Simple regular expression in oracle query

Question

hi guys, I have this challenge.
say I have a query:
select name, user_name, object_type from questions;
now, for the column object type, I can get values that end in 'Q' followed by number.
So object type columns can be 00Q1, ABCQ2, 56Q7 e.t.c. It can be any number really.
The thing is, I want to add a small grouping, so that for the rows which have the object type column ending in Q followed by number, I can have an additional column whose value changes to question.
So the query now becomes:
select name, user_name, object_type, column_type from questions;
So column_type can be question if object type ends with Q and a number, otherwise just give it a default value, like Others or something.
Is this possible and if so how can I please achieve it.
Thanks very much.

Answer 1

Hope this will help.
SQL> with t as
  2  ( select '00Q1' element_name from dual union all
  3    select 'ABCQ2' from dual union all
  4    select '56QA7 ' from dual union all
  5    select '56Q7 ' from dual union all
  6    select 'ABCQA' from dual)
  7  select * from t
  8  where regexp_like(element_name,'\Q[0-9]')
  9  /
ELEMEN
00Q1
ABCQ2
56Q7Or something like this
SQL> with t as
  2  ( select '00Q1' element_name from dual union all
  3    select 'ABCQ2' from dual union all
  4    select '56QA7 ' from dual union all
  5    select '56Q7 ' from dual union all
  6    select 'ABCQA' from dual)
  7  select t.*, DECODE(regexp_instr(element_name,'\Q[0-9]'),0,'Not Found',element_name ) comments
  8  from t
  9  /
ELEMEN COMMENTS
00Q1   00Q1
ABCQ2  ABCQ2
56QA7  Not Found
56Q7   56Q7
ABCQA  Not FoundEdited by: Saubhik on May 18, 2010 6:41 AM