Xml file with xsl style sheet reference

I am trying to learn this from a book, I copied the code like
it shows, but the page on the server keeps coming back with an
error starting on line 54 involving the four "End If" quotes. I
have tried everything I can think of and can't get it to work. Any
help would be greatly appreciated.
Here's the code:
<%@Language=VBScript%>
<%option explicit%>
<%
dim domDoc
dim aFilename
Dim node
Dim nodes
dim mainNodes
dim mainnode
dim attr
dim root
Set domDoc = Server.CreateObject("MSXML.DOMDocument")
afilename =server.MapPath("ch19i1.xml")
if not domDoc.load(afilename) then
Response.Write "Could not load the file " & aFilename
& "<br>"
Response.End
end if
%>
<html>
<head></head>
<body>
<%
' display the root node
set root = domDoc.documentElement
Response.Write "<h1>" & root.nodename & ": "
& root.nodevalue & "</h1>"
Set mainNodes = root.childNodes
For Each mainNode in mainNodes
If mainNode.hasChildNodes = False Then
Response.Write "<h2>" & mainNode.nodeName & ":
" & mainNode.text & "</h2><br>"
Else
Response.Write "<h3>" & mainNode.nodeName & ":
" & mainNode.text & "</h3>"
Set nodes = mainNode.childNodes
If nodes.lenght > 0 Then
Set node = nodes(0)
If Not node.Attributes Is Nothing Then
If node.Attributes.lenght > 0 Then
Response.Write "<table border='1'>"
Response.Write "<thead>"
For Each attr In node.Attributes
Response.Write "<th>" & attr.nodeName &
"</th>"
Next
Response.Write "</tr>"
For Each node In nodes
Response.Write "<tr>"
For Each attr In node.Attributes
If attr.nodeValue = "" Then
Response.Write "<td>" & " " &
"</td>"
Else
Response.Write "<td>" & attr.nodeValue &
"</td>"
End If
Next
Response.Write "</table>"
End If
End If
End IF
End If
Next
%>
</body>
</html>

Is the error message displayed in Firefox or in IE, or in a customized window that doesn't identify the browser?
''If it displays in Firefox:''
It's possible that the Troubleshooter doesn't work correctly unless IE is your default browser. You could test that possibility by having IE make itself the default and testing the Troubleshooter again.
''If it displays in IE or embedded in another Microsoft application:''
In a web search I found these suggestions:
(1) Reset your Internet Explorer settings, according to http://answers.microsoft.com/en-us/ie/forum/ie8-windows_7/cannot-view-xml-using-xsl-style-sheet/ccfe80c6-c0db-4594-a7e3-475f9eac0e85
(2) Try the System File Checker, according to http://ask-leo.com/why_do_i_get_the_xml_page_cannot_be_displayed_after_running_a_microsoft_troubleshooter.html
Any luck?

Similar Messages

Cannot view XML input using XSL style sheet. Please correct the error and..

Hi All,
Scenario XML to IDOC.
The interface determination decides whether to create IDOC X or IDOC Y based on a xml segment value.
I have an error in the SXMB_MONI:

