Sql query - help reqd (new)
Hi,
I have follwing dataset
"herb with garden"
"garden without herb"
"herb with zbc"
"garden with pqr"
Now i want sql query like
select * from table where text1 = "herb and garden"
This should populate
herb with garden
garden without herb
And
select * from table where text1 = "herb or garden"
This should populate
"herb with garden"
"garden without herb"
"herb with zbc"
"garden with pqr"
SQL> with t
2 as
3 (
4 select 'herb with garden' str from dual union all
5 select 'garden without herb' str from dual union all
6 select 'herb with zbc' str from dual union all
7 select 'garden with pqr' str from dual
8 )
9 select *
10 from t
11 where lower(str) like '%herb%'
12 and lower(str) like '%garden%'
13 /
STR
herb with garden
garden without herb
SQL> with t
2 as
3 (
4 select 'herb with garden' str from dual union all
5 select 'garden without herb' str from dual union all
6 select 'herb with zbc' str from dual union all
7 select 'garden with pqr' str from dual
8 )
9 select *
10 from t
11 where lower(str) like '%herb%'
12 or lower(str) like '%garden%'
13 /
STR
herb with garden
garden without herb
herb with zbc
garden with pqr
Similar Messages
-
Hi,
I require help for sql query. The query will be like
"SELECT * FROM XYZ WHERE TEXT = 'h*s' "
and the results will be come like
“his”
“homes”
“houses”
“horses”,
“horticulturalists”
“herbaceous”.
Thanks,
KapilHello,
SELECT *
FROM XYZ
WHERE TEXT LIKE ('h%s');Regards
Edited by: OrionNet on Feb 2, 2009 12:33 AM -
Table name: xyz
Column1 Column2
x 1
x 2
x 3
x 7
y 1
y 3
y 6
z 4
z 2
z 0
I want a query to output all Column1 only if Column2 value not in (1,2,3) - all inclusive. In the above example, I want y & z in the output.I may be wrong but I think the OP is asking for something more like:
[email protected](161)> select * from xyz;
C COLUMN2
x 1
x 2
x 3
x 7
y 1
y 3
y 6
z 4
z 2
z 0
10 rows selected.
[email protected](161)> select column1
2 from xyz
3 minus
4 select column1
5 from xyz
6 where column2 in (1, 2, 3)
7 group by column1
8 having count(distinct column2) = 3
9 /
C
y
zI.e., values from column1 which don't have ALL of (1, 2, 3) in column2.
cheers,
Anthony -
I'm having trouble with an SQL query. I've created a simple logon page wherein a user will enter their user name and password. The program will look in an Access database for the user name, sort it by Date/Time modified, and check to see if their password matches the most recent password. Unfortunately, the query returns no results. I'm absolutely certain that I'm doing the query correctly (I've imported it directly from my old VB6 code). Something simple is eluding me. Any help would be appreciated.
private void LogOn() {
//make sure that the user name/password is valid, then load the main menu
try {
//open the database connection
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
Connection con = DriverManager.getConnection("jdbc:odbc:LawOffice2000", "", "");
Statement select = con.createStatement();
String strTemp = "Select * From EMPLOYEES Where INITIALS = '" + txtUserName.getText() + "' Order By DATE Desc, TIME Desc";
ResultSet result = select.executeQuery(strTemp);
while(result.next()) {
if (txtPassword.getPassword().toString() == result.getString("Password")) {
MenuMain.main();
else {
System.out.println("Password Bad");
System.out.println(txtUserName.getText());
System.out.println(result.getString("Password"));
break; //exit loop
//close the connection
con.close(); }
catch (Exception e) {
System.out.println("LawOfficeSuite_LogOn: " + e);
return; }
}The problem is here: "txtPassword.getPassword().toString() == result.getString("Password"))"
Don't confuse String's equals() method with the equality operator '=='. The == operator checks that two references refer to the same object. If you want to compare the contents of Strings (whether two strings contain the same characters), use equals(), e.g. if (str1.equals(str2))...
