Starting RMIRegistry

I could not able to start or locate RmiRegistry. I am getting Error like this :
java.lang.SecurityException: SHA MessageDigest not available
at sun.rmi.server.UnicastServerRef.computeMethodHash(UnicastServerRef.java:573)
at sun.rmi.server.UnicastServerRef.createMethodTable(UnicastServerRef.java:533)
at sun.rmi.server.UnicastServerRef.getMethodTable(UnicastServerRef.java:477)
at sun.rmi.server.UnicastServerRef.exportObject(UnicastServerRef.java:126)
at sun.rmi.registry.RegistryImpl.setup(RegistryImpl.java:95)
at sun.rmi.registry.RegistryImpl.<init>(RegistryImpl.java:81)
at sun.rmi.registry.RegistryImpl.main(RegistryImpl.java:320)
Please help me on this. what should i do ???
I Am running on Windows NT server.
REgards
Sampath Ramanujan

It's a little hard to understand what you are doing and what you want just by an error message.
For starting the rmiregistry:
type 'rmiregistry' in a console box. It's an application located in your /bin/ directory of your JDK installation.
As for being unable to locate the RMI registry. I rather see you code on how you try to locate it, because just this error doesn't give me a clue what might be wrong. So, please post your code.. Use the '[ code ]' and '[ /code ]' tags please.
Regards,

Similar Messages

How do I start "rmiregistry" from Eclipse IDE?

Could somebody tell me how I can start rmiregistry from the Eclipse IDE which is running j2se 5.0 ?
Also if I try starting from the command prompt I get
Windows cannot find rmiregistry
with
C:\>java -version
java version "1.5.0_06"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.5.0_06-b05)
Java HotSpot(TM) Client VM (build 1.5.0_06-b05, mixed mode, sharing)

You need a plugin to start/stop your rmi registry. Search for plugins in google.
You need to set the classpath for starting the rmi registry from console.

Starting RMIRegistry in ksh, how to set classpath?

Hi,
I'm a newbie to Unix and have a question. Here's the situation:
I'm
using HP-UX version 11.0 with the latest complete JDK 1.1.7 avail
for
that platform. The shell is ksh. I have a classpath exported
from my
.profile file. I start the rmi registry with the command
"$rmiregistry
&". It starts alright but can NOT find my stub files!
What am I missing? Does the child process I create inherit my
environment settings? How am I or how is the rmi registry
executable
determine the classpath??
Any help would be appreciated.
Frank
null

