SUBSTR or regular expression needed

Hello,
I have the below example:
CREATE TABLE "ARCHITECT"."TEST_DD"
(     "TABLE_NAME" VARCHAR2(100),
     "APPLICATION_NAME" VARCHAR2(100),
     "COLUMN_NAME" VARCHAR2(100),
     "COLUMN_DESCRIPTION" VARCHAR2(2000)
) PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255 NOCOMPRESS LOGGING
STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT)
TABLESPACE "MYTABLESPACE"
i want to have the below result
CREATE TABLE "ARCHITECT"."TEST_DD"
(     "TABLE_NAME" VARCHAR2(100),
     "APPLICATION_NAME" VARCHAR2(100),
     "COLUMN_NAME" VARCHAR2(100),
     "COLUMN_DESCRIPTION" VARCHAR2(2000)
That is mean i want to cut every think after PCTFREE, the above create table is just and example, i may have any create table statement with the PCTFREE keyword
Please can i have your help

modify the transform parameters
SQL> begin
2     dbms_metadata.set_transform_param(dbms_metadata.session_transform,'STORAGE',false);
3     dbms_metadata.set_transform_param(dbms_metadata.session_transform,'TABLESPACE',false);
4     dbms_metadata.set_transform_param(dbms_metadata.session_transform,'SEGMENT_ATTRIBUTES', false);
5 end;
6 /
PL/SQL procedure successfully completed.
SQL>
SQL> select dbms_metadata.get_ddl ('TABLE', 'EMP')
2    from dual
3
SQL> /
DBMS_METADATA.GET_DDL('TABLE','EMP')
CREATE TABLE "SCOTT"."EMP"
   (    "EMPNO" NUMBER(4,0) NOT NULL ENABLE,
        "ENAME" VARCHAR2(10),
        "JOB" VARCHAR2(9),
        "MGR" NUMBER(4,0),
        "HIREDATE" DATE,
        "SAL" NUMBER(7,2),
        "COMM" NUMBER(7,2),
        "DEPTNO" NUMBER(2,0)
SQL>

Similar Messages

How to fetch substring using regular expression

Hi,
I am new to using regular expression and would like to know some basic details of how to use them in Java.
I have a String example= "http://www.google.com/foobar.html#*q*=database&aq=f&aqi=g10&fp=c9fe100d9e542c1e" and would like to get the value of "q" parameter (in bold) using regular expression in java.
For the same example, when we tried using javascript:
match = example.match("/^http:\/\/(?:(?!mail\.)[^\.]+?\.)?google\.[^\?#]+(?:.*[\?#&](?:as_q|q)=([^&]+))?/i}");
document.write('
' + match);
We are getting the output as: http://www.google.com/foobar.html#q=database,*database* where the bold text is the value of "q" parameter.
In Java we are trying to get the value of the q parameter separately or atleast resembles the output given by JavaScript. Please help me resolving this issue.
Regards
Praveen

BalusC wrote:
Regex is a cumbersome solution for fixed patterns like URL's. String#substring() in combination with String#indexOf would most likely already suffice.I usually agree, although, in this case, finding the exact parameter might be difficult without a small regex, perhaps:
"\\wq=\\s*"in conjunction with Pattern/Matcher, used similarly to an indexOf() to find the start of the parameter value.
Winston

Searching for a substring using Regular Expression

I have a lengthy String similar to repetetion of the one below
String str="<option value='116813070'>Something1</option><option value='ABCDEF' selected>Something 2</option>"I need to search for the Sub string "<option value='ABCDEF' selected>" (need to get the starting index of sub string) and but the value ABCDEF can be anything numberic with varying length.
Is there any way i can do it using regular expressions(I have no other options than regular expression)?
thanks in advance.