Example:String s1 = "foo";
String s2 = new String("foo");
System.out.println("s1 == s2: " + (s1 == s2)); // false
System.out.println("s1.equals(s2): " + (s1.equals(s2))); // trueFor more information, check out Comparison operators: equals() versus == -
Sql query slow in new redhat enviornment
We just migrated to a new dev environment in Linux REDHAT5, and now the query is very slow, and I used the TOAD to run the query, it took like 700 msecond to finish, however from any server connection, the sql query takes hours to finish.
I checked toad monitor, it said need to increase db_buffer_cache and shared pool too small.
Also three red alert from toad is:
1. Library Cache get hit ratio: Dynamic or unsharable sql
2. Chained fetch ratio: PCT free too low for a table
3. parse to execute ratio: HIgh parse to execute ratio.
App team said it ran real quick in the old AIX system, however I ran it in old system, and monitored in the toad, it gave me all same 5 red alerts in old system, and it did provide query results a lot quicker though.
Here is the parameters in the old system (11gr1 on AIX):
SQL> show parameter target
NAME TYPE VALUE
-------------------------------- archive_lag_target integer 0
db_flashback_retention_target integer 1440
fast_start_io_target integer 0
fast_start_mttr_target integer 0
memory_max_target big integer 0
memory_target big integer 0
pga_aggregate_target big integer 278928K
sga_target big integer 0
SQL> show parameter shared
NAME TYPE VALUE
-------------------------------- hi_shared_memory_address integer 0
max_shared_servers integer
shared_memory_address integer 0
shared_pool_reserved_size big integer 31876710
shared_pool_size big integer 608M
shared_server_sessions integer
shared_servers integer 0
SQL> show parameter db_buffer
SQL> show parameter buffer
NAME TYPE VALUE
-------------------------------- buffer_pool_keep string
buffer_pool_recycle string
db_block_buffers integer 0
log_buffer integer 2048000
use_indirect_data_buffers boolean FALSE
SQL>
In new 11gr2 Linux REDHAT parameter:
NAME TYPE VALUE
----------- archive_lag_target integer 0
db_flashback_retention_target integer 1440
fast_start_io_target integer 0
fast_start_mttr_target integer 0
memory_max_target big integer 2512M
memory_target big integer 2512M
parallel_servers_target integer 192
pga_aggregate_target big integer 0
sga_target big integer 1648M
SQL> show parameter shared
NAME TYPE VALUE
----------- hi_shared_memory_address integer 0
max_shared_servers integer
shared_memory_address integer 0
shared_pool_reserved_size big integer 28M
shared_pool_size big integer 0
shared_server_sessions integer
shared_servers integer 1
SQL> show parameter buffer
NAME TYPE VALUE
----------- buffer_pool_keep string
buffer_pool_recycle string
db_block_buffers integer 0
log_buffer integer 18857984
use_indirect_data_buffers boolean FALSE
SQL>
Please help. Thanks in advance.846422 wrote:
why need ddl? we have a sql query slow.The DDL shows the physical structure of the table and physical storage characteristics. All relevant in performance tuning.
As for the SQL query being slow. It is not.
You have not provided any evidence that it is slow. And no, comparing performance with a totally different system is not a valid baseline for comparison. (most cars have 4 wheels, a gearbox and a steering wheel - but that does not mean you can compare different cars like a VW Beetle with a VW Porsche)
What is slow? What are the biggest wait states for the SQL? What does the execution plan say?
You have not defined a problem - you identified a symptom called "+query is slow+". You need to diagnose the condition by determining exactly what the SQL qeury is doing in the database. (and please, do not use TOAD and similar tools in an attempt to do this - do it properly instead) -
SQL Query Help - Is this possible or impossible????
Hi guys,
I need help with an SQL query that I'm trying to develop. It's very easy to explain but when trying to implement it, I'm struggling to achieve the results that I want.....