- <SAP:Error xmlns:SAP="http://sap.com/xi/XI/Message/30" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" SOAP:mustUnderstand="">
<SAP:Category>XIServer</SAP:Category>
<SAP:Code area="IF_DETERMINATION">CX_ID_PLSRV</SAP:Code>
<SAP:P1>Problem evaluating a condition: Exception CX_SWF_RLS_RULE occurred (program: CL_SWF_RLS_CONDITION==========CP, include: CL_SWF_RLS_CONDITION==========CM00Q, line: 160).</SAP:P1>
<SAP:P2 />
<SAP:P3 />
<SAP:P4 />
<SAP:AdditionalText />
<SAP:ApplicationFaultMessage namespace="" />
<SAP:Stack>Error when determining the inbound interface: Problem evaluating a condition: Exception CX_SWF_RLS_RULE occurred (program: CL_SWF_RLS_CONDITION==========CP, include: CL_SWF_RLS_CONDITION==========CM00Q, line: 160). Problem evaluating a condition: Exception CX_SWF_RLS_RULE occurred (program: CL_SWF_RLS_CONDITION==========CP, include: CL_SWF_RLS_CONDITION==========CM00Q, line: 160). Exception CX_SWF_RLS_RULE occurred (program: CL_SWF_RLS_CONDITION==========CP, include: CL_SWF_RLS_CONDITION==========CM00Q, line: 160). Exception CX_SWF_RLS_OPERAND_MISSING occurred (program: CL_SWF_RLS_COMPARISON=========CP, include: CL_SWF_RLS_COMPARISON=========CM002, line: 63). Exception CX_SWF_RLS_OPERAND_MISSING occurred (program: SAPMSSY1, include: , line: 0). Exception CX_SWF_EXP_EVALUATE occurred (program: CL_SWF_EXP_EXPRESSION=========CP, include: CL_SWF_EXP_EXPRESSION=========CM027, line: 38). Exception CX_SWF_EXP_EXPRESSION occurred (program: CL_SWF_EXP_EXPRESSION=========CP, include: CL_SWF_EXP_EXPRESSION=========CM01Z, line: 520). Exception CX_SWF_EXP_EXPRESSION occurred (program: CL_SAI_SWF_RULE_ENGINE========CP, include: CL_SAI_SWF_RULE_ENGINE========CM00S, line: 42). Problem extracting values from the Payload: Check line 2 column 1 of the XML document</SAP:Stack>
<SAP:Retry>M</SAP:Retry>
</SAP:Error>
From the SXMB_MONI, the inbound message payload is truncated with an error:
- <ProductIdentification>
<GlobalProductIdentifier />
- <PartnerProductIdentification>
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
The following tags were not closed: Pip3B12ShippingOrderConfirmation, ShippingOrder, ShipmentLineItem, isContainsHazardousMa...
"> <GlobalPartnerClassificationCode />
<ProprietaryProductIdentifier>000000000000101369</ProprietaryProductIdentifier>
</PartnerProductIdentification>
</ProductIdentification>
- <QuantityInformation>
- <confirmedQuantity>
<ProductQuantity>1.00</ProductQuantity>
</confirmedQuantity>
I've checked that the xml format is OK.
As a matter of fact, if I try to resend the xml file from directory, the message is processed correctly and the payload shows all the xml file.
Thanks.
Daniele
Edited by: Daniele*Verdone on Feb 1, 2010 11:22 AM
Edited by: Daniele*Verdone on Feb 1, 2010 11:23 AM

Hi Suraj,
That option is not available in FTP mode..
This option is applicable only for the File adapter. If you enter a value in this field when configuring the sender FTP adapter, it will have no effect.
Yes, you're right !!
Are you sure that the message is not getting picked in half-way
Now, at this time, I can't see the XML data in the CC monitoring because the tool shows only the recent polling execute in the last 10 minutes. If the error recurs, I will check the payload of CC.
How can I solve the problem with reading incomplete file (FTP mode)?
...Meanwhile I will try with Full cache refresh.
Thanks
Daniele

XML page cannot be displayed cannot view XML input using XSL style sheet Please correct the error and then click the REfresh

XML page cannot be displayed cannot view XML input using XSL style sheet Please correct the error and then click the REfresh

Is the error message displayed in Firefox or in IE, or in a customized window that doesn't identify the browser?
''If it displays in Firefox:''
It's possible that the Troubleshooter doesn't work correctly unless IE is your default browser. You could test that possibility by having IE make itself the default and testing the Troubleshooter again.
''If it displays in IE or embedded in another Microsoft application:''
In a web search I found these suggestions:
(1) Reset your Internet Explorer settings, according to http://answers.microsoft.com/en-us/ie/forum/ie8-windows_7/cannot-view-xml-using-xsl-style-sheet/ccfe80c6-c0db-4594-a7e3-475f9eac0e85
(2) Try the System File Checker, according to http://ask-leo.com/why_do_i_get_the_xml_page_cannot_be_displayed_after_running_a_microsoft_troubleshooter.html
Any luck?

