Table hierarchy

I have user which consists of 150 tables.
I want to hierarchical list of tables in such as way that referential tables will be displayed first then base tables display.
e.g.
Dept and Emp table.
Emp(dept_id) references to Dept(dept_id)
So I should display in following manner
1. Emp
2. Dept
How can i get that list?
Thanks,

Hi!
Please look at this example. Is it what you are looking for?
SELECT MIN(a.table_name) OVER (partition by a.table_name order by a.table_name), b.table_name
FROM   user_constraints a, user_constraints b
WHERE a.constraint_name = b.r_constraint_name
GROUP BY a.table_name, b.table_name
MIN(A.TABLE_NAME)OVER(PARTITIO TABLE_NAME
COUNTRIES                      LOCATIONS
DEPARTMENTS                    EMPLOYEES
DEPARTMENTS                    JOB_HISTORY
EMPLOYEES                      EMPLOYEES
EMPLOYEES                      DEPARTMENTS
EMPLOYEES                      JOB_HISTORY
JOBS                           EMPLOYEES
JOBS                           JOB_HISTORY
LOCATIONS                      DEPARTMENTS
REGIONS                        COUNTRIESyours sincerely
Florian W.

Similar Messages

Table hierarchy in a schema

Hi,
How to find the tables hierarchy in a schema?
the output show independent tables first then
primary key tables then foreign key tables.
I am not asking for single table.we need overall the tables in a schema in hierarchy manner.

check this link....
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:661009003696
and your query might me something like....
select rpad( '*', (level-1)*2, '*' ) || table_name table_name
   from (select a.table_name,
        a.constraint_name pkey_constraint,
            b.constraint_name fkey_constraint,
             b.r_constraint_name
    from user_constraints a, user_constraints b
where a.table_name = b.table_name
   and a.constraint_type = 'P'
    and b.constraint_type = 'R'
    union all
    select table_name, constraint_name, null, null from user_constraints where
constraint_type= 'P'
) start with fkey_constraint is null
--and table_name = '<tablename>' this is used when you want to know the hierarchy starting with a particular table.
connect by nocycle prior pkey_constraint = r_constraint_name Ravi Kumar

How can i find out the table hierarchy

Hi experts,
I have one doubt. how can i find out the table hierarchy in the particular schema.
Let me explain my requirement in detail.. In my Database i have nearly 250 table each table have it's own temporary table(for authorization purpose we are maintaining the temporary tables) for each day i have to clear the temporary table data.
All temporary table connected with each other. i mean all the table having foreign key relationship.. while i attempt the delete the data from the temporary table it showed ORA-02292: integrity constraint violated - child record found.
So can any one please tell how can i delete the child table record first and then parent record table record.
Thanks in advance
Arun