For example,
I have 2 tables
The first table is:
1) COMPANY create table company (manufacturer varchar2(25),
date_established date,
location varchar2(25) );My sample test date is:
insert into company values ('Ford', 1902, 'USA');
insert into company values ('BMW', 1910, 'Germany');
insert into company values ('Tata', 1922, 'India');The second table is:
2) MODELS create table models (manufacturer varchar(25),
model varchar2(25),
price number(10),
year date,
current_production_status varchar2(1) ) ;My sample test data is:
insert into models values ('Ford', 'Mondeo', 10000, 2010, 0);
insert into models values ('Ford', 'Galaxy', 12000, 2008, 0);
insert into models values ('Ford', 'Escort', 10000, 1992, 1);
insert into models values ('BMW', '318', 17500, 2010, 0);
insert into models values ('BMW', '535d', 32000, 2006, 0);
insert into models values ('BMW', 'Z4', 10000, 1992, 0);
insert into models values ('Tata', 'Safari', 4000, 1999, 0);
insert into models values ('Tata', 'Sumo', 5500, 1996, 1);
insert into models values ('Tata', 'Maruti', 3500, 1998, 0);And this is my query:
SELECT
com.manufacturer,
com.date_established,
com.location,
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.model),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.price),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.year),
mod.current_production_status
FROM
company com,
models mod
WHERE
mod.manufacturer = com.manufacturer
and com.manufacturer IN ('Ford', 'BMW', 'Tata')
and mod.current_production_status IN (1,0)
ORDER BY
mod.current_production_status DESCWhat I want the query to output is this:
com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
Ford 1902 USA Escort 10000 1992 1
BMW 1910 Germany - - - 0
Tata 1922 India Sumo 5500 1998 1If current_production_status is 1 it means this particular model has been discontinued
If current_production_status is 0 it means the manufacturer does not have any discontinued models and all are in procuction.
The rule is only one record per manufacturer is allowed to have a current_production_status of 1 (so only one model from the selection the manufactuer offers is allowed to be discontinued).
So the query should output the one row where current_production_status is 1 for each manufacturer.
If for a given manufacturer there are no discontinued models and all have a current_production_status of 0 then ouput a SINGLE row that only includes the data from the COMPANY table (as above). The rest of the columns from the MODELS table should be populated with a '-' (hyphen).
My query as it is above will output all the records where current status is 1 or 0 like this
com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
Ford 1902 USA Escort 10000 1992 1
Tata 1922 India Sumo 5500 1998 1
Ford 1902 USA - - - 0
Ford 1902 USA - - - 0
BMW 1910 Germany - - - 0
BMW 1910 Germany - - - 0
BMW 1910 Germany - - - 0
Tata 1922 India - - - 0
Tata 1922 India - - - 0However this is not what I want.
Any ideas how I can achieve the result I need?
Thanks!
P.S. Database version is '10.2.0.1.0'Hi Vishnu,
Karthiks query helped...
But this is the problem I am facing...
SELECT
com.manufacturer,
com.date_established,
com.location,
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.model),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.price),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.year),
mod.current_production_status
FROM
company com,
models mod
WHERE
mod.manufacturer = com.manufacturer
and com.manufacturer = 'Ford'
and mod.current_production_status IN (1,0)
ORDER BY
mod.current_production_status DESCThe value of:
and com.manufacturer = 'Ford'will be dependent on front end user input....
When I run the query above I get all the rows where current_production_status is either 1 or 0.
I only require the rows where current_production_status is 1.
So if I amend it to look like this:
and mod.current_production_status = 1This works....
BUT if a user now passes in more than one manufacturer EG:
and com.manufacturer IN ('Ford', 'BMW')The query will only return the one row for Ford where current_production_status is 1. However because BMW has no models where current_production_status is 1 (all 3 are 0), I still want this to be output - as one row....
So like this:
com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
Ford 1902 USA Escort 10000 1992 1
BMW 1910 Germany - - - 0So (hopefully you understand), I want both cases to be catered for.....whether a user enters one manufacturer or more than one...
Thanks you so much!
This is really driving me insane :-( -
SQL QUERY to create new schema in Oracle 10g Express
Can anyone provide the SQL query to create a new schema in Oracle 10g Express edition.