Transfer 100M XML file with XSL

Hi,
I am trying to transfer 100M XML file with XSL. Input.xml is the XML file, format.xsl is the XSL file. I type in the command line as:
java org.apache.xalan.xslt.Process -IN input.xml -XSL format.xsl -OUT output.xml
It got "out of memeory" error. My questions are:
1. Is it possible to transfer such large XML file with XSLT?
2. The XSL processor used SAX or DOM to parse XML file?
3. Any suggestions?
Thanks.
James

maybe?
java -Xmx200m org.apache.xalan.xslt.Process -IN input.xml -XSL format.xsl -OUT output.xml
http://java.sun.com/j2se/1.3/docs/tooldocs/win32/java-classic.html

Split XML files with XSL result document

Hi All,
I have below xml file...
<?xml version="1.0" encoding="ISO-8859-1"?>
<T0020
xsi:schemaLocation="http://www.safersys.org/namespaces/T0020V1 T0020V1.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.safersys.org/namespaces/T0020V1">
<INTERFACE>
<NAME>SAFER</NAME>
<VERSION>04.02</VERSION>
</INTERFACE>
<TRANSACTION>
<VERSION>01.00</VERSION>
<OPERATION>REPLACE</OPERATION>
<DATE_TIME>2009-09-01T00:00:00</DATE_TIME>
<TZ>CT</TZ>
</TRANSACTION>
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_BASE_COUNTRY>US</IRP_BASE_COUNTRY>
<IRP_BASE_STATE>AR</IRP_BASE_STATE>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
<IRP_ACCOUNT_TYPE>I</IRP_ACCOUNT_TYPE>
<IRP_STATUS_CODE>100</IRP_STATUS_CODE>
<IRP_STATUS_DATE>2007-11-06</IRP_STATUS_DATE>
<IRP_UPDATE_DATE>2009-08-03</IRP_UPDATE_DATE>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>A P SUPPLY CO</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
<STREET_LINE_1>1400 N OATS</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>71854</ZIP_CODE>
<COUNTY>MILLER</COUNTY>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
<STREET_LINE_1>P O BOX 1927</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>TEXARKANA</CITY>
<STATE>AR</STATE>
<ZIP_CODE>75504</ZIP_CODE>
<COUNTY/>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
and i want to take this xml file and split it into multiple files through java code like this ...
File1.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
File2.xml
<T0020>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
<IRP_ACCOUNT> ..... </IRP_ACCOUNT>
</T0020>
so i have applied following xslt ...
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.safersys.org/namespaces/T0020V1" version="2.0">
<xsl:output method="xml" indent="yes" name="xml" />
<xsl:variable name="accounts" select="t:T0020/t:IRP_ACCOUNT" />
<xsl:variable name="size" select="10" />
<xsl:template match="/">
<xsl:for-each select="$accounts[position() mod $size = 1]">
<xsl:variable name="filename" select="resolve-uri(concat('output/',position(),'.xml'))" />
<xsl:result-document href="{$filename}" format="xml">
<T0020>
<xsl:for-each select=". | following-sibling::t:IRP_ACCOUNT[position() < $size]">
<xsl:copy-of select="." />
</xsl:for-each>
</T0020>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Now i want to apply this XSL to xml through Java Code...
TransformerFactory tFactory = TransformerFactory.newInstance();
Source xslSource = new StreamSource(xslFilePath);
Transformer trans = tFactory.newTransformer(xslSource);
trans.transform(new StreamSource(xmlFileName), new StreamResult( ????));
here how can i map new StreamResult( ) input parameter with xsl Result document argument ??
Please help me.....
Or Can you give me a link of Example which use result document and Java transform method to Output multiple doucment ??
Here new StreamResult take only 1 file as to be transformed ....

hi Tejas ,
I have done as you said but now able to generate multiple xml file .
I am giving you the xsl file i have used ....
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.safersys.org/namespaces/T0020V1" version="2.0">
     <xsl:output method="xml" indent="yes" name="xml" />
     <xsl:variable name="accounts" select="t:T0020/t:IRP_ACCOUNT" />
     <xsl:variable name="size" select="5" />
     <xsl:template match="/">
          <xsl:for-each select="$accounts[position() mod $size = 1]">
               <xsl:variable name="filename" select="concat(position(),'.xml')" />
                    <xsl:result-document href="{$filename}" format="xml">
                         <T0020>
                              <xsl:for-each select=". | following-sibling::t:IRP_ACCOUNT[position() < $size]">
                                   <xsl:copy-of select="." />
                              </xsl:for-each>
                         </T0020>
                    </xsl:result-document>
          </xsl:for-each>
     </xsl:template>
</xsl:stylesheet>
and i have done transformation like this ...
Transformer trans = tFactory.newTransformer(xslSource);
trans.transform(new StreamSource(xmlFileName), new DOMResult());
but not getting any result .
Can you please help me out ?
- Nisarg

