Sorting XML nodes in Java

I have a java code that reads various xml files, filters cetain elements and writes the results of these files to one large xml file. Problem is, when the files are read into the large xml, all the nodes are sorted alphabetically. I tried looking for an API that's responsible for this but I cant find one. Can anyone please help?? Here's the portion of my code that writes the file:
         private static void writeFile(Document doc, ArrayList docIdList,
               BufferedWriter output) {
          try {
               Element loElmt = null;
               NodeList loDocumentList = XMLUtil.getNodeList(doc,
                         "/XML_EXPORT_FILE/DOCUMENT");
               for (int i = 0; i < loDocumentList.getLength(); i++) {
                    Element loDocument = (Element) loDocumentList.item(i);
                    String lsDocCode = loDocument.getAttribute("DOC");
                    String lsDocId = loDocument.getAttribute("DOCS");
                    //System.out.println(lsDocCode + "\t\t" + lsDocId);
                    // doc identifer is in list
                    if (isDocInList(docIdList, lsDocCode, lsDocId)) {
                         String document = XMLUtil.transformToString(loDocument);
                         System.out.println("Writing " + lsDocCode + "\t\t"
                                   + lsDocId + " to output file");
                         output.write(document);
          } catch (Exception e) {
               e.printStackTrace();
          }

Similar Messages

XML: sorting XML nodes

How would I sort a bunch of XML nodes? I don't necessarily
need to change the existing structure, but I do need to iterate
through in a specific order. In AS2 I would use the childNodes
array and use Array.sort.

And here's a attribute sort function from
http://freerpad.blogspot.com/2007/07/more-hierarchical-sorting-e4x-xml-for.html.
var xml:XML =
<root>
<node id="2">alpha</node>
<node id="3">delta</node>
<node id="5">bravo</node>
<node id="0">foxtrot</node>
<node id="1">echo</node>
<node id="4">charlie</node>
</root>
sortXmlAttribute(xml,"id",true, Array.CASEINSENSITIVE);
trace(xml)
function sortXmlAttribute
( avXml :XML,
avAttributeName :String,
avPutEmptiesAtBottom :Boolean,
avArraySortArgument0 :* = 0,
avArraySortArgument1 :* = 0 )
:void
var lvChildrenCount:int
= avXml.children().length();
if( lvChildrenCount == 0 )
return;
if( lvChildrenCount > 1 )
var lvAttributeValue :String;
var lvXml :XML;
var lvSortOptions:int
= avArraySortArgument0 is Function
? avArraySortArgument1 : avArraySortArgument0;
var lvSortCaseInsensitive:Boolean
= ( lvSortOptions & Array.CASEINSENSITIVE )
== Array.CASEINSENSITIVE;
var lvArray:Array = new Array();
for each( lvXml in avXml.children() )
lvAttributeValue
= lvXml.attribute( avAttributeName );
if( lvSortCaseInsensitive )
lvAttributeValue
= lvAttributeValue.toUpperCase();
if( lvArray.indexOf( lvAttributeValue ) == -1 )
lvArray.push( lvAttributeValue );
} // for each
if( lvArray.length > 1 )
lvArray.sort
avArraySortArgument0,
avArraySortArgument1
if( avPutEmptiesAtBottom )
if( lvArray[0] == "" )
lvArray.push( lvArray.shift() );
} // if
} // if
var lvXmlList:XMLList = new XMLList();
for each( lvAttributeValue in lvArray )
for each( lvXml in avXml.children() )
var lvXmlAttributeValue:String
= lvXml.attribute( avAttributeName );
if( lvSortCaseInsensitive )
lvXmlAttributeValue
= lvXmlAttributeValue.toUpperCase();
if( lvXmlAttributeValue == lvAttributeValue )
lvXmlList += lvXml;
} // for each
} // for each
avXml.setChildren( lvXmlList );
} // if
for each( var lvXmlChild:XML in avXml.children() )
sortXmlAttribute
lvXmlChild,
avAttributeName,
avPutEmptiesAtBottom,
avArraySortArgument0,
avArraySortArgument1
} // for each
} // sortXmlAttribute

Sort Xml nodes

I want to find the XML entry with the highest votes. then
append that <song> to another file. Every 2 Minutes.
my xml is
<?xml version="1.0" encoding="utf-8"?>
<files>
<song>
<songID>1</songID>
<name>Is This It</name>
<artist>The Strokes</artist>
<album>This is It</album>
<genre>Unknown</genre>
<bitrate>224 </bitrate>
<length>2:35 </length>
<filename>01 Is This It.mp3</filename>
<votes>0</votes>
<played>0</played>
</song>
obviously this needs to be done with a timer in
actionscript.