CREATE OR REPLACE FUNCTION get_child_tables (
ptable VARCHAR2,
powner VARCHAR2 DEFAULT 'SCOTT',
plevel NUMBER DEFAULT 10
RETURN stringarray
-- -- create this ON SQL*PLUS "CREATE OR REPLACE TYPE STRINGARRAY AS TABLE OF VARCHAR2(50);"
-- AUTHID CURRENT_USER
PIPELINED
AUTHOR DATE VERSION COMMENTS
======================================================================================
[email protected] 26-OCT-2009 1.0 Developed to ease developers effort to find Nth level of Referential integrity
======================================================================================
-- PURPOSE -> To find PARENT=> CHILD relational TABLE(S) in Oracle upto a depth max N Level.
--SYNTAX TO USE
SELECT * FROM TABLE( get_child_tables('DEPT','SCOTT',3)); Store this query in a file for your use
SELECT * FROM TABLE( get_child_tables('EMPLOYEE')); Store this query in a file for your use
-- RESULTS looks as below
--1 => DEPT
--2 => EMP
--2 => EMP2
--3 => EMP_CHILD
--3 => EMP2_CHILD
-- and so on
--This can be leveraged to use in any oracle database REGION 10g having and above.
--This FUNCTION gives formatted result of the Oracle 10g Hierarchical query result coded in the cursor
--to find MASTER => CHILD relational TABLE(S) upto a depth max 10 Level.
--The result of the PIPELINED function can be retrieved using Oracle new operator
--TABLE(array name) in SQL query.
--Due to the AUTHID CURRENT_USER compiler directive any user can use based on his/her access privileges on the database.
--GRANT EXECUTE ON SCOTT.get_child_tables TO PUBLIC;
--CREATE OR REPLACE PUBLIC SYNONYM get_child_tables FOR SCOTT.get_child_tables;
IS
atname stringarray := stringarray ();
-- create this ON SQL*PLUS CREATE OR REPLACE TYPE STRINGARRAY AS TABLE OF VARCHAR2(50);
vlevel NUMBER;
vtname VARCHAR2 (50);
nindex NUMBER := 0;
bprocessed BOOLEAN := FALSE;
CURSOR c1 (powner_in IN VARCHAR2, ptable_in VARCHAR2, plevel_in NUMBER)
IS
SELECT LEVEL, LPAD (' ', (LEVEL - 1) * 2, ' ') || pt AS "TNAME"
FROM (SELECT a.owner w1, a.table_name pt, a.constraint_name c1,
a.r_constraint_name r1, b.owner w2, b.table_name ct,
b.constraint_name c2, b.r_constraint_name r2
FROM all_constraints a, all_constraints b
WHERE a.constraint_name = b.r_constraint_name(+)
AND a.owner = b.owner(+)
AND a.owner =
UPPER (powner)
-- Change Owner here while testing
--AND A.r_constraint_name IS NULL
AND a.constraint_type IN ('P', 'R')) v1
START WITH pt =
UPPER
(ptable)
-- Change your master table here while testing the QUERY
CONNECT BY PRIOR ct = pt AND LEVEL <= plevel;
-- Change lavel here while testing
BEGIN
atname.EXTEND;
atname (1) := 'NOTHING';
OPEN c1 (powner, ptable, plevel);
LOOP
bprocessed := FALSE;
FETCH c1
INTO vlevel, vtname;
IF nindex > 1 AND atname (atname.LAST - 1) = vtname
THEN
--DBMS_OUTPUT.PUT_LINE('2 ==== vtname ' ||vtname || ' '|| atname.count|| ' '||atname.last || ' '||atname( atname.last-1));
bprocessed := TRUE;
END IF;
IF NOT bprocessed
THEN
nindex := nindex + 1;
atname.EXTEND;
atname (nindex) := vtname;
PIPE ROW (vlevel || ' => ' || vtname);
DBMS_OUTPUT.put_line ( ' **** nindex - atname( nindex) '
|| nindex
|| ' - '
|| atname (nindex)
DLOG('ADDING ',vTname); A LOGGING ATONOMUS PROCEDURE FOR DEBUG PURPOSE
END IF;
EXIT WHEN c1%NOTFOUND;
END LOOP;
CLOSE c1;
FOR i IN 1 .. atname.COUNT
LOOP
DBMS_OUTPUT.PUT_LINE('atname (i) ' ||atname (i));
END LOOP;
RETURN;
EXCEPTION
WHEN no_data_needed
THEN -- THIS EXCEPTION HAS TO BE THERE TO GET THE FUCTION WORKABLE
DBMS_OUTPUT.put_line (SQLERRM);
RETURN;
--SELECT * FROM TABLE( get_child_tables('TB_XOP_LETR_TEMPLATE','OPS$CMS',5));
END get_child_tables;
Edited by: user3066657 on Jul 21, 2011 8:42 AM
Edited by: user3066657 on Jul 21, 2011 11:26 AM

How to find full tables hierarchy in schema

Hi,
How to find the table hierarchy list from oracle schema by using Reference Key constraint?
In my schema I am having many tables, approximate 4000 and from there I needs to get a single list which should be based in the Foriegn key based (Parent tables should be first then child tables)
Regards
Anee

You can start with this
select A.table_name children,
         B.TAble_name Father
from DBA_CONSTRAINTS A,
        DBA_CONSTRAINTS B
WHERE A.CONSTRAINT_TYPE = 'R'
     And B.Constraint_name = a.r_Constraint_name

