Subquery referencing parent query table????

Question

Well my problem ( which I hope has a solution :) ) is the following:
I work on a little OS Advertising project.
When an advertiser wants to start a campaign, he must see the list of the publisher websites where he can advertise.
::::SELECT [...] FROM website wsite[...]
With their places count
::::[...]COUNT(place.id) AS placeCnt[...]INNER JOIN place ON place.website_id = wsite.id[...]
-Yes but the websites that have at least 1 place
::::[...]GROUP BY wsite.id HAVING COUNT(place.id)>0[...]
-And here comes my big dead end problem:
I would like to remove the websites where the advertiser can't advertiser.
I mean by there > if every ads of the advertiser are blacklisted for the site "google.com", he can't see "google.com" in the list because he won't be able to advertiser on in anyway.
however, if the advertiser has 4 ads, and all of it are blacklisted excepted the 4th, he must see "google.com" because he can advertise with the ad #4.
There is 2 types of blacklisting :
targetted ( by defining a website id on the blacklist line )
global ( by setting the website id = null , so for example if ad#1 is globally blacklisted by user #1, ad#1 couldn't be able to advertise on every websites of user#1 )
I thought I found a solutoin put it doesn't seem to work:
::::WHERE 0< (
SELECT COUNT(DISTINCT ad.id)
FROM ad
LEFT OUTER JOIN blacklist bl ON bl.ad_id =ad.id AND (bl.website_id=wsite.id OR bl.site_id IS NULL)
WHERE ad.user_id= $userid
AND bl.id IS NULL
A concrete scenario example: ( SQL included at the end of the post )
the user [email protected] ( userid = 2 ) has 3 ads.
-"my forbidden ad" ( id = 1)
-"my ad" ( id = 2 )
-"my unappreciated ad" ( id = 3 )
the user [email protected] ( userid = 1 ) has 3 websites
-google.com ( id = 1 )
-yahoo.com ( id = 2 )
[email protected] has blacklisted the following ads:
-"my unappreciated ad" ON yahoo.com, type targetted, ( website_id = 2, ad_id = 3 , publisher_id = 1)
-"my forbidden ad" type global, ( website_id = null , ad_id = 1 publisher_id = 1)
so the publisher websites we'll see with the resulting query should be ( as the the advertiser, user 2 ) :
google.com
yahoo.com
lol.com
WHY?
-Because the advertiser can advertise thanks to ad 2 ( ad2 is allowed to be advertised on each website )
-Even if "forbidden ad" is blacklisted globally, unapprediated ad remains for google.com
NOW, if the publisher adds another blacklist restriction
-"my ad" , type global ( website_id = null, ad_id = 2 , publisher_id = 1)
the result would be ( as the the advertiser, user 2 )
google.com
WHY?
-Because the advertiser do not have any ad to put on yahoo.com. Ad 1 and Ad 2 are blacklisted globally, ad 3 is blacklisted for yahoo.com
WELL, I thought I found the solution by this query but mysql returns an error > unknown colum on the subquery
THe only thing I want to is to LINK the parent query WITH the subquery ON bl.site_id=psite.id
Enfin bon, tout ça pour un truc qui semblait être possible avec cette requête mais qui renvoie donc une erreur de unknown column:
SELECT wsite.*,COUNT(place.id) AS placeCnt
FROM website wsite
INNER JOIN place ON place.website_id = wsite.id
WHERE 0< (
SELECT COUNT(DISTINCT ad.id)
FROM ad
LEFT OUTER JOIN blacklist bl ON bl.ad_id =ad.id AND (*bl.website_id=wsite.id* OR bl.website_id IS NULL)
WHERE ad.advertiser_id= 2
AND bl.id IS NULL
GROUP BY wsite.id
HAVING COUNT(place.id)>0
WELL THANKS A LOT to have read this post, AND THANK YOU EVEN MORE IF SOMEONE FIND A TRICK!
PS :
( the only solution I can see for the moment is a loop like )
foreach($publisher_sites as $s){
if(advertiserCanAdvertiser($s['id'])) $sites[]=$s
but the performances are really bad
I think the following would help :)
MySQL Data Transfer
Source Host: localhost
Source Database: orads
Target Host: localhost
Target Database: orads
Date: 10/20/2009 1:02:03 PM
SET FOREIGN_KEY_CHECKS=0;
-- Table structure for ad
DROP TABLE IF EXISTS `ad`;
CREATE TABLE `ad` (
`id` int(11) NOT NULL auto_increment,
`title` varchar(32) NOT NULL,
`url` varchar(50) NOT NULL,
`advertiser_id` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
-- Table structure for blacklist
DROP TABLE IF EXISTS `blacklist`;
CREATE TABLE `blacklist` (
`id` int(11) NOT NULL auto_increment,
`ad_id` int(11) NOT NULL,
`website_id` int(11) default NULL,
`publisher_id` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;
-- Table structure for place
DROP TABLE IF EXISTS `place`;
CREATE TABLE `place` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(32) NOT NULL,
`website_id` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
-- Table structure for user
DROP TABLE IF EXISTS `user`;
CREATE TABLE `user` (
`id` int(11) NOT NULL auto_increment,
`email` varchar(64) NOT NULL,
`password` varchar(16) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;
-- Table structure for website
DROP TABLE IF EXISTS `website`;
CREATE TABLE `website` (
`id` int(11) NOT NULL auto_increment,
`title` varchar(32) NOT NULL,
`url` varchar(32) NOT NULL,
`publisher_id` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
-- Records
INSERT INTO `ad` VALUES ('1', 'my forbidden ad 1', 'http://www.no.com', '2');
INSERT INTO `ad` VALUES ('2', 'my ad 2', 'http://www.lol.com', '2');
INSERT INTO `ad` VALUES ('3', 'my unappreciated ad 3', 'http://www.abc.com', '2');
INSERT INTO `blacklist` VALUES ('1', '1', null, '1');
INSERT INTO `blacklist` VALUES ('2', '3', '2', '1');
INSERT INTO `place` VALUES ('1', 'banner1', '1');
INSERT INTO `place` VALUES ('2', 'yahoo banner', '2');
INSERT INTO `user` VALUES ('1', '[email protected]', 'publisher');
INSERT INTO `user` VALUES ('2', '[email protected]', 'advertiser');
INSERT INTO `website` VALUES ('1', 'google', 'http://www.google.com', '1');
INSERT INTO `website` VALUES ('2', 'yahoo', 'http://www.yahoo.com', '1');
Edited by: user12086067 on Oct 20, 2009 4:51 AM

Answer 1

Hi,
Welcome to the forum!
Interesting problem!
Here's one way to do that in Oracle:
SELECT DISTINCT     w.*
FROM     website     w
JOIN     place     p  ON     p.website_id     = w.id
JOIN     ad     a  ON     w.publisher_id     NOT IN (
                                SELECT     b.publisher_id
                                FROM     blacklist     b
                                WHERE     b.ad_id     = a.id
                                AND     COALESCE ( b.website_id
                                                , w.id
                                         ) = w.id
WHERE     a.advertiser_id     = 2     -- parameter
;Thanks for posting the CREATE TABLE and INSERT statements. Since this is an Oracle forum, you should post statementts that will work in Oracle.
I don't know anything about MySQL, so I don't know if you'll need to change query above or not.
This doesn't quite produce the output you requested, since lol.com isn't in the website table. Do you need to get lol.com from the user table somehow?