I want to find the XML entry with the highest votes. then
append that <song> to another file. Every 2 Minutes.
my xml is
<?xml version="1.0" encoding="utf-8"?>
<files>
<song>
<songID>1</songID>
<name>Is This It</name>
<artist>The Strokes</artist>
<album>This is It</album>
<genre>Unknown</genre>
<bitrate>224 </bitrate>
<length>2:35 </length>
<filename>01 Is This It.mp3</filename>
<votes>0</votes>
<played>0</played>
</song>
obviously this needs to be done with a timer in
actionscript.

ANN: Oracle XML Parser for Java v2.0.0.1

A new maintenance release of the Oracle Parser for Java is
available for download. It has the following fixes and changes:
Bug fixes for #920536, i.e. Cannot access element attributes via
XSLT; #898423. i.e. ElementDecl's in DTDs; #774774, i.e. DOM
extensions using XSL pattern matching; #863890 i.e. SAX
IOException not thrown.
New APIs in the following new interface:
1. oracle.xml.parser.v2.NSResolver
- resolveNamespacePrefix( find the namespace definition in scope
for a given namespace prefix )
New APIs in the following classes:
1. oracle.xml.parser.v2.XMLNode
- selectNodes( Selects nodes from the tree which match the given
pattern; client can provide an NSResolver implementation to
resolve namespace prefixes in the pattern ).
2. oracle.xml.parser.v2.ElementDecl
- getParseTree( Returns the root Node of Content Model parse
tree, which could then be traversed node by node using
getFirstChild() and getLastChild(). The Node types are: PLUS,
COMMA, ASTERISK, ELEMENT, QMARK ).
This is the first beta patch release for v2.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
null

unzip -l appsborg2.zip | grep 9.0.4
0 04-18-03 20:10 .xdkjava_version_9.0.4.0.0_production
do i still need to do that step?No, you do not have to since "XML Parser for Java v9.0.4" is already installed as part of appsborg2.zip

Create dynamically xml file from java.

Hi all,
I got class information in java program. I have to put method name and return type into xml. The xml file is like this and i have created this file.
<method>
<name></name>
<returnType></returnType>
</method>
Now when I get method information I want to put it in xml, not by writing each method name explicitly in file, mean i have to load this xml into memory for that what should i do?
Please help me I am new in XML.
Thanks in advance.
-regards
bunty

If you save your XML file as "methodinfo.xml", you can use the following code:import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
try {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder parser = factory.newDocumentBuilder();
Document doc = parser.parse(new File("methodinfo.xml"));
Node nameNode = doc.getElementsByTagName("name").item(0);
Node returnTypeNode = doc.getElementsByTagName("returnType").item(0);
nameNode.setTextContent("the name of the method");
returnTypeNode.setTextContent("the return type of the method");
DOMSource source = new DOMSource(doc);
StreamResult result = new StreamResult(System.out);
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
System.out.println("This is the content of the XML document:\n");
transformer.transform(source, result);
catch (Exception e){
...The content of the XML document will be displayed as follows:<?xml version="1.0" encoding="UTF-8" ?>
<method>
<name>the name of the method</name>
<returnType>the return type of the method</returnType>
</method>