SAP-BW text table,hierarchy

why we need text table in sap bw.Explian about hierarchy table in sap-bw

Hi,
BW text tables help in maintaining separate texts in different languages for the same code.
BIC/T<>
BW can maintain external hierachies for an infoobject which are stored in separate tables.Hierachies are stored separate (out of the basic star schema) by using these tables.
BIC/H<>Hierarchy table
BIC/I<>SID Hierachy structure
BIC/K<>Hierarchy SID table
BIC/J<>Hierarchy interval table
Assign points if helpful

Data base table hierarchy

hi ,
when i opened the Data Base table in SE11 ..the hierarchy of the fields r not displaying in a standard order.can anyone tell where we can find the setting option to rectify the correct sequence of the fields.
Suman R

Hi suman,
   You can do anything with the fields created already ,
   while displaying you can hide some fields and display
   goto the selection screen of table , in menu settings>format list>choose fields

Automatic assignment of hierarchy field in the main table

Hi,
We are upgrading from SRM-MDM catalog 2.0 to SRM-MDM catalog 3.0 sp07 patch 10.
In the main table, we have the standard field Hierarchy, that is a lookup on table Hierarchy.
In order to value this field, we have a specific field in the Main table, the UNSPSC code, that is a lookup on a specific reference table. This reference table makes the link between UNSPSC codes and nodes of the Hierarchy table.
After importing a new record that contains the UNSPSC code, we want to automatically assign a value to the hierarchy field in the Main table by the assignment's expression "[main table]UNSPSC code. [specific table]name of hierarchy. [Hierarchy table]name of hierarchy".
When executing this assignment, we get the error "Assignment operation failed: A runtime error occurred while evaluating an assignment, validation or calculated field".
Do you know if this kind of assignment is possible (it worked in MDM 5.5 but not anymore in 7.1) ? Or if there is a workaround ?
Thanks for your kind help.
Catherine

Hi Mandeep,
Thanks for your answer.
But, I do not want to assign a specific value to the Hierarchy field in the Main table. I want to determine it via a specific table.
Here is a sample of our data model to try to explain :
Main table :
item reference [Display field]
hierarchy --- lookup on Hierarchy table
UNSPSC code --- lookup on Specific reference table
Hierarchy table :
hierarchy name [Display field]
hierarchy code
Specific reference table, type flat :
UNSPSC code [Display field]
hierarchy name --- lookup on Hierarchy table
After import, in the Main table, item reference and UNSPSC code are valued.
In order to value the hierarchy field in the Main table, we would like to use the specific reference table :
[Main table]UNSPSC code >>> [Specific reference table]hierarchy name >>> [Hierarchy]hierarchy name.
This assignment works if the assignment field is a plain text field but not if it is the Hierarchy field of the Main table, which is on lookup on the Hierarchy table.
Thanks for your help !
Best regards,
Catherine

Custom Report Layout with mutliple child tables

I am trying to create a custom report layout (using Bi Publisher) where I have parent data (multiple jobs on a page) and several child tables for each job (JobDays and JobStops) and several child tables for JobDays (JobDayProviders, JobDayCrew). On the apex screen, I have a join on Jobs and JobDays and I am using functions to string each child row value for JobDayProviders and JobDayCrew together and putting a <br> in between so that they will format on separate lines within a cell. It works fine on the screen but when trying to print to pdf, it ignores these line breaks. I have also tried using <br></br> (saw an article that said just use HTML in bi pulisher) which puts two lines in between each value on the screen and is still ignored on the pdf.
for example:
Table hierarchy:
Jobs table
Job Stops
Job Days
Job Day Service Providers
Job Day Crew
Report Layout per job (will have mutlipe jobs to print, just printing 1 day per job):
Jobs.col1 JobStops.row1 JobDay.col1 JobDayProviders.row1 JobDayCrew.r1
JobStops.row2 JobDayProviders.row2 JobDayCrew.r2
JobDayProviders.row3
Thanks,
Linda
First, is there a way to get bi publisher to recognize the line breaks? If not, what is the best way to create a custom report for this scenario? I tried to create a report query with mutliple queries, but cannot determine how to link the child queries to the paren query. I have seen an example where a button is pressed to print one parent row and the id of that row is saved and referenced as a parameter in each of the queries, but if printing mutliple parents on a report, how would I link the child queries to the parent query?

