Swapping little endian short to big endian short

Question

I am trying to read a unsigned short value that a C program generates in my Java MIDlet. I am reading the data using a ByteArrayInputStream in conjunction with a DataInputStream. I tried calling readShort but it was returning bogus values. Here's the problem:
The short I am trying to read in is 0xb500 (it was generated on a little endian machine) the value should be 181. I realized my mistake using readShort (it was signing the value) and so I called readUnsignedShort instead. Now the value of the int after the call to readUnsignedShort is 0xb500 (46336). I need to swap this value back to 0x00b5 (181) on the Java side. I have used the following function, but it returns 0xb50000 and i'm not exactly sure why.
The swap function is like so:
public static int swapInt(int i)
     return ((i << 24)
| ((i & 0x0000ff00) << 8)
| ((i & 0x00ff0000) >>> 8)
| (i >>> 24));
I do not have any idea what >>> is in Java. I found this function on google groups. If anyone could help me find a solution to my problem it would be much appreciated.

Answer 1

An int is a signed 4 byte value (as I am sure you know)
You are using an int to represent an unsigned 2 byte value.
Now you want to swap the 2 bytes of your unsigned 2 byte value.
This means that you only want to swap the two least significant bytes of your int.
Oh, by the way, USE CODE TAGS TO FORMAT CODE!!!
[code]
public static int swapUnsignedShort(int i) {
    return ((i & 0x00FF) << 8) | ((i & 0xFF00) >> 8);
}[[i]code]