Sql query to get number of days monthwise

Question

Hi,
i am new to sql, can anyone please tell me query to find number of working days between two dates month wise.
say
firstdate last date
21/03/2011 25/06/2011
march april may june
9 22 23 18

Answer 1

Hi,
918373 wrote:
even a result like,
stud_id month amount
1234 MAR-11 xyz
1234 JUL-11 ...Please post the exact output that you want.
Do you want 'xyz' in the output, or do you want a number like 42 (2 hours * 6 weekdays in March 2011, plus 5 hpours * 6 weekdays = 12 + 30 = 42)?
If you want 42, then post 42. Spend 5 minutes (if it comes to that much) with a calendar and a calculator to get the exact results you want.
>
>
is much better,
in that case i want it as a view, so that i can get further details from the view....Substituting your table and column names, into the query I posted earlier and replacing COUNT (*) with SUM (no_of_hours), the query is
WITH     cntr     AS
     SELECT     LEVEL - 1     AS n
     FROM     (
              SELECT  MAX (enddate - startdate)     AS days_in_range
              FROM    class_dets
     CONNECT BY     LEVEL     <= 1 + days_in_range
SELECT       x.stud_id
,       TO_CHAR ( TRUNC (x.startdate + c.n, 'MONTH')
            , 'fmMonth YYYY'
            )               AS month
,       SUM (no_of_hours)          AS total_hours
FROM       class_dets  x
JOIN       cntr        c  ON   x.enddate >= x.startdate + c.n
WHERE       TO_CHAR ( x.startdate + c.n
              , 'DY'
            , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If necessary
            )      NOT IN ('SAT', 'SUN')
GROUP BY  x.stud_id
,            TRUNC (x.startdate + c.n, 'MONTH')
ORDER BY  x.stud_id
,            TRUNC (x.startdate + c.n, 'MONTH')
;The output, with the sample data you posted, is:
`  STUD_ID MONTH                                     TOTAL_HOURS
      1234 March 2011                                         42
      1234 April 2011                                        147
      1234 May 2011                                          154
      1234 June 2011                                         154
      1234 July 2011                                          72
      1234 August 2011                                        46
      1234 September 2011                                     14
      1235 June 2011                                          36
      1235 July 2011                                          84
      1235 August 2011                                        92
      1235 September 2011                                     88
      1235 October 2011                                       12
      1236 June 2012                                          56
      1236 July 2012                                         154
      1236 August 2012                                        14Aside from pivoting, is that what you want?
i edited the your query,
WITH     all_dates     AS
     SELECT     start_date + LEVEL - 1     AS a_date
     FROM     (
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=1236), 'DD/MM/YYYY')     AS start_date
               ,     TO_DATE ((select enddate from class_dets where stud_id=1236), 'DD/MM/YYYY')     AS end_dateInstead of the 2 lines above, the query I posted had
SELECT  MAX (enddate - startdate)     AS days_in_rangeWhy did you make that change?
The first argument to TO_DATE is supposed to be a string. You're calling TO_DATE with this as the first argument
(select startdate from class_dets where stud_id=1236)which is a DATE, not a string.
               FROM     dual
     CONNECT BY     LEVEL     <= end_date + 1 - start_date
SELECT     TO_CHAR ( TRUNC (a_date, 'MONTH')
          , 'fmMonth YYYY'
          )               AS month
,     COUNT (*) * (select fee from class_dets where stud_id=1236) * (select no_of_hours from class_dets where stud_id=1236)               AS amount
FROM     all_dates
WHERE     a_date - TRUNC (a_date, 'IW')     < 5
GROUP BY TRUNC (a_date, 'MONTH')
ORDER BY TRUNC (a_date, 'MONTH')
it works very well, but instead of specifying stud_id as 1236,
but when i say,
WITH     all_dates     AS
     SELECT     start_date + LEVEL - 1     AS a_date
     FROM     (
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=cd.stu_id), 'DD/MM/YYYY')     AS start_date
               ,     TO_DATE ((select enddate from class_dets where stud_id=cd.stud_id), 'DD/MM/YYYY')     AS end_date
               FROM     dual
     CONNECT BY     LEVEL     <= end_date + 1 - start_date
SELECT     cd.stud_id,TO_CHAR ( TRUNC (a_date, 'MONTH')
          , 'fmMonth YYYY'
          )               AS month
, count(*)
,     COUNT (*) * (select fee from class_dets where stud_id=1236) * (select no_of_hours from class_dets where stud_id=1236)               AS amount
FROM     all_dates,class_dets cd
WHERE     a_date - TRUNC (a_date, 'IW')     < 5
GROUP BY TRUNC (a_date, 'MONTH'),cd.stud_id
ORDER BY TRUNC (a_date, 'MONTH'),cd.stud_id
i get error
               SELECT     TO_DATE ((select startdate from class_dets where stud_id=cd.stu_id), 'DD/MM/YYYY')     AS start_date
ERROR at line 6:
ORA-00904: "CD"."STU_ID": invalid identifierThere's no column called stu_id in class_dets. There is a column called stud_id (with 2 'd's).
>
what should i do?
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