ANN: XML Parser for Java v2.0.2.6

The v2.0.2.6 of the XML Parser for Java is now available for download. The following features and bug fixes are included:
Changes:
Conformance to the XSLT/XPATH October REC.
New API in XSLStylesheet class:
removeParam(String param)
resetParams()
Bug fixes:
Bug #1111423: OutOfMemory exception, if multiple calls made to document()
Bug #1101028: Unexpected character error in DTD parsing document using Docbook DTD
Bug #1101021: #default not supported in exclude-result-prefixes
Bug #1099830: Extra characters inserted into output using the XML Parser
Bug #1099663: HTML output does not allow only doctype-public to be specified
Bug #1099536: HTML output does not disable escaping for script, style unless lowercase
Bug #1098738: ArrayOutOfBoundsException xsl:if test="not(@a)'"
Bug #1095047: XSLProcessor NPE'S on named templates with non-empty namespaces
Bug #1094971: XSLStylesheet needs methods for removing parameters
Bug #1092351: Using valueof() shuffles order of elements in my source document
Bug #1086663: xsl:sort data-type attribute can now be a namespace-prefixed name
Bug #1086661: xsl:version attribute now required on literal result element
Bug #1064692: Default xml-serialization should use empty-element syntax
Bug #1064689: Current() function doesn't work correctly
This is the sixth production patch release for v2.
Oracle XML Team http://technet.oracle.com
Oracle Technology Network
null

The link has been fixed. You will go to the v2 download page
now. Sorry for the inconvience.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Renilton Oliveira (guest) wrote:
: I didn't find the file for version 2.0.0.0 as well.
: Renilton
: Andrei Filimonov (guest) wrote:
: : I tried to download XML Parser for Java v2 it seems that
only
: v
: : 1.0.1.4 is available. Could you please give an exact URL for
: v2
: : download?
: : Andrei Filimonov
: : Oracle XML Team wrote:
: : : The Oracle XML v2 parser is now available for download
here
: as
: : : an early beta release and is written in Java. It features
: an
: : : improved architecture over the Oracle XML v1 parser and
has
: : : shown better performance on small to large XML documents.
: It
: : : will also be able to format the XML document according to
a
: : : stylesheet, having integrated an XSLT processor.
: : : Version 2 of the XML Parser for Java, besides
incorporating
: an
: : : XSLT processor, has been re-architected from version 1.
This
: : has
: : : resulted in a number of changes to the class names
: especially
: : : those that support Namespaces. See v2changes.txt and
: the .diff
: : : difference files in the sample directory.
: : : Oracle XML Team
: : : http://technet.oracle.com
: : : Oracle Technology Network
null

How to write as XML file using java 1.5

hi all,
i am trying to create an XML file using java 1.5. I took a XML creating java file which was working with java 1.4 and ported same file into java 1.5 with changes according to the SAX and DOM implmentation in java 1.5 and tried to compile. But while writing as a file it throws error "cannot find the symbol."
can any body help me out to solve this issue.......
thankx in advance
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.w3c.dom.NamedNodeMap;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.DocumentHandler;
import org.xml.sax.InputSource;
import org.xml.sax.helpers.ParserFactory;
import java.io.*;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
               dbf.setNamespaceAware(true);
DocumentBuilder db = dbf.newDocumentBuilder();
Document xmlDoc = db.newDocument();
// this creates the xml document ref
// parent node reference
Element rootnd = (Element) xmlDoc.createElement("ALL_TABLES");
// root node
xmlDoc.appendChild(rootnd);
Element rownd = (Element) xmlDoc.createElement("ROW");
rootnd.appendChild(rownd);
Element statusnd = (Element) xmlDoc.createElement("FILE_STATUS");
rownd.appendChild(statusnd);
statusnd.appendChild(xmlDoc.createTextNode("Y")
FileOutputStream outpt = new FileOutputStream(outdir + "//forbranch.xml");
Writer outf = new OutputStreamWriter(outpt, "UTF-8");
//error is occuring here Since write method is not available in the Document class
xmlDoc.write(outf);
outf.flush();

Hi,
when I look in the JDK1.4.2 specification I don't see any write method in the Document interface.
However, your solution is the Transformer class. There you transform your DOM tree into any output you need. Your code sould look something like this:     TransformerFactory tf = TransformerFactory.newInstance();
     // set all necessary features for your transformer -> see OutputKeys
     Transformer t = tf.newTransformer();
     t.transform(new DOMSource(xmlDoc), new StreamResult(file));Then you have your XML file stored in the file system.
Hope it helps.