Helen,
The best way for your case is to use a content folder and customize it whichever way you like.
however, your question is about reports. the problem in reports is this that you have to use just one single query and the layout of the results of this query are displayed in a peculiar way.
anyway. something similar but not exactly the same as what you wanted do is the following.
use a query like the following: (with a union in between)
SELECT COLUMN1,NULL , NULL ,NULL ,NULL
FROM my_source_table
WHERE myCriteria LIKE 'SoAndSo%'
UNION
SELECT NULL,COLUMN2 , COLUMN3, COLUMN4, COLUMN5
FROM my_source_table
WHERE myCriteria LIKE 'SoAndSo%'
---------- Now, have the following codes in the layout segments:

<table border="0" cellpadding="1" cellspacing="1" width="20%" align="center">

<tr align="center">
<td><table border="0" cellpadding="1" cellspacing="0" width="30%" align="center">
<tr align="center">
<TH><#COLUMN1.FIELD#></TH>
</tr>
</table>
</td>
<TD class="report_cell" ALIGN="LEFT"><#COLUMN2.FIELD#></TD>
<TD class="report_cell" ALIGN="LEFT"><#COLUMN3.FIELD#></TD>
<TD class="report_cell" ALIGN="LEFT"><#COLUMN4.FIELD#></TD>
<TD class="report_cell" ALIGN="LEFT"><#COLUMN5.FIELD#></TD>
</tr>

<TR><TD></TD></TR>
this should produce a report with a table structure (you may see the whole if you give BORDER="1" in the main table tag). Within this table, the first column of the first row should be showing top-leftmost column value once (COLUMN1 value) and then the next rows would show last four column values as a table block on the right-bottom part.
with kind regards,
naqvi

Table Header not getting repeated in subsequent pages

Hi,
I have a table and i want to table header to be repeated in subsequent pages but only till 2nd page the table header is repeated from the 3rd page onwards the table header is not repeated.
I have selected the Header Row in hierarchy and in Pagination tab for the header row i have checked the the check box Insert Header Row in Subsequent Pages.
After selecting the checkbox also table header is repeated only in 2 pages and not repeated after the second page.
My table hierarchy in form is :
TableSubform
---Table
HeaderRow
Row1
I am using Designer 8.0 and Acrobat Reader 8.1.2
Can you please help me in solving this issue.
Regards,
Bala Baskaran.s

Hi All,
I have selected the the check box Insert Header Row in Subsequent Pages then also the header is not getting flowed in subsequent pages only till 2nd page its getting flowed.
I have used table wizard to create table and i have made the table subform as flowed then also table header is not repeating in subsequent pages.
MainForm (Flowed)
TableSubform1(Flowed)
Table1
HeaderRow
Row1
TableSubform2(Flowed)
Table2
HeaderRow
Row1
I selected TableSubform1 and in Pagination tab OverFlow Leader dropdown i selected HeaderRow, the same i did for TableSubform2 also but the table header is not getting repeated in subsequent pages.
Please help me in solving this problem.
Regards,
Bala Baskaran.S

OBIEE 11g Time Hierarchy with YTD function problem

Hi all,
Platform: OBIEE 11.1.1.5.0.
We have a Calendar dimension (*time dimension*), that includes the usual time hierarchy (Year > Semester > Quarter> Month > Day).
Creating a Pivot Table with a YTD measure, using also the Calendar Table hierarchy, everything works fine, and we can drill up & down always getting the right YTD values.
But, if we add to this analysis, a year and month prompts (filters), we only receive true YTD values, at the day and month levels of the hierarchy. Above this, values will sum up instead of getting the right YTD aggregated value.
YTD logical column definition = TODATE(Table A.Measure B , Hieararchy.Year)
Example of pivot values returned:
*2011*=1192812 (Sum of the 3 Semester not the YTD value)
Semester 1 = 377305 (Sum of the 4 Quarter not the YTD value)
Quarter 1= 107460 (Sum of the 3 months not the YTD value)
Jan = 18507 (YTD value)
Feb = 35223 (YTD value)
Mar = 53730 (YTD value)
Is there anything that we might be doing wrong?
Thanks in advance,
Ricardo

Ricardo,
You might be aggregatign values twice either at RPD level or at reprot level. Please check on that.