If you go through the tutorial then you will find this on the second page:
import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
    public static void main(String[] args){
        Console console = System.console();
        if (console == null) {
            System.err.println("No console.");
            System.exit(1);
        while (true) {
            Pattern pattern =
            Pattern.compile(console.readLine("%nEnter your regex: "));
            Matcher matcher =
            pattern.matcher(console.readLine("Enter input string to search: "));
            boolean found = false;
            while (matcher.find()) {
                console.format("I found the text \"%s\" starting at " +
                   "index %d and ending at index %d.%n",
                    matcher.group(), matcher.start(), matcher.end());
                found = true;
            if(!found){
                console.format("No match found.%n");
}It's does everything you need and a bit more. Adapt it to your needs then write a regular expression. Then if you have problems by all means come back and post them up here, but first at least attempt to solve it yourself.

Java Regular Expression Need Help

I want regular Expression that accept all numbers and it should skip the numbers if it comes in {}

No this is not workingThen you need to be MUCH clearer as to exactly what you are trying to acheive...
We aren't mind readers... try posting the string you are parsing and the exact result that you want to get

Help with regular expression needed

Hi,
Perhaps someone here can help me with my regular expression I'm trying to build in my Java code.
The regular expression that I'm looking to build consists of any non-whitespace character up until it finds one or two <>= symbols and then any character thereafter. So both these Strings would match the expression:
City 1==London
Age>=18
The regular expression that I'm using is as follows:
(\\S+)([><=]){1,2}(.+)However, group 1 always retrieves the first <>= symbol as in "City 1=". How can I make the <>= part greedy so that it retrieves both operator symbols?
Thanks.

Make the first group, the non-spaces, reluctant:
"(\\S+?)([<>=]{1,2})(.+)"

Regular expression needed to escape dots

Hello
In a file , I might have several times a line like this :
VALOR DESCUENTO .......                           1,505,728.80What is the regular expression to get *1,505,728.80* ? Please note that there are dots ..how do i escape them ?
This is what I use , but it does not work
String descuentoPattern = "VALOR DESCUENTO(?:\\s+?)(?:^\\s+?)(?:\\s+?)(.*)"; cheers,
deibys

BigDaddyLoveHandles wrote:
The same way you escape any character -- with a backslash.Remembering to double-up backslashes in Java strings, of course.
@deibys, your regex is wrong. Try this instead:
String foo = "VALOR DESCUENTO .......                           1,505,728.80";
String pattern = "VALOR DESCUENTO\\s*\\.+\\s+(.*)";
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(foo);
if (m.matches()) {
     System.out.println("Match found: " + m.group(1));
}

Question on Substring or Regular Expression

Experts,
I have values is column similar to this:
Remarks:
IHCIS 651216 K6
KORE 657526
COR SWITX 658999 K6 ADHOC
I need to pull out the number starting with "6" (it always starts with 6, and it is always six characters). I then need to set the value of another column to that substring.
Update table x
set p_code = "Query returning the substring value"
I've used substring before but I don't know how to search for the "6" since it is in different locations for each row.
Any help is greatly appreciated.
Rich

Hi,
Here is an example using "SUBSTR':
SQL> select substr('IHCIS 651216 K6', instr('IHCIS 651216 K6', '6') , 6) from dual;
SUBSTR
651216

Regular Expression needed for a password validator

Business Rules:
Password must be at least 8 characters
Contain at least 1 non alpha character and no spaces.
Here is what I got so far:
String regex = "(?=^.{8,}$)((?!.*\\s)(?=.*[^a-zA-Z])(?=.*[a-zA-Z0-9]))^.*$";
        String [] password = new String [7];
        password [0] = "H@ffman1";
        password [1] = "hoffman1";
        password [2] = "Hoffman1";
        password [3] = "Hoffman 1";
        password [4] = "hoffman 1";
        password [5] = "hoffmans";
        password [6] = "123456789";
        for(int i=0; i<password.length; i++){
            Pattern pattern = Pattern.compile(regex.trim());
            Matcher matcher = pattern.matcher(password);
System.out.println(password[i] + " == " + matcher.matches());
}Output:
H@ffman1 == true
hoffman1 == true
Hoffman1 == true
Hoffman 1 == false
hoffman 1 == false
hoffmans == true // (This is a problem)
123456789 == true // (This is a problem)

YoungWinston wrote:
prometheuzz wrote:
which is pretty much what our OldWinston suggested...Actually, I was thinking more along the lines of
System.out.println( password.matches("^[^\\s]{8,}$")
&& password[i].matches("[^a-zA-Z]") );
(I may have got the number of backslahes wrong; 'always forget that stuff).Ah, I see. But you probably meant:
password.matches(".*[^a-zA-Z].*")and they're cryptic enough as it is :-).
Cryptic? Nah...