Transform Large XML files with XSL

HELP, LARGE XML FILES
I have got 30 - 50 MB large xml file, and i would like to transform it
with xslt, i tried but i have got OutOfMemory Exception.
I tried to find out the solution on JAVA site, but i didn't find it.
I can not displit my xml file. I hope for some help.
I tried really everything.
Thanks a lot

What is your machine configuration ?
The above 2 suggestions would help, but it does depend on how your software is written.
Please post more info about your environment and object design.
Chintan

Combine several XML files with same structure

Hello,
I have several XML files with the same structure and I want to combine them and create a new XML file to be bale to compare that information easily. It does not look very difficult but as I am very new in this I am not bale to get it
The structure of my actual files would be something simlar to:
Root->...-> Name->Address, Telephone
And what I would like to have si something like
Root->.... ->Address-> Name 1,Name 2....
Root -> ...->Telephone-> Name 1, Name 2....
Does anyone know how to do this.
Thanks

You could write a XSL transformation file that does this and transform your input file via
     * Transform XML file with a style sheet.
     * <p><b>Example:</b><p>
<table align="center" bgcolor="#E0E0E0" border=1 cellpadding="10" cellspacing="0"><tr><td><pre style="margin-top:0; margin-bottom:0">
XMLTransformer t = new XMLTransformer();
FileOutputStream fos = new FileOutputStream("C:/Project/result.html");
String xmlFile = "C:/Project/source.xml";
String styleSheet = "C:/Project/stylesheet.xsl";
t.transform(xmlFile, styleSheet, fos);
</pre></td></tr></table>
     * @param xmlfile The XML file to transform.
     * @param style Stylesheet to use for transformation.
     * @param outputStream OutputStream to write the transformed result to.
    public void transform(String xmlfile, String style, OutputStream outputStream) {
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        //factory.setNamespaceAware(true);
        //factory.setValidating(true);
            //todo: use inputstreams instead of file names
            try {
                File stylesheet = new File(style);
                File datafile   = new File(xmlfile);
                DocumentBuilder builder = factory.newDocumentBuilder();
                document = builder.parse(datafile);
                // Use a Transformer for output
            TransformerFactory tFactory = TransformerFactory.newInstance();
            StreamSource stylesource = new StreamSource(stylesheet);
            Transformer transformer = tFactory.newTransformer(stylesource);
            DOMSource source = new DOMSource(document);
            StreamResult sr = new StreamResult(outputStream);
            transformer.transform(source, sr);
        } catch (TransformerConfigurationException tce) {
           // Error generated by the parser
           System.out.println ("\n**XMLTransformerr Factory error");
           System.out.println("   " + tce.getMessage() );
           // Use the contained exception, if any
           Throwable x = tce;
           if (tce.getException() != null) {
               x = tce.getException();
           x.printStackTrace();
        } catch (TransformerException te) {
           // Error generated by the parser
           System.out.println ("\n** Transformation error");
           System.out.println("   " + te.getMessage() );
           // Use the contained exception, if any
           Throwable x = te;
           if (te.getException() != null) {
               x = te.getException();
           x.printStackTrace();
         } catch (SAXException sxe) {
           // Error generated by this application
           // (or a parser-initialization error)
           Exception x = sxe;
           if (sxe.getException() != null) {
               x = sxe.getException();
           x.printStackTrace();
        } catch (ParserConfigurationException pce) {
            // Parser with specified options can't be built
            pce.printStackTrace();
        } catch (IOException ioe) {
           // I/O error
           ioe.printStackTrace();
    }//transform()

Issue with reading a xml file from xsl

Hi,
When I am trying to read a xml file from xsl, I am getting unwanted output.
Following is the XSL:
<?xml version="1.0" encoding="UTF-8" ?>
<?oracle-xsl-mapper

