Sort without BY addition & Table Key

Experts,
From SAP Help,
If no explicit sort key is entered using the BY addition, the internal table itab is sorted according to the table key.
I have code as below,
data: lt_vkonto type table of VKONT_KK. "Cont Acc No
"Fetch Cont Acc no against Contract
select vkonto from ever into table lt_vkonto where vertrag = wa_data-vertrag.
if sy-subrc eq 0.
sort lt_vkonto.
endif.
As seen above, I have sort statement without BY addition for internal table lt_vkonto which does not have a UNIQUE or NON UNIQUE key.
Will adding BY addition --> SORT lt_vkonto by vkonto imrpove the performance of sort statement.
Please share your valuable inputs.
BR,
Aspire

Hi
I don't know if you'll imporve the performace in your case, you should do some measurement, the problem should be the table key for a standard internal table (like yours) is the set of all CHAR fields.
In you situation you've only one fields, but probably if the table has several char fields the performance can be improved
Anyway I suppose it's always better to explicit an option else the system will have to deduct it by itself, so the system will do an additional step: in your case without BY, the system has to deduct the key to be used for the sorting.
Max

Similar Messages

How to Freeze Table/Column Header "without using additional scrollbars" ?

hi people,
I am hoping someone can help me here. I have a large table and would like to freeze the first row. Scrolling down the table "_*using the existing scrollbars*_" in the browser while ensuring the header rows are still visible (like Excel when you freeze panes). If you scroll to the right the header rows should stay frozen and not follow.
I know there are other threads which talk about freezing table/column header, but my requirement is to have it "without using additional scrollbar".
Thanks in advance,
RAKESH

Hi,
there is no default key for this. You will have to code your own JavaScript for this. Also, I am not sure you want the column to be selected but a field in the column for the row you are in - correct ?
Frank

Filter in Update (or Transfer) Rules without additional table write

Hi
For filtering out records on a master data attribute in Update Rules (in order to not fill them into Data Target) you can use a start routine like the example blow (from Björn - thanks!)
From the coding I guess that it at least creates and writes into one table.
Is there any way to do this filtering purely in RAM, so the Update Rule just passes on the matching records while simply dropping the filtered records without writing any additional tables than normal during the Update Process?
Full points will be assigned!
Thanks,
German
PROGRAM UPDATE_ROUTINE.
$$ begin of global - insert your declaration only below this line -
TABLES: ...
TABLES: /BI0/PCUSTOMER.
DATA:   ...
DATA: i_t_customer like /BI0/PCUSTOMER occurs 0 with header line.
$$ end of global - insert your declaration only before this line   -
... internal definitions ...
$$ begin of routine - insert your code only below this line        -
fill the internal tables "MONITOR" and/or "MONITOR_RECNO",
to make monitor entries
DATA: i_l_data_package LIKE LINE OF DATA_PACKAGE,
          i_t_data_package LIKE STANDARD TABLE OF DATA_PACKAGE.
select * from /BI0/PCUSTOMER into table i_t_customer.
LOOP AT DATA_PACKAGE.
    MOVE-CORRESPONDING DATA_PACKAGE TO i_l_data_package.
    read table i_t_customer with key
      CUSTOMER = i_l_data_package-CUSTOMER.
    IF sy-subrc = 0.
      IF i_t_customer-COUNTRY = 'DE'.
          APPEND i_l_data_package TO i_t_data_package.
      ENDIF.
    ENDIF.
ENDLOOP.
REFRESH DATA_PACKAGE.
DATA_PACKAGE[] = i_t_data_package.
REFRESH i_t_data_package.
if abort is not equal zero, the update process will be canceled
ABORT = 0.
$$ end of routine - insert your code only before this line         -

Really, if it is your requirement, do the filter in the start routine is less expensive in term of memory consumption and performance.
But I suggest to make a code like this:
select * from /BI0/PCUSTOMER into table i_t_customer.
LOOP AT DATA_PACKAGE.
read table i_t_customer with key
CUSTOMER = DATA_PACKAGE-CUSTOMER.
IF sy-subrc = 0 and i_t_customer-COUNTRY = 'DE'.
No Customer with country DE will be in data target!!!!
delete data_package.
ENDIF.
ENDLOOP.
And no other code!
regards,
Sergio