Can anyone provide a SQl query to create a
schema/user named 'test' with username as 'system'
and password as 'manager'system user is created during database creation, it's internal Oracle admin user that shouldn't be used as schema holder.
In Oracle database, Oracle user is schema holder there's no seperate schema name to be defined other than username. -
Very Urgent: SQL Query Help
Hi,
I have a table which has location ID and text for these locations are stored in a seperate table.
I am running query on table which has location ID but for every location I want it display its text which is stored in another table.
How can this be done with SQL? This is a bit urgent, please help.
Thank you,
Rajamight be a good idea to improve basic SQL knowledge by reading
http://tahiti.oracle.com
http://oreilly.com/catalog/9780596006327/index.html
http://asktom.oracle.com
... whatever ...will give you some new insight about something very urgent -
hi guys
i have sample data as mentioned below... need to find the duplicate rows where cd=cd and dt1=dt1 and tm1 difference should be less than or equal to 4 hrs..
i can get the data with the query written below but my problem is that i am not allowed to use in-built sql server function... can you help me in writing the same without using in-built function...
CREATE TABLE #t (id INT,dt1 datetime, tm1 datetime,cd varchar(10))
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:20:00.000','TC')
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:30:00.000','TC')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 14:30:00.000','MN')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 09:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-11-27','1900-01-01 09:50:00.000','LM')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 15:07:00.000','XY')
select * From #t
WITH MyCTE (rn,id, dt1, tm1, cd)
AS(
select row_number() over (partition by id ORDER BY dt1, tm1) rn,* from #t
select case when ((dt1 = lead_start_Date) and (ct <='4.0') and (base_cd = lead_cd)) then 'Duplicate_Req' else '' end dt123,* from
select abs(convert(decimal(5,1),datediff(MI,lead_Start_time,tm1)/60.00)) ct, * from
SELECT base.rn b_rn,LEAd.rn l_rn,BASE.id
,BASE.dt1
,BASE.tm1
,base.cd base_cd
,LEAD.dt1 LEAD_START_DATE
,LEAD.tm1 LEAD_START_TIME
,lead.cd lead_cd
--,DATEADD(dd,-1,LEAD.dt1) EXPECTED_END_DATE
FROM MyCTE BASE
LEFT JOIN MyCTE LEAD ON BASE.id = LEAD.id
AND BASE.rn = LEAD.rn+1
) b
)cif this code will not work for you then not sure if there are any other options
Converted the CTE into an actual temp table.
CTE and barebones T-SQL code are included in the script below.
CREATE TABLE #t (id INT,dt1 datetime, tm1 datetime,cd varchar(10))
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:20:00.000','TC')
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:30:00.000','TC')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 14:30:00.000','MN')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 09:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-11-27','1900-01-01 09:50:00.000','LM')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 15:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
select * From #t
;WITH MyCTE (rn,id, dt1, tm1, cd)
AS(
select row_number() over (partition by id ORDER BY dt1, tm1) rn,* from #t
select case when ((dt1 = lead_start_Date) and (ct <='4.0') and (base_cd = lead_cd)) then 'Duplicate_Req' else '' end dt123,* from
select abs(convert(decimal(5,1),datediff(MI,lead_Start_time,tm1)/60.00)) ct, * from
SELECT base.rn b_rn,LEAd.rn l_rn,BASE.id
,BASE.dt1
,BASE.tm1
,base.cd base_cd
,LEAD.dt1 LEAD_START_DATE
,LEAD.tm1 LEAD_START_TIME
,lead.cd lead_cd
--,DATEADD(dd,-1,LEAD.dt1) EXPECTED_END_DATE
FROM MyCTE BASE
LEFT JOIN MyCTE LEAD ON BASE.id = LEAD.id
AND BASE.rn = LEAD.rn+1
) b
)c
select * into #copy From #t order by id, cd, dt1, tm1
alter table #copy add seqno int identity(1,1)
select distinct y.id,y.cd,y.dt1,y.tm1,y.seqno,case when z.cd is not null then 'Duplicate_Req' else '' end dt123
from #copy y
left outer join
(select a.id,a.cd,a.dt1,a.tm1
From #copy a
left outer join #copy b
on a.id = b.id
and a.cd = b.cd
and a.dt1 = b.dt1
where a.seqno > b.seqno
and abs(datediff(MINUTE,b.tm1,a.tm1)) <= 240) z
on y.id = z.id
and y.cd = z.cd
and y.dt1 = z.dt1
and y.tm1 = z.tm1
order by y.dt1,y.tm1
drop table #copy
drop table #t -
Hi,
I was wondering if I could have some help with the query I have below for this general data set, please? I need to do it in a single SQL statement. We're currently running Oracle 10g. The piece I'm struggling with is identifying that the person has all the items in a collection and to include the collection in the resulting collection of items.
