SQL query - select one row from each date group

Hi,
I have data as follows.
Visit_Date Visit_type Consultant
05/09/2009 G name1
05/09/2009 G name2
05/09/2009 G name3
06/09/2009 I name4
07/09/2009 G name5
07/09/2009 G name6
How to select data as follows
05/09/2009 G name1
06/09/2009 G name4
07/09/2009 G name5
i.e one row from every visit_date
Thanks,
MK Nathan
Edited by: k_murali on Oct 7, 2009 10:44 PM

Are you after this (one row per date per visit_type)
with dd as (select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name1' Consultant from dual
            union all
            select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name2' Consultant from dual
            union all
            select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name3' Consultant from dual
            union all
            select to_date('06/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name4' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name5' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name6' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'F' Visit_type, 'name7' Consultant from dual)
select trunc(visit_date) visit_date, visit_type, min(consultant)
from   dd
group by trunc(visit_date), visit_type
order by trunc(visit_date);
VISIT_DAT V MIN(C
09/MAY/09 G name1
09/JUN/09 G name4
09/JUL/09 G name5
09/JUL/09 F name7or are you after only one row per date?:
with dd as (select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name1' Consultant from dual
            union all
            select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name2' Consultant from dual
            union all
            select to_date('05/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name3' Consultant from dual
            union all
            select to_date('06/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name4' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name5' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'G' Visit_type, 'name6' Consultant from dual
            union all
            select to_date('07/09/2009','MM/DD/YYYY') Visit_Date, 'F' Visit_type, 'name7' Consultant from dual)
select trunc(visit_date) visit_date, min(visit_type) visit_type, min(consultant)
from   dd
group by trunc(visit_date)
order by trunc(visit_date);
VISIT_DAT V MIN(C
09/MAY/09 G name1
09/JUN/09 G name4
09/JUL/09 F name5

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Frank,
You are marvelous.
That is what I was expecting, but basically I want to display the row with highest page rank which is 'A' and 'D' in this case.
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WITH mainq AS
     (SELECT a.file_name,
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FILE_1     4/1/2010     4/15/2010     B     1111     1     1     A     10     This must be in my result
FILE_1     4/16/2010     4/30/2010     N     1111     1     2     D     40     Must not be in my resultMy apologies that I gave you wrong forecast and memo values in my earlier post.
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Earlier I was using cursor to do that and it was not doing any good performance wise.
Thanks to every body for your time and your efforts.
I appreciate it.
Have fun.
~Raj

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Post Author: farnaz
CA Forum: WebIntelligence Reporting
I have 3 objcts that one of them is ID and second one is internal code and the third one is quantity.There is more than one value for each ID (becouse of internal code).I want to create a report based on ID and quantity (not based on internal code).I make a break on ID but the result shows me more than one row for each ID.so how can i have just one row for each ID?
another question:
how can I post screen shot of the results to my messag in forum?

Post Author: jsanzone
CA Forum: WebIntelligence Reporting
farnaz:
Have you tried to omit "internal code" from your grid? In normal circumstances, if you have "ID" and "Quantity" on the grid, then WebI will on its own summarize Quantity based on ID, however, this is provided that Quantity has been set up as a measure (or metric). The quickest way to tell if Quantity is a metric or not is to observe the color of its icon when you look at it in the data panel. If it is a purple (or sometimes appears as pink or fuscia) dot, then it's a measure, but if it is a blue box then it is a dimension. If you need Quantity as a measure then this will have to be modified at the universe (make it look like "sum(Quantity)" in the select phase of the object, and insure the object is defined as a number....

How to select a row from duplicate set of records?

