SQL query to count number of VMs

In OVM 2.2 I could run a SQL query against the OVM database to count the number of VMs that I had created, for automated reporting purposes.
I've looked at the 3.1 OVM database and it looks like most of the data is kept in BLOB columns. So does anyone know how I might query the 3.1 database to count the number of VMs?
Thanks.

Hi,
Combine the relevant data from the three tables (using UNION ALL) in a sub-query. without the GROUP BY.
Your main query can select from the sub-query's result set, as if it were a table. Do the GROUP BY in the main query.
That is:
WITH     u     AS
     SELECT     TO_CHAR (emp_start, 'YYYY') AS yr     FROM     Adminstaff
    UNION ALL
     SELECT     TO_CHAR (emp_start, 'YYYY') AS yr     FROM     Clerk
    UNION ALL
     SELECT     TO_CHAR (emp_start, 'YYYY') AS yr     FROM     ITstaff
SELECT     COUNT (*)      AS cnt
,     yr
FROM     u
GROUP BY     yr
ORDER BY     cnt     DESC
;Since empno is the primary key, it's easier not to mention empno at all in the sub-query, and use "COUNT (*)" instead of "COUNT (empno)" in the main query. The results are the same.
It might be a little more efficient to GROUP BY in all three branches of the sub-query, and then to SUM the results in another GROUP BY in the main query. That means more code, of course, which I'll leave as an exercise for you.
Why do you have three separate tables? I can understand that nobody else wants to be near the IT Staff, but it seems like lots of things (including this job) would be a lot simpler if all employees were all in one table, with a column to designate to which group (Adminstaff, Clerk or ITStaff) each one belongs.

Similar Messages

How to write sql query for counting pairs from below table??

Below is my SQL table structure.
user_id | Name | join_side | left_leg | right_leg | Parent_id
100001 Tinku Left 100002 100003 0
100002 Harish Left 100004 100005 100001
100003 Gorav Right 100006 100007 100001
100004 Prince Left 100008 NULL 100002
100005 Ajay Right NULL NULL 100002
100006 Simran Left NULL NULL 100003
100007 Raman Right NULL NULL 100003
100008 Vijay Left NULL NULL 100004
It is a binary table structure.. Every user has to add two per id under him, one is left_leg and second is right_leg... Parent_id is under which user current user is added.. Hope you will be understand..
I have to write sql query for counting pairs under id "100001". i know there will be important role of parent_id for counting pairs. * what is pair( suppose if any user contains both left_leg and right_leg id, then it is called pair.)
I know there are three pairs under id "100001" :-
1. 100002 and 100003
2. 100004 and 100005
3. 100006 and 100007
100008 will not be counted as pair because it does not have right leg..
But i dont know how to write sql query for this... Any help will be appreciated... This is my college project... And tommorow is the last date of submission.... Hope anyone will help me...
Suppose i have to count pair for id '100002'. Then there is only one pair under id '100002'. i.e 100004 and 100005

Sounds like this to me
DECLARE @ID int
SET @ID = 100001--your passed value
SELECT left_leg,right_leg
FROM table
WHERE (user_id = @ID
OR parent_id = @ID)
AND left_leg IS NOT NULL
AND right_leg IS NOT NULL
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

Sql query to get number of days monthwise

Hi,
i am new to sql, can anyone please tell me query to find number of working days between two dates month wise.
say
firstdate last date
21/03/2011 25/06/2011
march april may june
9 22 23 18