Wrong XML parsing in Java 6.0 , the same code works fine with Java 5.0

I have the following xml data in a file ( C:\_rf\jrebug.xml ) :
<?xml version="1.0" encoding="UTF-8"?>
<rs>
     <data
          input3='aa[1]'
          input4='bb[1]'
          input6='cc[2]'
          input8='dd[7]'
          output2='ee[7]'
          output4='ff[511]'
          output6='gg[15]'
          output7='hh[1]'
     />
</rs>
I have the following code to parse this XML data :
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.xml.sax.SAXException;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXParseException;
public class DomParserBug {
     Document dom;
     public void runExample() {
parseXmlFile("C:\\_rf\\jrebug.xml");
          parseDocument();
     private void parseXmlFile(String filename){
          //get the factory
          DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
          //dbf.setValidating(true);
dbf.setValidating(false);
          try {
               //Using factory get an instance of document builder
               DocumentBuilder db = dbf.newDocumentBuilder();
               db.setErrorHandler(new MyErrorHandler());
               //parse using builder to get DOM representation of the XML file
               dom = db.parse(filename);
          }catch(ParserConfigurationException pce) {
               pce.printStackTrace();
          catch(SAXParseException spe) {
               spe.printStackTrace();
          catch(IOException ioe) {
               ioe.printStackTrace();
          catch(SAXException se) {
               se.printStackTrace();
private void parseDocument()
Element docEle = dom.getDocumentElement();
NodeList nl = docEle.getElementsByTagName("data");
if(nl != null && nl.getLength() > 0)
for(int i = 0 ; i < nl.getLength();i++)
Element el = (Element)nl.item(i);
NamedNodeMap attrsssss = el.getAttributes();
for (int ii=0; ii<attrsssss.getLength(); ++ii)
Node attr = attrsssss.item(ii);
System.out.println("Attribute name is =" attr.getNodeName() " AND Attribute value is ="+attr.getNodeValue());
     public static void main(String[] args){
          DomParserBug dpe = new DomParserBug();
          dpe.runExample();
     class MyErrorHandler implements ErrorHandler {
          public void error(SAXParseException e) {
          System.out.println("error : " +e.toString());
     // This method is called in the event of a non-recoverable error
     public void fatalError(SAXParseException e) {
     System.out.println("fatalError : " +e.toString());
     // This method is called in the event of a warning
     public void warning(SAXParseException e) {
     System.out.println("warning : " +e.toString());
The parsed output is :
Attribute name is =input3 AND Attribute value is =aa[1]
Attribute name is =input4 AND Attribute value is =bb[1]
Attribute name is =input6 AND Attribute value is =cc[2]
Attribute name is =input8 AND Attribute value is =dd[7]
Attribute name is =output2 AND Attribute value is =ee[7]
Attribute name is =output4 AND Attribute value is =ff[511]
Attribute name   is =output6 AND Attribute value is =hh[1]]
Attribute name   is =output7 AND Attribute value is =hh[1]
THE LAST TWO LINES ARE SIMPLY WRONG.
With java 5.0 the last two lines are parsed correctly :
Attribute name   is =output6 AND Attribute value is =gg[15]
Attribute name   is =output7 AND Attribute value is =hh[1]
I have seen this issue only after I upgraded to java 6.0. I have searched the java 6.0 bug database but there is nothing there.
I have also submitted a bug to the bugdatabase last month but have not heared anything.
Anybody have any clue about this ???
Thanks
Edited by: skaushik on Jan 4, 2008 12:40 AM
Edited by: skaushik on Jan 4, 2008 6:38 PM

I have seen similar issue. I found that if you remove the square brackets from the first line in teh XML file, the last two lines are parsed correctly.
Replace the follwing line : :
Attribute name is =input3 AND Attribute value is =aa[1]
with :
Attribute name is =input3 AND Attribute value is =aa
and the output is CORRECT :
Attribute name is =input3 AND Attribute value is =aa
Attribute name is =input4 AND Attribute value is =bb[1]
Attribute name is =input6 AND Attribute value is =cc[2]
Attribute name is =input8 AND Attribute value is =dd[7]
Attribute name is =output2 AND Attribute value is =ee[7]
Attribute name is =output4 AND Attribute value is =ff[511]
Attribute name   is =output6 AND Attribute value is =gg[15]
Attribute name   is =output7 AND Attribute value is =hh[1]

Xml in JTree: how to not collpase JTree node, when renaming XML Node.