persons_items
person item
Ted cup
Ted saucer
Ted plate
Ted fork
Alice book
Alice thimble
Alice knife
Alice cup
Joe cup
Joe saucer
Joe plate
Joe knife
Joe fork
Joe spoon
Jessica spatula
Jessica dish
collections
collection_name item
crockery cup
crockery saucer
crockery plate
cutlery knife
cutlery fork
cutlery spoon
Query:
What single items and collections does Ted have? fork, crockery
What single items and collections does Alice have? book, thimble, knife, cup
What single items and collections does Joe have? crockery, cutlery
What single items and collections does Jessica have? spatula, dish
Thanks in advance.
PatExpanding on Brendan's solution...
For 11g:
SQL> ed
Wrote file afiedt.buf
1 WITH person_items AS (
2 SELECT 'Ted' person, 'cup' item FROM DUAL UNION
3 SELECT 'Ted', 'saucer' FROM DUAL UNION
4 SELECT 'Ted', 'plate' FROM DUAL UNION
5 SELECT 'Ted', 'fork' FROM DUAL UNION
6 SELECT 'Alice', 'book' FROM DUAL UNION
7 SELECT 'Alice', 'thimble' FROM DUAL UNION
8 SELECT 'Alice', 'knife' FROM DUAL UNION
9 SELECT 'Alice', 'cup' FROM DUAL UNION
10 SELECT 'Joe', 'cup' FROM DUAL UNION
11 SELECT 'Joe', 'saucer' FROM DUAL UNION
12 SELECT 'Joe', 'plate' FROM DUAL UNION
13 SELECT 'Joe', 'knife' FROM DUAL UNION
14 SELECT 'Joe', 'fork' FROM DUAL UNION
15 SELECT 'Joe', 'spoon' FROM DUAL UNION
16 SELECT 'Jessica', 'spatula' FROM DUAL UNION
17 SELECT 'Jessica', 'dish' FROM DUAL
18 ), collections AS (
19 SELECT 'crockery' collection_name, 'cup' item FROM DUAL UNION
20 SELECT 'crockery', 'saucer' FROM DUAL UNION
21 SELECT 'crockery', 'plate' FROM DUAL UNION
22 SELECT 'cutlery', 'knife' FROM DUAL UNION
23 SELECT 'cutlery', 'fork' FROM DUAL UNION
24 SELECT 'cutlery', 'spoon' FROM DUAL
25 ), person_item_colls AS (
26 SELECT pi.person, pi.item, co.collection_name,
27 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
28 FROM person_items pi
29 LEFT JOIN collections co
30 ON co.item = pi.item
31 )
32 select person, listagg(collection_name,',') within group (order by collection_name) as collections
33 from (
34 SELECT DISTINCT person, collection_name
35 FROM person_item_colls
36 WHERE collection_name IS NOT NULL
37 AND n_col > 1
38 UNION ALL
39 SELECT person, item
40 FROM person_item_colls
41 WHERE collection_name IS NULL
42 OR n_col = 1
43 )
44* group by person
SQL> /
PERSON COLLECTIONS
Alice book,cup,knife,thimble
Jessica dish,spatula
Joe crockery,cutlery
Ted crockery,forkFor 10g:
SQL> ed
Wrote file afiedt.buf
1 WITH person_items AS (
