Slow query response

Question

Hi all,
I have an entry here from TKPROF, this is from the production environment. Is there any way that I can make this query run faster?
I would greatly appreciate also if you could explain to me the details of the query below.
SELECT KIB.INT_BASIS_DESC,KBR.INT_BASIS_RATE  
  FROM FM_INT_BASIS KIB,FM_BASIS_RATE KBR 
WHERE KIB.INT_BASIS = :b1 
   AND KBR.INT_BASIS = KIB.INT_BASIS 
   AND KBR.CCY = :b2 
   AND KBR.EFFECT_DATE = (SELECT MAX(EFFECT_DATE)  
                            FROM FM_BASIS_RATE KBR 
                           WHERE KBR.EFFECT_DATE <=
                                 NVL(:b3,:b4) 
                             AND KBR.INT_BASIS = KIB.INT_BASIS 
                             AND KBR.CCY = :b2)
call     count       cpu    elapsed       disk      query    current        rows
Parse        2      0.00       0.00          0          0          0           0
Execute      2      0.01       0.01          0          0          0           0
Fetch        2     21.40      20.91          0     752251          0           2
total        6     21.41      20.92          0     752251          0           2Misses in library cache during parse: 1
Optimizer goal: CHOOSE
Rows     Row Source Operation
      1  FILTER 
   1450   SORT GROUP BY
1925600    CONCATENATION 
      0     FILTER 
      0      TABLE ACCESS BY INDEX ROWID FM_BASIS_RATE
      0       NESTED LOOPS 
      0        NESTED LOOPS 
      0         TABLE ACCESS BY INDEX ROWID FM_INT_BASIS
      0          INDEX UNIQUE SCAN KIB_PK (object id 3474)
      0         INDEX RANGE SCAN KBR_PK (object id 3427)
      0        INDEX RANGE SCAN KBR_PK (object id 3427)
1925600     FILTER 
1925600      TABLE ACCESS BY INDEX ROWID FM_BASIS_RATE
1926929       NESTED LOOPS 
   1328        NESTED LOOPS 
      1         TABLE ACCESS BY INDEX ROWID FM_INT_BASIS
      1          INDEX UNIQUE SCAN KIB_PK (object id 3474)
   1328         INDEX RANGE SCAN KBR_PK (object id 3427)
1925600        INDEX RANGE SCAN KBR_PK (object id 3427)
SELECT KIB.INT_BASIS_DESC,KBR.INT_BASIS_RATE  
  FROM FM_INT_BASIS KIB,FM_BASIS_RATE KBR 
WHERE KIB.INT_BASIS = :b1 
   AND KBR.INT_BASIS = KIB.INT_BASIS 
   AND KBR.CCY = :b2 
   AND KBR.EFFECT_DATE = (SELECT MAX(EFFECT_DATE)  
                            FROM FM_BASIS_RATE KBR 
                           WHERE KBR.EFFECT_DATE <=
                                 NVL(:b3,:b4) 
                             AND KBR.INT_BASIS = KIB.INT_BASIS 
                             AND KBR.CCY = :b2)
Rows     Execution Plan
      0  SELECT STATEMENT   GOAL: CHOOSE
      1   FILTER
   1450    SORT (GROUP BY)
1925600     TABLE ACCESS   GOAL: ANALYZED (BY INDEX ROWID) OF
                'FM_BASIS_RATE'
      0      NESTED LOOPS
      0       NESTED LOOPS
      0        TABLE ACCESS   GOAL: ANALYZED (BY INDEX ROWID) OF 'FM_INT_BASIS'
      0         INDEX   GOAL: ANALYZED (UNIQUE SCAN) OF 'KIB_PK' (UNIQUE)
      0        INDEX   GOAL: ANALYZED (RANGE SCAN) OF 'KBR_PK' (UNIQUE)
      0       INDEX   GOAL: ANALYZED (RANGE SCAN) OF 'KBR_PK' (UNIQUE)Thank you very much!
Message was edited by:
ABS

Answer 1

I don't have the tables here to test with, but you might verify that this query
select int_basis_desc
     , kbr.int_basis_rate
  from ( select kib.int_basis_desc
              , kbr.int_basis_rate
              , max(case when kbr.effect_date <= nvl(:b3,:b4) then kbr.effect_date end)
                over (partition by kbr.int_basis) max_effect_date
              , effect_date
           from fm_int_basis kib
              , fm_basis_rate kbr
          where kib.int_basis = :b1
            and kbr.int_basis = kib.int_basis
            and kbr.ccy = :b2
where effect_date = max_effect_date
/gives the same results as the original query.
If still not satisfied, could you paste an explain plan and tkprof output of the new query?
Regards,
Rob.