Hi.
I'm writing some kind of XML editor. I want to view my XML document in JTree and make user able to edit contents of XML. I made my own TreeModel for JTree, which straight accesses XML DOM, produced by Xerces. Using DOM Events, I made good-looking JTree updates without collapsing JTree on inserting or removing XML nodes.
But there is a problem. I need to produce to user some method of renaming nodes. As I know, there is no way to rename node in w3c DOM. So I create new one with new name and copy all children and attributes to it. But in this way I got a new object of XML Node instead of renamed one. And I need to initiate rebuilding (treeStructureChanged event) of JTree structure. Renamed node collapses. If I use treeNodesChanged event (no rebuilding, just changes string view of JTree node), then when I try to operate with renamed node again, exception will be throwed.
Is there some way to rename nodes in my program without collpasing JTree?
I'am new to Java. Maybe there is a method in Xerces DOM implementation to rename nodes without recreating?
Thanks in advance.

I assume that "rename" means to change the element name? Anyway your question seems to be "When I add a node to a JTree, how do I make sure it is expanded?" This is completely concerned with Swing, so it might have been better to post it in the Swing forum, but if it were me I would do this:
1. Copy the XML document into a JTree.
2. Allow the user to edit the document. Don't attempt to keep an XML document or DOM synchronized with the contents of the JTree.
3. On request of the user, copy the JTree back to a new XML document.
This way you can "rename" things to the user's heart's content without having the problem you described.

XML parsers in JAVA

Hi all,
I need to parse XML files in JAVA. Is there any specific package in java for XML parsing?

Example for using DOM :
import java.io.File;
import javax.xml.parsers.*;
import org.w3c.dom.*;
// using DOM
public class ParseXML_Dom {
    public static void main(String[] args) {
        File file = new File("test.xml");
        try {
            DocumentBuilder builder =
                    DocumentBuilderFactory.newInstance().newDocumentBuilder();
            Document doc = builder.parse(file);
            NodeList nodes = doc.getElementsByTagName("topic");
            for (int i = 0; i < nodes.getLength(); i++) {
                Element element = (Element) nodes.item(i);
                NodeList title = element.getElementsByTagName("title");
                Element line = (Element) title.item(0);
                System.out.println("Title: " + getCharacterDataFromElement(line));
                NodeList url = element.getElementsByTagName("url");
                line = (Element) url.item(0);
                System.out.println("Url: " + getCharacterDataFromElement(line));
        } catch (Exception e) {
            e.printStackTrace();
     The file "text.xml" might contain this :
<?xml version="1.0"?>
<howto>
<topic>
      <title>Searching</title>
      <url>http://www.google.com</url>
</topic>
    <topic>
      <title>Masturbation</title>
      <url>http://www.jackinworld.com</url>
</topic>
      <topic>
        <title>Shopping</title>
        <url>http://www.amazon.com</url>
</topic>
      <topic>
        <title>Sound</title>
        <url>http://www.dailywav.com</url>
</topic>
</howto>
    public static String getCharacterDataFromElement(Element e) {
        Node child = e.getFirstChild();
        if (child instanceof CharacterData) {
            CharacterData cd = (CharacterData) child;
            return cd.getData();
        return "?";
}

How to sort Jtree node?

Now, I want to sort tree node by increasing.
for example there are three child node:
[20 -40][
10 - 20]
[30- 60].
they are added to JTree node by different order.but are shown in increasingorder.
like this:
[10 - 20]
[20 -40][
[30- 60].
how to control tree node.

