Specify characters in a string

I'm a beginner at Java.
I need to create a program that will validate only binary characters in a string and count the number of 0s in the string. For some reason I keep getting an error message. For the life of me, I can't figure it out.
char a = '1';
char b = '0';
int hmo;
int totalzeroes=0;
String input = JOptionPane.showInputDialog(null, "Please Enter a Binary Number");
for (hmo=0; hmo<input.charAt(hmo);hmo++)
System.out.println(input.charAt(hmo));
totalzeroes++;
OUTPUT:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range:
at java.lang.String.charAt(Unknown Source)
at cop.main(cop.java:19)

...hmo<input.charAt(hmo)...You have to loop up to input.length(), not to the value of the character at certain position.
Mike

Similar Messages

Specify Valid Characters in a String

I'm a beginner at Java.
I need to create a program that will validate only binary characters in a string and count the number of 0s in the string. For some reason I keep getting an error message. For the life of me, I can't figure it out.
char a = '1';
char b = '0';
int hmo;
int totalzeroes=0;
String input = JOptionPane.showInputDialog(null, "Please Enter a Binary Number");
for (hmo=0; hmo<input.charAt(hmo);hmo++)
System.out.println(input.charAt(hmo));
totalzeroes++;
OUTPUT:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range:
at java.lang.String.charAt(Unknown Source)
at cop.main(cop.java:19)>

Just a suggestion.. for this kind of stuff you should probably use regular expressions.. You can easily validate that a string contains only 0 and 1 with something like this:
public boolean validate(String s)
     String PATTERN = "[01]+";
     Pattern pattern = Pattern.compile(PATTERN, Pattern.CANON_EQ);
     Matcher matcher = pattern.matcher(s);
     if (matcher.matches())
          return true;
     else
          return false;
Here, you can easily change the PATTERN if you want the string to match something else..

How to count number of repeated characters in a String

I have a String.... 10022002202222.
I need to know how many 2's are there in the string... here the string contains eight 2's..
Thanks in advance..

it is workingYes, but... attention to surprises...
SQL> var v1 varchar2(1000);
SQL> exec :v1 := 'How to count the number of occurences of a characters in a string';
PL/SQL procedure successfully completed.
SQL> select length(:v1) - length(replace(:v1,'c')) from dual;
LENGTH(:V1)-LENGTH(REPLACE(:V1,'C'))
6
SQL> exec :v1 := 'cccccc';
PL/SQL procedure successfully completed.
SQL> select length(:v1) - length(replace(:v1,'c')) from dual;
LENGTH(:V1)-LENGTH(REPLACE(:V1,'C'))
SQL> select length(:v1) - nvl(length(replace(:v1,'c')),0) from dual;
LENGTH(:V1)-NVL(LENGTH(REPLACE(:V1,'C')),0)
6
SQL>

How to search special characters in a string

Hi all,
I want to search special characters in all string columns and all rows in the table.
The table has about 5 string columns and about 5.000.000 rows. For each row and column, I have to search entries, which included special characters like ", !, ? or something else (f.ex. "Mama?Mia" or "!!!Hotel out of order!!!"). The problem, the character could stand at each position in the string.
What's the best and most performance possibility to search such entries?? Is it possibility only by SQL; is there a special function for this?? Or must I use PL/SQL.
Thanks for helping
Dana

HTH
Laurent Schneider
OCM DBA
SQL> select * from z;
S
Mama?Mia
a b c
123
SQL> select * from z where translate(s,'~ABCDEFGHIJKLMNOPQRSTUVWXYZ abcdefghijklmnopqrstuvwxyz1234567890','~') is not null;
S
Mama?Mia
SQL> select * from z where regexp_like(s, '[^[:alnum:][:space:]]');
S
Mama?Mia

How do I drop the last 3 characters in a string?

Hello. I'm trying to find a way to drop the last 3 characters in a string. The length varies because it is a last name field. The problem is that when a customer has a suffix on their name, III for example, it is appended to the last name all in the last name field. If I use the ProperCase function, I end up with "Smith Iii". How can I tell it to drop the last 3 characters? I'll then append an UpperCase edition of the last 3 characters to that. Thank you!