I want to select a row from a duplicate set of records.
below is the explanation of my requirement.
select * from test_dup;
COL_BILL     COL_SERV     COL_SYS
b1     s1     c
b1     s1     g
b1     s2     c
b1     s2     g
b2     s2     g
b2     s3     c
b2     s3     g
b3     s3     c
Here what I want is, for a distinct col_sys if col_bill and col_serv is same then I need the row where col_sys='c'
from the above result set I need the following:
b1     s1     c
b1     s2     c
b2     s3     c
I am using the following SQL query which is giving me the correct result set. But it will hamper the performance because there are total 45 columns in the table and total volume is around 50 million.
select * from test_dup where col_bill||col_serv in (
select col_bill||col_serv from (
select col_bill,col_serv,count(*) from test_dup
where col_sys in ('c','g')
group by col_bill,col_serv having count(*) >1)) and
col_sys='c';
Can anyone please provide me the optimize SQL query for the same.

Hi,
Another way,
SQL> with test_dup
as
     select 'b1' col_bill, 's1' col_serv, 'c' col_sys from dual union all
     select 'b1', 's1', 'g' from dual union all
     select 'b1', 's2', 'c' from dual union all
     select 'b1', 's2', 'g' from dual union all
     select 'b2', 's2', 'g' from dual union all
     select 'b2', 's3', 'c' from dual union all
     select 'b2', 's3', 'g' from dual union all
     select 'b3', 's3', 'c' from dual
select col_bill, col_serv, min(col_sys) col_sys
    from test_dup
   where col_sys in ('c', 'g')
group by col_bill, col_serv
having count( * ) > 1
     and count(nullif(col_sys, 'g')) > 0;
CO CO C
b1 s1 c
b2 s3 c
b1 s2 c
3 rows selected.Regards
Peter
Edited by: Peter on Feb 18, 2009 1:10 AM
- Added test data, thanks Karthick

Help with this sql. Select only employees from a distinct Org??

Hi guys, simple query.
create table balancetest(emp_id number, balance_id number, balance number, org number);
insert into balancetest values (111, 1, 1, 0);
insert into balancetest values (111, 1, 1, 0);
insert into balancetest values (111, 2, 1, 1);
insert into balancetest values (222, 1, 2, 1);
insert into balancetest values (333, 3, 4, 3);
insert into balancetest values (333, 3, 4, 2);
commit;
SQL> select * from balancetest;
    EMP_ID BALANCE_ID    BALANCE        ORG
       111          1          1          0
       111          1          1          0
       111          2          1          1
       222          1          2          1
       333          3          4          3
       333          3          4          2
6 rows selected.As you can see, emp_id 111 appears on different Org (0 and 1). I need to calculate the balance but the requirement says that I need to retrieve employees appearing only in 1 org.. It won't matter which org is selected (the business rules ensure balance will be the same), as long as if an employee is in multiple org, this employee is selected only once for an org. So, my result will be something like:
    EMP_ID BALANCE_ID    BALANCE        ORG
       111          1          1          0
       111          1          1          0
       222          1          2          1
       333          3          4          3
       333          3          4          2or,
    EMP_ID BALANCE_ID    BALANCE        ORG
       111          2          1          1
       222          1          2          1
       333          3          4          3
       333          3          4          2In other words, an employee must appear only in 1 org in my result.
any ideas? I tried:
select * from balancetest bal1
where not exists ( select bal2.emp_id from
                           balancetest bal2
                           where bal2.emp_id = bal1.emp_id
                           and bal2.org <> bal1.org
                           );But I guess it won't be that simple!!

Hi,
You can find the lowest-numbered org for each employee like this:
SELECT    emp_id
,         MIN (org) AS min_org
FROM      balancetest
GROUP BY emp_id;You can get the results you want by selecting only rows from balancetest that match a row in this the result set above. There are many ways to do that, such as a join:
WITH g AS
    SELECT    emp_id
    ,         MIN (org) AS min_org
    FROM      balancetest
    GROUP BY emp_id
SELECT b.*
FROM    balancetest b
JOIN                 g ON b.emp_id = g.emp_id
                        AND b.org    = g.min_org;

SQL query - select one row from each date group

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