Command line style regular expression string parser

Hi people,
I am currently working on a program where I need to parse a file (or any input stream) line by line. I then need to parse every line for arguments. Each line is formatted similar to how arguments are passed to the command line. The regular expression needs to split every line by any encountered whitespace, but needs to be able to retain any whitespace within double quotes (i.e. "some spaced text here"). Arguments can be numbers, booleans and (quoted) strings. Quoted strings must also be able to have escaped quotes in it (as below). The quotes for the quoted string (the outer ones, obviously not the escaped ones) do not necessarily have to be retained.
An example input line:
arg1 arg2 "arg 3" "arg 4" 987 arg6 "arg \"arg \"arg 7"
Desired example output:
arg1
arg2
arg 3
arg 4
987
arg6
arg "arg "arg 7
After the input line has been split up the program will handle any parsing (i.e. numbers, booleans, etc.). The program currently uses a simple for loop to iterate over all characters in the line and splits it up appropriately by checking every character. However, if this can be done automatically by using a regular expression passed to String.split() (or with some use of the regex package), it would remove quite a bit of redunant code and make the program that much more maintainable.
I do not have much experience with regular expressions since I have never really had the need to use them, but if they can work in this case it would be great.
Thanks in advance for any help.

Almost any parsing problem can be solved if you throw a big enough and ugly enough regex at it, or so I'm told.
I think what you are doing is also amenable to java.io.StreamTokenizer:
import java.io.*;
import static java.io.StreamTokenizer.*;
public class StreamTokenizerExample {
    public static void main(String[] args) throws IOException {
        StringReader input = new StringReader("arg1 arg2 \"arg 3\" \"arg 4\" 987 arg6 \"arg \\\"arg\\\" arg 7\"\nnextline");
        StreamTokenizer in = new StreamTokenizer(input);
        in.eolIsSignificant(true);
        for(int ttype; (ttype = in.nextToken()) != TT_EOF; ) {
            switch (ttype) {
                case TT_WORD:
                    System.out.println("String[" + in.sval + "]");
                    break;
                case TT_NUMBER:
                    System.out.println("number[" + in.nval + "]");
                    break;
                case TT_EOL:
                    System.out.println("[EOL]");
                    break;
                case '"':
                    System.out.println("quoted[" + in.sval + "]");
                    break;
                default:
                    System.out.println("unexpected " + ttype);
{code}

Need help in unix regular expressions

Hi All,
I'm new to shell scripting. Please help me in achieving this
I am trying to a find regular expression that need to pick a file with begin with the below format and mask variable is called in xml file.
currently the script accepts:
mask="CLIENT_ID+'_ADHSUITE_IN_'+date2str(now,'MMddyy','US/Eastern')+'.txt'"
But it should accept in the below format
2595_ADHSUITE_IN_ANNWEL_030309_2009-02-10_15-12-46-000_648.TXT715.outpgp_out
where CLIENT_ID=2595. How to place wild card character '*' in the below to accept file in the above format. here is what i made changes.
mask="CLIENT_ID+'_ADHSUITE_IN_'*+date2str(now,'MMddyy','US/Eastern')*+'.TXT'*+'.outpgp_out'"
Please help.
Thanks