Sorting Order for SAP Tables in DB2 database

Dear Experts -
ISSUE: When an ABAP program selects data from the DB into an internal
table, it is changing the way the data is sorted. In other words, the
internal table data is in a different sort order than what is in the
DB. It is not working this way in all other non-production systems
(DEV, QAS, SAX, etc).
Temporary solution for the programs that have been identified as
impacted: Use the ABAP Command 'sort' on the internal table.
Permanent solution needed : Since it is impossible to identify all
of the programs that will be impacted, we need PRD to work like DEV,
QAS, SAX, etc. when selecting data into internal tables. The data
should be in the same order as it is in the DB (sorted by the key).
ADDITIONAL INFO: DB2 storage disks crashed a day before. H/W team recovered everything. We are facing this only after the recovery.
Thanks,
Dinesh

can you please check in your code if the sql that is being sent has an order by clause .
Please let us know the SQL statements that is basically used to fill up the internal table.
When data is fetched from the database, it is not sorted always. Probably you had a clustered index on the tables and the clustering is not there now.
Edited by: Ratnajit Dey on Dec 16, 2011 1:56 PM

R3load procedure creates additional tables in the target system

Hi All
My source system is 46C SR2 /oracle 817/HP_UX PARISC and
Target System is 46CSR2 /Oracle 10202/HPUX IA
I used R3load procedure to export database from source system and completed import successfully into target system without any problem.The new system is up and running.
My Source system has total 23193 tables but the target system has 23771 tables and source system has 27011 indexes and the target system has 27701 indexes.
Can someone tell me why there are additional tables and indexes in my Target system.
Your help will be appreciated.
Thanks

I used wrong id.I want to open a new message

Select multple rows in ALV without pressing pressing CTRL key

Hi experts,
Is there any way that I can select multple rows in an ALV without pressing pressing CTRL key?
I am using set_table_for_first_display method for displaying the ALV.
I tried different options of sel_mode, but none of them works without the CTRL key.
Thanks,
Mohit.

Hi,
You can add checkbox using ALV grid display.
Call your ALV grid as below. Pass 'wa_layout' with 'WA_LAYOUT-BOX_FIELDNAME' as your selection column name.
CALL FUNCTION 'REUSE_ALV_GRID_DISPLAY'
      EXPORTING
        I_CALLBACK_PROGRAM       = SY-REPID
        I_CALLBACK_PF_STATUS_SET = 'F_GUI_STATUS'
        I_CALLBACK_USER_COMMAND = 'F_USERCOMMAND'
        I_GRID_TITLE             = TEXT-026
        IS_LAYOUT                = WA_LAYOUT
        IT_FIELDCAT              = I_FIELDCAT
      TABLES
        T_OUTTAB                 = I_OUTTAB
      EXCEPTIONS
        PROGRAM_ERROR            = 1
        OTHERS                   = 2.
Check below link for more help.
[http://www.sapfans.com/forums/viewtopic.php?t=40968]
Thanks,
Archana

How to sort index_by pl/sql tables data in Oracle 9i Release 9.2.0.1.0 ?

Hi all,
I have populated an index_by binary_integer pl/sql table :
declare
type rec_ty is record(ligne number,code_enreg number(2),code_enreg_ordered number(2));
     type tab_ty is table of rec_ty index by binary_integer;
     vtab tab_ty;
     i pls_integer := 1;
begin
for venreg in(select * from fichier_tempo where num > 0 order by num) loop
          vtab(i).ligne := venreg.num;
          vtab(i).code_enreg := to_number(substr(venreg.texte,7,2));
          i := i + 1;
     end loop;
end;
Now I want to sort the code_enreg data of vtab into its code_enreg_ordered field. I must do that because I must verify that each code_enreg data entered are ordered. So if code_enreg is not equal to code_enreg_ordered at a specified index of vtab then I must take a decision in my program code ; I must code something when this disorder happens.
How to do that ?
Thank you very much indeed.