Frank,
Thanks for your help, but found my problem. I was using an
environment variable that was lowercase, rmiregistry was looking
for it as UPPERCASE!
Thanks,
Frank
~~~~~~~~~~~~~~~~~~~~~~~~~
Frank Zhang (guest) wrote:
: Frank:
: You could start rmiregistry in your server's constructor, if it
: is an option.
: Frank
: Frank Garber (guest) wrote:
: : Hi,
: : I'm a newbie to Unix and have a question. Here's the
: situation:
: : I'm
: : using HP-UX version 11.0 with the latest complete JDK 1.1.7
: avail
: : for
: : that platform. The shell is ksh. I have a classpath
exported
: : from my
: : .profile file. I start the rmi registry with the command
: : "$rmiregistry
: : &". It starts alright but can NOT find my stub files!
: : What am I missing? Does the child process I create inherit
my
: : environment settings? How am I or how is the rmi registry
: : executable
: : determine the classpath??
: : Any help would be appreciated.
: : Frank
null

Can i start rmiregistry from inside class, and then bind to it, etc?

I want to have my app running and then have it start RMIregistry. if registry is already running, it attaches to it and binds itself.
if registry not already running, it starts it and then binds to it.
Also, if i did this, how would an app on another server find it?
how would it check to see if registry from similar app is running on another computer?

I want to have my app running and then have it start RMIregistryHave a look on java.rmi.registry.LocateRegistry class. It provides methods to create registry from the application (createRegistry) and one to check for registry running (getRegistry).
how would it check to see if registry from similar app is running on another computer?Registry is always "seen" over the network, though you have to use the same port. This service is global even if you start it from application.
Best regards,
Martin

Can't start rmiregistry from application

Hi!
This is my code, which works, when I start rmiregistry from command-line:
public class RemoteDBStarter extends RMIStarter {
private final static int PORT = 2359;
private final static String NAME = "DB";
public RemoteDBStarter() {
    super(RemoteDBInterface.class);
public void serverOrClientContinue() {
    try {
      RemoteDBInterface db = new RemoteDB();
      RemoteDBInterface stub = (RemoteDBInterface)UnicastRemoteObject
          .exportObject(db, PORT);
      Registry registry = LocateRegistry.getRegistry();
      registry.rebind(NAME, stub);
    catch(Exception e) {
      //TODO
      e.printStackTrace();
public static void main(String[] args) {
    new RemoteDBStarter();
}But when I try to add createRegistry
LocateRegistry.createRegistry(PORT);
RemoteDBInterface db = new RemoteDB();
RemoteDBInterface stub = (RemoteDBInterface)UnicastRemoteObject
    .exportObject(db, PORT);I get exception
java.rmi.ConnectException: Connection refused to host: 10.x.x.x; nested exception is:
     java.net.ConnectException: Connection refused: connect
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:574)
     at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:185)
     at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:171)
     at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:306)
     at sun.rmi.registry.RegistryImpl_Stub.rebind(Unknown Source)
     at server.RemoteDBStarter.serverOrClientContinue(RemoteDBStarter.java:32)
     at common.RMIStarter.<init>(RMIStarter.java:15)
     at server.RemoteDBStarter.<init>(RemoteDBStarter.java:16)
     at server.RemoteDBStarter.main(RemoteDBStarter.java:41)
Caused by: java.net.ConnectException: Connection refused: connect
     at java.net.PlainSocketImpl.socketConnect(Native Method)
     at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333)
     at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195)
     at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:182)
     at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366)
     at java.net.Socket.connect(Socket.java:520)
     at java.net.Socket.connect(Socket.java:470)
     at java.net.Socket.<init>(Socket.java:367)
     at java.net.Socket.<init>(Socket.java:180)
     at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:22)
     at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:128)
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:569)
     ... 8 moreI tried to set hostname
System.setProperty("java.rmi.server.hostname", "localhost");but it gives me same exception, as if it didn't even look for this property. Any suggestions?

I'm getting lost here, so I'll put whole code once more:
Server
public class RemoteDBStarter {
private final static int PORT = 1099;
private final static String NAME = "DB";
private static Registry registry;
public static void main(String[] args) throws ClassNotFoundException,
                                                SQLException {
    System.setProperty("java.security.policy",
        "D:/work/data/allow_all.policy");
    if(System.getSecurityManager() == null) {
      System.setSecurityManager(new SecurityManager());
    try {
      registry = LocateRegistry.createRegistry(PORT);
      RemoteDBInterface db = new RemoteDB();
      RemoteDBInterface stub = (RemoteDBInterface)UnicastRemoteObject
          .exportObject(db, PORT);