2 SELECT 'Ted' person, 'cup' item FROM DUAL UNION
3 SELECT 'Ted', 'saucer' FROM DUAL UNION
4 SELECT 'Ted', 'plate' FROM DUAL UNION
5 SELECT 'Ted', 'fork' FROM DUAL UNION
6 SELECT 'Alice', 'book' FROM DUAL UNION
7 SELECT 'Alice', 'thimble' FROM DUAL UNION
8 SELECT 'Alice', 'knife' FROM DUAL UNION
9 SELECT 'Alice', 'cup' FROM DUAL UNION
10 SELECT 'Joe', 'cup' FROM DUAL UNION
11 SELECT 'Joe', 'saucer' FROM DUAL UNION
12 SELECT 'Joe', 'plate' FROM DUAL UNION
13 SELECT 'Joe', 'knife' FROM DUAL UNION
14 SELECT 'Joe', 'fork' FROM DUAL UNION
15 SELECT 'Joe', 'spoon' FROM DUAL UNION
16 SELECT 'Jessica', 'spatula' FROM DUAL UNION
17 SELECT 'Jessica', 'dish' FROM DUAL
18 ), collections AS (
19 SELECT 'crockery' collection_name, 'cup' item FROM DUAL UNION
20 SELECT 'crockery', 'saucer' FROM DUAL UNION
21 SELECT 'crockery', 'plate' FROM DUAL UNION
22 SELECT 'cutlery', 'knife' FROM DUAL UNION
23 SELECT 'cutlery', 'fork' FROM DUAL UNION
24 SELECT 'cutlery', 'spoon' FROM DUAL
25 ), person_item_colls AS (
26 SELECT pi.person, pi.item, co.collection_name,
27 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
28 FROM person_items pi
29 LEFT JOIN collections co
30 ON co.item = pi.item
31 )
32 select person, ltrim(sys_connect_by_path(collection_name,','),',') as collections
33 from (
34 select person, collection_name, row_number() over (partition by person order by collection_name) as rn
35 from (
36 SELECT DISTINCT person, collection_name
37 FROM person_item_colls
38 WHERE collection_name IS NOT NULL
39 AND n_col > 1
40 UNION ALL
41 SELECT person, item
42 FROM person_item_colls
43 WHERE collection_name IS NULL
44 OR n_col = 1
45 )
46 )
47 where connect_by_isleaf = 1
48 connect by person = prior person and rn = prior rn + 1
49* start with rn = 1
SQL> /
PERSON COLLECTIONS
Alice book,cup,knife,thimble
Jessica dish,spatula
Joe crockery,cutlery
Ted crockery,fork -
Hello,
I need help with SQL... My database version is Oracle 10g Release 1.2.
I have two table with the exact same structure as follows...
create table t1(cust_id number(5), zone_number number(2), part_number varchar2(10))
create table t2(cust_id number(5), zone_number number(2), part_number varchar2(10))
I need a query that would give me two counts per pairs of customer between t1 and t2..
1.Count of part_number matches between the same zones in table 1 and table 2 for pairs of customers
for Customer 1 and 10 for zone 1 this total shoulb be 2 because between cust 1 and 10 for Zone 1 there are two part number matches A and B.