Thank you Jeneesh , it works with a few modifications about the assignement of the pl/sql tables.
Fantasy > Your blog talks about sorting the pl/sql table through the key. But I want to sort it through the field data. And my field data contains duplicated data. So you did not really reply to my need. Thank you anymore.

Convert table keys from random to sequential :: algorithm

Hello
I hope I am at the right forume..
We are using Oracle as our DB.
One of our major data table has random keys. this is due to legacy issues.
This table is getting big and the random access process is slowing the system down.
We want to change the table Id's from random to sequential.
In order to do that we have to change the original Id's to sequential ones.
Our table has 2 columns:
id (number - 10)
value (varchar -1024)
The table contains about 500 million rows (as for now)
this table also has junk records that needs to be deleted.
I am trying to think of a way to convert all the random id values into sequential ones, and change all of their references accordingly.
I tried to look for an algorithm to do that.
Is copying such a table is time consuming?
is there a way to change the id's into sequential ones without copying the table?
I'm a JAVA developer - not a DBA, so I don't really know the "cost" of these actions..
Any Idea would be great
Thanks,
Carol

Has your table a trigger ? A primary key ? Other tables with foreign key references ?
You could probably use an Oracle sequence and update your table, helping within a trigger before update to update the subsequents tables from old to new value. However, since you have millions rows, and the update will have to go through every single row, it will be a slow process.
You could also have a look to the Tom Kyte solution for the update cascade of PK :
http://tkyte.blogspot.com/2009/10/httpasktomoraclecomtkyteupdatecascade.html
Nicolas.

Adding Additional Tables to an Existing Query

Dear All
I have the following tables and relationships:
I have the following query that returns records from the table SENAlert where the StudentID and the TeacherUsername are passed in as parameters.
Also, records are only returned if there isn’t a corresponding record in the SENAlertHistory table (i.e. SENAlertHistorySENAlertID IS NULL).
This query is returning the results that I would expect:
SELECT
SENAlert.SENAlertID, SENAlertType.SENAlertTypeDescription
FROM
SENAlertHistory RIGHT OUTER JOIN
Teacher INNER JOIN
Class ON Teacher.TeacherCode = Class.ClassTeacherCode INNER JOIN
ClassMember INNER JOIN
SENAlert INNER JOIN
SENAlertType ON SENAlert.SENAlertType = SENAlertType.SENAlertTypeID INNER JOIN
Student ON SENAlert.SENAlertStudentID = Student.StudentID ON ClassMember.ClassMemberStudentID = Student.StudentID ON
Class.ClassClassCode = ClassMember.ClassMemberClassCode ON SENAlertHistory.SENAlertHistorySENAlertID = SENAlert.SENAlertID AND
SENAlertHistory.SENAlertHistoryTeacherCode = Teacher.TeacherCode
WHERE
(Student.StudentID = 011763) AND (Teacher.TeacherUsername = 'dsmith') AND (SENAlertHistory.SENAlertHistorySENAlertID IS NULL)
However, I need to extend this query to include additional teachers who may also teach this student. I am trying to add in 3 additional copies of
the Teacher table as Teacher_1, Teacher_3 and Teacher _3 in order to include them in the query also.
However, when I add these tables in I no longer get any results returned.
I have managed to do this on other queries but not this one.
SELECT SENAlert.SENAlertID, SENAlertType.SENAlertTypeDescription
FROM SENAlertHistory INNER JOIN
Teacher ON SENAlertHistory.SENAlertHistoryTeacherCode = Teacher.TeacherCode INNER JOIN
Teacher AS Teacher_1 ON SENAlertHistory.SENAlertHistoryTeacherCode = Teacher_1.TeacherCode INNER JOIN
Teacher AS Teacher_2 ON SENAlertHistory.SENAlertHistoryTeacherCode = Teacher_2.TeacherCode INNER JOIN
Teacher AS Teacher_3 ON SENAlertHistory.SENAlertHistoryTeacherCode = Teacher_3.TeacherCode RIGHT OUTER JOIN
Class INNER JOIN
ClassMember INNER JOIN
SENAlert INNER JOIN
SENAlertType ON SENAlert.SENAlertType = SENAlertType.SENAlertTypeID INNER JOIN
Student ON SENAlert.SENAlertStudentID = Student.StudentID ON ClassMember.ClassMemberStudentID = Student.StudentID ON
Class.ClassClassCode = ClassMember.ClassMemberClassCode ON Teacher_3.TeacherCode = Class.ClassTeacherCode AND
Teacher_2.TeacherCode = Class.ClassTeacherCode AND Teacher_1.TeacherCode = Class.ClassTeacherCode AND
Teacher.TeacherCode = Class.ClassTeacherCode AND SENAlertHistory.SENAlertHistorySENAlertID = SENAlert.SENAlertID
WHERE (Student.StudentID = 011763) AND (SENAlertHistory.SENAlertHistorySENAlertID IS NULL)
AND (Teacher.TeacherUsername = 'admin\dsmith' OR Teacher_1.TeacherUsername = 'admin\dsmith' OR Teacher_2.TeacherUsername = 'admin\dsmith' OR Teacher_3.TeacherUsername = 'admin\dsmith')
No results are returned from this adapted query. I have noticed that by adding the additional tables, it keeps changing the type of joins that I
have between certain tables. I have tried all sorts of combinations but haven't been able to make it work.
I would be really grateful for any advice that you may be able to offer.
Many thanks
Daniel

