System.out.printIn errors

Question

ok the book gives me this source code:
public class Ellsworth {
public static void main(String[] arguments) {
String line1 = "The advancement of the arts, from year\n";
String line2 = "to year, taxes our credulity, and seems\n";
String line3 = "to presage the arrival of that period\n";
String line4 = "when human improvement must end.";
String quote = line1 + line2 + line3 + line4;
String speaker = "Henry Ellsworth";
String title = "U.S. Commissioner of Patents";
String from = "1843 Annual Report of the Patent Office";
System.out.printIn('\u0022' + quote + '\u0022');
System.out.printIn("\t" + speaker);
System.out.printIn("\t" + title);
System.out.printIn("\t" + from);
I type that in, and in msdos when I type javac ellsworth.java, it gives me the following:
ellsworth.java:11: cannot resolve symbol
symbol : method printIn (java.lang.String)
location: class java.io.PrintStream
System.out.printIn('\u0022' + quote + '\u0022');
�
ellsworth.java:12: cannot resolve symbol
symbol : method printIn (java.lang.String)
location: class java.io.PrintStream
System.out.printIn("\t" + speaker);
�
ellsworth.java:13: cannot resolve symbol
symbol : method printIn (java.lang.String)
location: class java.io.PrintStream
System.out.printIn("\t" + title);
�
ellsworth.java:14: cannot resolve symbol
symbol : method printIn (java.lang.String)
location: class java.io.PrintStream
System.out.printIn("\t" + from);
�
can anyone solve this for me please? I have SDK 1.3.1_04 (folder called jdk 1.3.1_04) and this is seroiusly pissing me off, I also have windows 2000 built on NT4.0 technology. any way to solve this would be very appreciated :)

Answer 1

Actual behaviour of 1.4.0_01 in Windows 98se is as follows:
Case 1
        Class name A
        File name  A.java
        javac A.java    compiles clean
        javac a.java    compiles clean
Case 2
        Class name a
        File name  a.java
        javac A.java    compiles clean
        javac a.java    compiles clean
Case 3
        Class name a
        File name  A.java
        javac A.java    compile fails
        javac a.java    compiles clean
Case 4
        Class name A
        File name  a.java
        javac A.java    compiles clean
        javac a.java    compile fails
A generalized statement of the behaviour is:.
If (class name and file name case match) {
    the program will compile with any commandline name case
If (class name and file name case do not match) {
    if (the commandline name case matches the class name case) {
        the program will compile
    } else {
        the program will fail to compile
}