      registry.rebind(NAME, stub);
    catch(Exception e) {
      e.printStackTrace();
}Client
public class Client {
private final static int PORT = 1099;
private final static String NAME = "DB";
private static Registry registry;
public void callForData() {
    try {
      registry = LocateRegistry.getRegistry(PORT);
      System.out.println(registry);
      RemoteDBInterface stub = (RemoteDBInterface)registry.lookup(NAME);
      stub.retrieveDBTable();
    catch (Exception e) {
      e.printStackTrace();
}Console after calling callForData() method
RegistryImpl_Stub[UnicastRef [liveRef: [endpoint:[x.x.x.x:1099](remote),objID:[0:0:0, 0]]]]
java.rmi.ConnectException: Connection refused to host: x.x.x.x; nested exception is:
     java.net.ConnectException: Connection refused: connect
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:574)
     at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:185)
     at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:171)
     at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:94)
     at java.rmi.server.RemoteObjectInvocationHandler.invokeRemoteMethod(RemoteObjectInvocationHandler.java:179)
     at java.rmi.server.RemoteObjectInvocationHandler.invoke(RemoteObjectInvocationHandler.java:132)
     at $Proxy0.retrieveDBTable(Unknown Source)
     at com.gk_software.es.pklasna.client.Client.callForData(Client.java:36)
     at com.gk_software.es.pklasna.gui.GUI.actionPerformed(GUI.java:85)
     at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:1849)
     at javax.swing.AbstractButton$Handler.actionPerformed(AbstractButton.java:2169)
     at javax.swing.DefaultButtonModel.fireActionPerformed(DefaultButtonModel.java:420)
     at javax.swing.DefaultButtonModel.setPressed(DefaultButtonModel.java:258)
     at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(BasicButtonListener.java:236)
     at java.awt.Component.processMouseEvent(Component.java:5517)
     at javax.swing.JComponent.processMouseEvent(JComponent.java:3135)
     at java.awt.Component.processEvent(Component.java:5282)
     at java.awt.Container.processEvent(Container.java:1966)
     at java.awt.Component.dispatchEventImpl(Component.java:3984)
     at java.awt.Container.dispatchEventImpl(Container.java:2024)
     at java.awt.Component.dispatchEvent(Component.java:3819)
     at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:4212)
     at java.awt.LightweightDispatcher.processMouseEvent(Container.java:3892)
     at java.awt.LightweightDispatcher.dispatchEvent(Container.java:3822)
     at java.awt.Container.dispatchEventImpl(Container.java:2010)
     at java.awt.Window.dispatchEventImpl(Window.java:1791)
     at java.awt.Component.dispatchEvent(Component.java:3819)
     at java.awt.EventQueue.dispatchEvent(EventQueue.java:463)
     at java.awt.EventDispatchThread.pumpOneEventForHierarchy(EventDispatchThread.java:242)
     at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:163)
     at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:157)
     at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:149)
     at java.awt.EventDispatchThread.run(EventDispatchThread.java:110)
Caused by: java.net.ConnectException: Connection refused: connect
     at java.net.PlainSocketImpl.socketConnect(Native Method)
     at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333)
     at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195)
     at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:182)
     at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366)
     at java.net.Socket.connect(Socket.java:520)
     at java.net.Socket.connect(Socket.java:470)
     at java.net.Socket.<init>(Socket.java:367)
     at java.net.Socket.<init>(Socket.java:180)
     at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:22)
     at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:128)
     at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:569)
     ... 32 moreIPs form println and exception are same.

Question about starting rmiregistry

Folks,
After having used rmi in its basic form for many years, but always doing it the same way, i still have a question:
everytime i have created an rmi object, i have had to set the classpath with my classes added in the classpath before starting the rmiregistry.
if not, i get a ClassNotFoundException on my stub class.
Is this the way it's supposed to be done (set classpath before starting rmiregistry) or is there a better way?
Thanks,
Nilesh

Your new question is unanswerable without a survey.In the few RMI projects that I was involved in, we used the second solution - using a clean rmiregistry process and using codebase for applications. Based on customer feedback of the RMI Plug-in I think there is a slight bias towards using a clean separate registry, but maybe it's because the RMI Plug-in encourages such usage.
IMHO Using a clean registry classpath and using codebase has several advantages:
- You can share a single RMI registry between several projects (e.g., have it started when the machine boots) and stop caring about the startup classpath.
- It is better for projects that involve more than one server VM (VM crash resilience. The server VM can crash, but it is unlikely that a rmiregistry vm will crash)