for Customer 1 and 10 for zone 2 this total shoulb be 0 because between cust 1 and 10 for Zone 2 there are no part number matches
for Customer 1 and 20 for zone 1 this total shoulb be 0 because between cust 1 and 20 for Zone 1 there are no part number matches
for Customer 1 and customer 20 zone 2 this total shoulb be 0 because between cust 1 and 20 for Zone 2 there is one part number matches , which is 'F'
for Customer 1 and customer 20 zone 3 this total shoulb be 0 because there is no zone 3 for Customer 1
same way
.. cust 2 and cust 10 Zone 1 counts and zone2 counts
.. for 2 and cust 20 zone 1, 2, and 3 counts
2. Total unique Part nmbers between the same zones for pairs of customers in table 1 and table2
for example
unique part numbers between cust 1 and 10 for zone 1 are A,B and C so the count should be 3
unique part numbers between cust 1 and 10 for zone 2 are B,F, D and E so the count should be 3
unique part numbers between cust 1 and 20 for zone 1 are A,B,C and G so the count should be 4
and so on so forth
insert into t1 values(1, 1, 'A')
insert into t1 values(1, 1, 'B')
insert into t1 values(1, 1, 'C')
insert into t1 values(1, 2, 'B')
insert into t1 values(1, 2, 'F')
insert into t1 values(1, 2, 'D')
insert into t1 values(1, 2, 'E')
insert into t1 values(2, 1, 'F')
insert into t1 values(2, 2, 'G')
insert into t1 values(2, 2, 'H')
insert into t2 values(10, 1, 'A')
insert into t2 values(10, 1, 'B')
insert into t2 values(10, 2, null)
insert into t2 values(20, 1, 'G')
insert into t2 values(20, 2, 'F')
insert into t2 values(20, 2, 'H')
insert into t2 values(20, 3, 'I')
insert into t2 values(20, 3, 'J')
My query result should be as follows...
cust1 cust2 zone pn_match_count total_unique_pn_count
1 10 1 2 3
1 10 2 0 4
1 20 1 0 4
1 20 2 1 5
1 20 3 0 2
2 10 1 0 3
2 10 2 0 2
2 20 1 0 2
2 20 2 1 3
2 20 3 0 2
I would really appreciate your help in writing this query.
Thanks in Advanceuser00 wrote:
No, that doesn't do it... I get no results with this query becuase the Cust_id in table 1 and table 2 are not the same.Yeah, I only realised that after I posted my query. I had interpreted pairs as "matching pairs" when what you meant was "permutations".
Cheers, APC
blog: http://radiofreetooting.blogspot.com -
SQL Query Help/ Converts seconds to day:hr:mi:se
I have query that returns value in seconds. How i will convert those seconds in DAY:HOUR:MIN:SEC in the same query? What will be the mathematical formulae or alogorithim for this?
Thanks
Munis Warsi
nullSeriously, you post 750+ lines of unformatted SQL statement and a completely unreadable and unformatted explain plan and you expect people to be able to help with that?
From what I can see it looks like some sort of query against an Oracle APPS database, and there are numerous calls to PL/SQL functions in there, so you're creating a multitude of context switches between the SQL and PL engines... that's known to cause performance problems.
Take a read of the discussions linked in the FAQ: Re: 3. How to improve the performance of my query? / My query is running slow.
And also consider if your question would be better asked in the Oracle Apps forum space instead. -
String filtering SQL Query help
We have a table set up as follows
| Type | Content | Date |
(date is unimportant for my problem, however)
I have a string which I am checking to see if it contains any of the words in the table with the type 'TEXT' using the following query.
SELECT content FROM content_blocking WHERE type = 'TEXT' and upper(?) like upper('%' || content || '%')
Basically this filter is returning words that it should not because they are contained within legitimate words. Basically I would like to filter all of the words with type 'ACCTEXT', which we have just added, out of the string before I check for the unallowed words of type 'TEXT'
I have been hacking away at getting a query that can do it, but for some reason can't put my finger on exactly how to do it. If anyone could help, it would be greatly appreciated.
Thanks,
MarshallThere is Oracle Text functionality which already does this. Check it out ...
SQL> CREATE TABLE codex_verbumum_prohibitorum (naughty_word varchar2(10))
2 /
Table created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('GOSH')
2 /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('CRIPES')
2 /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('CRIVVENS')
2 /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('HECK')
2 /
1 row created.
SQL> INSERT INTO codex_verbumum_prohibitorum VALUES ('SEMEN')
2 /
SQL> CREATE TABLE what_ever (id number, some_text varchar2(100))
2 /
Table created.
SQL> INSERT INTO what_ever VALUES (1, 'Blah blah blah cripes blah')
2 /
1 row created.
