Simple number program error

Question

I am trying to create a simple program to input to real numbers and display the largest. This will then be used in a menu selection program that I am creating. I keep getting the error:
---------- Capture Output ----------
"C:\j2sdk1.4.2\bin\javac.exe" SmallestNumber.java
SmallestNumber.java:27: 'else' without 'if'
     else
^
1 error
Terminated with exit code 1
But to me - the code looks correct. Can anyone pick up my error?
I am using the SavitchIn class from the book: "An introduction to computer science" by Walter Savitch
public class SmallestNumber {
    public static void displayNumber() {
        double num1 = 0;
        double num2 = 0;
        float average, count;
        System.out.println("Plese enter a positive number:");
        num1 = SavitchIn.readDouble();
        System.out.println("Please enter a second postive number:");
        num2 = SavitchIn.readDouble();
        if (num1 > num2);
        System.out.println ("The smallest number is: ");
        System.out.println (num2);
         else
             if (num2 > num1);
            System.out.println ("The smallest number is: ");
             System.out.println (num1);
    } //end main
} //end classI have tried including and removing brackets around both if statemetnts.
Any help would be appreciated.
Thankyou

Answer 1

>
if (num1 > num2);
System.out.println ("The smallest number is:
ber is: ");
System.out.println (num2);
     else
     if (num2 > num1);
System.out.println ("The smallest number
lest number is: ");
     System.out.println (num1);What do you mean "the code looks correct" to you????
You have a semicolon after the if statement. Also if you have more than one statement to execute for an "if" condition, you need to enclose them in brackets { and }
Here's the proper code:
         if (num1 > num2) {
           System.out.println ("The smallest number is: ");
           System.out.println (num2);
         } else if (num2 > num1) {
           System.out.println ("The smallest number is: ");
           System.out.println (num1);
         }