Use the instring and right string functions then UpperCase

How to find out if there are repeated characters in a string

hey guys
well i kinda have a little problem figuring out how to find out
if there are repeated characters in a string.
if anyone can help, would appreciate it.
thanks
milos

Try using the StringTokenizer class. if u already know which character to trace. this could do the job.
eg. String str = "here and there its everywhere";
StringTokenizer st = new StringTokenizer(str, "e");
int rep = st.countTokens();

Removing non english characters from my string input source

Guys,
I have problem where I need to remove all non english (Latin) characters from a string, what should be the right API to do this?
One I'm using right now is:
s.replaceAll("[^\\x00-\\x7F]", "");//s is a string having chinese characters.
I'm looking for a standard Solution for such problems, where we deal with multiple lingual characters.
TIA
Nitin

Nitin_tiwari wrote:
I have a string which has Chinese as well as Japanese characters, and I only want to remove only Chinese characters.
What's the best way to go about it?Oh, I see!
Well, the problem here is that Strings don't have any information on the language. What you can get out of a String (provided you have the necessary data from the Unicode standard) is the script that is used.
A script can be used for multiple languages (for example English and German use mostly the same script, even if there are a few characters that are only used in German).
A language can use multiple scripts (for example Japanese uses Kanji, Hiragana and Katakana).
And if I remember correctly, then Japanese and Chinese texts share some characters on the Unicode plane (I might be wrong, 'though, since I speak/write neither of those languages).
These two facts make these kinds of detections hard to do. In some cases they are easy (separating latin-script texts from anything else) in others it may be much tougher or even impossible (Chinese/Japanese).

Need help in replacing special characters in a string

Hi,
please let me know the best way to replace all the special characters in a string with space.
other than alphabets and numbers
with regards.
sumanth.

please let me know the best way to replace all the special characters in a string with space.
other than alphabets and numbers
>
Sumanth Nag Kristam wrote:
> actually i need to replace hexa decimal char 0X1A in a string.... that is 'substitue' as per the chart
> any pointers....
>
> chk the link for the ASCII codes
> http://www.techonthenet.com/ascii/chart.php
But in Hexa decimal value there is no special characters?

Sample code to identify special characters in a string

Hi,
I need to identify special characters in a string.... could anybody send me some code please.......
Thanks,
Best regards,
Karen

data: str(100) type c.
data: str_n type string.
data: str_c type string.
data: len type i.
data: ofst type i.
str = '#ABCD%'.
len = strlen( str ).
do.
if ofst = len.
    exit.
endif.
if str+ofst(1) co sy-abcde.
    concatenate str_c str+ofst(1) into str_c.
else.
    concatenate str_n str+ofst(1) into str_n.
endif.
ofst = ofst + 1.
enddo.
write:/ str.
write:/ str_c.
write:/ 'spacial chracter',20 str_n.
Function module <b>SF_SPECIALCHAR_DELETE</b> <b>DX_SEARCH_STRING</b>
l_address1 = i_adrc-street.
CHECK NOT L_ADDRESS1 IS INITIAL.
len = STRLEN( l_address1 ).
do len times.
if not l_address1+l(1) ca
'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789 '.
if i_adrc-street+l(1) CO sy-abcde.
elseif i_adrc-street+l(1) CO L_NUMCHAR.
exit.
endif.
l = l + 1.
enddo.
data : spchar(40) type c value '~!@#$$%^&()?...'etc.
data :gv_char .
data:inp(20) type c.
take the string length .
len = strlen (i/p).
do len times
MOVE FNAME+T(1) TO GV_CHAR.
IF gv_char CA spchar.
MOVE fnameT(1) TO inp2T(1).
ENDIF.
T = T + 1.
enddo.
REPORT ZEX4 .
PARAMETERS: fname LIKE rlgrap-filename .
DATA: len TYPE i,
T TYPE I VALUE 0,
inp(20) TYPE C,
inp1(20) type c,
inp2(20) type c,
inp3(20) type c.
DATA :gv_char.
data : spchar(20) type c value '#$%^&*()_+`~'.
START-OF-SELECTION.
CONDENSE fname.
len = strlen( fname ).
WRITE:/ len.
DO len TIMES.
MOVE FNAME+T(1) TO GV_CHAR.
IF gv_char ca spchar.
MOVE fnameT(1) TO inpT(1).
ENDIF.
T = T + 1.
ENDDO.
CONDENSE INP.
write:/ 'Special Characters :', inp.
Rewards if useful..........
Minal

RegExp for excluding special characters in a string.

