Similar row fetch

Question

Hi,
I have created a table 'emp' with three columns 'empno','ename','sal'.
Column 'empno' is of primary key.
Following is the table data :
empno ename     sal
101 emp1 20000
102 emp2 10000
105 emp2 13000
104 emp4 12500
103 emp3 14000
106 emp3 23000
If the table contains 'emp2' as well as 'emp3' then I want to fetch the rows of employees whose ename is 'emp2' and 'emp3'. If only one employee exist then no need to fetch any row.
For the above data if I give input as 'emp2' and 'emp3' the following output should come
102 emp2 10000
105 emp2 13000
103 emp3 14000
106 emp3 23000
Thanks,
Prakash
Edited by: user625058 on Apr 6, 2010 3:17 PM

Answer 1

Another way..
select e.* from emp e,
(select ename from emp group by ename having count(*)  > 1) e1
where e.ename=e1.ename
and e.ename in ('emp2','emp3')
PRAZY@11gR1> /
EMP ENAM SAL
102 emp2 10000
105 emp2 13000
103 emp3 14000
106 emp3 23000
Elapsed: 00:00:00.09or
select empno,ename,sal from (
select e.*,sum(1) over (partition by ename) tot from emp e)
where tot>1
and ename in ('emp2','emp3')
PRAZY@11gR1> /
EMP ENAM SAL
102 emp2 10000
105 emp2 13000
103 emp3 14000
106 emp3 23000
Elapsed: 00:00:00.01Note: Remove and ename in ('emp2','emp3') from where clause if you need to retrieve all the duplicates.
Regards,
Prazy
Edited by: Prazy on Apr 6, 2010 3:41 PM
Added ename in where clause.