Split a Date Range N days into N row, possible?

Question

hi all,
i am planning to create a view for my peoplesoft custom component
Record structure
Employee id | Date From | Date To
123 | 10-Aug-2010 | 13-Aug-2010
Can it convert into a view with the following row?
Employee | Date
123 | 10-Aug-2010
123 | 11-Aug-2010
123 | 12-Aug-2010
123 | 13-Aug-2010
Thanks for the help

Answer 1

SBH wrote:
Try it as below
WITH C AS
SELECT 123 EMPID,TO_DATE('10-Aug-2010','DD-MM-YYYY') STDT,TO_DATE('13-Aug-2010','DD-MM-YYYY') ENDT
FROM DUAL
SELECT EMPID, DT
FROM (SELECT EMPID, STDT+LEVEL-1 DT
FROM C
CONNECT BY LEVEL <= (ENDT-STDT+1)
SQL> /
EMPID DT
123 10-AUG-10
123 11-AUG-10
123 12-AUG-10
123 13-AUG-10
Works ok for a single row of data, but not if there are multiples with different date ranges. For that you'd need something more along the lines of...
SQL> ed
Wrote file afiedt.buf
  1  WITH c AS
  2    (
  3    select 123 as empid, to_date('10-Aug-2010','DD-MM-YYYY') as stdt, to_date('13-Aug-2010','DD-MM-YYYY') as endt from dual union all
  4    select 234, to_date('17-Aug-2010','DD-MM-YYYY'), to_date('25-Aug-2010','DD-MM-YYYY') from dual
  5    )
  6  -- END OF TEST DATA
  7  select empid, stdt+x.rn-1 as dt
  8  from c, (select rownum as rn from dual connect by rownum <= (select max(endt-stdt+1) as mx_rn from c)) x
  9  where stdt+x.rn-1 <= endt
10* order by empid, stdt+x.rn-1
SQL> /
     EMPID DT
       123 10/08/2010 00:00:00
       123 11/08/2010 00:00:00
       123 12/08/2010 00:00:00
       123 13/08/2010 00:00:00
       234 17/08/2010 00:00:00
       234 18/08/2010 00:00:00
       234 19/08/2010 00:00:00
       234 20/08/2010 00:00:00
       234 21/08/2010 00:00:00
       234 22/08/2010 00:00:00
       234 23/08/2010 00:00:00
       234 24/08/2010 00:00:00
       234 25/08/2010 00:00:00
13 rows selected.
SQL>