tutorial/collections/index.html] to get hold of the relevant elements in a tree structure.
Use JSTL´s [c:forEach|http://java.sun.com/javaee/5/docs/tutorial/doc/bnakh.html] tag to iterate over a Collection in JSP.
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Show file content

hi folks,
one more try
in wd abap i can make an upload of an file, are there any (besides office and pdf) viewers available to view those files in a wd abap application.
kind regards,
oliver

Why don't you use Java Script to reference the xml file and open it in a new window from your JSP?
String browserFilePath = request.getContextPath() + "/some_directory/myfile.xml";
then in your jsp
<% if (...???) { %>
<Script>window.open('<%=browserFilePath%>')</Script>
{% } %>

FILE UPLOAD PROBLEM SHOWING THE CONTENTS IN THE SAME BROWSER WINDOW

Hi,
This is amit Joshi
I have uploaded content using input tag of type file and posted to jsp as multipart/form-data type
in that jsp i am using following code to display the content in browser but only first content is displayed How can i modify it to show all content in the file ..
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
//dbm.insert_data(f,"mms3");
%>
<%
if (ServletFileUpload.isMultipartContent(request)){
ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
List fileItemsList = servletFileUpload.parseRequest(request);
strBuilder.append("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>").append('\r').append('\n').append("<xpage version=\"1.0\">").append('\r').append('\n');
String optionalFileName = "";
FileItem fileItem = null;
Iterator it = fileItemsList.iterator();
ServletOutputStream outputStream=null;
while (it.hasNext()){
FileItem fileItemTemp = (FileItem)it.next();
if (fileItemTemp.isFormField()){
%>
<b>Name-value Pair Info:</b>
Field name: <%= fileItemTemp.getFieldName() %>
Field value: <%= fileItemTemp.getString() %>
<%
if (fileItemTemp.getFieldName().equals("filename"))
optionalFileName = fileItemTemp.getString();
else
fileItem = fileItemTemp;
if (fileItem!=null){
String fileName = fileItem.getName();
%>
<b>Uploaded File Info:</b>
Content type: <%= fileItem.getContentType() %>
Field name: <%= fileItem.getFieldName() %>
File name: <%= fileName %>
<%
if(fileItem.getContentType().equals("image/jpeg")) { %>
File : <p><%
     //response.setContentType("image/gif");
     byte[] bArray=fileItem.get();
     response.setContentType("image/jpeg");
     outputStream=null;
     outputStream= response.getOutputStream();
     outputStream.write(bArray);
     outputStream.flush();
     outputStream.close();
else if(fileItem.getContentType().equals("text/plain"))
     %> File : <%= fileItem.getString() %>
<%
byte[] bArray=fileItem.get();
response.setContentType("text/plain");
     outputStream = response.getOutputStream();
     out.println();
     outputStream.write(bArray);
     outputStream.flush();
     outputStream.close();
%> </p> <%
%>
</body>
</html>
Edited by: Amit_Joshi on Nov 13, 2007 10:58 PM

Well Well Well..
That would not work...
What you have to do is save the uploaded file content on to a location and then pass the fileName as a request parameter to a deidicated which displays the contents of that file.
Just as an example
<html>
<head>
<title>File Upload Display</title>
</head>
<body>
<%
//ServletOutputStream sout=response.getOutputStream();
StringBuilder strBuilder = new StringBuilder();
int count=0;
String f;
f=request.getParameter("filedb");
DBManager dbm = new DBManager();
//dbm.createTable("mms3");
//log.info("In JSP : "+ f);
//dbm.insert_data(f,"mms3");
%>
<%
if (ServletFileUpload.isMultipartContent(request)){
ServletFileUpload servletFileUpload = new ServletFileUpload(new DiskFileItemFactory());
List fileItemsList = servletFileUpload.parseRequest(request);
strBuilder.append("<?xml version=\"1.0\" encoding=\"UTF-8\" ?>").append('\r').append('\n').append("<xpage version=\"1.0\">").append('\r').append('\n');
String optionalFileName = "";
FileItem fileItem = null;
Iterator it = fileItemsList.iterator();
ServletOutputStream outputStream=null;
while (it.hasNext()){
   FileItem fileItemTemp = (FileItem)it.next();
%>
Name-value Pair Info:
Field name: <%= fileItemTemp.getFieldName() %><br/>
Field value: <%= fileItemTemp.getString() %><br/>
<%
if (fileItemTemp.getFieldName().equals("filename"))
    optionalFileName = fileItemTemp.getString();
if(!fileTempItem.isFormFiled()){
   String fileName = fileItem.getName();
   fileItem.write(optionalFileName);
%>
Uploaded File Info:
Content type: <%= fileItem.getContentType() %><br/>
Field name: <%= fileItem.getFieldName() %><br/>
File name: <%= fileName %><br/>
<%
if(fileItem.getContentType().equals("image/jpeg") || fileItem.getContentType().equals("image/pjeg")) {
%>
<img src="FileServlet?fileName=<%=optionalFileName%>"
<%
%>
</body>
</html>a sample code snippet for FileServlet.
String fileName = request.getParameter(fileName);
File file = new File(fileName);
   if(!file.exists())
     return;
// If JSP
String mimeType = application.getMimeType("fileName");
       If you are using servlet
       String mimeType = this.getServletContext().getMimeType(fileName);
     response.setContentType(mimeType);
     response.setHeader("Content-Disposition","inline;filename=\\"+fileName+"\\");
BufferedOutputStream out1 = null;
InputStream in = null;
if(mimeType == null)
     mimeType = "application/octet-stream";
try{
     in = new FileInputStream(f);
     response.setContentLength(in.available());
     BufferedOutputStream out1 = new BufferedOutputStream(response.getOutputStream(),1024);
     int size = 0;
     byte[] b = new byte[1024];
     while ((size = in.read(b, 0, 1024)) > 0)
        out1.write(b, 0, size);
}catch(Exception exp){
}finally{
      if(out1 != null){
         try{
            out1.flush();
            out1.close();
         }catch(Exception e){}
      if(in != null){
        try{in.close();}catch(Exception e){}
} Hope that might answer your question :)
However,this is not the recommended way of doing this make use of MVC pattern.Would be a better approach.
you might think of googling on this and can findout what is the best practise followed for problems of this sort
REGARDS,
RaHuL

From browse button of input type=file, can I show the content of a file

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-thanx

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You can ask questions and advice about web development at the mozillaZine Web Development/Standards Evangelism forum.<br />
A good place to ask questions and advice about web development is at the mozillaZine Web Development/Standards Evangelism forum.<br />
The helpers at that forum are more knowledgeable about web development issues.<br />
You need to register at the mozillaZine forum site in order to post at that forum.<br />
See http://forums.mozillazine.org/viewforum.php?f=25

Show file content in jsp

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