- Sometimes it can help you to detect problems early - if there is a problem with a codebase, it's better to find it when the object is being registered than when a client first tries to use it.
Disadvantages of using a separate registry process:
- stale class file definitions. During development you will probably have to restart the registry quite often to reload the updated class definitions.
- no API to stop it. you can only forcefully kill it.
Probably there is more...
Genady Beryozkin
Author of the RMI Plug-in for Eclipse.

Start rmiregistry in background

I am using windows NT. I'ld like to start rmiregistry in background.
I already tried to write in a bat file :
- "start rmiregistry" but it open a new command window which stay in foreground
- "start /b rmiregistry". It doesn't open a news window but the main command window doesn't disappear
I would like to launch a bat file which start only the "rmiregistry.exe". I would like to see the rmiregistry only in the task manager and not in a command window on the task bar. That is what i mean with "background". The rmiregistry must be hidden to a common windows user.

However, if there is not another solution, do you
know if running the rmiregistry in java code is
slower than running the .exe file ?That I cannot say for sure, but I don't think it would make any big difference.
That can be a good idea. Do you know how I can do
that on NT and XP?I must admit that I am inexperienced starting .exe-files as service. I do know though how to start a java-application as a service:
http://wrapper.tanukisoftware.org/doc/english/introduction.html
If you use the software above, wrap this class and the rmiregistry should be launched as a service:
public RMIRegistryStarter {
       public static void main(String[] args) {
                int port = 1099;
                if (args.length > 0) {
                      try {
                          port = Integer.parseInt(args[0]);
                      } catch(Exception ex) {}
                LocateRegistry.createRegistry(port);
                while(true) {
                     Thread.sleep(1000);
And can a bat file start this service?Of course:
net start my_rmi_service_name

When do I need to start RMIRegistry?

Hello, there:
I am now joining a project and they are using Eclipse and Tomcat. Within Eclipse they started RMIResigtry first then Tomcat. Why is that? We do have a RMI-related jar in the project, is it the reason why? But if we deploy the project to the product server, how can we do the configuration to make sure the step of RMI registry is not missed?
Thanks,
Sway

RMIRegistry is not for Tomcat, it's for some RMI code that is being used.
Make a deployment script or something that can start everything in order.

Start rmiregistry

I am on Windows98_ 2nd. All my classes and everything is on C:\ . When I attempt to enter rmiregistry in the directory where all my class files are (C:\) I recieve a "Bad Command"
RMI is new to me. I did get rmic to generate stub and skel classes, but I had to drag and drop from
C:\j2sdk1.4.0\bin to C:\. Could that be the problem. I am following Intro to RMI-Sun Java Tutorial.
Thanks .
personal email is : [email protected]
The tutorial tells me to just go to the dir where my classes are which is C:\ and type
"rmiregistry" is this correct?

I also have been working on this problem for one week. i have been successful in making exe file with the help of visual cafe(symantec).
i can run this exe file on my computer very well but it does't run on other pc.The error which is encountered is dll file not found.
i suggest you do work on it, iam also working on it if i will be successful in making and running exe file on every pc i will post whole procedure and in other condition if you r successful then i hope you will post solution to me. my email adress is ([email protected])&(ob_waheed@hotmail)
bye
waheed (a student of java)

Why rmiregistry & Server must start in the same directory.

I have 2 servers & one rmiregisty for both. I want to start this servers separetely from different directories.
But if I try to start server from the directory other than where I've already started rmiregistry the server doesn't bind.
Please, can anyone explain why rmiregisty & server must start from the same directory?

Are you sure the classpath when rmiregistry is started includes jar/directories where rmiregistry can find your server stubs ???
rmiregistry does not need your implementation, but it needs your stubs to be able to register your server objects ...

How to run rmiregistry each time windows starts

Can anybody tell me how to run rmiregistry each time windows starts.
I want to start my RMIserver automatically to work.First I need to start rmiregistry then I want to start my RMIServer class as windows service.

Stick a shorcut to it in your Startup folder or create a new Key in the registry @ HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Run
If you have arguements to rimreg (like port number) create a .bat script and use that to launch it.

Error!! in starting remote object registry

Hi!
To start RMI Registry on server ,I execute the
start rmiregistry command at command prompt.
But it gives me an error message stating that