Hi,
918373 wrote:
even a result like,
stud_id month amount
1234 MAR-11 xyz
1234 JUL-11 ...Please post the exact output that you want.
Do you want 'xyz' in the output, or do you want a number like 42 (2 hours * 6 weekdays in March 2011, plus 5 hpours * 6 weekdays = 12 + 30 = 42)?
If you want 42, then post 42. Spend 5 minutes (if it comes to that much) with a calendar and a calculator to get the exact results you want.
>
>
is much better,
in that case i want it as a view, so that i can get further details from the view....Substituting your table and column names, into the query I posted earlier and replacing COUNT (*) with SUM (no_of_hours), the query is
WITH     cntr     AS
     SELECT     LEVEL - 1     AS n
     FROM     (
              SELECT MAX (enddate - startdate)     AS days_in_range
              FROM    class_dets
     CONNECT BY     LEVEL     <= 1 + days_in_range
SELECT       x.stud_id
,       TO_CHAR ( TRUNC (x.startdate + c.n, 'MONTH')
            , 'fmMonth YYYY'
            )               AS month
,       SUM (no_of_hours)          AS total_hours
FROM       class_dets x
JOIN       cntr        c ON   x.enddate >= x.startdate + c.n
WHERE       TO_CHAR ( x.startdate + c.n
              , 'DY'
            , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If necessary
            )      NOT IN ('SAT', 'SUN')
GROUP BY x.stud_id
,            TRUNC (x.startdate + c.n, 'MONTH')
ORDER BY x.stud_id
,            TRUNC (x.startdate + c.n, 'MONTH')
;The output, with the sample data you posted, is:
` STUD_ID MONTH                                     TOTAL_HOURS
      1234 March 2011                                         42
      1234 April 2011                                        147
      1234 May 2011                                          154
      1234 June 2011                                         154
      1234 July 2011                                          72
      1234 August 2011                                        46
      1234 September 2011                                     14
      1235 June 2011                                          36
      1235 July 2011                                          84
      1235 August 2011                                        92
      1235 September 2011                                     88
      1235 October 2011                                       12
      1236 June 2012                                          56
      1236 July 2012                                         154
      1236 August 2012                                        14Aside from pivoting, is that what you want?
i edited the your query,
WITH     all_dates     AS
     SELECT     start_date + LEVEL - 1     AS a_date
     FROM     (
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=1236), 'DD/MM/YYYY')     AS start_date
               ,     TO_DATE ((select enddate from class_dets where stud_id=1236), 'DD/MM/YYYY')     AS end_dateInstead of the 2 lines above, the query I posted had
SELECT MAX (enddate - startdate)     AS days_in_rangeWhy did you make that change?
The first argument to TO_DATE is supposed to be a string. You're calling TO_DATE with this as the first argument
(select startdate from class_dets where stud_id=1236)which is a DATE, not a string.
               FROM     dual
     CONNECT BY     LEVEL     <= end_date + 1 - start_date
SELECT     TO_CHAR ( TRUNC (a_date, 'MONTH')
          , 'fmMonth YYYY'
          )               AS month
,     COUNT (*) * (select fee from class_dets where stud_id=1236) * (select no_of_hours from class_dets where stud_id=1236)               AS amount
FROM     all_dates
WHERE     a_date - TRUNC (a_date, 'IW')     < 5
GROUP BY TRUNC (a_date, 'MONTH')
ORDER BY TRUNC (a_date, 'MONTH')
it works very well, but instead of specifying stud_id as 1236,
but when i say,
WITH     all_dates     AS
     SELECT     start_date + LEVEL - 1     AS a_date
     FROM     (
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=cd.stu_id), 'DD/MM/YYYY')     AS start_date
               ,     TO_DATE ((select enddate from class_dets where stud_id=cd.stud_id), 'DD/MM/YYYY')     AS end_date
               FROM     dual
     CONNECT BY     LEVEL     <= end_date + 1 - start_date
SELECT     cd.stud_id,TO_CHAR ( TRUNC (a_date, 'MONTH')
          , 'fmMonth YYYY'
          )               AS month
, count(*)
,     COUNT (*) * (select fee from class_dets where stud_id=1236) * (select no_of_hours from class_dets where stud_id=1236)               AS amount
FROM     all_dates,class_dets cd
WHERE     a_date - TRUNC (a_date, 'IW')     < 5
GROUP BY TRUNC (a_date, 'MONTH'),cd.stud_id
ORDER BY TRUNC (a_date, 'MONTH'),cd.stud_id
i get error
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=cd.stu_id), 'DD/MM/YYYY')     AS start_date
ERROR at line 6:
ORA-00904: "CD"."STU_ID": invalid identifierThere's no column called stu_id in class_dets. There is a column called stud_id (with 2 'd's).
>
what should i do?
(sorry about the query format...how display query in a formatted way? )This site noramlly compresses whitespace.
Whenever you post formatted text (including, but not limited to, code) on this site, type these 6 characters:
\(small letters only, inside curly brackets) before and after each section of formatted text, to preserve spacing.

Sql query to count

Hi guys,
I need to count number of values in one column which I need to query it and display the count and values as two.
column_name data
moderator yes,no
so here in the moderator column there is two values with ',' separator. now I need to take count as two values.
Please suggest me how to query this as count is 2. Can any one help on this.
Thanks in advance!
Regards,
LK

WITH T AS (
SELECT 'yes,no' MCOL FROM DUAL
UNION
SELECT 'yes' MCOL FROM DUAL
UNION
SELECT 'no' MCOL FROM DUAL
SELECT SUM(CASE WHEN INSTR(MCOL,',') > 0 THEN 2 ELSE 1 END) TOTAL FROM t;If you'll have more than 1 comma in your values, there can be written a function to count commas etc...
Best Regards,
Gokhan
If this question is answered, please mark appropriate posts as correct/helpful and the thread as closed. Thanks

