Take out time difference from 2 dates....

Hi Guys,
I have two date columns with date datatype in my table.
Office_Time and Employee_Time, date and time is stored in these columns.
I want to get the time difference between to dates and times.
Like if the office_time is 12-MAR-05 09:00:00 and Employee_Time is 12-MAR-05 10:15:00 then the differnce shud be 01:15:00 hours.
How to apply such a formula.. please help!
Imran Baig

Hi,
You can read the next topic :
Re: how to get time diff between to date
Nicolas.

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See following SQL.
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from dual
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1. FM for difference betwwen two times:SCOV_TIME_DIFF
Import parameters               Value
IM_DATE1                        2008-01-01
IM_DATE2                        2008-01-01
IM_TIME1                        10:00:00
IM_TIME2                        11:30:00
Export parameters               Value
EX_DAYS                         0
EX_TIME                         01:30:00
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Hi,
I would like to know a clue as below in the same thread as it is more relavant to this, if you do not mind.
I have one more query using the same table and set of data for one of the report.
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Calls by n min interval
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Please find the attached script for generating table and populating data.
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2 as
3 select 441132394629 cli, to_date('02102006 17:30','ddmmyyyy HH24:MI') call_date from dual union all
4 select 441132394629, to_date('05102006 17:00','ddmmyyyy HH24:MI ') from dual union all
5 select 441132533793, to_date('04102006 14:30','ddmmyyyy HH24:MI ') from dual union all
6 select 441132533793, to_date('05102006 12:20','ddmmyyyy HH24:MI ') from dual union all
7 select 441142373223, to_date('04102006 10:30','ddmmyyyy HH24:MI ') from dual union all
8 select 441142373223, to_date('05102006 13:50','ddmmyyyy HH24:MI ') from dual union all
9 select 441227763301, to_date('02102006 16:30','ddmmyyyy HH24:MI ') from dual union all
10 select 441227763301, to_date('04102006 11:20','ddmmyyyy HH24:MI ') from dual union all
11 select 441227763301, to_date('05102006 17:20','ddmmyyyy HH24:MI ') from dual union all
12 select 441227763301, to_date('08102006 17:30','ddmmyyyy HH24:MI ') from dual
13 /

Have you see my answer in Re: Total call Date report using increment date ?<br>
<br>
Nicolas.

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Perry
Solved!
Go to Solution.
Attachments:
Keithley 24XX Sweep and Acquire Measurements.vi ‏26 KB

As Dennis said, if you're using the built-in sweep function, you'll have to check the manual. See Section 10-16 (That's section 10 page 16, not sections 10 though 16) of the Keithley 2400 User Manual.
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Hi Jaggy99,
According to your description, you need to get the date difference between a given date and the last day of that month, right?
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Take out time difference from 2 dates....

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