No Results after build a Parent-Child Hierarchy in OBIEE11G

Hi All:
Here's an problem. I followed the "http://sandybi.wordpress.com/2010/08/17/hierarchies-in-obiee-11g-part-1/" this article step by step to create a parent-child hierarchy in admin tool in OBIEE11G.
But after check in and try to retrieve the hierarchy data in Answer. There's always displays "No Results."
Is there any suggestions for this ? Really urgent and thanks for your help.
Best regards
Sunny

@Aketi
It is One way that We derive
"sys_connect_by_path(RowIDToChar(RowID),'.') as
RowIDList"
Then
We use Left Join Using
"instr(RowIDList,RowIDToChar(RowID))".sorry, didn't catch what you mean.
my site :-)
http://oraclesqlpuzzle.hp.infoseek.co.jp/4-13.html
pity, I don't know Japanese :(
@Rob
your query is good and simple :) probably it's the best alternative for the OP.
But it won't work with not a plain hierarchy, e.g.:
      1
    2   3
      4
    5   6
SQL> create table hierarchy (child,parent)
2     as
3     select 1, null from dual union all
4     select 2, 1 from dual union all
5     select 3, 1 from dual union all
6     select 4, 3 from dual union all
7     select 4, 2 from dual union all
8     select 5, 4 from dual union all
9     select 6, 4 from dual
10 /
Table created
SQL>
SQL> create table data (hierarchyid,value)
2    as
3    select 5, 10 from dual union all
4    select 6, 25 from dual
5 /
Table created
SQL>
SQL> select h.child
2           , sum(connect_by_root d.value)
3        from hierarchy h
4           , data d
5       where h.child = d.hierarchyid (+)
6     connect by prior h.parent = h.child
7       group by h.child
8       order by h.child
9 /
     CHILD SUM(CONNECT_BY_ROOTD.VALUE)
         1                          70
         2                          35
         3                          35
         4                          70
         5                          10
         6                          25
6 rows selected
SQL>

Aggregation with a parent child hierarchy

Hi
I have 2 tables, hierarchy and data
hierarchy has 2 columns parent and child
data contains values for the lowest rungs of the hierarchy described.
What i'd like to do is, using the hierarchy described, sum the lowest rung values up to their parent values and so on.
Quick example:
Hierarchy
child parent
1 null
2 1
3 1
4 2
5 2
Data
hiearchyid value
3 10
4 20
5 30
output required
1 60
2 50
3 10
4 20
5 30
The last 3 rows are just the 2nd table so i can just union those in but how would i work out the first two values using sql... have tried combinations of connect by, analytics (partition by etc) and rollup but to no avail...
Any help would be appreciated..
Cheers
Alex

@Aketi
It is One way that We derive
"sys_connect_by_path(RowIDToChar(RowID),'.') as
RowIDList"
Then
We use Left Join Using
"instr(RowIDList,RowIDToChar(RowID))".sorry, didn't catch what you mean.
my site :-)
http://oraclesqlpuzzle.hp.infoseek.co.jp/4-13.html
pity, I don't know Japanese :(
@Rob
your query is good and simple :) probably it's the best alternative for the OP.
But it won't work with not a plain hierarchy, e.g.:
      1
    2   3
      4
    5   6
SQL> create table hierarchy (child,parent)
2     as
3     select 1, null from dual union all
4     select 2, 1 from dual union all
5     select 3, 1 from dual union all
6     select 4, 3 from dual union all
7     select 4, 2 from dual union all
8     select 5, 4 from dual union all
9     select 6, 4 from dual
10 /
Table created
SQL>
SQL> create table data (hierarchyid,value)
2    as
3    select 5, 10 from dual union all
4    select 6, 25 from dual
5 /
Table created
SQL>
SQL> select h.child
2           , sum(connect_by_root d.value)
3        from hierarchy h
4           , data d
5       where h.child = d.hierarchyid (+)
6     connect by prior h.parent = h.child
7       group by h.child
8       order by h.child
9 /
     CHILD SUM(CONNECT_BY_ROOTD.VALUE)
         1                          70
         2                          35
         3                          35
         4                          70
         5                          10
         6                          25
6 rows selected
SQL>

How do I stop IN CLAUSE when query a hierarchy of object.

