Soap response returns gzipped stream

Question

I am accessing a webservice. The webservice returns a gzipped file stream. I am able to succesfully call the webservice and get the expected results, but I am having trouble unzipping and reading the file stream. I have tried using utl_compress.lz_uncompress with no luck (including the code that has been posted to test for FCOMMENT) Below is an example of the response that is returned:
Response> status_code: "200"
Response> reason_phrase: "OK"
Response> http_version: "HTTP/1.1"
Response> length: "153281"
=== Print first 20 lines of HTTP response... ===
[00]: <soap:Envelope xmlns:soap="http://schemas.xmlsoap.
[01]: org/soap/envelope/"><soap:Body><ns1:getClientDbXml
[02]: Response xmlns:ns1="http://service.clientag.ppd.co
[03]: m/"><return><buffer>H4sIAAAAAAAAANS963LjSJIu+H/N9h
[04]: 1g9WOs2k5lVk/X2Yv1dM+xIBAko4QLCwCZpP4cg8hIES0QYOOi
[05]: FPPd1vaR9hXWPUBSlJRNBxw8tntsxqpVlZHxCXHx8Ovnf/tvL7
[06]: vMetZllRb533/6989//snS+brYpPnj33+ax+NP/+dP/+0//9f/
[07]: 5W/LXWa7Svox/Itl/e2l+mu13updYqWbv/90/sOfLJgur/7+0/
[08]: GHv77Az9u63v/111+/ffv2+dtvn4vy8de//PnP//7r0nMjM8Vp
[09]: 7K7aJHXy95+aMj9OXn3apeuyqIqv9ad1sfsrjPvUjvrJ/BrtL6
[10]: IzvdN5beXJTr/5Xdqhf1WVA/8T6frvP9Vlo8//fV5puylL+Ktu
[11]: sU4yffzj48zt3IC6z/RLfNjr838//sm2SNfa2qV5sF43JXwnLN
[12]: 0ueTn9W5M/FE2+0ZufLv7ij37hhQwjFfhvh11Df/3zSv+zgd36
[13]: +IdXcP67cn6yapjx7z/hDHUJO/3Tu8/4tdOEjojljaaKgnlocy
[14]: b726//ehnMn/2rJTR/ePwliA06Hqf/0fvTwtxue47z+cL7//fC
[15]: /ncn8IT6H3/+b72+7a/9P8H6CleJ6H+65W1/6//vF7b9O0bYv7
[16]: 4MP57nwwzt72KeMnxDjxK4/aNXcfyfduyMPsViX1p/+d9+sf7y
[17]: 53//yy/Wn3/765//DP9vSSf+268Xg81fRtH7n9f+ghlghrai9T
[18]: /Haakf0nLjjP726/E/wW90mvg//3b5uJ+38j///bd4KkMxk/O/
[19]: /fr6Xy8H4fGHYfVWl8leN3W6rs5DzZ8hynHyfwHylz//5c8T6c
[20]: todRXkL38GvcGa6FxHh6rWu+oXS+Xrz33RfluMVBDZ8K9X0X77
Any tips/suggestions on how I can get the file stream unzipped and in a readable format?

Answer 1

Any tips/suggestions on how I can get the file stream unzipped and in a readable format?The stream is base64-encoded so you have to decode it first, then you can call LZ_UNCOMPRESS.
This should get you started :
SQL> DECLARE
  2 
  3    v_response   xmltype := xmltype(
  4  '<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  5   <soap:Body>
  6    <ns1:getClientDbXmlResponse xmlns:ns1="http://service.clientag.ppd.com/">
  7     <return>
  8      <buffer>H4sIAAAAAAAAC7Mpys8vsbMpSS0usQtxDQ6x0QczbfTB4gD5B/mWHgAAAA==</buffer>
  9     </return>
10    </ns1:getClientDbXmlResponse>
11   </soap:Body>
12  </soap:Envelope>');
13 
14    v_buffer     varchar2(4000);
15 
16  BEGIN
17 
18    select utl_raw.cast_to_varchar2(
19             utl_compress.lz_uncompress(
20               utl_encode.base64_decode(
21                 utl_raw.cast_to_raw(buffer)
22               )
23             )
24           )
25    into v_buffer
26    from xmltable(
27           xmlnamespaces(
28             'http://schemas.xmlsoap.org/soap/envelope/' as "s"
29           , 'http://service.clientag.ppd.com/' as "ns1"
30           )
31         , '/s:Envelope/s:Body/ns1:getClientDbXmlResponse/return'
32           passing v_response
33           columns buffer varchar2(4000) path 'buffer'
34         )
35    ;
36 
37    dbms_output.put_line(v_buffer);
38 
39  END;
40  /
<root><test>TEST</test></root>
PL/SQL procedure successfully completed