String filtering SQL Query help

We have a table set up as follows
| Type | Content | Date |
(date is unimportant for my problem, however)
I have a string which I am checking to see if it contains any of the words in the table with the type 'TEXT' using the following query.
SELECT content FROM content_blocking WHERE type = 'TEXT' and upper(?) like upper('%' || content || '%')
Basically this filter is returning words that it should not because they are contained within legitimate words. Basically I would like to filter all of the words with type 'ACCTEXT', which we have just added, out of the string before I check for the unallowed words of type 'TEXT'
I have been hacking away at getting a query that can do it, but for some reason can't put my finger on exactly how to do it. If anyone could help, it would be greatly appreciated.
Thanks,
Marshall

There is Oracle Text functionality which already does this. Check it out ...
SQL> CREATE TABLE codex_verbumum_prohibitorum (naughty_word varchar2(10))
  2  /
Table created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('GOSH')
  2  /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('CRIPES')
  2  /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('CRIVVENS')
  2  /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('HECK')
  2  /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('SEMEN')
  2  /
SQL> CREATE TABLE what_ever (id number, some_text varchar2(100))
  2  /
Table created.
SQL> INSERT INTO what_ever VALUES (1, 'Blah blah blah cripes blah')
  2  /
1 row created.
SQL> INSERT INTO what_ever VALUES (2, 'Blah blah blah gosh blah')
  2  /
1 row created.
SQL> INSERT INTO what_ever VALUES (3, 'Blah blah blah poop blah')
  2  /
1 row created.
SQL> INSERT INTO what_ever VALUES (4, 'Blah heck blah cripes blah')
  2  /
1 row created.
SQL> INSERT INTO what_ever VALUES (5, 'Blah advertisement blah')
  2  /
1 row created.
SQL> COMMIT
  2  /
Commit complete.
SQL> CREATE INDEX cvp_word ON codex_verbumum_prohibitorum (naughty_word)
  2  INDEXTYPE IS CTXSYS.CTXRULE
  3  /
Index created.
SQL>
SQL> SELECT w.id, cvp.naughty_word
  2  FROM codex_verbumum_prohibitorum cvp, what_ever w
  3  WHERE MATCHES(cvp.naughty_word, w.some_text)>0
  4  /
        ID NAUGHTY_WO
         1 CRIPES
         2 GOSH
         4 CRIPES
         4 HECK
SQL> You'll notice I have taken a flier at what I think is the naughty word in "advertisement" ;)
You may also be interested in an alternate Text implementation posted by Re: forbidden words list and intermedia index.
Cheers, APC
I see the forum nanny still thinks p00p is a dirty word :(
Message was edited by:
APC