Implement the Comparable interface in t he userobject class and possibly the toString(0 as well.
Ex.
public class UserObject implements java.lang.Comparable{
public int compareTo(Object obj) throws ClassCastException
public String toString()

ANN: XML Parser for Java v2.0.2.5

The v2.0.2.5 of the XML Parser for Java is now available for
download. The following features and bug fixes are included:
Conformance to the XSLT/XPATH October PR.
Support for internationalized error messages has been added. The
locale can be set using setLocale(java.util.Locale) function in
XSLProcessor, SAXParser, and DOMParser.
New APIs in XMLNode class:
value-of(String pattern)
selectNodes(String pattern)
selectSingleNode(String pattern)
selectSingleNode(String pattern, NSResolver ns)
New API in XSLStylesheet class
setParam(String param, String value)
Bug fixes:
Bug #957465: Missing a way to set stylesheet-level param-
variables
Bug #962290: selectNodes() improvements
Bug #1033472: Html output prints empty elements for non-empty
elements
Bug #1040717: Character entity for greater that in html output
style
Bug #1046003: Bug is parsing text nodes larger than 16K
Bug #1051671: 'xsl:namespace-alias' not supported
Bug #1052387: Disable-output-escaping doesn't flush while
printing
Bug #1053273: 'xsl:message' terminate attribute not supported
Bug #1058004: No access to media-type and encoding on xsl:output
Bug #1058008: xsl:version attribute not copied to result
Bug #1061159: Exclude-result-prefixes not supported
Bug #1067965: Bug in Non-validating parser while reading QNames
in DTD
This is the fifth production patch release for v2.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
null

The link has been fixed. You will go to the v2 download page
now. Sorry for the inconvience.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Renilton Oliveira (guest) wrote:
: I didn't find the file for version 2.0.0.0 as well.
: Renilton
: Andrei Filimonov (guest) wrote:
: : I tried to download XML Parser for Java v2 it seems that
only
: v
: : 1.0.1.4 is available. Could you please give an exact URL for
: v2
: : download?
: : Andrei Filimonov
: : Oracle XML Team wrote:
: : : The Oracle XML v2 parser is now available for download
here
: as
: : : an early beta release and is written in Java. It features
: an
: : : improved architecture over the Oracle XML v1 parser and
has
: : : shown better performance on small to large XML documents.
: It
: : : will also be able to format the XML document according to
a
: : : stylesheet, having integrated an XSLT processor.
: : : Version 2 of the XML Parser for Java, besides
incorporating
: an
: : : XSLT processor, has been re-architected from version 1.
This
: : has
: : : resulted in a number of changes to the class names
: especially
: : : those that support Namespaces. See v2changes.txt and
: the .diff
: : : difference files in the sample directory.
: : : Oracle XML Team
: : : http://technet.oracle.com
: : : Oracle Technology Network
null

XML Parser for Java v2. Applying XSLT to DOM tree

I encountered pretty weird behavior of XML Parser for Java v2.
While applying XSLT to XML document created in memory using DOM
interface I couldn't access element attributes. For example,
given the XML document:
<root>
<Item ID="00001">Value of Item 00001</Item>
<Item ID="00002">Value of Item 00002</Item>
</root>
and XSLT:
<xsl:template match="/">
<HTML>
<HEAD>
<TITLE>XSLT Test</TITLE>
</HEAD>
<BODY>
<xsl:for-each select="/Error">
<H1>Error</H1><xsl:value-of select="."/>
</xsl:for-each>
<TABLE border="0" cellspacing="0" cellpadding="2">
<TBODY>
<xsl:for-each select="/root">
<TR>
<TH style="background-color:khaki">
<xsl:text>Attribute</xsl:text>
</TH>
<TH style="background-color:khaki">
<xsl:text>Value</xsl:text>
</TH>
</TR>
<xsl:for-each select="Item">
<TR>
<TD><xsl:value-of select="@ID"/></TD>
<TD><xsl:value-of select="."/></TD>
</TR>
</xsl:for-each>
</xsl:for-each>
</TBODY>
</TABLE>
</BODY>
</HTML>
</xsl:template>
If I build DOM tree by parsing XML file the resulting HTML
document after applying XSLT will display
Attribute Value
00001 Value of Item 00001
00002 Value of Item 00002
But if I build DOM tree using following code:
XMLDocument xDoc = new XMLDocument();
Element root = xDoc.createElement( "root" );
xDoc.appendChild( root );
Element elem = xDoc.createElement( "Item" );
elem.setAttribute( "ID", "00001" );
root.appendChild( elem ).
appendChild( xDoc.createTextNode( "Value of Item 00001" ) );
elem = xDoc.createElement( "Item" );
elem.setAttribute( "ID", "00002" );
root.appendChild( elem )
.appendChild( xDoc.createTextNode( "Value of Item 00002" ) );
the same XSLT will produce the following HTML output:
Attribute Value
Value of Item 00001
Value of Item 00002
So the value for the ID attribute is not displayed. At the same
time I can access this attribute using DOM interface. For
example, following code
NodeList nList = xDoc.getElementsByTagName( "Item" );
Element e;
for( int i = 0; i < nList.getLength(); i++ )
e = (Element)nList.item( i );
System.out.println( "ID: " + e.getAttribute( "ID" ) );
produces an output
ID: 00001
ID: 00002
Here is the code for applying XSLT to DOM tree:
DOMParser parser = new DOMParser();
parser.parse( new FileInputStream( "test.xsl" ) );
XMLDocument xsldoc = parser.getDocument();
XSLStylesheet xsl = new XSLStylesheet( xsldoc, createURL( "" ) );
XMLDocument out = new XMLDocument();
out.appendChild( new XSLProcessor().processXSL(xsl, xDoc) );
out.print( new FileOutputStream( "test.html" ) );
Andrei Filimonov
null

