Split XML files with XSL result document

Question

Hi All,
I have below xml file...
<?xml version="1.0" encoding="ISO-8859-1"?>
<T0020
xsi:schemaLocation="http://www.safersys.org/namespaces/T0020V1 T0020V1.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.safersys.org/namespaces/T0020V1">
<INTERFACE>
<NAME>SAFER</NAME>
<VERSION>04.02</VERSION>
</INTERFACE>
<TRANSACTION>
<VERSION>01.00</VERSION>
<OPERATION>REPLACE</OPERATION>
<DATE_TIME>2009-09-01T00:00:00</DATE_TIME>
<TZ>CT</TZ>
</TRANSACTION>
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_BASE_COUNTRY>US</IRP_BASE_COUNTRY>
<IRP_BASE_STATE>AR</IRP_BASE_STATE>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
<IRP_ACCOUNT_TYPE>I</IRP_ACCOUNT_TYPE>
<IRP_STATUS_CODE>100</IRP_STATUS_CODE>
<IRP_STATUS_DATE>2007-11-06</IRP_STATUS_DATE>
<IRP_UPDATE_DATE>2009-08-03</IRP_UPDATE_DATE>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>A P SUPPLY CO</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
<STREET_LINE_1>1400 N OATS</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>71854</ZIP_CODE>
<COUNTY>MILLER</COUNTY>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
<STREET_LINE_1>P O BOX 1927</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>75504</ZIP_CODE>
<COUNTY/>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
and i want to take this xml file and split it into multiple files through java code like this ...
File1.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
File2.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
so i have applied following xslt ...
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.safersys.org/namespaces/T0020V1" version="2.0">
<xsl:output method="xml" indent="yes" name="xml" />
<xsl:variable name="accounts" select="t:T0020/t:IRP_ACCOUNT" />
<xsl:variable name="size" select="10" />
<xsl:template match="/">
<xsl:for-each select="$accounts[position() mod $size = 1]">
<xsl:variable name="filename" select="resolve-uri(concat('output/',position(),'.xml'))" />
<xsl:result-document href="{$filename}" format="xml">
<T0020>
<xsl:for-each select=". | following-sibling::t:IRP_ACCOUNT[position() < $size]">
<xsl:copy-of select="." />
</xsl:for-each>
</T0020>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Now i want to apply this XSL to xml through Java Code...
TransformerFactory tFactory = TransformerFactory.newInstance();
Source xslSource = new StreamSource(xslFilePath);
Transformer trans = tFactory.newTransformer(xslSource);
trans.transform(new StreamSource(xmlFileName), new StreamResult( ????));
here how can i map new StreamResult( ) input parameter with xsl Result document argument ??
Please help me.....
Or Can you give me a link of Example which use result document and Java transform method to Output multiple doucment ??
Here new StreamResult take only 1 file as to be transformed ....

Answer 1

hi Tejas ,
I have done as you said but now able to generate multiple xml file .
I am giving you the xsl file i have used ....
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.safersys.org/namespaces/T0020V1" version="2.0">
     <xsl:output method="xml" indent="yes" name="xml" />
     <xsl:variable name="accounts" select="t:T0020/t:IRP_ACCOUNT" />
     <xsl:variable name="size" select="5" />
     <xsl:template match="/">
          <xsl:for-each select="$accounts[position() mod $size = 1]">
               <xsl:variable name="filename" select="concat(position(),'.xml')" />
                    <xsl:result-document href="{$filename}" format="xml">
                         <T0020>
                              <xsl:for-each select=". | following-sibling::t:IRP_ACCOUNT[position() < $size]">
                                   <xsl:copy-of select="." />
                              </xsl:for-each>                              
                         </T0020>
                    </xsl:result-document>                    
          </xsl:for-each>
     </xsl:template>
</xsl:stylesheet>
and i have done transformation like this ...
Transformer trans = tFactory.newTransformer(xslSource);
trans.transform(new StreamSource(xmlFileName), new DOMResult());
but not getting any result .
Can you please help me out ?
- Nisarg