<mapSources>
    <source type="XSD">
      <schema location="../xsd/B2BMarketProperties.xsd"/>
      <rootElement name="ReceipentIDType" namespace="http://www.example.org"/>
    </source>
</mapSources>
<mapTargets>
    <target type="XSD">
      <schema location="../xsd/B2BMarketProperties.xsd"/>
      <rootElement name="ReceipentIDType" namespace="http://www.example.org"/>
    </target>
</mapTargets>

?>
<xsl:stylesheet version="1.0"
                xmlns:bpws="http://schemas.xmlsoap.org/ws/2003/03/business-process/"
                xmlns:xp20="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.Xpath20"
                xmlns:mhdr="http://www.oracle.com/XSL/Transform/java/oracle.tip.mediator.service.common.functions.MediatorExtnFunction"
                xmlns:bpel="http://docs.oasis-open.org/wsbpel/2.0/process/executable"
                xmlns:oraext="http://www.oracle.com/XSL/Transform/java/oracle.tip.pc.services.functions.ExtFunc"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                xmlns:ns0="http://www.example.org"
                xmlns:dvm="http://www.oracle.com/XSL/Transform/java/oracle.tip.dvm.LookupValue"
                xmlns:hwf="http://xmlns.oracle.com/bpel/workflow/xpath"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:med="http://schemas.oracle.com/mediator/xpath"
                xmlns:ids="http://xmlns.oracle.com/bpel/services/IdentityService/xpath"
                xmlns:bpm="http://xmlns.oracle.com/bpmn20/extensions"
                xmlns:xdk="http://schemas.oracle.com/bpel/extension/xpath/function/xdk"
                xmlns:xref="http://www.oracle.com/XSL/Transform/java/oracle.tip.xref.xpath.XRefXPathFunctions"
                xmlns:xsd="http://www.w3.org/2001/XMLSchema"
                xmlns:ora="http://schemas.oracle.com/xpath/extension"
                xmlns:socket="http://www.oracle.com/XSL/Transform/java/oracle.tip.adapter.socket.ProtocolTranslator"
                xmlns:ldap="http://schemas.oracle.com/xpath/extension/ldap"
                exclude-result-prefixes="xsi xsl ns0 xsd bpws xp20 mhdr bpel oraext dvm hwf med ids bpm xdk xref ora socket ldap">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:variable name="ReceipentID" select="document('../xsd/B2BMarketProperties.xml')"/>
<xsl:template match="/">
    <ns0:ReceipentIDType>
    <xsl:for-each select="$ReceipentID">
      <ns0:ReceipentID>
        <xsl:value-of select="$ReceipentID"/>
      </ns0:ReceipentID>
      </xsl:for-each>
    </ns0:ReceipentIDType>
</xsl:template>
</xsl:stylesheet>
Following is the XML ( B2BMarketProperties.xml)
<?xml version="1.0" encoding="UTF-8" ?>
<ReceipentIDType xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                 xsi:schemaLocation="http://www.example.org B2BMarketProperties.xsd"
                 xmlns="http://www.example.org">
<ReceipentID>123</ReceipentID>
<ReceipentID>345</ReceipentID>
</ReceipentIDType>
The output i am getting with this code is
<?xml version="1.0" encoding="UTF-8"?>
<ns0:ReceipentIDType xmlns:ns0="http://www.example.org">
    <ns0:ReceipentID>123345</ns0:ReceipentID>
</ns0:ReceipentIDType>
But, I need output in the following format
<ns0:ReceipentIDType xmlns:ns0="http://www.example.org">
    <ns0:ReceipentID>123</ns0:ReceipentID>
     <ns0:ReceipentID>345</ns0:ReceipentID>
</ns0:ReceipentIDType>
Could you guys let me know what i am doing wrong. Any help would be appreciated.
Thanks,

This worked for me :
<xsl:template match="/">
    <ns0:ReceipentIDType>
      <xsl:for-each select="document('B2BMarketProperties.xml')/*:ReceipentIDType/*:ReceipentID">
        <xsl:variable name="count" select="position()"/>
        <ns0:ReceipentID>
          <xsl:value-of select="document('B2BMarketProperties.xml')/*:ReceipentIDType/*:ReceipentID[$count]"/>
        </ns0:ReceipentID>
      </xsl:for-each>
    </ns0:ReceipentIDType>
</xsl:template>