We are not getting what you're getting on Solaris. See the
following:
Script started on Tue Jun 22 18:53:56 1999
Processing /view/test/vobs/oracore3/.ndeprodrc.csh
Processing /private/.nderc.csh
[test] > cat bruno.xml
<my_grandpa age="88">
<my_dad age="66">
<me age="44">
<my_son age="22">
</my_son>
</me>
</my_dad>
</my_grandpa>
[test] > cat bruno.xsl
<?xml version="1.0"?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/XSL/Transform/1.0">
<xsl:template match="me">
<xsl:value-of select="my_son/@age"/>
<xsl:value-of select="@age"/>
<xsl:value-of select="../@age"/>
<xsl:value-of select="../../@age"/>
</xsl:template>
</xsl:stylesheet>
[test] > java XSLSample bruno.xsl bruno.xml
<root>
22446688
</root>
[test] > exit
script done on Tue Jun 22 18:54:22 1999
What platform are you on and does your stylesheet and xml doc
match ours?
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Bruno Bontempi (guest) wrote:
: I had a similar problem in accessing element attributes from
an
: XSLT sheet.
: It seems like the processor correctly accesses element
attributes
: in the context node, but does not retrieve values of
attributes
: outside the context node.
: For example, for an XML document like:
: <my_grandpa age="88">
: <my_dad age="66">
: <me age="44">
: <my_son age="22">
: </my_son>
: </me>
: </my_dad>
: </my_grandpa>
: and an XSL stylesheet like:
: <xsl:template match="me">
: <xsl:value-of select="my_son/@age"/>
: <xsl:value-of select="@age"/>
: <xsl:value-of select="../@age"/>
: <xsl:value-of select="../../@age"/>
: </xsl:template>
: I expect an output like:
: 22446688
: but all I get is
: 44
: I am also using Jim Clark's XT, which is returning the
expected
: result.
: Thanks in advance for your help,
: Bruno.
: Andrei Filimonov (guest) wrote:
: : I encountered pretty weird behavior of XML Parser for Java
v2.
: : While applying XSLT to XML document created in memory using
DOM
: : interface I couldn't access element attributes. For example,
: : given the XML document:
: : <root>
: : <Item ID="00001">Value of Item 00001</Item>
: : <Item ID="00002">Value of Item 00002</Item>
: : </root>
: : and XSLT:
: : <xsl:template match="/">
: : <HTML>
: : <HEAD>
: : <TITLE>XSLT Test</TITLE>
: : </HEAD>
: : <BODY>
: : <xsl:for-each select="/Error">
: : <H1>Error</H1><xsl:value-of select="."/>
: : </xsl:for-each>
: : <TABLE border="0" cellspacing="0" cellpadding="2">
: : <TBODY>
: : <xsl:for-each select="/root">
: : <TR>
: : <TH style="background-color:khaki">
: : <xsl:text>Attribute</xsl:text>
: : </TH>
: : <TH style="background-color:khaki">
: : <xsl:text>Value</xsl:text>
: : </TH>
: : </TR>
: : <xsl:for-each select="Item">
: : <TR>
: : <TD><xsl:value-of select="@ID"/></TD>
: : <TD><xsl:value-of select="."/></TD>
: : </TR>
: : </xsl:for-each>
: : </xsl:for-each>
: : </TBODY>
: : </TABLE>
: : </BODY>
: : </HTML>
: : </xsl:template>
: : If I build DOM tree by parsing XML file the resulting HTML
: : document after applying XSLT will display
: : Attribute Value
: : 00001 Value of Item 00001
: : 00002 Value of Item 00002
: : But if I build DOM tree using following code:
: : XMLDocument xDoc = new XMLDocument();
: : Element root = xDoc.createElement( "root" );
: : xDoc.appendChild( root );
: : Element elem = xDoc.createElement( "Item" );
: : elem.setAttribute( "ID", "00001" );
: : root.appendChild( elem ).
: : appendChild( xDoc.createTextNode( "Value of Item
00001" )
: : elem = xDoc.createElement( "Item" );
: : elem.setAttribute( "ID", "00002" );
: : root.appendChild( elem )
: : .appendChild( xDoc.createTextNode( "Value of Item
00002" )
: : the same XSLT will produce the following HTML output:
: : Attribute Value
: : Value of Item 00001
: : Value of Item 00002
: : So the value for the ID attribute is not displayed. At the
same
: : time I can access this attribute using DOM interface. For
: : example, following code
: : NodeList nList = xDoc.getElementsByTagName( "Item" );
: : Element e;
: : for( int i = 0; i < nList.getLength(); i++ )
: : e = (Element)nList.item( i );
: : System.out.println( "ID: " + e.getAttribute( "ID" ) );
: : produces an output
: : ID: 00001
: : ID: 00002
: : Here is the code for applying XSLT to DOM tree:
: : DOMParser parser = new DOMParser();
: : parser.parse( new FileInputStream( "test.xsl" ) );
: : XMLDocument xsldoc = parser.getDocument();
: : XSLStylesheet xsl = new XSLStylesheet( xsldoc, createURL
: : XMLDocument out = new XMLDocument();
: : out.appendChild( new XSLProcessor().processXSL(xsl, xDoc) );
: : out.print( new FileOutputStream( "test.html" ) );
: : Andrei Filimonov
null