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    22          SELECT 'cutlery', 'knife' FROM DUAL UNION
    23          SELECT 'cutlery', 'fork' FROM DUAL UNION
    24          SELECT 'cutlery', 'spoon' FROM DUAL
    25  ), person_item_colls AS (
    26          SELECT pi.person, pi.item, co.collection_name,
    27                 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
    28            FROM person_items pi
    29            LEFT JOIN collections co
    30              ON co.item = pi.item
    31  )
    32  select person, listagg(collection_name,',') within group (order by collection_name) as collections
    33  from (
    34        SELECT DISTINCT person, collection_name
    35        FROM   person_item_colls
    36        WHERE  collection_name IS NOT NULL
    37        AND    n_col > 1
    38        UNION ALL
    39        SELECT person, item
    40        FROM   person_item_colls
    41        WHERE  collection_name IS NULL
    42        OR     n_col = 1
    43       )
    44* group by person
    SQL> /
    PERSON  COLLECTIONS
    Alice   book,cup,knife,thimble
    Jessica dish,spatula
    Joe     crockery,cutlery
    Ted     crockery,forkFor 10g:
    SQL> ed
    Wrote file afiedt.buf
      1  WITH person_items AS (
      2          SELECT 'Ted' person, 'cup' item FROM DUAL UNION
      3          SELECT 'Ted', 'saucer' FROM DUAL UNION
      4          SELECT 'Ted', 'plate' FROM DUAL UNION
      5          SELECT 'Ted', 'fork' FROM DUAL UNION
      6          SELECT 'Alice', 'book' FROM DUAL UNION
      7          SELECT 'Alice', 'thimble' FROM DUAL UNION
      8          SELECT 'Alice', 'knife' FROM DUAL UNION
      9          SELECT 'Alice', 'cup' FROM DUAL UNION
    10          SELECT 'Joe', 'cup' FROM DUAL UNION
    11          SELECT 'Joe', 'saucer' FROM DUAL UNION
    12          SELECT 'Joe', 'plate' FROM DUAL UNION
    13          SELECT 'Joe', 'knife' FROM DUAL UNION
    14          SELECT 'Joe', 'fork' FROM DUAL UNION
    15          SELECT 'Joe', 'spoon' FROM DUAL UNION
    16          SELECT 'Jessica', 'spatula' FROM DUAL UNION
    17          SELECT 'Jessica', 'dish' FROM DUAL
    18  ), collections AS (
    19          SELECT 'crockery' collection_name, 'cup' item FROM DUAL UNION
    20          SELECT 'crockery', 'saucer' FROM DUAL UNION
    21          SELECT 'crockery', 'plate' FROM DUAL UNION
    22          SELECT 'cutlery', 'knife' FROM DUAL UNION
    23          SELECT 'cutlery', 'fork' FROM DUAL UNION
    24          SELECT 'cutlery', 'spoon' FROM DUAL
    25  ), person_item_colls AS (
    26          SELECT pi.person, pi.item, co.collection_name,
    27                 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
    28            FROM person_items pi
    29            LEFT JOIN collections co
    30              ON co.item = pi.item
    31  )
    32  select person, ltrim(sys_connect_by_path(collection_name,','),',') as collections
    33  from (
    34        select person, collection_name, row_number() over (partition by person order by collection_name) as rn
    35        from (
    36              SELECT DISTINCT person, collection_name
    37              FROM   person_item_colls
    38              WHERE  collection_name IS NOT NULL
    39              AND    n_col > 1
    40              UNION ALL
    41              SELECT person, item
    42              FROM   person_item_colls
    43              WHERE  collection_name IS NULL
    44              OR     n_col = 1
    45             )
    46        )
    47  where connect_by_isleaf = 1
    48  connect by person = prior person and rn = prior rn + 1
    49* start with rn = 1
    SQL> /
    PERSON  COLLECTIONS
    Alice   book,cup,knife,thimble
    Jessica dish,spatula
    Joe     crockery,cutlery
    Ted     crockery,fork

  • Urgent SQL query help

    Hello,
    I need help with SQL... My database version is Oracle 10g Release 1.2.
    I have two table with the exact same structure as follows...
    create table t1(cust_id number(5), zone_number number(2), part_number varchar2(10))
    create table t2(cust_id number(5), zone_number number(2), part_number varchar2(10))
    I need a query that would give me two counts per pairs of customer between t1 and t2..
    1.Count of part_number matches between the same zones in table 1 and table 2 for pairs of customers
    for Customer 1 and 10 for zone 1 this total shoulb be 2 because between cust 1 and 10 for Zone 1 there are two part number matches A and B.
    for Customer 1 and 10 for zone 2 this total shoulb be 0 because between cust 1 and 10 for Zone 2 there are no part number matches
    for Customer 1 and 20 for zone 1 this total shoulb be 0 because between cust 1 and 20 for Zone 1 there are no part number matches
    for Customer 1 and customer 20 zone 2 this total shoulb be 0 because between cust 1 and 20 for Zone 2 there is one part number matches , which is 'F'
    for Customer 1 and customer 20 zone 3 this total shoulb be 0 because there is no zone 3 for Customer 1
    same way
    .. cust 2 and cust 10 Zone 1 counts and zone2 counts
    .. for 2 and cust 20 zone 1, 2, and 3 counts
    2. Total unique Part nmbers between the same zones for pairs of customers in table 1 and table2
    for example
    unique part numbers between cust 1 and 10 for zone 1 are A,B and C so the count should be 3
    unique part numbers between cust 1 and 10 for zone 2 are B,F, D and E so the count should be 3
    unique part numbers between cust 1 and 20 for zone 1 are A,B,C and G so the count should be 4
    and so on so forth
    insert into t1 values(1, 1, 'A')
    insert into t1 values(1, 1, 'B')
    insert into t1 values(1, 1, 'C')
    insert into t1 values(1, 2, 'B')
    insert into t1 values(1, 2, 'F')
    insert into t1 values(1, 2, 'D')
    insert into t1 values(1, 2, 'E')
    insert into t1 values(2, 1, 'F')
    insert into t1 values(2, 2, 'G')
    insert into t1 values(2, 2, 'H')
    insert into t2 values(10, 1, 'A')
    insert into t2 values(10, 1, 'B')
    insert into t2 values(10, 2, null)
    insert into t2 values(20, 1, 'G')
    insert into t2 values(20, 2, 'F')
    insert into t2 values(20, 2, 'H')
    insert into t2 values(20, 3, 'I')
    insert into t2 values(20, 3, 'J')
    My query result should be as follows...
    cust1 cust2 zone pn_match_count total_unique_pn_count
    1 10 1 2 3
    1 10 2 0 4
    1 20 1 0 4
    1 20 2 1 5
    1 20 3 0 2
    2 10 1 0 3
    2 10 2 0 2
    2 20 1 0 2
    2 20 2 1 3
    2 20 3 0 2
    I would really appreciate your help in writing this query.
    Thanks in Advance

