Sysdate on dbms_job Next_date

Question

Hi, actually i did post this before, i gonna repost again since no one reply me
my current code is like this:
DECLARE
JOBNUMBER NUMBER;
BEGIN
  dbms_job.submit(JOB => jobnumber,
  WHAT => 'BEGIN .........end;',
  NEXT_DATE => to_date('26/06/2009 23:00','DD/MM/YYYY HH24:MI'),
  INTERVAL => '(SYSDATE) + 1' );
COMMIT;
END;how to make it run on today date (sysdate) with the run time set on 11pm. The all_jobs should be like this:
Job     LAST_DATE       LAST_SEC    THIS_DATE  THIS_SEC   NEXT_DATE     NEXT_SEC        TOTAL_TIME                                      TOTAL INTERVAL
525     26-JUN-09     23:00:00     (null)     (null)     27-JUN-09     23:00:35     21.00000000000000000000000000000000000004     (sysdate) + 1Thanks
Edited by: newBJeat on Jun 26, 2009 12:40 AM
Edited by: newBJeat on Jun 26, 2009 12:48 AM

Answer 1

Hi
Current code works fine, but didn't work as what i want. Yeah in my case both are null, like this:
Job  LAST_DATE LAST_SEC THIS_DATE THIS_SEC  NEXT_DATE  NEXT_SEC   TOTAL_TIME    TOTAL INTERVAL
530     (null)     (null)     (null)     (null)     26-06-2009 23:00:00     23:00:00     (SYSDATE) + 1I just need the job run everyday exactly on 11pm follow the system date and keep run routine without user to run manually....I just don't know how the sysdate format is? (like what in my code
NEXT_DATE => to_date('26/06/2009 23:00','DD/MM/YYYY HH24:MI'),where sysdate have to place in my code???
Thanks
Edited by: newBJeat on Jun 26, 2009 1:02 AM
Edited by: newBJeat on Jun 26, 2009 1:06 AM