SQL select all sessionid for which ONLY exist actionid 1 OR 2 OR 5

Question

Create Table:
create table x ( sessionid number, actionid number, sessionactionid number, a3 varchar2(10));
Inserts;
insert into x values (1000, 1, 100, 'asdfsadf' );
insert into x values (1000, 2, 101, 'asdfsadf' );
insert into x values (1000, 3, 102, 'asdfsadf' );
insert into x values (1000, 4, 103, 'asdfsadf' );
insert into x values (1001, 1, 104, 'asdfsadf' );
insert into x values (1001, 3, 105, 'asdfsadf' );
insert into x values (1001, 6, 106, 'asdfsadf' );
insert into x values (1001, 1, 107, 'asdfsadf' );
insert into x values (1001, 1, 108, 'asdfsadf' );
insert into x values (1002, 1, 109, 'asdfsadf' );
insert into x values (1002, 2, 110, 'asdfsadf' );
insert into x values (1002, 5, 111, 'asdfsadf' );
insert into x values (1003, 1, 112, 'asdfsadf' );
insert into x values (1003, 2, 113, 'asdfsadf' );
insert into x values (1003, 5, 114, 'asdfsadf' );
insert into x values (1003, 4, 115, 'asdfsadf' );
insert into x values (1004, 2, 116, 'asdfsadf' );
insert into x values (1004, 5, 117, 'asdfsadf' );
Query to resolve;
select all sessionid for which ONLY exist one actionid for each of 1 and 2 and 5
also important that all 3 actionid must exist for that sessionid otherwise that record is not valid for us.
with the table above the result should be;
SESSIONID
=======
1002
PS: Sorry my db is not accessible at the moment and therefore could not test the above CREATE and INSERTS statements.
Edited by: Andre on Jan 19, 2012 5:17 PM

Answer 1

Hi, Andre,
Andre wrote:
Create Table:
create table x ( sessionid number, actionid number, sessionactionid number, a3 varchar2(10));
Inserts;
insert into x values (1000, 1, 100, 'asdfsadf' );
insert into x values (1000, 2, 101, 'asdfsadf' );
insert into x values (1000, 3, 102, 'asdfsadf' );
insert into x values (1000, 4, 103, 'asdfsadf' );
insert into x values (1001, 1, 104, 'asdfsadf' );
insert into x values (1001, 3, 105, 'asdfsadf' );
insert into x values (1001, 6, 106, 'asdfsadf' );
insert into x values (1001, 1, 107, 'asdfsadf' );
insert into x values (1001, 1, 108, 'asdfsadf' );
insert into x values (1002, 1, 109, 'asdfsadf' );
insert into x values (1002, 2, 110, 'asdfsadf' );
insert into x values (1002, 5, 111, 'asdfsadf' );
insert into x values (1003, 1, 112, 'asdfsadf' );
insert into x values (1003, 2, 113, 'asdfsadf' );
insert into x values (1003, 5, 114, 'asdfsadf' );
insert into x values (1003, 4, 115, 'asdfsadf' );
insert into x values (1004, 2, 116, 'asdfsadf' );
insert into x values (1004, 5, 117, 'asdfsadf' );
Query to resolve;
select all sessionid for which ONLY exist one actionid for each of 1 and 2 and 5
also important that all 3 actionid must exist for that sessionid otherwise that record is not valid for us.
with the table above the result should be;
SESSIONID
=======
1002Why isn't 1003 included? It has only 1 each of 1, 2, and 5, and it has all 3 of those actionids.
This does what you requested:
SELECT       sessionid
FROM       x
WHERE       actionid     IN (1, 2, 5)
GROUP BY  sessionid
HAVING       COUNT (actionid)          = 3
AND       COUNT (DISTINCT actionid)     = 3
;This does not assume anything is uniue.
Did you mean that the sessionids displayed must not have any actionids other than 1, 2 and 5? If so:
SELECT       sessionid
FROM       x
GROUP BY  sessionid
HAVING       COUNT (actionid)          = 3
AND       COUNT (DISTINCT actionid)     = 3
AND       COUNT ( CASE
               WHEN  actionid  IN (1, 2, 5)
               THEN  1
            END
          )               = 3
;Either way, GROUP BY ... HAVING is a natural way to approach the problem. You're interested in groups of rows, not single rows (that's what GROUP BY is all about), and the group as a whole must meet certain conditions (that's what HAVING is all about).
Edited by: Frank Kulash on Jan 19, 2012 11:22 PM
Added 2nd guess