Xml file with embedded xsl reports unknow error: An unknown error has occurred (805303f4)

Hi,
I have an xml file with embedded xsl link like below :
XML :
<pre><nowiki><?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="http://abc.com/x.xsl"?>
<catalog>
<cd>
<title>Empire Burlesque</title>
<artist>Bob Dylan</artist>
<country>USA</country>
<company>Columbia</company>
<price>10.90</price>
<year>1985</year>
</cd>
</catalog></nowiki></pre>
When opening xml file on IE, opera, safary ... it works ok. But when opening it on FireFox, i have an error like :
Error loading stylesheet: An unknown error has occurred (805303f4)
http://abc.com/x.xsl
How could i solve this problem ?

A good place to ask questions and advice about web development is at the mozillaZine Web Development/Standards Evangelism forum.
The helpers at that forum are more knowledgeable about web development issues.
You need to register at the mozillaZine forum site in order to post at that forum.
See http://forums.mozillazine.org/viewforum.php?f=25

How do you display xml file with xlst sheet in jsp

I have an xml file with accompanying xslt file (and several images that are used in a single directory. If I doubleclick on the xml file, it displays perfectly in my browser - Formatting, images and all!
          The 100 dollar question - How do I duplicate this behavior in a JSP page in WebLogic 8.1 using the code in the xml and the accompanying xslt (formatting) file? I tried simple embedding the xml code in the jsp, but that didn't seem to work. What is the secret?
          Okay, I need to add a bit more information here. I understand that it is really easy to just redirect to the XML file. The issue is really security. I want the XML to be inside a jsp that will only allow validated users to view it.
          Another way to look at the problem would be, can I add a jsp security tag to the xml file? Or how to I add the xml code inside a jsp and keep the path references to the xslt and graphics.
          Hope the added information helps
          Thanks,
          Ken
          Message was edited by: KLee - 20050609 10:25 MST
          [email protected]

This proved out to be the answer. Thanks for the direction!
          import java.io.File;
          import java.io.IOException;
          import java.io.InputStream;
          import java.io.OutputStream;
          import java.io.FileNotFoundException;
          import java.io.FileOutputStream;
          import javax.servlet.ServletException;
          import javax.servlet.http.HttpServlet;
          import javax.servlet.http.HttpServletRequest;
          import javax.servlet.http.HttpServletResponse;
          import javax.xml.transform.Transformer;
          import javax.xml.transform.TransformerConfigurationException;
          import javax.xml.transform.TransformerException;
          import javax.xml.transform.TransformerFactory;
          import javax.xml.transform.stream.StreamResult;
          import javax.xml.transform.stream.StreamSource;
          public class XML_XSLT_Servlet extends HttpServlet {
          protected void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
                    String xmlfile = req.getParameter("xmlfile"); if (xmlfile==null) xmlfile = "test.xml";
                    String xsltfile = req.getParameter("xsltfile"); if (xsltfile==null) xsltfile = "test.xslt";
                    /* Test if file exists!, or use default file */
                    File f1 = new File(getServletContext().getRealPath("WEB-INF/displayfiles/"), xmlfile);
                    File f2 = new File(getServletContext().getRealPath("WEB-INF/displayfiles/"), xsltfile);
               if (f1.exists() && f2.exists()) {
                         // System.out.println("Files Found");
                    } else {
                         System.out.println("XML and XSLT Files NOT Found");
                         System.out.println(f1.getPath());
                         System.out.println(f1.getName());
                         xmlfile = "test.xml";
                         xsltfile = "test.xslt";
          InputStream fileXML = getServletContext().getResourceAsStream("WEB-INF/displayfiles/" + xmlfile);
          InputStream fileXSLT = getServletContext().getResourceAsStream("WEB-INF/displayfiles/" + xsltfile);
          OutputStream os = res.getOutputStream();
          TransformerFactory xFactory = TransformerFactory.newInstance();
          StreamSource stylesheet = new StreamSource(fileXSLT);
          Transformer xformer = null;
          try {
          xformer = xFactory.newTransformer(stylesheet);
          } catch (TransformerConfigurationException tfce) {
          tfce.printStackTrace();
          StreamSource input = new StreamSource(fileXML);
          StreamResult output = null;
          try {
          output = new StreamResult(os);
          } catch (Exception e) {
          e.printStackTrace();
          try {
          xformer.transform(input, output);
          } catch (TransformerException xfe) {
          xfe.printStackTrace();
          <pre></pre><pre></pre>