I have a base class which is annotated with
@Entity(name="UdmHierarchyObject")
@Table(name="UDM_HIERARCHIES")
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
public class UdmHierarchyObject ...
I have a single table hierarchy of objects which use the following annotation:
@Entity(name="Lookup")
@DiscriminatorValue(value="Lookup")
public class Lookup extends UdmHierarchyObject ....
Now I may have MANY classes that extend the base and this is were I am worried. When I query, EclipseLink always creates an IN CLAUSE including all the subclassed entities, which I don't really need. And I worry about it's size.
An example query produces the SELECT below.
select l from Lookup l join l.data d
where l.hierarchyObjectName = :name and d.name = 'Code'
order by d.value"
2008-05-28 14:06:31,773 DEBUG [oracle.toplink.sql:135] - ClientSession(22145060)--Connection(23069842)--
SELECT t1.ID, t1.JPA_DISC, t1.OBJECT_NAME, t1.OBJECT_TYPE, t1.UPDATED_ON, t2.ID, t2.HIERARCHY_NAME, t2.PARENT_ID, t2.REFERENCE_ID FROM UDM_DATA t0, UDM_HIERARCHIES t2, UDM_OBJECTS t1 WHERE (((((t2.HIERARCHY_NAME = ?) AND (t0.DATA_NAME = ?)) AND (t2.ID = t1.ID)) AND (t1.JPA_DISC IN (?, ?))) AND (t0.OWNER_ID = t1.ID)) ORDER BY t0.DATA_VALUE ASC
bind => [StateCode, Code, Lookup, EventTypeCode]
The actual query is fine, however I don't always need the t1.JPA_DISC IN (?, ?) part because I am providing sufficient filtering.
Is there a way to suppress this in the query, or should I not be bothered with a large IN CLAUSE?
You comments would be appreciated.

The issue is you are querying a branch class, so only the children of this branch must be filtered. Unless you are noticing real performance issues with the IN, I would not worry about it too much.
Otherwise, you could consider using joined inheritance, or some level in between joined and single table (JPA does not support this, but TopLink does if you customize your descriptors).
You could also customize your TopLink descriptors using a DescriptorCustomizer to change how subclasses are filtered. You would need to set the ClassDescriptor's InheritancePolicy's withAllSubclassesExpression.
-- James : http://www.eclipselink.org

ALV WebDynpro Hierarchy -Setting non-numeric values in the header level row

Hi Experts,
When setting up an ALV table as a table hierarchy the standard ALV settings only seem to allow for numeric values to be displayed in the higher hierarchy levels. Is there a way to also set the values for some non-numeric columns into these higher-level rows - programmatically or through the ALV Settings?
Example: I have delivery item level data in my context and the delivery number as a hierarchy column. Some columns in my context however actually come from the delivery header e.g. delivery block, delivery priority, ship-to etc and I would like to display these in the collapsed header rows of the delivery number.
It seems obvious to me that this should be doable otherwise if you are looking at at a list of hundreds of deliveries and all you see besides the delivery number is numeric data such as sums & totals, it's kind of hard to know which delivery you might want to expand the sub-level for.
Please help,
Peter

Hi,
Even we have faced the same issue.
In ALV hierarchy, we cannot display data at header items/levels. this is a constraint in ALV. You can achieve the same usign TABLE UI element.

How to understand the hierarchy structure of 0PLANT io?

how to understand the hierarchy structure of 0PLANT io ?
i can understand the hierarchy structure of PRODUCT io,
well, i hope someone could explain the hierarchy structure of 0PLANT io
thanks.

Hi
You can use following hierarchy tables
RSTHIERNODE - Texts of Non-Postable Hierarchy Nodes
RSEHIERNODE - Master Data: Hierarchy Nodes that Cannot Be Posted To
RSMHIERNODE - Master data: Hierarchy nodes that cannot be posted to
RSHIEDIR - Hierarchy Catalog
RSHIEDIRT - Hierarchy directory texts
RSREQHIER - Data Request hierarchy
RSROLEHIERARCHY - Role hierarchy
In addition to these have a look at K table & I table for 0PLANT.
K table - Hierarchy SID table
I table - Hierarchy structure table
Hope this will help..!!
Thanks,
Vikrant

Table hierarchy

Similar Messages

Maybe you are looking for