Hi All,
Im using Flex RegExpValidator. Can anyone suggest me the correct expression to validate this condition?....
I have tried this expression :----- /^[^///\/</>/?/*&]+$/...But in this it is also negating the alphabets.Also I have tried with opposite condition that in the String we should have alphabets and the expression is:-- ([a-z]|[A-Z]|[0-9]|[ ]|[-]|[_])*..... Please can anyone help me on this.
Thanks in advanced to all.
Munira

sorry but you are posting things back that do not make any sense
what do you mean with the below comment?
munira06 wrote:
Yes you are correct ,but I have tried this with single special character
say
Re: RegExp for excluding special characters in a string.
here is a sample app taken from the live docs
using ^[a-zA-Z0-9 \-_]*$ as the regex accepts all characters from a-z, A-Z, 0-9 - [space] and_
run the example tell me what regex you are using and what test strings fail when they should pass or pass when they should fail
<?xml version="1.0" encoding="utf-8"?>

<s:Application xmlns:fx="http://ns.adobe.com/mxml/2009"
        xmlns:s="library://ns.adobe.com/flex/spark"
        xmlns:mx="library://ns.adobe.com/flex/mx">
    <fx:Script>
        <![CDATA[
            import mx.events.ValidationResultEvent;
            import mx.validators.*;
            // Write the results to the
            private function handleResult(eventObj:ValidationResultEvent):void {
                if (eventObj.type == ValidationResultEvent.VALID) {
                    // For valid events, the results Array contains
                    // RegExpValidationResult objects.
                    var xResult:RegExpValidationResult;
                    reResults.text = "";
                    for (var i:uint = 0; i < eventObj.results.length; i++) {
                        xResult = eventObj.results[i];
                        reResults.text=reResults.text + xResult.matchedIndex + " " + xResult.matchedString + "\n";
                } else {
                    reResults.text = "";
        ]]>
    </fx:Script>
    <fx:Declarations>
        <mx:RegExpValidator id="regExpV"
                source="{regex_text}" property="text"
                flags="g" expression="{regex.text}"
                valid="handleResult(event)"
                invalid="handleResult(event)"
                trigger="{myButton}"
                triggerEvent="click"/>
    </fx:Declarations>
    <s:Panel title="RegExpValidator Example"
            width="75%" height="75%"
            horizontalCenter="0" verticalCenter="0">
        <s:VGroup left="10" right="10" top="10" bottom="10">
            <s:Label width="100%" text="Instructions:"/>
            <s:Label width="100%" text="1. Enter text to search. By default, enter a string containing the letters ABC in sequence followed by any digit."/>
            <s:Label width="100%" text="2. Enter the regular expression. By default, enter ABC\d."/>
            <s:Label width="100%" text="3. Click the Button control to trigger the validation."/>
            <s:Label width="100%" text="4. The results show the index in the text where the matching pattern begins, and the matching pattern. "/>
            <mx:Form>
                <mx:FormItem label="Enter text:">
                    <s:TextInput id="regex_text" text="xxxxABC4xxx" width="100%"/>
                </mx:FormItem>
                <mx:FormItem label="Enter regular expression:">
                    <s:TextInput id="regex" text="ABC\d" width="100%"/>
                </mx:FormItem>
                <mx:FormItem label="Results:">
                    <s:TextInput id="reResults" width="100%"/>
                </mx:FormItem>
                <mx:FormItem >
                    <s:Button id="myButton" label="Validate"/>
                </mx:FormItem>
            </mx:Form>
        </s:VGroup>
    </s:Panel>
</s:Application>

Unable to read more than 255 characters in a string data type.

Hello,
I am using Crystal Reports version 11.5.8.826 to generate reports from databases such as MS-Excel & BaaN.
In Excel, there are records which carry string lengths of more than 255 characters. All though the fields are getting displayed in the report, the data being displayed gets truncated once it reaches a length of 255 characters.
Kindly provide me with a solution this problem.
Regards