Dear All
I followed the advice and created the query again from scratch, one table and relationship at a time checking that I am getting the expected result. I have put much of the query back together with the correct output:
SELECT
SENAlert.SENAlertID,
SENAlertType.SENAlertTypeDescription
FROM dbo.SENAlert
INNER JOIN dbo.SENAlertType
ON SENAlert.SENAlertType = SENAlertType.SENAlertTypeID
INNER JOIN dbo.Student
ON SENAlert.SENAlertStudentID = Student.StudentID
INNER JOIN dbo.ClassMember
ON ClassMember.ClassMemberStudentID = Student.StudentID
INNER JOIN dbo.Class
ON ClassMember.ClassMemberClassCode = Class.ClassClassCode
INNER JOIN dbo.Teacher
ON Class.ClassTeacherCode = Teacher.TeacherCode
LEFT OUTER JOIN dbo.Teacher AdditionalTeacher1
ON AdditionalTeacher1.TeacherCode = Class.ClassAdditionalTeacherCode1
LEFT OUTER JOIN dbo.Teacher AdditionalTeacher2
ON AdditionalTeacher2.TeacherCode = Class.ClassAdditionalTeacherCode2
LEFT OUTER JOIN dbo.Teacher AdditionalTeacher3
ON AdditionalTeacher3.TeacherCode = Class.ClassAdditionalTeacherCode3
WHERE Student.StudentID = 011763
AND (Teacher.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher1.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher2.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher3.TeacherUsername = 'admin\dsmith')
The problem arises when I try to add the SENAlertHistory table back in. I only want to show results where a related record does not exist in SENAlertHistory. I have tried every combination of relationship but none have been successful.
I think maybe I need to be using a subquery instead.
Thanks for your help
Daniel
do you mean this?
SELECT
SENAlert.SENAlertID,
SENAlertType.SENAlertTypeDescription
FROM dbo.SENAlert
INNER JOIN dbo.SENAlertType
ON SENAlert.SENAlertType = SENAlertType.SENAlertTypeID
INNER JOIN dbo.Student
ON SENAlert.SENAlertStudentID = Student.StudentID
INNER JOIN dbo.ClassMember
ON ClassMember.ClassMemberStudentID = Student.StudentID
INNER JOIN dbo.Class
ON ClassMember.ClassMemberClassCode = Class.ClassClassCode
INNER JOIN dbo.Teacher
ON Class.ClassTeacherCode = Teacher.TeacherCode
AND NOT EXISTS ( SELECT 1
FROM SENAlertHistory
WHERE SENALertHistoryTeacherCode = Teacher.TeacherCode
AND SENAlertHistorySENAlertID = SENAlert.SENAlertID)LEFT OUTER JOIN dbo.Teacher AdditionalTeacher1
ON AdditionalTeacher1.TeacherCode = Class.ClassAdditionalTeacherCode1
AND NOT EXISTS (SELECT 1
FROM SENAlertHistory
WHERE SENAlertHistoryTeacherCode = AdditionalTeacher1.TeacherCode
AND SENAlertHistorySENAlertID = SENAlert.SENAlertID
LEFT OUTER JOIN dbo.Teacher AdditionalTeacher2
ON AdditionalTeacher2.TeacherCode = Class.ClassAdditionalTeacherCode2
AND NOT EXISTS (SELECT 1
FROM SENAlertHistory
WHERE SENAlertHistoryTeacherCode = AdditionalTeacher2.TeacherCode
AND SENAlertHistorySENAlertID = SENAlert.SENAlertID
LEFT OUTER JOIN dbo.Teacher AdditionalTeacher3
ON AdditionalTeacher3.TeacherCode = Class.ClassAdditionalTeacherCode3
AND NOT EXISTS (SELECT 1
FROM SENAlertHistory
WHERE SENAlertHistoryTeacherCode = AdditionalTeacher3.TeacherCode
AND SENAlertHistorySENAlertID = SENAlert.SENAlertID
WHERE Student.StudentID = 011763
AND (Teacher.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher1.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher2.TeacherUsername = 'admin\dsmith'
OR AdditionalTeacher3.TeacherUsername = 'admin\dsmith')
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

