Tabular form update manual

Dears ,
i have manual tabular form
select htmldb_item.checkbox(1,rownum) " ",
       x.service_id,
       x.service_name,
htmldb_item.checkbox( 4, flag,decode( flag, 1, 1, 0) ) flag
from (
select htmldb_item.hidden(2,c.service_id) service_id,
          htmldb_item.text(3,s.service_name)  service_name,
           htmldb_item.checkbox( 4, flag,decode( flag, 1, 1, 0) ) flag
from  CUST_SERVICES c,SERVICES s
where c.service_id=s.service_id
and  c.cust_id=:p6_customer_id) x
order by 2and make process to save
Type:     PL/SQL anonymous block
Process Point : on submit - after computation and validation
Run Process : once per page visit (defult)
source code :
for i in 1..htmldb_application.g_f01.count
loop
update CUST_SERVICES set flag = htmldb_application.g_f04(htmldb_application.g_f01(i));
-- where CUST_ID=:p6_customer_id
-- and  SERVICE_ID =htmldb_application.g_f02(htmldb_application.g_f01(i));
end loop;put it's not save , please help

Hi Phil,
You can add in the in-built MRU update process that will do this for you. When you add a process, select Data Manipulation then Multi Row Update, then follow the prompts to link it to your table.
In your code snippet, htmldb_application.g_f01 refers to the first column in your form (even if this is hidden). Normally this is the Primary Key for the table on which the form is based. htmldb_application.g_f02 refers to the second column and so on, although you can assign any number from 1 to 50 to each field when you create the sql statement.
The replace() function is used because some of the fields will contain %null% which needs to be converted to null before updating the table.
Regards
Andy

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    Denes Kubicek
    http://deneskubicek.blogspot.com/
    http://www.opal-consulting.de/training
    http://apex.oracle.com/pls/otn/f?p=31517:1
    http://www.amazon.de/Oracle-APEX-XE-Praxis/dp/3826655494
    -------------------------------------------------------------------

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