'c:\jdk1.4\bin\start' is not recognized as internal or external command,operable program or batch file.
I am new to RMI.Will any one Please help me to solve this problem !!
(note: I do not have lan-card in my computer)

write the
c:>cd\
c:\cd jdk1.4\bin
c:\jdk1.4\bin>rmiregistry

How to start a RMI program

I have write RMI program the problem it's that I don't now how to start it
This is my Interface
import java.rmi.*;
import java.rmi.Remote;
public interface DataInterface extends Remote {
public String testRemote() throws RemoteException ;
This is my server
import java.rmi.*;
import java.rmi.server.*;
import java.rmi.registry.*;
public class DataServer extends UnicastRemoteObject implements DataInterface {
DataServer() throws RemoteException{
super();
public String testRemote() throws RemoteException{
return "Merge obiectul remote";
public static void main(String[] args) {
System.setSecurityManager(new RMISecurityManager());
try{
//LocateRegistry.createRegistry(1099);
DataServer testServer = new DataServer();
Naming.rebind("//localhost/SERVER", testServer);
}catch(Exception e){
e.printStackTrace();
This is my client
import java.rmi.*;
import java.rmi.registry.*;
import java.rmi.server.*;
public class DataClient {
public static void main(String[] args) {
System.setSecurityManager(new RMISecurityManager());
try{
Remote remoteServer = Naming.lookup("//localhost/SERVER");
DataServer server = (DataServer)remoteServer;
System.out.println(server.testRemote());
} catch(Exception e){
e.printStackTrace();
And this is my policy file
grant {
permission java.net.SocketPermission "*:1024-65535",
"connect,accept";
permission java.net.SocketPermission "*:80", "connect";
All this files are in c:\temp and this directory is in my PATH variable. I've compilated the interface, server, client with
javac -classpath file.java
After that I generate with rmic the stub skel file in c:\temp. In this point I have all the files that I need. If is somebody kind to tell me from now what do I have to do to make this program work :)). Thanks for any help.

so..u have everything ready..
open cmd prompt and say 'start rmiregistry' - >this opens a new cmd prompt for rmi registry.let it run
now first run ur server by saying 'java DataServer' // include options as u like. this should be running without terminating.
now open new cmd prompt for ur client and say 'java DataClient '.
thats all.
if you want to run the client from a different machine, then try copying the client file into another m/c after changing the code from 'localhost' to the ip address of the server m/c. then just say 'java DataClient '
hope this works fine!

How to stop rmiregistry through java coding?

Hi,
I don't know how to write java program to stop rmiregistry running on port 1099 ?
Could anyone please help me?
If possible please tell me the logic behind server shutdown program, like what we have in tomcat server, jboss etc.,
Thanks and Regards
Ram

hi,
Consider I'm working in the same JVM, I started rmiregistry using the command "LocateRegistry.createRegistry()". With respect to this scenario, please tell me how to stop the rmiregistry (say running on the port 1099)?
Thanks and Regards,
Ram

Starting the RMI server on Windows

Hi
I am just trying to use the three files in suns tutorial: http://java.sun.com/javase/6/docs/technotes/guides/rmi/hello/hello-world.html
Hello.java - a remote interface
Server.java - a remote object implementation that implements the remote interface
Client.java - a simple client that invokes a method of the remote interface
I have started the rmiregistry by running "start rmiregistry" in the java bin directory. There is no output in this window, i hope this is correct.
But when I try to run the server I get the following message:
Server exception: java.rmi.ServerException: RemoteException occurred in server thread; nested exception is:
     java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is:
     java.lang.ClassNotFoundException: Hello
java.rmi.ServerException: RemoteException occurred in server thread; nested exception is:
     java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is:
     java.lang.ClassNotFoundException: HelloI'm suspecting it has to do with the codebase parameter that I have omitted. But even if I try to add it I can't seem to figure out a way for it to start.

I have started the rmiregistry by running "start rmiregistry" in the java bin directory. There is no output in this window, i hope this is correct. This is correct.
I'm suspecting it has to do with the codebase parameter that I have omitted.Omitted from what?
But even if I try to add it I can't seem to figure out a way for it to start.'It' being what?
The RMI 'codebase' is a list of URLs where classes can be found. You define it in your server JVM via the java.rmi.server.codebase property. Normally the URLs are http: URLs, which means you need an HTTP server which will serve classes or JAR files from the specified URLs.
Alternatively you can:
(a) start the client with a classpath that contains the classes mentioned in the remote interface, including itself, and
(b) (i) start the Registry ditto, or
(b) (ii) start the Registry inside the server JVM via LocateRegistry.createRegistry.

Starting RMIRegistry

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