Is it possible to use u2018CALL TRANSACTIONu2019 without a BDC table ?

HIIIIIIIIIIII
Is it possible to use u2018CALL TRANSACTIONu2019 without a BDC table ?
THANKS

Hi,
Yes you can,
CALL TRANSACTION ta { [AND SKIP FIRST SCREEN] .
This addition suppresses the display of a screen of the initial dynpro of a called dialog transaction. The addition AND SKIP FIRST SCREEN suppresses the first screen under these prerequisites:
For the initial dynpro, in the Screen Painter the own dynpro number must not be specified as the next screen number.
All mandatory input fields of the initial dynpro must be filled completely and with the correct values by the SPA/GPA parameters
If these prerequisites are met, that screen of the dynpro is displayed that is specified in the Screen Painter as the next dynpro of the initial dynpro.
Regards
Jana

What is the difference between READ TABLE ITAB WITH KEY and TABLE KEY

Hi Experts,
what is the difference between
READ TABLE <ITAB> WITH KEY <K1> = <C1>
<Kn> = <Cn> .
and
READ TABLE <ITAB> WITH TABLE KEY <K1> = <C1>
<Kn> = <Cn> .
Thanks
Akash.

Hi akashdeep,
Nice question. I also tried to find out, but no much success. My opinion is that for practical purposes there is no difference.
It may have difference in case of searching, especially sorted tables. (binary search or normal linear search).
Case1: If our table is sorted table with defined key fields, and we give WITH TABLE KEY, then faster binary search is used.
Case2 : If our table is sorted table with defined key fields, and we give WITH KEY, (and no field contained in the keys), then normal linear search is used.
regards,
amit m.

Differences between Standard , sorted and hashed internal tables

Can any body please tell me what are the main Differences between
1) Standard internal table
2) Hashed internal table
3) Sorted internal table
Please give me a clear idea about these Three.
Thanks
Prabhudutta