    user00 wrote:
    No, that doesn't do it... I get no results with this query becuase the Cust_id in table 1 and table 2 are not the same.Yeah, I only realised that after I posted my query. I had interpreted pairs as "matching pairs" when what you meant was "permutations".
    Cheers, APC
    blog: http://radiofreetooting.blogspot.com

  • SQL Query Help/ Converts seconds to day:hr:mi:se

    I have query that returns value in seconds. How i will convert those seconds in DAY:HOUR:MIN:SEC in the same query? What will be the mathematical formulae or alogorithim for this?
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    Munis Warsi
    null

    Seriously, you post 750+ lines of unformatted SQL statement and a completely unreadable and unformatted explain plan and you expect people to be able to help with that?
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    Take a read of the discussions linked in the FAQ: Re: 3. How to  improve the performance of my query? / My query is running slow.
    And also consider if your question would be better asked in the Oracle Apps forum space instead.

  • Sql Query Help to find values?

    Hi! 
    i have a table structure like this...
    you can see the image here.
    http://postimg.org/image/3k5nvkvn5/
    i which i need to find some values.
    Example: i need to find all column "District" values where value=46
    then in that case you can see in above image that row 1 to 4 has to fetched because these columns contains value between 45-52, also in row 5 where value is 46,47 the also it  has to be fetched, here i have to kind of structure to be used in table one
    is comma separated and another one is comma and dash separated value, so how can i find these values in table. so how can achieve this using query, Any help would be triplicated.

    Ah this is not correct way to store data in table
    If you store like this you've to do lots of manipulations before values can be used in  filter
    So as per above you would require something like this
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    AS
    SELECT 1
    UNION ALL
    SELECT 1
    UNION ALL
    SELECT 1
    UNION ALL
    SELECT 1
    UNION ALL
    SELECT 1
    UNION ALL
    SELECT 1
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    AS
    SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1))
    FROM Numbers n1
    CROSS JOIN Numbers n2
    CROSS JOIN Numbers n3
    CROSS JOIN Numbers n4
    CROSS JOIN Numbers n5
    CROSS JOIN Numbers n6
    CROSS JOIN Numbers n7
    CROSS JOIN Numbers n8
    SELECT DISTINCT t.po_city_st_zip
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    SELECT LEFT(f.Val,CHARINDEX('-',f.Val+'-')-1) AS StartVal,
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    t.*
    FROM YourTable t
    CROSS APPLY do.ParseValues(t.District,',')f
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    INNER JOIN Num_Matrix n
    ON n.N BETWEEN m.StartVal AND m.EndVal
    WHERE n.N = <your Value>
    See ParseValues UDF here                                                                 
    http://visakhm.blogspot.ae/2010/02/parsing-delimited-string.html
    Please Mark This As Answer if it solved your issue
    Please Vote This As Helpful if it helps to solve your issue
    Visakh
    My Wiki User Page
    My MSDN Page
    My Personal Blog
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  • I need sql query help

    I have 5 tables.i want to select one respective record from 5 table .But i will pass only one argument...
    what is the query for that..................

    I didn't understand that that's why i made it
    again.If you ask a question and you don't understand the answer, then you should ask for an explanation of the answer.
    If you get an explanation and you still don't understand, then maybe that is an indication that you don't have enough knowledge of the basics. In this case, perhaps you should try to read a book on SQL and relational database theory.
    Myself only asked that question also.
    Now also i am asking u r able to solve this question
    or not.As I said, I will read the other thread (where you have started to get help) and if I have anything to add, I will post there.

  • Very Urgent: SQL Query Help

    Hi,
    I have a table which has location ID and text for these locations are stored in a seperate table.
    I am running query on table which has location ID but for every location I want it display its text which is stored in another table.
    How can this be done with SQL? This is a bit urgent, please help.
    Thank you,
    Raja

    might be a good idea to improve basic SQL knowledge by reading
          http://tahiti.oracle.com
          http://oreilly.com/catalog/9780596006327/index.html
          http://asktom.oracle.com
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