ANN: XML Parser for Java Release 1.0.1.4

A new maintenance release of the Oracle Parser for Java is
available for download. It has the following fixes and changes:
Bug fixes for #893971, i.e XML parser cannot parse documents
from InputStream;
#900146 normalize() is wrong if the literal contains angle
brackets;
#898423, multiplicity info about elements enhancement.
New API in the following Classes:
1. oracle.xml.parser.ElementDecl
-getParseTree( Returns the root Node of Content Model
parse tree, which could then be traversed node by node using
getFirstChild() and getLastChild() ).
This is the fourth production patch release. Oracle XML Parser
1.0.1.4.0
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
null

The link has been fixed. You will go to the v2 download page
now. Sorry for the inconvience.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Renilton Oliveira (guest) wrote:
: I didn't find the file for version 2.0.0.0 as well.
: Renilton
: Andrei Filimonov (guest) wrote:
: : I tried to download XML Parser for Java v2 it seems that
only
: v
: : 1.0.1.4 is available. Could you please give an exact URL for
: v2
: : download?
: : Andrei Filimonov
: : Oracle XML Team wrote:
: : : The Oracle XML v2 parser is now available for download
here
: as
: : : an early beta release and is written in Java. It features
: an
: : : improved architecture over the Oracle XML v1 parser and
has
: : : shown better performance on small to large XML documents.
: It
: : : will also be able to format the XML document according to
a
: : : stylesheet, having integrated an XSLT processor.
: : : Version 2 of the XML Parser for Java, besides
incorporating
: an
: : : XSLT processor, has been re-architected from version 1.
This
: : has
: : : resulted in a number of changes to the class names
: especially
: : : those that support Namespaces. See v2changes.txt and
: the .diff
: : : difference files in the sample directory.
: : : Oracle XML Team
: : : http://technet.oracle.com
: : : Oracle Technology Network
null

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