Substring instr issue in obiee

Question

Hi,
I want to use the INSTR function in OBIEE
POSITION function found in the forum
INSTR function takes four values:
INSTR (string1, string2, number, number)
Eg IP address
111.222.333.444
The desired result
SUBSTR (IP_ADD, 1, INSTR (IP_ADD, '.', 1,3) -1)
111.222.333
POSITION function, how should I use?
Thanks,
Mino

Answer 1

1st example '0.0.0.0' will def be a problem here. Unfortunately, I don't think any other OBIEE string function could support this.
I was assuming for min 2 numbers like 00.00.00.00. Do you have any case like the first one in your table ?
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As I said, you can't use POSITION function here..Just do help for String Function in RPD)
Position
Returns the numerical position of the character_expression1 in a character expression. If the character_expression1 is not found, the function returns 0.
Syntax:
POSITION(character_expression1 IN character_expression2)
where:
character_expression1
Any expression that evaluates to a character string. Used to search in the second string.
character_expression2
Any expression that evaluates to a character string.
So, these are the 2 expression, In your case its '.' & IP_ADDR.
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Hope its helpful