Generate report from database using .xsl style sheet

I am trying to view test result histories for specific uut serial numbers.
We are logging all test data to the default access database template that was provided with Teststand.
Is there a method of generating reports from the database that match the format of those generated at runtime?
I was surprised to find that the default access database did not contain any gui or pre-made reports matching the xsl style sheets chosen in the report options dialog.
My database skills are weak, I am able to browse the raw data and I see the relationships between some of the tables, but the prospect of recreating one of the xml report formats in access seems daunting. Am I missing something? what is the best way to print a uut report from test data stored in access?

Hello msears,
Thank you for posting on the NI Discussion Forums. Unfortunately there are no tools available in TestStand for directly converting an Access database to a formatted .xsl report. It is possible to have a step in a sequence that reads the information from the database, and create the .xsl report as if it had been generated at sequence run-time, by writing those values directly to Locals.ResultList. Admittedly, this would require some knowledge of Microsoft Access, and the ability to write a program that will extract information from the database, in order to include it as a step in the sequence.
Is there anything stopping you from creating a formatted .xsl report when the sequence is run (instead of trying to create it from previous data stored in an Access database)?
Chris_G
Sr Test Engineer
Medtronic, Inc.

How Can I dispaly XML file with CSS?

hi,all
There is maybe a simple way to dispaly a XML file with a CSS file in program.But I don't know.Who can tell me?
Thank you very much!

Hi,
XML documents don't have the link or style elements that are used in HTML to connect style information to particular documents. Instead, the W3C has defined a processing instruction that provides that information, based on the model of the HTML link element. To connect a CSS style sheet to your XML document so that the browser can find it, use a processing instruction like
<?xml-stylesheet type="text/css" href="URI"?>
where URI is the address of the style sheet. We'll use a style sheet called display1.css for our first test document. The processing instruction can go right after the XML declaration.
<?xml version="1.0" ?>
<?xml-stylesheet type="text/css" href="display1.css"?>
<test>
Hope this may help you.
Regards,
Anil.
Technical Support Engineer.

Adding report header lines using expand.xsl style sheet

Hello
I would like to add a few header lines (appears only at the first page of the report) into my XML report that is based on expand.xsl style sheet.
Since I am not familiar with XML, is there any example or a modified (ready to run) expand.xsl style sheet that implements it?
Thank you
Zvika

Hey Zvika,
Chek out this website: http://zone.ni.com/devzone/cda/epd/p/id/4759
NI doesn't support any changes in the xsl however so if you change it you are on your own. You can look to this website for help with that: http://www.w3.org/XML/
Regards,
jigg
CTA, CLA
teststandhelp.com
~Will work for kudos and/or BBQ~

Finding and Editing the DynamicHomePage.xsl Style Sheet in MII 12.0

I'd like to edit the DynamicHomePage.xsl style sheet but I'd not sure where to find it in MII 12.0. Is it editable through the workbench?
Thanks!
David

David,
you can modify the Logo in the File DefaultHeader.xml. You can find it under the Web/Themens,
in the Sample Project as Jeremy said.
Please include this in your project as Jeremy described.
Regards
Pedro

Create XML file with worksheet's dynamically assigned through XSLT

Hi all
I have a requirement to create a xml file with worksheets dynamically created based on a field value in the internal table .
I have all my values in internal table, and am calling the transformation from bsp application.
Say the internal table has field dataxyz, for every change in value in this field dataxyz i need to create separate worksheet and populate that sheet with some corresponding values .
please guide me how to create worksheet dynamically.
thanks in advance.
Bharathy
Edited by: elam.bharathy on May 16, 2011 6:51 AM

Can you use a schema when we compose XML doc from Database tables?
Actually, I'm using SQL Server (sorry, wrong forum). But, I thought a Java tool would have a solution for me.

Xml file with xsl style sheet reference

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