Hello Manish,
I know that older versions of Crystal (Crystal 10 and older ) had a limitation of only 256 Characters for a string value. You should be able to use this code to get what you need.
We were successfully able to print out the Declaration of Independence through a Crystal report using something very similiar to this.
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
Shared StringVar Array strings;
Shared NumberVar arrayMax := 1;
Shared NumberVar maxLength := 250;
Shared BooleanVar firstTime := true;
Redim strings[arrayMax];
strings[1] := u201Cu201D;
u2018done!u2019
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
Here is my main loop that I used in the group header:
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
WhilePrintingRecords;
Shared StringVar Array strings;
Shared NumberVar arrayMax;
Shared NumberVar maxLength;
Shared BooleanVar firstTime;
Local StringVar enteredString;
Local NumberVar lenStr;
Local NumberVar lenArr;
Local NumberVar lenLeft;
enteredString := [Field Name];
enteredString := IIF(firstTime,enteredString, u201C, u201D & enteredString);
firstTime := false;
lenStr := Length(enteredString);
lenArr := Length(strings[arrayMax]);
lenLeft := maxLength u2013 lenArr;
if (lenLeft >= lenStr) then
strings[arrayMax] := strings[arrayMax] & enteredString;
u201D
else
strings[arrayMax] := strings[arrayMax] & left(enteredString, lenLeft);
arrayMax := arrayMax + 1;
redim preserve strings[arrayMax];
strings[arrayMax] := u201Cu201D;
strings[arrayMax] := strings[arrayMax] & right(enteredString, lenStr u2013 lenLeft);
u201D
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
and then to display the different sets in the text area. I would have one of these for every element I need displayed and change the display number variable.
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
Shared StringVar Array strings;
Shared NumberVar arrayMax;
Local NumberVar displayNumber := [element in array];
if(arrayMax >= displayNumber) then
strings[displayNumber];
else
u201D;
u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2014u2013
I like this version better because the array is completely dynamic. It can be as big or as small as it needs to be. There is always room for optimizations. But hopefully this will get you started on the right path.
Jenny

Counting Characters in a string

HI all!
I am new working with java and i have an application where I have to count specific characters in a string e.g. 'a','.','H','4' and so on! I found an entry in the forum with this script:
String text = "Hello World!";
int count = 0;
for (int x = 0; x < text.length(); x++)
if (text.charAt(x) == 'l')
count++;
This Script count all the 'I', but I could not get CharAt to count different characters at once!
Is there a way?
Thx for your help!
LeBite

String text = "Hello World!";
int countl = 0;
int counto = 0;
for (int x = 0; x < text.length(); x++)
    if (text.charAt(x) == 'l') countl++;
    if (text.charAt(x) == 'o') counto++;
[/code[

Removing non-alpha-numeric characters from a string

How can I remove all non-alpha-numeric characters from a string? (i.e. only alpha-numerics should remain in the string).

Or even without a loop ?
Extract from the help for the Search and Replace String function :
Right-click the Search and Replace String function and select Regular Expression from the shortcut menu to configure the function for advanced regular expression searches and partial match substitution in the replacement string.
Extract from the for the advanced search options :
[a-zA-Z0-9] matches any lowercase or uppercase letter or any digit. You also can use a character class to match any character not in a given set by adding a caret (^) to the beginning of the class. For example [^a-zA-Z0-9] matches any character that is not a lowercase or uppercase letter and also not a digit.
Message Edité par JB le 05-06-2008 01:49 PM
Attachments:
Example_VI_BD4.png ‏2 KB

Is there a limitation of characters in a String variable in 8.0.2?

Is there a limitation of characters in a String variable?
I'm trying to create an email within my script and when I paste my text into my parameter, which is a String variable, it will only paste up to 80 characters (including spaces).
In 7.0 I was able to paste my paragraphs and the larges paragraph had 346 characters (including spaces).
Thanks,
Debbie

Greg,
Ah.... that's it.
I modified the value of the parameter within the script and added the text that I needed. I added the following:
"To transfer the file over to the router's flash you will need an TFTP or FTP program. Start your application and make sure that the default directory is pointed to the directory where you copied the greeting. Now log into the router that needs to be updated. Once you are in the router issue one of these commands:"
It accepted it and was able to use the entire value. So it must be the web page that will not allow me to enter more then 40 characters.
Do I need to get this submitted as a bug?
Thank you,
Debbie

Scanning values of characters in a string

Hey guys,
I'm trying to figure out a way I can scan the individual characters of a string to find their value [unicode value, if it's a number, punctuation etc] and I'm a bit stumped. I know I'll have to be using the chatAt method, but I can't think of how I could implement this to continuiously scan through a string.
If someone could help point me in the right direction it would be great.
Thanks in advance.

Do you know what a loop is?
http://java.sun.com/docs/books/tutorial/java/nutsandbolts/index.html
Do you know how to find out about methods of the String class such as toCharArray?
http://java.sun.com/javase/6/docs/api/java/lang/String.html

Specify characters in a string

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