SQL> INSERT INTO what_ever VALUES (2, 'Blah blah blah gosh blah')
2 /
1 row created.
SQL> INSERT INTO what_ever VALUES (3, 'Blah blah blah poop blah')
2 /
1 row created.
SQL> INSERT INTO what_ever VALUES (4, 'Blah heck blah cripes blah')
2 /
1 row created.
SQL> INSERT INTO what_ever VALUES (5, 'Blah advertisement blah')
2 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL> CREATE INDEX cvp_word ON codex_verbumum_prohibitorum (naughty_word)
2 INDEXTYPE IS CTXSYS.CTXRULE
3 /
Index created.
SQL>
SQL> SELECT w.id, cvp.naughty_word
2 FROM codex_verbumum_prohibitorum cvp, what_ever w
3 WHERE MATCHES(cvp.naughty_word, w.some_text)>0
4 /
ID NAUGHTY_WO
1 CRIPES
2 GOSH
4 CRIPES
4 HECK
SQL> You'll notice I have taken a flier at what I think is the naughty word in "advertisement" ;)
You may also be interested in an alternate Text implementation posted by Re: forbidden words list and intermedia index.
Cheers, APC
I see the forum nanny still thinks p00p is a dirty word :(
Message was edited by:
APC -
I have 5 tables.i want to select one respective record from 5 table .But i will pass only one argument...
what is the query for that..................I didn't understand that that's why i made it
again.If you ask a question and you don't understand the answer, then you should ask for an explanation of the answer.
If you get an explanation and you still don't understand, then maybe that is an indication that you don't have enough knowledge of the basics. In this case, perhaps you should try to read a book on SQL and relational database theory.
Myself only asked that question also.
Now also i am asking u r able to solve this question
or not.As I said, I will read the other thread (where you have started to get help) and if I have anything to add, I will post there. -
SQL Query help ( On connect By level clause)
Hi all,
I have this query developed with data in with clause.
With dat As
select '@AAA @SSS @DDD' col1 from dual union all
select '@ZZZ @XXX @TTT @RRR @ZZA' col1 from dual
Select regexp_substr( col1 , '[^@][A-Z]+',1,level) Show from dat
connect by level <= regexp_count(col1, '@');Current output :-
SHOW
AAA
SSS
DDD
RRR
ZZA
TTT
RRR
ZZA
XXX
DDD
RRR
SHOW
ZZA
TTT
RRR
ZZA
. . .1st row comes fine, But next row data is getting duplicated. And total record count = 30. I tried with some but didn't work.
Expected output :-
SHOW
AAA
SSS
DDD
ZZZ
XXX
TTT
RRR
ZZAI need some change on my query and I am not able to find that. So anybody can add on that or can also provide some different solution too.
Thanks!
AshutoshHi,
When you use something like "CONNECT BY LEVEL <= x", then at least one of the following must be true:
(a) the table has no more than 1 row
(b) there are other conditions in the CONNECT BY clause, or
(c) you know what you are doing.
To help see why, run this query
SELECT SYS_CONNECT_BY_PATH (dname, '/') AS path
, LEVEL
FROM scott.dept
CONNECT BY LEVEL <= 3
;and study the results:
PATH LEVEL
/ACCOUNTING 1
/ACCOUNTING/ACCOUNTING 2
/ACCOUNTING/ACCOUNTING/ACCOUNTING 3
/ACCOUNTING/ACCOUNTING/RESEARCH 3
/ACCOUNTING/ACCOUNTING/SALES 3
/ACCOUNTING/ACCOUNTING/OPERATIONS 3
/ACCOUNTING/RESEARCH 2
/ACCOUNTING/RESEARCH/ACCOUNTING 3
/ACCOUNTING/RESEARCH/RESEARCH 3
/ACCOUNTING/RESEARCH/SALES 3
/ACCOUNTING/RESEARCH/OPERATIONS 3
/ACCOUNTING/SALES 2
/ACCOUNTING/SALES/ACCOUNTING 3
84 rows selected.
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