Hi,
Standard Internal Tables
Standard tables have a linear index. You can access them using either the index or the key. If you use the key, the response time is in linear relationship to the number of table entries. The key of a standard table is always non-unique, and you may not include any specification for the uniqueness in the table definition.
This table type is particularly appropriate if you want to address individual table entries using the index. This is the quickest way to access table entries. To fill a standard table, append lines using the (APPEND) statement. You should read, modify and delete lines by referring to the index (INDEX option with the relevant ABAP command). The response time for accessing a standard table is in linear relation to the number of table entries. If you need to use key access, standard tables are appropriate if you can fill and process the table in separate steps. For example, you can fill a standard table by appending records and then sort it. If you then use key access with the binary search option (BINARY), the response time is in logarithmic relation to
the number of table entries.
Sorted Internal Tables
Sorted tables are always saved correctly sorted by key. They also have a linear key, and, like standard tables, you can access them using either the table index or the key. When you use the key, the response time is in logarithmic relationship to the number of table entries, since the system uses a binary search. The key of a sorted table can be either unique, or non-unique, and you must specify either UNIQUE or NON-UNIQUE in the table definition. Standard tables and sorted tables both belong to the generic group index tables.
This table type is particularly suitable if you want the table to be sorted while you are still adding entries to it. You fill the table using the (INSERT) statement, according to the sort sequence defined in the table key. Table entries that do not fit are recognised before they are inserted. The response time for access using the key is in logarithmic relation to the number of
table entries, since the system automatically uses a binary search. Sorted tables are appropriate for partially sequential processing in a LOOP, as long as the WHERE condition contains the beginning of the table key.
Hashed Internal Tables
Hashes tables have no internal linear index. You can only access hashed tables by specifying the key. The response time is constant, regardless of the number of table entries, since the search uses a hash algorithm. The key of a hashed table must be unique, and you must specify UNIQUE in the table definition.
This table type is particularly suitable if you want mainly to use key access for table entries. You cannot access hashed tables using the index. When you use key access, the response time remains constant, regardless of the number of table entries. As with database tables, the key of a hashed table is always unique. Hashed tables are therefore a useful way of constructing and
using internal tables that are similar to database tables.
Regards
Sudheer

Recovery mode without command or windows keys

Hello,
I am a mac newbie, but experienced linux and windows user. I am trying to restore my mac mini (mid 2011) running mavericks. The process should normally be very simple; press command-R keys while booting to start recovery mode and go from there.
Unfortunately my keyboard is a palm-sized keyboard without command or windows keys. So I am stuck. I have 2 windows laptops that I can use to remote login but I cannot do remote login during boot.
I tried mapping the Command key to Ctrl key inside OS X, but it seems like this only works after reboot.
I tried to use recovery disk assistant as it requires "Option" key, but the assistant does not allow me select the HD, as I guess I do not have a recovery system on the HD.
I tried doing network install, but it requires the install CD, which I don't have.
Can you help me get out of this situation? I have an ipad and two iphones if it helps.
Thanks!

I tried to use recovery disk assistant as it requires "Option" key, but the assistant does not allow me select the HD, as I guess I do not have a recovery system on the HD.
If you mean holding down the OPTION (alt) key during restart, that takes you to the Startup Manager. AFAIK, there's no recovery disk assistant app in OS X. If you can't do that, then get an Apple keyboard. Without a recovery HD, you'll have to reinstall the OS.

Sorting not working if table linked to another table

Got a table with student marks:
Table 1 student
mark
A
98
B
79
C
82
if I copy/paste the marks to another table then sort (ascending, sort by B entire table), it is sorting as expected:
Table 2 student
Mark
B
79
C
82
A
98
if instead I go in Table 2 and enter a formula in B2 to get the mark from table 1 (=Table1::B2), fill down the cells, Table 2 will not sort correctly and output this instead!!!!:
Table 2 student
Mark
B
98
C
79
A
82
Yet another bug and it got submitted to Apple but if more users complain as well (using Provide Numbers Feedback), we might finally get Apple to release a bug-free version of Numbers that works as well as Excel for such basic tasks.

squarebox is styled in three different places
http://mljdesigns.com.au/Beaumaris%20North_2-2013/index-beaunps4.css line#513
http://mljdesigns.com.au/Beaumaris%20North_2-2013/index-beaunps4.css line#623
In the main document line#10
I do noy know if this has anything to do with your problem as I cannot fault the position of the image.
You may also want to have a look at line#104 of the main document where there is a stray ending division tag.

How to display ICONS in normal report without using icons table

Hi Friends,
I have to display icons(traffic lights) in a normal report.
Can we do that without using icons table?
If yes, please let me know how?
Thanks,

Hi Pagidala,
Go to txcode - ABAPDOCU and in that expand BC-ABAP Programming->ABAP User Dialog->Screens->complex screen elements->status icons on Screens.
In this you can see sample code which may help you.
Cheers!!

Sort without BY addition & Table Key

Similar Messages

Maybe you are looking for