I believe your statement is being passed over twice:
First Pass: (This is done by something like javascript)
CLIENT_ID+'_ADHSUITE_IN_'+'.*'+date2str(now,'MMddyy','US/Eastern')+'.*'+'.TXT'+'.*'+'.outpgp_out'In this pass the variables and functions that are enclosed in literals are processed:
(1) CLIENT_ID is replaced by 2595 or whatever is current value is:
(2) date2str(now,'MMddyy','US/Eastern') gets replaced by 040609 (if the current time now is 4th april 2009).
So at the end of this first pass we have a string:
2595_ADHSUITE_IN_.\*040609.\*.TXT.*.outpgp_outThis string at the end of the first pass is a Posix basic regular expression. (ref: [http://en.wikipedia.org/wiki/Regular_expression] ) accessed at time of post).
This is the string I put in the Regular Expression text box on [http://www.fileformat.info/tool/regex.htm]
and it matches "2595_ADHSUITE_IN_ANNWEL_040609_2009-01-27_17-02-28-000_631.TXT715.outpgp_out" for me (though I prefer my egrep test).
I hope this is somewhat clearer. Remember I have very little information about your system/application and I make big guesses.
NB: (I should thank Frits earlier for pointing my sloppiness between wildcards (for eg unix shell filename expansion) and regular expressions).
For the second pass this used to compared other strings to see

I need help renaming a file using regular expressions in Bridge.

Hi,
I work at a university, and we are working through files for our Thesis and Dissertations. We have been renaming them to make them more consistent. I am just wondering if there is a regular expression that could help with this process?
Here is come examples of current file names;
THESIS 1981 H343G
Thesis 1981 g996e
THESIS-1981-A543G
I don't need to change the actual names of the files. just how they are formatted.
Proper case on Thesis.
Hyphens(-) in all white space.
First letter capital, last letter lowercase on the call no (H343g)
So the list above should look like;
Thesis-1981-H343g
Thesis-1981-G996e
Thesis-1981-A543g
I have seen people do some pretty cool things with regular expressions! Any help would be greatly appreciated. Thanks!

You would be better off using a script to do this as an example as I don't think it would be possible in the Bridge re-name.
Using ExtendScript Toolkit or a Plain text editor copy the code into either and save it out as Filename.jsx
This needs to be saved into the correct folder. this is found by going to the preferences in Bridge, selecting Startup Scripts, this will open the folder where the script is to be saved.
Once this is done close and re-start Bridge.
To Use: Goto the Tools Menu and select Rename PDFs
Make sure you test the code with a few copied files into a seperate folder first to make sure it does what you want.
The script will do all PDF files in the selected folder.
#target bridge
if( BridgeTalk.appName == "bridge" ) {
renamePDFs = MenuElement.create("command", "Rename PDFs", "at the end of Tools");
renamePDFs.onSelect = function () {
app.document.deselectAll();
var thumbs = app.document.getSelection("pdf");
for( var z in thumbs){
var Name = decodeURI(thumbs[z].spec.name);
var parts = Name.toLowerCase().replace(/\s/g,'-').match(/(.*)(-)(.*)(-)(.*)(\.pdf)/);
var NewName = parts[1].replace(/^[a-z]/, function(s){ return s.toUpperCase() });
NewName += parts[2]+parts[3]+parts[4]+parts[5].toUpperCase().replace(/[A-Z]$/, function(s){ return s.toLowerCase() });
NewName += parts[6];
thumbs[z].spec.rename(NewName);

Help needed regarding regular expressions

hello
i need to write a program that recieves a matematical expression and evaluates
it...in other words a calculator :)
i know i need to use regular expressions inorder to determine if the input is legal or not ,but i'm really having trouble setting the pattern
the expression can be in the form : Axxze2223+log(5)+(2*3)*(5+4)
where Axxze2223 is a variable(i.e a combination of letters and numbers.)
where as: l o g (5) or log() or Axxx33aaaa or () are illegal
i tried to set the pattern but i got exceptions or it just didnt work the way i wanted it .
here's what i tried to do at least for the varibale form:
"\\s*(*([a-zA-Z]+\\d)+)*\\s*";
i'm really new to this...and i can't seem to set the pattern by using regular expressions,how can i combine all the rules to one string?
any help or references would be appreciated
thanks