QUERY WHICH COUNTS NUMBER OF TIMES WORDS/LETTER APPEAR IN SENTENCE - Thanks

I have this query below
it gives the number of times a txn is hign comfort and Approved
.. nyumber of times txn is meduim comfort and approved etc.
There is a futher line whihc shows the number of times txn is blacklisted BL COUNT.
I am trying to get line of query which can show me the number of times txn is approved, is high comfort and blcklisted ( the same applies for
wl - watch listed)
The query i am using
SUM
(CASE
WHEN cc.Comment
LIKE ('BL(%') and cc.Comment
LIKE ('Approved%')
AND cc.Comment
LIKE ('%ComfortLevel=High Comfort%')
THEN 1
ELSE 0 END)AS hbcl - NO RESULTS BEING GIVEN
pLEASE CAN ANYONE HELP,. THANKS
QUERY
USE RiskManagementReporting
GO
DECLARE
@StartDate DATETIME,
@EndDate DATETIME
SET @StartDate
= '2014-01-01 00:00:00'
SET @EndDate
= '2014-03-31 23:59:59'
SELECT
CONVERT
(VARCHAR(10),
mt.OPacket_TransactionTime, 102)
AS [Date],
SUM
(CASE
WHEN cc.Comment
LIKE ('Approved%')
AND cc.Comment
LIKE ('%ComfortLevel=High Comfort%')
THEN 1 ELSE 0
END) AS [A - HighC],
SUM
(CASE
WHEN cc.Comment
LIKE ('Approved%')
AND cc.Comment
LIKE ('%ComfortLevel=Medium Comfort%')
THEN 1 ELSE 0
END) AS [A - MediumC],
SUM
(CASE
WHEN cc.Comment
LIKE ('Approved%')
AND cc.Comment
LIKE ('%ComfortLevel=Low Comfort%')
THEN 1 ELSE 0
END) AS [A - LowC],
SUM
(CASE
WHEN cc.Comment
LIKE ('Declined%')
AND cc.Comment
LIKE ('%ComfortLevel=Low Risk%')
THEN 1 ELSE 0
END) AS [D - LowR],
SUM
(CASE
WHEN cc.Comment
LIKE ('Declined%')
AND cc.Comment
LIKE ('%ComfortLevel=Medium Risk%')
THEN 1 ELSE 0
END) AS [D - MediumR],
SUM
(CASE
WHEN cc.Comment
LIKE ('Declined%')
AND cc.Comment
LIKE ('%ComfortLevel=High Risk%')
THEN 1 ELSE 0
END) AS [D - HighR],
SUM
(CASE
WHEN cc.Comment
LIKE ('BL(%')
THEN 1 ELSE 0
END) AS [BL Count],
SUM
(CASE
WHEN cc.Comment
LIKE ('WL(%')
THEN 1 ELSE 0
END) AS [WL Count],
SUM
(CASE
WHEN cc.Comment
LIKE ('Marked as Touched%')
THEN 1 ELSE 0
END) AS [Touched by DRT],
COUNT
(mt.csnTransactionId)
AS [Sent to DRT]
FROM MatchedTransaction mt
WITH (NOLOCK)
LEFT
JOIN CustomerComment cc
WITH (NOLOCK)
ON (mt.csnTransactionId
= cc.SenderMTCN
AND cc.InsertDate
BETWEEN @StartDate AND
DATEADD (D, 1, @EndDate)

I have adjusted this as
SUM
(CASE
WHEN cc.Comment
LIKE ('Approved%')
AND cc.Comment
LIKE ('%ComfortLevel=High Comfort%')
AND cc.Comment
LIKE ('%BL(%')THEN 1
ELSE 0 END)
AS hcbl,
Still no result

SQL query - using COUNT

I have a database structure like this:
Table - lodges
LodgeID (PK)
Lodge
etc
Table - scores
ScoreID (PK)
Score
CategoryID
LodgeID (FK)
I'm trying to return results in the form:
LodgeID, Lodge, Category, Number of Scores in that Category, Average Score in that Category
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lodges
LodgeID, Lodge
1, Lodge One
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1, 3, 101, 1
2, 5, 101, 1
3, 7, 101, 1
4, 10, 102, 2
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6, 30, 102, 2
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Ignore that - just needed to add a GROUP BY clause.

SQL QUERY FOR COUNT

HI all,
I need to know the no of records in a table in sap..
can anybody help on this how to get the count of the records.?
thanks in advance
kp

Hi KP,
You can code it this way
data var type i.
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write : var.
Here
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Hi,
I want to know how to a convert number (say, 54678) into hh:mi:ss format.
Any help.
Thanks.

You can test/troubleshoot it. This may or may not be perfect, you need to reverse engineer it and find (any) mistakes/logic errors. Hint: there is one.
set serveroutput on
create or replace procedure get_time (sod in number) as
v_diff number;
v_current number;
v_date date;
begin
v_current := to_number(to_char(sysdate,'SSSSS'));
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exec get_time(54678);
At the tone, the time is 03:11:18 PM
PL/SQL procedure successfully completed.Message was edited by:
stevencallan
Message was edited by:
stevencallan

SQL query that counts records??

I have an equipment maintenance table and I'm trying get a list of unique equipment IDs along with a count of total maintenance records for that peice of equipment.
Say for instance the table is set up like this
maintenance_table
equipment_id varchar(20)
maintenance_date DATE
maintenancelog_id varchar(20)
I'm trying to do something like
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condition = 'something';
The subquery works fine when I hard code an id in it, but I need it to be dynamic and show the correct count for each row.
Can anyone help?
Thanks,
George

SELECT equipment_id, count(*) from maintenance_table group by equipment_id;

SQL query - show integer number as text

Hello,
how can I reads data from the db that is either "-1" or "1" (it's define as integer)
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Thank you
Gian

Hi,
You can also do this:
select decode(<your_column>,-1,'YES','NO') from <your_table>;
Peter D.

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3 /
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SQL query to count number of VMs

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