so i'll explain
let's say i got token "abc22c"(let's call it "token")
i wan't to check if it's legal
i define:
String varPattern = "\\s*[a-zA-Z]+\\d+\\s*";If you want to check a sequence of ASCII characters, longer than one, followed by a single digit, the whole possibly surrounded by spaces -- yes.
>
now i want to check if it's o.k
so i check:
token.matches(varPattern);
am i correct?Quite. It's better to compile the Pattern (Pattern.compile(String)), create a java.util.regex.Matcher (Pattern#matcher(CharSequence)), and test the Matcher for Matcher#matches().
(Class.method -> static method, Class#method -> instance method)
>
now i'm having problem defining pattern for log()
sin() cos()
that brackets are mandatory ,and there must be an
expression inside
how do i do that?First, I'd check the overall function syntax (a valid name, brackets), then whether what's inside the brackets is a valid expression (maybe empty), then whether that expression is valid for that function (presumably always?).
I might add I'm no expert on parsing, so that's more a supposition than a guide.

Need help in writing regular expressions involving \w

Hi,
Here is my requirement .
I have a string : GTA - 12AB TRA - 12AB
I need a regex that represent above string.
GTA - Constant - This wont change
12AB - This will be \w (alphanumeric)
Here I cannot have TRA within this 4 characters.
The question is :
How can I write an expression which says it can be a word(the positions where I have 12AB in example) but not TRA in sequence.
Is this doable?
Thanks in advance.

Use lookarounds: [http://www.regular-expressions.info/lookaround.html]
The regex:
(?!.?TRA).{4}matches any 4 characters (except line breaks) that does not contain 'TRA'.

Need to remove Commas REgular Expressions?

How can I use java to remove commas from a number.
1,000 string
need it to be
1000
can I pass it through some sort of regular expression?

I was attempting to do it with regular expressions to learn how to do them better.
Thanks for your good comment.
nupevic

Regular expression for 2nd occurance of a substring in a string

Hi,
1)
i want to find the second occurrence of a substring in a string with regular expression so that i can modify that only.
Ex: i have a string like ---> axe,afn,sdk,jdi,afn,mki,mki
in this i want the second occurance of afn and change that one only...
which regular expression i have to use...
Note that ...i have to use regular expression only....no string manipulation methods...(strictly)
2)
How can i apply the multiple regular expressions multiple times on a single string ..i.e in the above instance i have to apply the same 2nd occurrence logic for
substring mki also. for this i have to use a single regular expression string that contains validations for both the sub strings mki and afn.
Thanks in advance,
Venkat

javafreak666 wrote:
Hi,
1)
i want to find the second occurrence of a substring in a string with regular expression so that i can modify that only.
Ex: i have a string like ---> axe,afn,sdk,jdi,afn,mki,mki
in this i want the second occurance of afn and change that one only...
which regular expression i have to use...
Note that ...i have to use regular expression only....no string manipulation methods...(strictly)
2)
How can i apply the multiple regular expressions multiple times on a single string ..i.e in the above instance i have to apply the same 2nd occurrence logic for
substring mki also. for this i have to use a single regular expression string that contains validations for both the sub strings mki and afn.
Thanks in advance,
VenkatWhat do you mean by using a regex to get the index of a second substring? There is not method in Java which uses regex to et the index of a substring.
There are various indexOf(...) methods for this:
String text = "axe,afn,sdk,jdi,afn,mki,mki";
String target = "afn";
int second = text.indexOf(target, text.indexOf(target)+1);
System.out.println("second="+second);Of course you can find the index of a group like this:
Matcher m = Pattern.compile(target+".*?("+target+")").matcher(text);
System.out.println(m.find() ? "index="+m.start(1) : "nothing found");but there is not single method that handles this: you'll have to call the find() and then the start(...) method on the Matcher instance, so the indexOf(...) approach is the favourable one, IMO.

SUBSTR or regular expression needed

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